Title: OXIDATION REDUCTION REACTIONS
1OXIDATION - REDUCTION REACTIONS
- Assigned reading Sparks Chapter 8, pp 245 - 255
and Lindsay pp.23-30 - Additional reading McBride 1.2f, 7.1a, b and
e, 7.2 Sposito Chap. 6 and Essington Chap. 9.
2Introduction
- Importance of biological reactions
- Oxidation and reduction reactions in soils are to
a great extent biologically mediated. - Redox reactions require an oxidizing agent
(electron acceptor) and reductant (electron
donor).
3- The scale of potential were developed assuming
- H e- 1/2 H2 Eo 0.00V
- The ?Go for this reaction is zero.
4Electrode potential Measurements
- Electrode Potentials
- Standard Electrode Potential (EHo)
- Example Reduction of Fe3
- Fe3 e- Fe2 Eo 0.771 V
- oxidize reduced
5- Defined vs. Standard Hydrogen Electrode
- H e- 1/2 H2 Eo 0.000
- Note This also defines the ? Gf 0 for H
- The overall reaction is
- Fe3 1/2H2 Fe2 H
6Basic Cell for Measurement of Electrode Potentials
SHE Half Cell
7- Half-cell Electrode Potentials (EH)
- Calculate the potential at other than standard
conditions. - Nernst equation
- Note the negative sign
8 9- At equilibrium with respect to SHE , EH 0 and
?G 0 and - and
10 11- Then the relationship between ?Go and Eo is
- ?Go -nFEo
- also
- ?G -nFEH
12Half-Cell Reactions of Common Electron Acceptors
in Soils
- Oxidized mH n electrons reduced H2O
- Nernst equation
- At 25 0C
RT
(reduced)
-
o
E
E
ln
H
m
nF
(oxidized)(H
)
13In Volts
14In millivolts
15Eo values for reactions in soils (McBride, Table
7.1)
16EH vs pH (Mcbride Figure 7.1)
17Sparks Fig 8.1
18Boundary reactions for electron acceptors that
limit EH in aqueous systems
- Upper boundary redox in water
- 1/4 O2 H e- 1/2 H2O Eo 1.23v
- Oxygen is an electron acceptor
- Lower boundary
- H e- 1/2 H2 Eo 0.00v
- Hydrogen is an electron acceptor
19Half Cell Reaction involving Organic Electron
Donors e. g. Glucose
- Organic electron donors supply the energy to
microbes in soils and sediments. The reaction
below is a half-reaction that illustrates this
process. In the soil the reaction goes from
right to left. - 1/4 CO2 H e- 1/24 C6H12O6 1/4 H2O
- EHo -0.014
- Carbon compounds are abundant electron donors in
soils
20Reaction in airSucrose donates ectrons to oxygen
- 1/4 O2 H e- 1/2 H2O Eo
1.23V - 1/24 C6H12O6 1/4 H2O 1/4 CO2 H e-
0.014 V - 1/24 C6H12O6 1/4 O2 1/4 CO2 1/4 H2O
1.24 V.
21"Electron Activity" (pe)
- We can imagine that electrons have a measurable
activity and use -log (e) pe, instead of EH. - For a half cell reaction.
- oxidized mH ne reduced
-
22"Electron Activity" (pe) (cont.)
- at 25C
- Let pe -log(e-)
- then
(reduced)
-
logK
nlog(e
)
log
mlog(H
)
-
-
(oxidized)
23"Electron Activity" (pe) (cont.)
- log K is sometimes called pe0
- Remember Electron activity is a convenient
fiction, not a physical reality.
24We also included protons in the Nernst equation
25Comparison of the Nernst and pe equations
26Equate the two equations
27At 25 C
28pe can easily be calculated from EH
29Combining half cell reactions to describe a
complete reaction.
- Question What is the equilibrium constant for
the oxidation of Fe2 by O2? - log K
- Fe2 e- Fe3 -13.04
- H 1/4O2 e- 1/2H2O 20.78
- --------------------------------------------------
------------- - H 1/4O2 Fe2 1/2H2O Fe3 7.74
- This equation says that O2 can readily oxidize
Fe2 at acid pH values
30Combining half cell reactions (cont.)
- log K pH -1/4log Po2 log(Fe3)/(Fe2)
31Combining half cell reactions (cont.)
- Find the pH at which (Fe3) (Fe2) at Po2
0.21 atm
32Answer
33Combining half cell reactions with solubility
reactions
- If (Fe3) is controlled by the solubility of
Fe(OH)3 in a soil then under reducing (flooded
soil) conditions Fe2 can be calculated as a
function of pH and EH. - Fe(OH)3 3H Fe3 3H2O log K 2.70
(Lindsay) - Predict Fe2 as a function of pe in soil
34Combining half cell reactions with solubility
reactions(cont.)
- log K
- Fe3 e- Fe2 13.04
- Fe(OH)3 3H Fe3 3H2O 2.70
- Soil
- --------------------------------------------------
-------------------- - Fe(OH)3 e- 3H Fe2 3H2O 15.74
- EH 0.93 V
- Similar to the value of pe in Sparks Table 1
- McBride Table 1 is different (is for freshly ppt
Fe(OH)3)
35Combining half cell reactions with solubility
reactions(cont.)
