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Conversion to polar coordinates

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Grouping terms of the same basis, Advection on a vector. Combining both the first and second terms and grouping basis terms, we see that ... – PowerPoint PPT presentation

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Title: Conversion to polar coordinates


1
Conversion to polar coordinates
  • Standard low pressure systems and tropical
    cyclones are two examples of in meteorology that
    clearly have a physical structure compatible with
    polar coordinate system

2
Polar coordinates - defined
  • Polar coordinates are defined in a 2-D
    coordinates system which measures positions in
    space based on
  • 1 - radial distance
  • 2 An azimuthal angle from a reference axis
    (usually the axis)
  • Relationship between polar and rectangular
    coordinates

3
Polar coordinates
  • From the figure we can see that rectangular
    coordinates and polar coordinates are related as
    follows
  • And additionally from these relationships we find

4
Polar coordinate basis vectors
  • Using the definitions of a vector from chapter 2
    we observe that the depicted radial vector has a
    magnitude and direction.
  • Magnitude
    as already observed
  • Direction

5
Polar coordinate basis vectors
  • Notice that depends on q, this is a major
    difference from rectangular coordinates!
  • To find the other basis vector, we wish to
    maintain an orthogonal coordinate system so
    simply find a vector perpendicular to .
    Assume a basis vector,
  • And recall that perpendicularity requires the dot
    product of the two basis vector are zero so
  • By inspection, we can see that
    is a sufficient choice for a
    perpendicular unit basis vector

6
Polar coordinate basis vectors
  • Another way to derive is to utilize the
    q-dependence of by adding 90 degrees to angle
    of interest
  • This yields the same result for as before.
    Notice that depends on q as well.
  • -- The orientation between the two polar basis
    vectors is shown below.

7
Polar coordinate basis vectors
  • We know have two polar basis vectors expressed in
    terms of the rectangular basis vectors.
  • We can solve for and in the above two
    equations (2 equations 2 unknowns)

8
The gradient operator defined in polar coordinates
  • Now that we have related the components and basis
    vectors of the polar and rectangular coordinates,
    we can express various operators in polar
    coordinates.
  • By use of the chain rule, the horizontal gradient
    is expressed in terms of partial or r and q as

9
The gradient operator defined in polar coordinates
  • From our previous relationships we observe that
  • To find and , utilize the
    fact that

10
The gradient operator defined in polar coordinates
  • Finally, recall that
  • Substitution of all of these terms in the above
    expression, we obtain
  • Which simplifies to

11
Velocity defined in polar coordinates
  • Let us now express, the radial vector
    specifically in terms of our new basis vectors,
  • Grouping basis terms together,
  • We obtain the radial vector again

12
Velocity defined in polar coordinates
  • To express velocity in polar coordinates,
    Consider a system where both r and q depend on
    time and take the time derivative of the radial
    vector (recall that the basis vector has q
    dependence)
  • Or
  • Where and

13
Advection on a scalar
  • Now that we have the velocity field and gradient
    representations in polar coordinates we can
    derive other quantities such as the advection or
    divergence.
  • First let us examine the advection on a scalar
    quantity, f(r,q).
  • Using the representation of the velocity field
    and gradient in polar coordinates and the
    orthogonal nature of the basis vectors, the
    advection of f in polar coordinates is simply

14
Advection on a vector
  • Now let us examine the advection on a vector
    which is of critical use since we can then
    express the equation of motion in polar
    coordinates
  • Substitution of the gradient and velocity vector
    in polar coordinates yields
  • The key difference in expanding the above
    expression is that we have to consider
    derivatives of the basis vectors now!
  • Let us examine each term individually.

15
Advection on a vector
  • The first term The first term is
    straightforward since we are looking at
    derivatives with respect to r and the basis
    vectors depend on q.

16
Advection on a vector
  • The second term Now we have to consider the
  • q-dependence of the basis vectors.
  • Grouping terms of the same basis,

17
Advection on a vector
  • Combining both the first and second terms and
    grouping basis terms, we see that

18
Equation of motion
  • The equation of motion is
  • Use of polar coordinates in the above yields the
    following two
  • Equations
  • Radial component ( )
  • Azimuthal component ( )
  • Notice the addition of the centripetal terms,
  • that account for effects of curvature in
    circular flows.

19
Gradient Wind
  • The 2-D equations of motion and 2-D
    incompressible conservation of mass in polar
    coordinates are

20
Gradient Wind- Assumptions
  • 1) The flow is steady
  • 2) The flow is axi-symmetric
  • 3) Flow is strictly tangential

21
Gradient Wind
  • The above assumption simplify the equations of
    motion to one radial equation
  • If we know the pressure field distribution then
    we can solve for the azimuthal flow in the
    gradient wind equation by the use of the
    quadratic equation

22
Gradient Wind-terminology
  • If the observed curved flow is greater than the
    theoretically predicted gradient wind is consider
    to be a super-gradient flow.

23
Gradient Wind-exercise
  • The gradient wind is expressed in rectangular
    coordinates as
  • What type of flow do we obtain if we consider the
    limit
  • ?

24
Gradient Wind
  • The gradient wind can represent various physical
    circumstances depending on direction of the
    azimuthally flow and the sign of the pressure
    gradient. Let us examine a few of these
    possibilities
  • 1) Normal cyclonic flow
  • This is a standard ideal low pressure system with
    cyclonic flow.
  • From a force relationship perspective, consider
    first a geostrophic balance. The straight flow
    is a balance between an inward directed pressure
    gradient and an outward directed Coriolis force.
    In the case of the gradient wind, there is a
    force imbalance where the pressure gradient force
    is larger than Coriolis force. This leads to net
    force directed inward and a resultant centripetal
    acceleration causing a curved cyclonic flow.

25
Gradient Wind
  • 2) Normal anti-cyclonic flow
  • The decreasing pressure from the origin indicates
    a high pressure system. Since the aziumthal flow
    is less than zero, the flow is antic-cyclonic and
    thus the flow represents a standard high pressure
    system.
  • There is a force imbalance where the outward
    directed pressure gradient force is less than
    inward directed Coriolis force. This force
    imbalance leads to net force directed inward and
    a resultant centripetal acceleration causing a
    curved anti-cyclonic flow.

26
Exercise
  • For a normal anti-cyclonic flow,
  • Determine if there is a limit on the magnitude of
    the pressure gradient.

27
Gradient Wind
  • 3) Anomalous anti-cyclonic flow about a high
    pressure system
  • This system has the same force balance as the
    previous example but considers the negative root
    of the quadratic solution.
  • Calculations show that the pressure gradient for
    the above solution to exist would be extremely
    small.
  • Although this flow is theoretically possible, it
    is not really empirically seen.
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