Title: GASES AND KINETICMOLECULAR THEORY
1CHAPTER 12
- GASES AND KINETIC-MOLECULAR THEORY
2CHAPTER GOALS
- Comparison of Solids, Liquids, and Gases
- Composition of the Atmosphere and Some Common
Properties of Gases - Pressure
- Boyles Law The Volume-Pressure Relationship
- Charles Law The Volume-Temperature
Relationship The Absolute Temperature Scale - Standard Temperature and Pressure
- The Combined Gas Law Equation
- Avogadros Law and the Standard Molar Volume
3CHAPTER GOALS
- Summary of Gas Laws The Ideal Gas Equation
- Determination of Molecular Weights and Molecular
Formulas of Gaseous Substances - Daltons Law of Partial Pressures
- Mass-Volume Relationships in Reactions Involving
Gases - The Kinetic-Molecular Theory
- Diffusion and Effusion of Gases
- Real Gases Deviations from Ideality
4Comparison of Solids, Liquids, and Gases
- The density of gases is much less than that of
solids or liquids.
- Gas molecules must be very far apart compared to
liquids and solids.
5Composition of the Atmosphere and Some Common
Properties of Gases
Composition of Dry Air
6Pressure
- Pressure is force per unit area.
- lb/in2
- N/m2
- Gas pressure as most people think of it.
7Pressure
- Atmospheric pressure is measured using a
barometer. - Definitions of standard pressure
- 76 cm Hg
- 760 mm Hg
- 760 torr
- 1 atmosphere
- 101.3 kPa
Hg density 13.6 g/mL
8Boyles Law The Volume-Pressure Relationship
- V ? 1/P or
- V k (1/P) or PV k
- P1V1 k1 for one sample of a gas.
- P2V2 k2 for a second sample of a gas.
- k1 k2 for the same sample of a gas at the same
T. - Thus we can write Boyles Law mathematically as
P1V1 P2V2
9Boyles Law The Volume-Pressure Relationship
- Example 12-1 At 25oC a sample of He has a volume
of 4.00 x 102 mL under a pressure of 7.60 x 102
torr. What volume would it occupy under a
pressure of 2.00 atm at the same T?
10Boyles Law The Volume-Pressure Relationship
- Notice that in Boyles law we can use any
pressure or volume units as long as we
consistently use the same units for both P1 and
P2 or V1 and V2. - Use your intuition to help you decide if the
volume will go up or down as the pressure is
changed and vice versa.
11Charles Law The Volume-Temperature
Relationship The Absolute Temperature Scale
absolute zero -273.15 0C
12Charles Law The Volume-Temperature
Relationship The Absolute Temperature Scale
- Charless law states that the volume of a gas is
directly proportional to the absolute temperature
at constant pressure. - Gas laws must use the Kelvin scale to be correct.
- Relationship between Kelvin and centigrade.
13Charles Law The Volume-Temperature
Relationship The Absolute Temperature Scale
- Mathematical form of Charles law.
14Charles Law The Volume-Temperature
Relationship The Absolute Temperature Scale
- Example 12-2 A sample of hydrogen, H2, occupies
1.00 x 102 mL at 25.0oC and 1.00 atm. What
volume would it occupy at 50.0oC under the same
pressure? - T1 25 273 298
- T2 50 273 323
15Standard Temperature and Pressure
- Standard temperature and pressure is given the
symbol STP. - It is a reference point for some gas
calculations. - Standard P ? 1.00000 atm or 101.3 kPa
- Standard T ? 273.15 K or 0.00oC
16The Combined Gas Law Equation
- Boyles and Charles Laws combined into one
statement is called the combined gas law
equation. - Useful when the V, T, and P of a gas are changing.
17The Combined Gas Law Equation
- Example 12-3 A sample of nitrogen gas, N2,
occupies 7.50 x 102 mL at 75.00C under a pressure
of 8.10 x 102 torr. What volume would it occupy
at STP?
18The Combined Gas Law Equation
- Example 12-4 A sample of methane, CH4, occupies
2.60 x 102 mL at 32oC under a pressure of 0.500
atm. At what temperature would it occupy 5.00 x
102 mL under a pressure of 1.20 x 103 torr? - You do it!
19The Combined Gas Law Equation
20Avogadros Law and theStandard Molar Volume
21Avogadros Law and theStandard Molar Volume
- Avogadros Law states that at the same
temperature and pressure, equal volumes of two
gases contain the same number of molecules (or
moles) of gas. - If we set the temperature and pressure for any
gas to be STP, then one mole of that gas has a
volume called the standard molar volume. - The standard molar volume is 22.4 L at STP.
- This is another way to measure moles.
- For gases, the volume is proportional to the
number of moles. - 11.2 L of a gas at STP 0.500 mole
- 44.8 L ? moles
22Avogadros Law and theStandard Molar Volume
- Example 12-5 One mole of a gas occupies 36.5 L
and its density is 1.36 g/L at a given
temperature and pressure. (a) What is its molar
mass? (b) What is its density at STP?
