Title: MER 439 Design of Thermal Fluid Systems
1- MER 439 - Design of Thermal Fluid Systems
- Pumps and Fans
- Professor Bruno
- Fall Term 2006
2Introduction
- A pump is a machine that expends energy to
increase the pressure of a fluid (liquid or gas)
and move it from one point to another. - Pumps gt Liquids
- Fans gt Air
- In this lecture we will learn about pump types,
pump performance curves and some general
guidelines for selecting a pump.
3Pump Types
- Two General Categories
- (1) Dynamic Pumps These pumps use a rotating
component to impart energy to the fluid in the
form of high velocity, high pressure or high
temperature. - (2) Positive Displacement Pumps Have a fixed
volume chamber that takes in and discharges the
pumped fluid.
4Dynamic Pumps
- Dynamic Pumps can be classified according to the
direction of the flow with respect to the
rotation axis. - (1) Radial Flow
- (2) Axial Flow
- (3) Mixed Flow
5Radial Flow (Centrifugal) Pumps
- Two main components
- The impeller consists of a number of blades
(vanes) arranged in a regular pattern about the
shaft. - The casing (housing) encloses the impeller
6Radial Flow (Centrifugal) Pumps
- Energy is added to the fluid by the rotating
blades - Both pressure and absolute velocity are increased
- The casing is designed to slow the fluid and
convert the KE of the fluid to an increase in
pressure.
7Axial Flow Pumps
- Used in low pressure
- drop applications.
- The motor rotates on a shaft onto which the
impeller is attached. - The rotating shaft is enclosed in a housing.
- Flow passage is bounded by this housing.
8Positive Displacement Pumps
- Reciprocating Pump a reciprocating piston draws
in fluid on an intake stroke and moves it out on
the discharge stroke. - Rotary Gear Pump Two meshed gears rotate within
a housing. Fluid enters between the gears and is
drawn into the volumes between adjacent teeth.
9Positive Displacement Pumps
10Performance Maps
- Pump performance is typically characterized by a
pressure head versus flow capacity curve. - Manufacturers tests the pumps and provide the
curves.
11Performance Maps
- Usually show different rotational speeds
- DP decreases as flow rate increases
- Iso-efficiency curves are shown
12Performance Maps
- Manufacturers supply summary plots of all types
of pumps.
13Example
- A pipeline that conveys water to an elevated
tank at a campsite is shown. The elevated tank
supplies water to people taking showers.
The 40 ft long pipeline contains 3 elbows and
one ball check valve and is made of 6-nominal
schedule 40 PVC pipe. The pump must deliver 250
gpm. Use the figure on the previous slide to
select a pump for this system and calculate the
pumping power.
14Solution
- Water Properties r 62.4 lbm/ft3,
- m 1.9 x 10 -5 lbf-s/ft2
- Pipe Properties ID 0.5054 ft
- A 0.2006 ft2
- The steady flow energy equation is
15Solution
- P1 P2 Patm 0 and V1 V2
- Z1 0 Z2 30 ft
- Q 250 gal/min 0.555 ft3/s
- V Q/A 2.76 ft/s
- Re 62.4(2.76)(0.5054)/1.9x10-5(32.2)
- 1.43x105
- e/D smooth gt f 0.0165 (Moody Diagram)
16Solution
- Minor Losses
- SK 3Kelbow Kinlet K valve Kexit
- From a fluids book
- SK 3(0.31) 1 70 1 72.9
17Solution
- Solving for hp we get
- A pump corresponding to region 01 will be
suitable for this application. The power is
18System Characteristics and Pump Selection
The energy equation between points 1 and 2 in the
system shown is hp is the actual head gained
by the fluid from the pump and ShL represents all
friction and minor losses.
19The System Equation
From our study of pipe flow we know that
typically hL varies approximately as the flow
rate squared Where K depends on the pipe
sizes, lengths and types and on the minor loss
coefficients. This system equation shows how
the head gained by the fluid from the pump is
related to the system losses.
20The System Equation
We can combine the system equation with the pump
performance curve to determine the operating
point. The intersection of the pump performance
curve and the system curve is the operating
point.
21Combining Pumps
- Pumps can be arranged in series or parallel to
provide additional head or flow capacity. - (a) In Series - add heads at same flow rate
- (b) In Parallel - add flow rates at same head.
22Example Problem
Water is to be pumped from one large open tank
to another as shown. The pipe diameter is 6 in
and the total length of the pipe between the pipe
entrance and exit is 200 ft. Minor loss
coefficients for the entrance, exit and the elbow
are shown on the figure and the friction factor
can be assumed to be 0.02.
23Example Problem
A certain centrifugal pump having the
performance characteristics shown is suggested as
a good pump for this flow system. With this pump
what would be the flow rate between the tanks? Do
you think this pump would be a good choice?
24Example Problem
- The steady flow energy equation between points
(1) and (2) is - With P1 P2 0 and V1 V2 0 and z2 -z1 10
ft, f 0.02, D 0.5 ft and L 200 ft
25Example Problem
- The velocity is related to the flow rate
- The system curve can be expressed as
26Example Problem
- We can plot this against the pump curve to locate
the operating point
27Example Problem
- The curves intersect at Q 1600 gal/min with the
corresponding head again of 66.5 ft. - Another concern to consider is the pump
efficiency. Although the pump is not operating at
peak efficiency it is close 84. Thus this pump
is a satisfactory choice. The power needed to
drive the pump is
28Net Positive Suction Head (NPSH)
- Low pressures are commonly encountered on the
suction side of a pump - Cavitation can occur
- Cavitation occurs when a liquid pressure at a
given location is reduced to the vapor pressure
of the liquid. Vapor bubbles form and the liquid
starts to boil. - Causes loss in efficiency and structural damage
to the pump.
29Net Positive Suction Head (NPSH)
- To characterize the potential for cavitation the
difference in the total head on the suction side
near the pump impeller inlet and the liquid vapor
pressure head is used
30Net Positive Suction Head (NPSH)
- The required NPSHR is the value that must be
maintained to avoid cavitation. - The available NPSHA represents the head loss that
actually occurs for the system.
31NPSH Example
- Example
- Q 0.5 ft3/sec
- NPSHR 15 ft
- T 80 oF
- P 14.7 psi
- kL 20, D 4 in
- Determine the maximum z1 for no cavitation
32NPSH Example
- The available NPSHA is
- The maximum z1 will occur when NPSHA NPSHR
33NPSH Example
- The velocity is
- The head loss is
- At T 80o F the vapor pressure of water is
0.5069 psia, and r 62.22 lb/ft3
34NPSH Example
To prevent cavitation the pump should not be
located higher than 7.65 ft above the water
surface.