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Synthesis of paminobenzoic acid: Step 2

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We have to oxidize the methyl group in p -acetotoluidide. ... prepared by oxidizing an alkyl side chain on aromatic ring. Carbon on the ring does not oxidize. ... – PowerPoint PPT presentation

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Title: Synthesis of paminobenzoic acid: Step 2


1
Synthesis of p-aminobenzoic acid Step 2
2
Goal
  • We have to oxidize the methyl group in p
    -acetotoluidide.
  • Characterization of the product by Melting Point,
    IR, and 1H NMR.

3
Terms
  • Carboxylic Acid.
  • Oxidation.
  • Coupling constant.

4
Introduction
  • Carboxylic acid is a important family in organic
    chemistry.
  • The name is the contraction of the parts the
    carbonyl and hydroxyl groups.
  • You can write general formula for an organic acid
    in three ways.

5
Sources
  • Carboxylic acid is naturally present in variety
    of eatables and living beings.
  • Stinging Ants, source of formic acid, HCOOH.

6
Sources
  • The root of Garden Heliotrope is a source of
    valeric acid, CH3(CH2)3COOH.

7
Sources
  • The bark of White Willow tree (Salix alba) is a
    source of salicylic acid, HO-C6H4-COOH, from
    which aspirin made.

8
Sources
  • Vinegar Acetic acid
  • Milk Propionic acid
  • Butter Butyric acid

9
Sources
  • The smell from the dirty gym socks and running
    shoes is due Caproic acid, CH3-CH2-CH2-CH2-CH2-COO
    H.

10
Preparation
  • Organic acids can be prepared by many ways
  • 1. Oxidation of primary alcohol or aldehydes.
  • 2. Oxidation of alkyl chain on aromatic rings.
  • 3. Reaction of Grignard reagents with CO2.
  • 4. Hydrolysis of alkyl cyanides.

11
Preparation
  • The most common reagents used for oxidizing
    alcohol to acids are
  • 1. KMnO4
  • 2. CrO3
  • 3. HNO3
  • 4. Ag2O

12
Preparation
  • KMnO4You can easily remove the waste i.e. MnO2.
  • CrO3 It is very difficult to separate chromium
    waste from the solution.
  • HNO3 Some times it may decompose your compound.
  • Ag2O Mild oxidant and it is useful for the
    oxidation of aldehydes to acids.

13
Preparation
  • Grignard reagents add to the carbon dioxide.
  • Hydrolysis of the intermediate (Mg-complex) gives
    the acid.

14
Preparation
  • Reaction with Grignard Reagent
  • You need a ultra dry condition.
  • You should maintain the inert atmosphere.

15
Preparation
  • The cyanide functional group can be hydrolyzed to
    acid.
  • This reaction requires acid or bases.
  • The nitrogen in the cyanide is converted into
    ammonium ion.

16
Preparation
  • Aromatic acids can be easily prepared by
    oxidizing an alkyl side chain on aromatic ring.
  • Carbon on the ring does not oxidize.
  • The reaction involves attack of oxidant at a C-H
    bond adjacent to the benzene ring.

17
Preparation
  • Longer side chains are also oxidized to a
    carboxyl group.

18
Preparation
  • If no C-H bond in the benzylic position (adjacent
    to the benzene ring), however, the aromatic ring
    is oxidized although only under severe reaction
    condition.

19
Preparation
  • Reagents other than KMnO4 for the oxidation of
    alkyl groups are
  • K2Cr2O7 / H2SO4
  • O2 / CH3COOH / Co (III)

20
Procedure
  • Take 3.75 g of p - acetotoluidide in a 500 mL
    Erlenmeyer flask.
  • Add 10 g of magnesium sulfate and 250 mL of
    distilled water.
  • Place it on a steam bath and maintain 85? C.

21
Procedure
  • Make a solution of 10.25 g of KMnO4 in 35 mL of
    hot water (boiling temperature).
  • Add the KMnO4 solution to the p - acetoluidide
    solution in small portions over 30 minutes with
    constant stirring or swirling the flask.

