Title: Chapter 5: Thermochemistry
1Chapter 5 Thermochemistry
2Thermochemistry
- In most chemical reactions, energy is absorbed or
released. - Thermochemistry is the correlation of chemical
processes and energy changes.
3Energy
- The capacity to do work or to produce heat.
4Law of Conservation of Energy
- Energy can be converted from one form to another
but can neither be created nor destroyed. - (Euniverse is constant)
5Two Types of Energy
- Kinetic energy - The energy of a particle by
virtue of its motion
EK ½ mv2
- Potential energy The energy of position
relative to other objects.
PE mgh
6System and Surroundings
- The system is a well-defined part of the universe
singled out for study. - The surroundings is the remainder of the
universe. - In a closed system energy, but not matter,
can be exchanged with the surroundings.
Closed System
7First Law of Thermodynamics
- There are essentially two ways to change the
energy of a system - heat (q) and work (w). - Our task is to understand how energy exchanges
can occur between system and its surroundings
Delta E change of internal energy
Energy is conserved!
8Heat and work
- Heat (q) is a form of energy transfer
- Units 1 calorie (cal) 4.184 J
- Energy used to cause the temperature of an
object to increase - Example combustion releases the energy stored in
molecules in the form of heat - Work (w) is exertion of a force over a distance.
- We will only consider expansion work
- w - PDV where P ?
pressure - V
? volume
9Heat
- q gt 0 Heat is transferred from
surroundings to system. Process is
endothermic. - q lt 0 Heat is transferred from system to
surroundings. Process is exothermic. Å
Surroundings
System
10Work
- work force ? distance
- since pressure force / area,
- work pressure ? volume
- wsystem ?P?V
11Potential Energy due to gravity
Potential energy converted to kinetic energy
As ball strikes ground, kinetic energy used to
do work in squashing the ball the rest is given
off as heat
12Internal Energy
- Internal energy (E) - The combined kinetic and
potential energies of all particles in a system. - The internal energy of a system is usually not
known. But energy changes can be measured. - DE Efinal - Einitial
?E mg(hf - hi)
13Å
14Relating ?E to heat and work
?E q w
15Work
- w gt 0 Surroundings does work on system.
- w lt 0 System does work on surroundings. Å
- We will only consider expansion work
- w - PDV where P ?
pressure - V
? volume
16State Functions
- State function - A property of a system that
depends only on its present state. - The change in a state function does not depend on
how the process is carried out.
?E is a State Function
The water could have reached 50C from either
direction
17Path Functions
- Work (w) and heat (q) are not state functions
because they depend on how the process is carried
out
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19First Law Example
What is ?E if 100 kJ of heat is added to a rigid
container of gas with a pressure of 10 psi?
?E q w
q - P?V
Since the volume doesnt change, ?V 0
?E q
100 kJ
20First Law Example
- What is DE if an insulated system at 1.0 atm
expands by a volume of 1.0 L?
V2 - V1 1.0 L
?E q w q - P?V
-P?V
Since no heat is transferred, q 0.
-1.0 L?atm
? 1.0 L
?E -1.0 atm
21Enthalpy
- Enthalpy H E PV
- ?E ?H ? P?V
- ?H ?E P?V
- At constant pressure,
- qP ?E P?V,
- where qP ?H at constant pressure
- ??H energy flow as heat (at constant
pressure)
22The Enthalpy
- Enthalpy (H) is a state function defined as
- H E PV
- At constant pressure, the change in enthalpy is
- DH H2 - H1 E2 PV2 - (E1 PV1)
- DH DE PDV
- From the First Law DE q - PDV
- DH q (constant P)
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24Chemical Energy
- The energy stored within substances and given off
when they take part in chemical reactions. - Can be converted to different forms of energy
- Burning fuel ? Heat ? electricity ? light
- Energy can neither be created or destroyed!