23Summary of Gas LawsThe Ideal Gas Law
- Boyles Law - V ? 1/P (at constant T n)
- Charles Law V ? T (at constant P n)
- Avogadros Law V ? n (at constant T P)
- Combine these three laws into one statement
- V ? nT/P
- Convert the proportionality into an equality.
- V nRT/P
- This provides the Ideal Gas Law.
- PV nRT
- R is a proportionality constant called the
universal gas constant.
24Summary of Gas LawsThe Ideal Gas Law
- We must determine the value of R.
- Recognize that for one mole of a gas at 1.00 atm,
and 273 K (STP), the volume is 22.4 L. - Use these values in the ideal gas law.
25Summary of Gas LawsThe Ideal Gas Law
- R has other values if the units are changed.
- R 8.314 J/mol K
- Use this value in thermodynamics.
- R 8.314 kg m2/s2 K mol
- Use this later in this chapter for gas
velocities. - R 8.314 dm3 kPa/K mol
- This is R in all metric units.
- R 1.987 cal/K mol
- This the value of R in calories rather than J.
26Summary of Gas LawsThe Ideal Gas Law
- Example 12-6 What volume would 50.0 g of ethane,
C2H6, occupy at 1.40 x 102 oC under a pressure of
1.82 x 103 torr? - To use the ideal gas law correctly, it is very
important that all of your values be in the
correct units! - T 140 273 413 K
- P 1820 torr (1 atm/760 torr) 2.39 atm
- 50 g (1 mol/30 g) 1.67 mol
27Summary of Gas LawsThe Ideal Gas Law
28Summary of Gas LawsThe Ideal Gas Law
- Example 12-7 Calculate the number of moles in,
and the mass of, an 8.96 L sample of methane,
CH4, measured at standard conditions. - You do it!
29Summary of Gas LawsThe Ideal Gas Law
30Summary of Gas LawsThe Ideal Gas Law
- Example 12-8 Calculate the pressure exerted by
50.0 g of ethane, C2H6, in a 25.0 L container at
25.0oC. - You do it!
31Determination of Molecular Weights and Molecular
Formulas of Gaseous Substances
- Example 12-9 A compound that contains only
carbon and hydrogen is 80.0 carbon and 20.0
hydrogen by mass. At STP, 546 mL of the gas has
a mass of 0.732 g . What is the molecular (true)
formula for the compound? - 100 g of compound contains 80 g of C and 20 g of
H.
32Determination of Molecular Weights and Molecular
Formulas of Gaseous Substances
33Determination of Molecular Weights and Molecular
Formulas of Gaseous Substances
34Determination of Molecular Weights and Molecular
Formulas of Gaseous Substances
- Example 12-10 A 1.74 g sample of a compound that
contains only carbon and hydrogen contains 1.44 g
of carbon and 0.300 g of hydrogen. At STP 101 mL
of the gas has a mass of 0.262 gram. What is its
molecular formula? - You do it!
35Determination of Molecular Weights and Molecular
Formulas of Gaseous Substances
36Determination of Molecular Weights and Molecular
Formulas of Gaseous Substances
37Daltons Law of Partial Pressures
- Daltons law states that the pressure exerted by
a mixture of gases is the sum of the partial
pressures of the individual gases. - Ptotal PA PB PC .....
38Daltons Law of Partial Pressures
- Example 12-11 If 1.00 x 102 mL of hydrogen,
measured at 25.0 oC and 3.00 atm pressure, and
1.00 x 102 mL of oxygen, measured at 25.0 oC and
2.00 atm pressure, were forced into one of the
containers at 25.0 oC, what would be the pressure
of the mixture of gases?
39Daltons Law of Partial Pressures
- Vapor Pressure is the pressure exerted by a
substances vapor over the substances liquid at
equilibrium.
40Daltons Law of Partial Pressures
- Example 12-12 A sample of hydrogen was collected
by displacement of water at 25.0 oC. The
atmospheric pressure was 748 torr. What pressure
would the dry hydrogen exert in the same
container?
41Daltons Law of Partial Pressures
- Example 12-13 A sample of oxygen was collected
by displacement of water. The oxygen occupied
742 mL at 27.0 oC. The barometric pressure was
753 torr. What volume would the dry oxygen
occupy at STP? - You do it!
42Daltons Law of Partial Pressures
43Mass-Volume Relationships in Reactions Involving
Gases
44Mass-Volume Relationships in Reactions Involving
Gases
- In this section we are looking at reaction
stoichiometry, like in Chapter 3, just including
gases in the calculations.
- 2 mol KClO3 yields 2 mol KCl and 3 mol O2
- 2(122.6g) yields 2 (74.6g) and 3
(32.0g) - Those 3 moles of O2 can also be thought of as
- 3(22.4L) or 67.2 L at STP
45Mass-Volume Relationships in Reactions Involving
Gases
- Example 12-14 What volume of oxygen measured at
STP, can be produced by the thermal decomposition
of 120.0 g of KClO3? - You do it!