22
Procedure
  • Filter the hot solution using filter paper and
    large funnel.
  • Wash the brown solid with little hot water (may
    be 20 mL)
  • Throw the brown solid to the trash. Why???
  • Brown solid is the MnO2 and it is waste product.
    Our compound is in the solution.

23
Procedure
  • If the filtrate (solution) is not colorless, add
    ethanol in drop wise until the color is
    discharged.
  • Filter the solution again using fresh filter
    paper.

24
Procedure
  • Cool the colorless solution and acidify it using
    20 sulfuric acid till the solution become
    acidic (use Blue litmus or Congo red)
  • You will see a nice white color solid.
  • Filter it using Buchner funnel.
  • Dry them using water suction.

25
Characterization
  • Do the following studies of dry compound.
  • 1. Melting Point.
  • 2. IR spectrum.
  • 3. 1H NMR spectrum.

26
1H NMR
27
1H NMR
  • 1H NMR is the most powerful tool available for
    structural determination of small organic
    compounds.
  • The number of signals shows how many different
    kinds of protons are present.
  • CH3-CH3 1 signal
  • CH3-CH2-Cl 2 signal
  • Benzene 1 signal

28
1H NMR
  • Electron withdrawing group or electronegative
    elements generally cause a downfield chemical
    shift.
  • C-CH3 0.9 ppm
  • CH3-CO 2.0 ppm
  • C-CH2-Cl 3.7 ppm
  • C-CH-Cl2 5.8 ppm
  • CH-Cl3 7.3 ppm

29
1H NMR
  • Hydrogen atom attached to a carbon that is part
    of a multiple bond or aromatic ring usually
    appear downfield.
  • C-CH2-CH2 1.20 1.35 ppm
  • CH2C 4.60 5.00 ppm
  • Benzene 6.60 8.00 ppm

30
1H NMR
  • We can integrate the area under each peak.
  • Peak area is directly proportional to number of
    proton responsible for the particular peak.

31
1H NMR
  • 13C nuclei gives single peak and does not split
    by neighboring 13C nuclei.
  • 1H nuclei signal split by neighboring protons.
  • The splitting pattern gives us information about
    the number of nearest 1H neighbors that a
    particular kind of 1H nucleus may have.

32
1H NMR
  • Chemically equivalent protons do NOT split each
    other.
  • Non equivalent protons on adjacent carbons always
    interact each other.
  • CH3 CH3 Do not split
  • CH3 CH2 - Cl Split each other

33
1H NMR
  • If you DO NOT have protons on neighboring carbon
    atom then the signal will not split.
  • CH3 CO CH2 Cl Do not split

34
1H NMR
  • If a 1H nucleus or a set of equivalent 1H nuclei
    has n 1H neighbors, its NMR signal will be
    split into n1 peaks.
  • CH3CH2O-CH2-CH3
  • CH3-CH2 will be appearing as a triplet.
  • CH3-CH2 will be appearing as a quartet.

35
1H NMR
  • Difference between the peaks of multiplet
    measured in Hz called coupling constant.
  • Not dependent on strength of the external field

36
1H NMR
  • If the chemical shift values are in ppm, then the
    coupling constant is
  • Difference between two peaks x Strength of the
    Magnet
  • The strength of our magnet is 200 MHz.

37
1H NMR
  • -OH, -NH2 protons always appear as a broad
    signal.
  • CH3-OH
  • NH2-CH2-CH2-NH2

38
1H NMR
  • Aldehydes (-CHO) and Carboxylic Acid (-COOH)
    protons are always appear at above 12.0 ppm.

39
1H NMR
  • The handouts have 1H NMR of p-toluidine.
  • Find the coupling constant for the aromatic
    protons.
  • Assign the signals with appropriate protons from
    the chemical shift.

40
1H NMR
  • Record 1H NMR for p - acetoluidide.
  • Find the coupling constant of aromatic 1H.
  • Compare the chemical shift values.
  • Assign the signals.

41
Notes
  • KMnO4 makes stain.
  • Work in pairs (means 2 students).
  • Do not spill the chemicals around the balance.
  • Use spatula to take the chemicals out from the
    container.
  • Do not leave any glass wares around the sink.
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