25Energy and Enthalpy
- Energy and enthalpy are numerically similar and
have energy units. (If DV 0, DH DE.) - Each is equal to q depending on how a process is
carried out - Constant volume qV DE
- Constant pressure qP DH
- Since most reactions are carried out at constant
pressure, DH is the more useful quantity.
26Enthalpies of Reaction
- The enthalpy change for a chemical reaction is
defined as - DH Hproducts - Hreactants
- A thermochemical equation includes the DH value
for stoichiometric quantities of reactants and
products. - CH4(g) 2 O2(g) CO2(g) 2 H2O(g)
DH -802 kJ
27Examples
- What is the sign of ?H for
- SO3-2(aq) OCl?(aq) ? SO4-2(aq) Cl?(aq)
?H 0
lt
28Examples
- What is the sign of ?H for
- NH4NO3(s) ? NH4(aq) NO3?(aq) ?H 0
gt
29Enthalpy Diagrams
- An enthalpy diagram shows H for the initial and
final states of a process.
- At constant pressure, q DH -802 kJ.
30Enthalpies of Reaction
- The enthalpy change depends on the states of
reactants and products. - CH4(g) 2 O2(g) CO2(g) 2 H2O(l) DH
-890 kJ
31Enthalpies of Reaction
- DH for a reaction is opposite in sign to DH for
the reverse reaction.
- CO2(g) 2 H2O(g) CH4(g) 2 O2(g) DH
802 kJ
32Enthalpies of Reaction
- H is an extensive property, so DH depends on the
amounts of reactants and products. - What is DH for the combustion of 11.0 g of CH4 in
excess oxygen? - CH4(g) 2 O2(g) CO2(g) 2 H2O(g) DH
-802 kJ
-550 kJ
11.0 g CH4
33Enthalpies of Reaction
- DH is a conversion factor between heat
transferred and moles of substance. - What mass of butane must react in order to
produce 100 kJ of heat? - 2 C4H10(g) 13 O2(g) 8 CO2(g) 10 H2O(g)
DH -5317 kJ
2.19 g C4H10
100 kJ
34Heat and Temperature Change
- How is heat transferred related to the change in
temperature of a system with mass m? - q specific heat ? m ? ?T
- The specific heat of a substance is the amount of
heat required to raise the temperature of 1 gram
by 1 K. - Hg 0.14 J/g?K
- Al 0.90 J/g?K
- H2O 4.18 J/g?K
35Heat and Temperature Change
- How much heat is required to raise the
temp-erature of 12.5 g H2O from 20.0C to 30.0C?
q specific heat ? m ? ?T
?12.5 g
?10.0 K
522 J
- What is the specific heat of iron if 540 J of
heat increases the temperature of 48.0 g by 25C?
0.45 J/g?K
specific heat
36Calorimetry
- A calorimeter measures the amount of heat
transferred during a reaction.
A simple constant- Pressure calorimeter
37Calorimeter Constant
- Some of the heat from your reaction will be
absorbed by the calorimeter - The heat lost to the calorimeter must be
accounted for - To determine Ccal, use the equation
-
- (mh)(sp.ht)(?Th) -(mc)(sp.ht.)(? Tc) Ccal ?
Tc - Solve for Ccal
38Bomb CalorimetryConstant Volume Calorimetry
- Reaction carried out under constant volume.
- Use a bomb calorimeter.
- Usually study combustion.
39Hesss Law
- Consider a reaction carried out in two steps.
What is ?H? - C(s) ½ O2(g) CO(g) DH1 -110 kJ
- CO(g) ½ O2(g) CO2(g) DH2 -283 kJ
- ____________________ __________
- C(s) O2(g) CO2(g) DH
- For a reaction carried out in a series of steps,
DH is the sum of enthalpy changes for the
individual steps.
-393 kJ
40Hesss Law
- Hesss law is based on the concept of enthalpy as
a state function.
Å
41 ?H1 ?H2 ?H3
42Formation Reactions
- Thermochemical data is provided in terms of
formation reactions. - Formation reaction The formation of one mole of
a substance from its elements in their standard
states (stable form at 25 and 1 atm) - What is the formation reaction for CaCO3(s)?