36Combining half cell reactions with solubility
reactions(cont.)
- If measured pH 7.0 and
- (Fe2) 1.0 x 10-5 M, what is pe?
37Answer
- pe 15.74 5 - 3(7)
- pe 15.74 - 16.0
- pe -0.26 and EH -0.014
38Combining half cell reactions with solubility
reactions(cont.)
- Plot pe (or EH) vs. pH
- Example Fe(OH)3 3H e- Fe2 3H2O
- pe log K - 3pH - log(Fe2)
- at log (Fe2) -5
- pe 20.74 - 3pH
39McBride Fig. 7.1
40pe - pH plot for Fe
41Consequences of flooding a soil
- 1. Oxygen is depleted.
- 2. Obligate and facultative anerobes utilize
other electron acceptors. - In order they are , nitrate, MnO2 , Fe(OH)3 and
other oxides of FeIII, and sulfate. - At very low EH methane is produced.
42Compare reactions using conditional log K (log
cK7.0 or Log Kw) at pH 7.0
- Conditional constants for pH dependent reactions
can be recalculated for pH 7.0 log(H) -7. - This allows for ranking of redox reactions at
near neutral pH values. - For reaction (1)
- log K pe pH - 1/4 log PO2
43Reactions in Flooded SoilsSee Sparks Table 8.7
- Note Sparks assumes soluble FeII and MnII
10-4M (Lindsay uses 10-5 - Electron acceptors Electron donors
- pe at pH 7
- logK logcK7.0
- (1) 1/4 O2(g) H(aq) e- 1/2 H2O 20.8
13.6 - (2) 1/4 NO3- 5/4 H e- 1/8 N2O(g) 5/8
H2O 18.9 9.6
44- (3) 1/2 MnO2 2H e 1/2 Mn2 H2O
- 20.7 8.8
- (4) Fe(OH)3 3H e- Fe2 3H2O
15.8 -1.2 - (5) 1/8 SO42- 5/4 H e- 1/8 H2S(aq) 1/2
H2O 5.2 -3.5
45- (6) 1/8 CO2(g) e- H 1/8 CH4(g) 1/2
H2O 2.9 -4.1 - (7) 1/4 CO2(g) e- H 1/24 C6H12O6
1/4H2O -0.2 -7.2 - (8) H e- 1/2 H2 0.0 -7.0
46Oxygen consumption in by organic carbon, when O2
is the electron acceptor
- Oxidation of organic carbon in soils generates
energy for microorganisms. - The most energy is gained by using electron
acceptors with highest log K (E0) . - Example, sucrose
- Combine reaction (1) with reaction (7)
- 1/24 C6H12O6 1/4 O2(g) 1/4 CO2(g) 1/4 H2O
- log K 21.0
- oxidation ---gt
- lt------ photosynthesis
47Can calculate ?Go fromlog K or E0
48Using nitrate as an electron acceptor
- Combine with reaction 7 and 2
- 1/24 C6H12O6(aq) 1/4 NO3- 1/4 H 1/8 N2O(g)
3/8 H2O log K 19.1 - Can calculate Gibbs free energy
- ?G - 109.2 kJ/mole
49When all electron acceptors are depleted then
fermentation
- Combine with reaction 7 and 6
- 1/24 C6H12O6(aq) 1/8 CH4(g) 1/8 CO2(g)
- log K 3.1
- eg. In methane digester or soil flooded for a
long time. - Low energy yield.
50Review of consequences of flooding a soil
- With flooding O2 is used up because O2 diffusion
in water is very slow. - When O2 is depleted NO3- becomes the electron
acceptor which yields the most energy, - This followed followed by MnO2, Fe(OH)3, and then
SO42-. - Kinetic considerations can be important.
- Thus, Fe(OH)3 reduction can begin before all of
the MnO2 is depleted. - Because of pH dependence, the exact order of
these reactions can vary slightly with pH,
51McBride Figure 7.1
52Chemical changes after flooding of a soil
(Sposito chapter 6)
53Changes in N chemistry with flooding (Sposito
Chapter 6)
54Changes in N chemistry with flooding (Sposito
Chapter 6)
55Determination of EH
- Measurements
- Use a bright Pt electrode and a reference
electrode. Essington suggests the use of a
Calomel (Hg2Cl2/Hg) electrode. In fact, most
people use an AgCl/Ag electrode.
56Reference electrode
- log K
- AgCls e- Ags Cl- 3.75
- Inside the electrode is an Ag plated wire with
AgCl and a fixed KCl concentration. The KCl is
generally in the range of 3 M to saturated.
Potential is about 0.2 v. (Compare to standard)
57Use reference electrode
- Measure E vs. the above electrode then add 0.2 V
to get EH - In practice standardize meter and reference
electrode vs. a solution like quihydrone
quinone/hydroquinone 1.0 - (at pH 4.01)
- EH 0.461v
58Reference standardQuinhydrone reaction
- 2H 2e- ?