46Mass-Volume Relationships in Reactions Involving
Gases
47The Kinetic-Molecular Theory
- The basic assumptions of kinetic-molecular theory
are - Postulate 1
- Gases consist of discrete molecules that are
relatively far apart. - Gases have few intermolecular attractions.
- The volume of individual molecules is very small
compared to the gass volume. - Proof - Gases are easily compressible.
48The Kinetic-Molecular Theory
- Postulate 2
- Gas molecules are in constant, random, straight
line motion with varying velocities. - Proof - Brownian motion displays molecular motion.
49The Kinetic-Molecular Theory
- Postulate 3
- Gas molecules have elastic collisions with
themselves and the container. - Total energy is conserved during a collision.
- Proof - A sealed, confined gas exhibits no
pressure drop over time.
50The Kinetic-Molecular Theory
- Postulate 4
- The kinetic energy of the molecules is
proportional to the absolute temperature. - The average kinetic energies of molecules of
different gases are equal at a given temperature. - Proof - Brownian motion increases as temperature
increases.
51The Kinetic-Molecular Theory
- The kinetic energy of the molecules is
proportional to the absolute temperature. The
kinetic energy of the molecules is proportional
to the absolute temperature. - Displayed in a Maxwellian distribution.
52The Kinetic-Molecular Theory
- The gas laws that we have looked at earlier in
this chapter are proofs that kinetic-molecular
theory is the basis of gaseous behavior. - Boyles Law
- P ? 1/V
- As the V increases the molecular collisions with
container walls decrease and the P decreases. - Daltons Law
- Ptotal PA PB PC .....
- Because gases have few intermolecular
attractions, their pressures are independent of
other gases in the container. - Charles Law
- V ? T
- An increase in temperature raises the molecular
velocities, thus the V increases to keep the P
constant.
53The Kinetic-Molecular Theory
54The Kinetic-Molecular Theory
- The root-mean square velocity of gases is a very
close approximation to the average gas velocity. - Calculating the root-mean square velocity is
simple
- To calculate this correctly
- The value of R 8.314 kg m2/s2 K mol
- And M must be in kg/mol.
55The Kinetic-Molecular Theory
- Example 12-17 What is the root mean square
velocity of N2 molecules at room T, 25.0oC?
56The Kinetic-Molecular Theory
- Example 12-18 What is the root mean square
velocity of He atoms at room T, 25.0oC? - You do it!
57The Kinetic-Molecular Theory
- Can you think of a physical situation that proves
He molecules have a velocity that is so much
greater than N2 molecules? - What happens to your voice when you breathe He?
58Diffusion and Effusion of Gases
- Diffusion is the intermingling of gases.
- Effusion is the escape of gases through tiny
holes.
59Diffusion and Effusion of Gases
- This is a demonstration of diffusion.
60Diffusion and Effusion of Gases
- The rate of effusion is inversely proportional to
the square roots of the molecular weights or
densities.
61Diffusion and Effusion of Gases
- Example 12-15 Calculate the ratio of the rate of
effusion of He to that of sulfur dioxide, SO2, at
the same temperature and pressure.
62Diffusion and Effusion of Gases
- Example 12-16 A sample of hydrogen, H2, was
found to effuse through a pinhole 5.2 times as
rapidly as the same volume of unknown gas (at the
same temperature and pressure). What is the
molecular weight of the unknown gas? - You do it!
63Real Gases Deviations from Ideality
- Real gases behave ideally at ordinary
temperatures and pressures. - At low temperatures and high pressures real gases
do not behave ideally. - The reasons for the deviations from ideality are
- The molecules are very close to one another, thus
their volume is important. - The molecular interactions also become important.
64Real GasesDeviations from Ideality
- van der Waals equation accounts for the behavior
of real gases at low temperatures and high
pressures.
- The van der Waals constants a and b take into
account two things - a accounts for intermolecular attraction
- b accounts for volume of gas molecules
- At large volumes a and b are relatively small and
van der Waals equation reduces to ideal gas law
at high temperatures and low pressures.
65Real GasesDeviations from Ideality
- What are the intermolecular forces in gases that
cause them to deviate from ideality? - For nonpolar gases the attractive forces are
London Forces - For polar gases the attractive forces are
dipole-dipole attractions or hydrogen bonds.
66Real GasesDeviations from Ideality
- Example 12-19 Calculate the pressure exerted by
84.0 g of ammonia, NH3, in a 5.00 L container at
200. oC using the ideal gas law. - You do it!
67Real GasesDeviations from Ideality
- Example 12-20 Solve Example 12-19 using the van
der Waals equation.
68Real GasesDeviations from Ideality
69End of Chapter 12
- Gases are the simplest state of matter.
- Liquids and solids are more complex.
- They are the subject of Chapter 13.