CaCO3(s)
Ca(s)
C(graphite)
3/2 O2(g)
43Standard Enthalpies of Formation, ???Hf, at 298 K
44Standard Enthalpy of Formation
- The standard enthalpy of formation, DHfº, of a
substance is the ?H? of its formation reaction. - Ca(s) C(graphite) 3/2 O2(g) CaCO3(s)
-
DHf(CaCO3,s) -1207 kJ - Ca(s) ½ O2(g) CaO(s) DHf(CaO,s) -636 kJ
- C(graphite) O2(g) CO2(g)
-
DHf(CO2,g) -394 kJ
45Standard Enthalpy of Formation
- What is DHf(O2,g)?
- O2(g) O2(g)
?H? 0
?Hf is zero for an element in its standard form.
- What is ?Hf(C,diamond)?
- C(graphite) ? C(diamond)
?H? 1.9 kJ
- What is ?Hf(Cl,g)?
- ½ Cl2(g) ? Cl(g)
?H? 122 kJ See Appendix
46Standard Enthalpy of Reaction
- Hesss Law can be used to find DHº for
- CaCO3(s) CaO(s) CO2(g)
DHº DHf(CaO,s) DHf(CO2,g) - DHf(CaCO3,s)
47Standard Enthalpy of Reaction
- In general, DH is given by
- DH å n DHf(products) - å n DHf(reactants)
- The ?H? value assumes reactants and products are
at the same temperature. - Since DHf values are tabulated at 25ºC, we can
only calculate DH at this temperature.
48Standard Enthalpy of Reaction
- Calculate DH at 25 for
- H(aq) OH?(aq) H2O(l)
- DH DHf(H2O,l) - DHf(H,aq) - DHf(OH?,aq)
- -285.83 kJ
- (-230.0 kJ)
-55.8 kJ
- 0
Experimental value
DH -58 kJ
49Standard Enthalpy of Reaction
- What is ?H? for combustion of C4H10? You try
- C4H10(g) 6½ O2(g) 5 H2O(l) 4 CO2(g)
?H?
5 ?Hf?(H2O,l)
4 ?Hf?(CO2,g)
- ?Hf?(C4H10,g)
- 6½ ?Hf?(O2,g)
4(-393.5)
5(-285.83)
- (-124.73)
- 6½(0)
kJ
-2878 kJ
50Standard Enthalpy of Reaction
- DH for combustion of C6H12O6 (glucose) is
-2816 kJ. What is DHf for glucose? You try - C6H12O6(s) 6 O2(g) 6 CO2(g) 6 H2O(l)
6 ?Hf?(CO2,g)
6 ?Hf?(H2O,l)
?H?
- ?Hf?(C6H12O6,s)
- 6 ?Hf?(O2,g)
- ?H?
6?Hf?(CO2,g)
6?Hf?(H2O,l)
?Hf?(C6H12O6,s)
6(-285.8)
- 6(0)
6(-393.5)
- (-2816)
kJ
-1260 kJ
51Combustion Reactions
- Combustion reactions are exothermic because of
the strong bonds formed in CO2 and H2O. - Fuels such as coal, petroleum, and
natural gas have high percentages
of carbon.
Sources of Energy consumed in US
52Energy Content of Foods
- Chemical energy in animals is derived from
carbohydrates, fats, and proteins. - Fuel value (kJ/g)
- Carbohydrates 17
- Fat 38
- Protein 17
- Fuel value is usually expressed in kcal or Cal
per serving. - 1 Cal 1 kcal 4.184 kJ
53Energy Content of Foods
- If a person uses about 420 kJ/mi when running,
how many candy bars are required to run three
miles? - 1 Butterfinger
- 42 g carbohydrates
- 11 g fat
- 3 g protein
- 56 g
710 kJ
420 kJ
50 kJ
1180 kJ