H2O -
- quinone hydroquinone
59What does a Pt electrode measure in soils?
- Measures EH only of electrode reactive reactions
(electrons can be transferred to or from
electrode). - Fe3 gt Fe2 is electrode reactive.
- 1/4 O2 H e- 1/2 H2O is not
- Cant measure O2 in soils or waters using Pt
electrodes - Sucrose gtH2O and CO2 is not electrode reactive.
60Electrode data allows for general statements
about redox status McBride (Fig.7-6)
61Range of measured pe and pH in soils
62Reactions in flooded soils vs. measured EH (Fig.
7.5)
63Compare to EH - pH diagrams McBride Fig. 7.1
64 pH Changes Following Flooding
- In low pH soils the pH increases to near
neutrality because H is consumed during the
reduction of most electron acceptors. Most
notably - 3H Fe(OH)3 e- Fe2 3H2O
- In calcareous soils pH decreases because of the
precipitation of carbonates at the high Pco2. - Ca2 H2O CO2 CaCO3 2H
65pH Changes Following Flooding (cont.)
- Also Mn(II) and Fe(II) carbonates precipitate
- Siderite, FeCO3
- Rhodochrosite, MnCO3,
- These minerals are important in controlling the
pH in many flooded soils. - These minerals both have a calcite type
structure with very similar unit cell sizes.
They form a solid solution series.
66Precipitation of Siderite
-
- log K
- Fe2 CO32- FeCO3 10.8
- H2O CO2 H HCO3- - 7.81
- HCO3- H CO32- -10.33
- --------------------------------------------------
----- - Fe2 H2O CO2 2H FeCO3 - 7.34
67 FeCO3 (cont.)
- From earlier slide
- Fe(OH)3 e- 3H Fe2 3H2O 15.74
- soil
- Fe2 H2O CO2 2H FeCO3 - 7.34
- --------------------------------------------------
------------------ - Fe(OH)3 e- CO2 H FeCO3 2H2O 8.40
68Example, FeCO3 (cont.)
- log K pH pe - log Pco2
- Thus at equilibrium pe is a function of pH and
Pco2, only. - Set the PC02 then calc. pH
- At pH 7.0 and Pco2 0.10
- pe log K - pH log Pco2
- pe 8.40 - 7.0 - 1.0
- pe 0.4
- EH (0.059)( 0.4) - 0.024 V
69pe - pH plot for Fe
70Sulfide precipitation in reduced soils
- Sulfate is reduced to S2- and can precipitate
with Fe2, Mn2, Zn2, Cd2 etc. - FeS is the predominant form of sulfide.
- Sulfide formation can reduce the bioavailablity
of heavy metals.
71Formation of sulfidic coastal swamps
72Formation of acid sulfate soils by draining
sulfidic swamps
73Formation of surface oxic layer in flooded soils
- Slow O2 diffusion can result in an oxic surface.
- The thickness of the layer is result of the O2
diffusion rate and O2 consumption rate. - In low OM mineral soils this layer may be gt 1 cm
- In high OM soil it may be only a few mm thick.
74Oxic surface in a rice paddy soil
75N transformations in the surface of a rice paddy
soil
76Phosphate is generally released by flooding
- Flooding releases P by
- 1. Raising pH of acid soils.
- 2. Lowering the pH of alkaline soils.
- 3. Reduction Fe(III) oxides that sorb P.
77Reduction Fe(III) phosphate (strengite)
- Fe3 e- Fe2 13.04
- FePO42H2O 2H Fe3 H2PO4- - 6.85
- --------------------------------------------------
------------- - FePO42H2O e- 2H Fe2 H2PO43- 6.19
78Redox reaction of strengite (cont.)
- pe 6.2 - log(Fe2) - log(H2PO4) - 2pH
- Let pH 7.0, (Fe2) 10-5 M, and
- (H2PO43-) 10-5 M
- pe 6.2 5 5 -14 2.2
- EH 0.129v
79Redox reaction of strengite (cont.)
- Comparison with previous computations shows
strengite is reduced at a similar pe as Fe(OH)3 - Reduction of iron oxides releases adsorbed P.
- Drainage and restoration of oxic conditions can
tie up P. - Following draining of rice soils, phosphate can
be tied up causing P deficiency for rotation
crops.
80Short Summary
- The log K (E0) of half cell reactions can be used
to calculate the log K of oxidation reduction
reactions. - EH can be converted to pe.
- The pe values do not represent real activities
of electrons. - Pt electrodes can be use to measure EH in flooded
soils. - The measured EH can only be approximately
predicted from measured concentrations and half
cell reactions.
81- In flooded soils consumption of O2 and other
electron acceptors by oxidation of reduced C
(organic C) lowers pe (EH) - Flooding increases the pH of acid soils and
decreases the pH of calcareous soils. - At very low EH sulfides can precipitate.
- A thin layer on the surface of flooded soils can
be oxic. - Flooding causes the release of bound P.
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