Title: Rules: Cell phones off
1Biol 423L Laboratories in Genetics
Rules Cell phones off Computers only for
class-related work No food or drink in lab room
Text Book Hartl and Jones Genetics analysis
of genes and genomes Sixth Edition from Jones
and Bartlett publishers 2005. Web page
www.bio.unc.edu/courses/2008Fall/Biol423L
2Goals for course
Reinforce basic genetic principles Introduce
model organisms commonly used by
geneticists Learn how genetics is used to
understand Disease Biochemical
pathways Development
3Lab reports Abstract Introduction Results D
iscussion Course information page has
instructions about preparing your lab reports.
4Grading Lab Reports 50 of grade 5 of that
is participation 1 day late, 50 off more than
that will only be graded under special
circumstances. Research Paper 10 of
grade Topics due Oct. 13. Outline due Oct.
27. Paper due Nov. 24. 2 quizzes 10 each of
final grade. Oct. 6 and Nov. 10. Final exam
20 of final grade comprehensive Dec. 8.
5Genes, Alleles and Epistasis
6Genetics starts with observation
Observe variability
Use genetics (patterns of inheritance) to
understand the cause of the variability. What
proteins or RNAs are responsible for the
variability you can see?
7Easy example, flower color
8How many genes affect flower color? How variable
are the proteins encoded by those genes? What
is the pathway to make flower color?
9List of terms
Trait some aspect of an organism that can be
observed, measured Phenotype the way a trait
appears in an individual, the combination of
genotype and environment. Genotype the
constitution of alleles at any gene in an
individual. Gene continuous stretch of DNA
sufficient to encode a messenger RNA or a
functional RNA. Locus A region of a
chromosome, usually for a single gene. Messenger
RNA the RNA message for a single
protein. Allele a variant of the sequence of a
given gene. Diploid an individual with two
copies of each chromosome. Haploid an individual
with one copy of each chromosome.
10How many genes affect flower color?
11First make sure the types are heritable and true
breeding (homozygous for flower color alleles)
All uniform
purple by purple (self)
X
Homozygous a diploid individual with two copies
of the same allele for a given gene. Heterozygous
a diploid individual with two different alleles
for a given gene.
12What are the relationships between color types?
X
purple is dominant to white
13Alleles are distributed as discrete units
X
F1 W/wa
White A wa/wa
Purple W/W
14Punnet square helps to predict genotypes and
phenotypes of the next generation
Two distinct alleles at the same locus
X
F1 W/wa
F1 W/wa
1 W/W 2 W/wa 1 wa/wa 3 purple 1 white
Female gametes
wa
W
Male gametes
W/W1
W/wa
W
wa
wa/wa
W/wa
15How many genes are required to make purple
pigment in flowers?
Complementation tests can be made between
recessive alleles.
If plants with recessive alleles are crossed and
the progeny also have the recessive trait,
The alleles are variants of the same gene
If plants with recessive alleles are crossed and
the progeny have the dominant trait,
The alleles are variants of different genes
A dominant allele cannot be used. Why?
16Allelism test 1 Cross different white flowered
plants
If the mutations are in the same gene, The
progeny will be white
X
F1 wa/wb
white A wa/wa
white B wb/wb
17Complementation test double check
F2 generation Cross white F1 to another white
F1 If the mutations are alleles of the same gene,
what is the next generation?
wa/wb
X
1 wa/wa, 2 wa/wb, 1 wb/wb
wa/wb
18Allelism test 2 Cross different white flowered
plants
If the mutations are in different genes, the
progeny will be pigmented
X
white A wa/wa
white C wc/wc
F1 W/wa W/wc
19Conclusions
W and wa are alleles of the same gene
wa and wc are alleles of different genes. The
dominant allele of wa and the dominant allele of
wc are needed for purple color to be
produced. Therefore, at least 2 gene products
are needed to produce purple pigment.
To avoid confusion, lets call W and wa R and r
and wc p with a dominant allele P.
20Allelism test Cross different white flowered
plants
If the mutations are in different genes, The
progeny will be pigmented
X
white A r/r P/P
white C R/R p/p
F1 R/r P/p
21white C
purple
X
white A
rrPP
RRpp
RrPp
22Pathway to purple
Precursor 1
R or P
Intermediate
R or P
Purple
23Complementation test double check
The discrete alleles of two different genes Will
assort randomly in future generations
X
white A r/r P/P
white B R/R p/p
F1 R/r P/p
24Punnet Square Predict the genotypes and
phenotypes in the F2 generation when the trait
is controlled by two genes with randomly
segregating alleles
F2 after RrPp X RrPp
Female gametes
Male gametes
rp
Rp
rP
RP
RRPP
RRPp
RrPP
RrPp
RP
9R_P_ 3R_pp 3rrP_ 1rrpp Phenotypes if both R
and P needed for purple color
RRPp
RRpp
RrPp
Rrpp
Rp
rP
RrPP
RrPp
rrPP
rrPp
9 purple and 7 white
rp
rrpp
RrPp
Rrpp
rrPp
25Using multiple allelism tests with diverse
recessive mutants, We can identify all the
genes specifically involved in making the purple
pigment
26Predict the genotypes and phenotypes in the F2
generation when the traits are independent. Eg.
petal color and leaf size.
27Punnet Square Predict the genotypes and
phenotypes in the F2 generation when the traits
are independent. Eg. petal color and leaf size.
RrPp X RrPp
Female gametes
9R_P_ 3R_pp 3rrP_ 1rrpp Phenotypes if R and P
affect independent traits Eg. petal color and
leaf size R- is purple, rr is white P- is long
leaf and pp is short leaf
Male gametes
rp
Rp
rP
RP
RrPp
RRPP
RRPp
RrPP
RP
RRPp
RRpp
RrPp
Rrpp
Rp
rP
RrPP
RrPp
rrPP
rrPp
9 purple, long 3 white, long 3 purple, short
1 white, short
rp
rrpp
RrPp
Rrpp
rrPp
28Calculate ratios with more loci
probability of RR or Rr is 3/4
probability of rr is 1/4
3 loci all dominant ¾ X ¾ X ¾ all recessive
¼ X ¼ X ¼ one dominant and two recessive ¾ X ¼
X ¼ Ad-inifinitum
29Chi-square test for goodness of fit
Does the data fit the model?
n
S (Oi-Ei)2/Ei
i1
n is the number of types of observations, ie.
the number of different phenotypic classes
Degrees of freedom n-1
P is probability that the data fits the
model/ ie. the null hypothesis is incorrect
30X2 values for different degrees of freedomand
the probabilities associated with the X2 values
31Mendels Laws
Mendel's First Law - the law of segregation
during gamete formation each member of the
allelic pair separates from the other member to
form the genetic constitution of the gamete
Mendel's Second Law - the law of independent
assortment this says that for two
characteristics, the genes are inherited
independently.
Maternal inheritance
Exceptions
32Maternal Inheritance
Some traits are encoded by genes in cytoplasmic
organelles Eg. Mitochondrial traits Eg.
Chloroplast traits in plants
Organelles are transferred to an embryo from the
egg, not the sperm. The organelles are
haploid and (usually) genetically uniform in
eggs. Therefore the trait of the mother will be
passed to all offspring.
33Examples of maternally inherited traits?
Mitochondrial
Mitochondrial myopathy Diabetes mellitus and
deafness Leber's hereditary optic neuropathy
Chloroplast
White leaves loss of chlorophyll, often partial
34Yeast complementation test for next week
Brewers Yeast Saccharomyces cerevisiae 16
chromosomes 12,052 kb DNA 6183 ORFs About 5800
expected to encode proteins
35Yeast is a very useful model for genetics
because of its life cycle
Haploid life cycle
36Yeast is a very useful model for genetics
because of its life cycle
Mating cycle Diploid
37Advantages of yeast for identification of genes
in a biosynthetic pathway
We can isolate mutants as haploids We can test
the mutations for allelism by a complementation
test Two haploids are mated. The resulting
diploid has both mutations. Either the
mutations are allelic and do not complement, or
they are mutations in two different genes and
they do complement.
38a2
a1
a1
Select mutants that are defective in Adenine
synthesis- cannot grow without adenine in
medium. Turn red on media with adenine because
an adenine precursor accumulates.
39X
a1
a1
a1
a2
a2
X
a1
a1
Which mating results in complementation?
40Summary of Lecture 1
Mendelian Genetics Mendels laws,
Segregation of two alleles at one locus
Segregation of two alleles at two independent loci
Punnet square, calculate expected ratios of
phenotypes
Chi-square test to test if observed results can
be explained by the model of choice.
Allelism tests
Yeast as a model, haploid and diploid life-style
41End