PH101 Serway Chapter 1 - PowerPoint PPT Presentation

1 / 19
About This Presentation
Title:

PH101 Serway Chapter 1

Description:

Math Review. Trigonometry. Q. c. a. b. sinQ = a/c, cosQ = b/c. tanQ = a/b. c2 =a2 b2 ... The dome light breaks off in a car moving at a constant velocity 30 m/s. ... – PowerPoint PPT presentation

Number of Views:433
Avg rating:3.0/5.0
Slides: 20
Provided by: pieterv3
Category:
Tags: chapter | ph101 | serway

less

Transcript and Presenter's Notes

Title: PH101 Serway Chapter 1


1
PH 105-003/4 ---- Friday, Aug. 22, 2007
Problem on uniform acceleration (from Ch. 2)A
bike moving at constant velocity 5 m/s passes a
car stopped at a light, as the light turns green
and the car begins to accelerate at 2 m/s2.(a)
When does the car pass the bike (in sec.)?
  • 5
  • 0.1

Equations vf vi a Dt xf xi vi t ½ a t2
2
A bike moving at constant velocity 5 m/s passes a
car stopped at a light, as the light turns green
and the car begins to accelerate at 2 m/s2.(a)
When does the car pass the bike?
(b) Where does this happen?
  1. 10 m from light
  2. 15 m
  3. 20 m
  4. 25 m
  5. 40 m
  6. 50 m

Equations vf vi a Dt xf xi vi t ½ a t2
3
Problem on uniform accelerationA bike moving at
constant velocity 5 m/s passes a car stopped at a
light, as the light turns green and the car
begins to accelerate at 2 m/s2.(a) When does
the car pass the bike?(b) Where does this
happen?
(c) How fast is the car moving then (in m/s)?
  • 10
  • 0.1
  • Equations
  • vf vi a Dt
  • xf xi vi t ½ a t2

4
Components of a Vector
PH 105-003/4Friday, Aug. 29, 2007
  • A component is a projection of a vector along an
    axis
  • Any vector can be completely described by its
    components
  • It is useful to use rectangular components
  • These are the projections of the vector along the
    x- and y-axes

5
Math Review
Trigonometry
c
a
sinQ a/c, cosQ b/c tanQ a/b
Q
b
c2 a2 b2
(Pythagorean Theorem)
V
vy
Example
Q
V 785 km/h, find Vx and Vy
Vx
Vx VsinQ 489 km/h Vy VcosQ 614
km/h CHECK 7852 4892 6142
6
Position and Displacement
PH 105-003/4Wednesday, September 5, 2007
  • The position of an object is described by its
    position vector,
  • The displacement of the object is defined as the
    change in its position

7
Instantaneous Velocity
  • The instantaneous velocity is the limit of the
    average velocity as ?t approaches zero
  • As the time interval becomes smaller, the
    direction of the displacement approaches that of
    the line tangent to the curve

8
Average Acceleration
9
Motion with Uniform Acceleration in 3D
  • The velocity vector can be obtained from the
    definition of acceleration
  • The position vector can be expressed as a
    function of time

10
Simplest case of uniformly-accelerated 2D
motionProjectile motion (free fall)
PH 105-003/4Friday, September 7, 2007
  • a constant (0, -g, 0) -g j
  • ax 0, ay -g, az 0

vx vix ax t x xi vix t ½ ax t2 vy
viy ay t y yi viy t ½ ay t2
vx vix (constant) x xi vix t vy viy gt
(NOT const.) y yi viy t ½ g t2
active figure 4.07
11
Clicker Question The dome light breaks off in a
car moving at a constant velocity 30 m/s. It
will hit the floor of the car
v 30 m/s
A
B
C
  1. Directly under its starting point
  2. Behind its starting point
  3. Ahead of its starting point

12
Assumptions of Projectile Motion
  • The free-fall acceleration is constant over the
    range of the motion
  • It is directed downward
  • This is the same as assuming a flat Earth over
    the range of the motion
  • It is reasonable as long as the range is small
    compared to the radius of the Earth
  • The effect of air friction is negligible
  • With these assumptions, an object in projectile
    motion will follow a parabolic path (y x2)

13
Sample clicker question (test-taking skills)A
man walks 40 meters in 20 seconds. What is his
average velocity, in m/s?
PH 105-003/4 -- Monday, September 10, 2007
  1. 0
  2. 1
  3. 2
  4. 3
  5. 4
  6. 5
  7. 6
  8. 7

14
Sample clicker question (test-taking skills) A
man walks 40 meters in 20 seconds. What is his
average velocity, in m/s?
  1. 0
  2. 1
  3. 2
  4. 3
  5. 4
  6. 5
  7. 6
  8. 7

15
Range of a Projectile
vx vix (constant) x xi vix t vy viy gt
(NOT const.) y yi viy t ½ g t2
means where does it return to y0?
0 0 viy t ½ g t2
viy ½ g t
t 2viy/g
is when, not where!
x 0 vix t 2 vix viy /g 2 vicosq vi sinq
/g
16
Range of a Projectile
17
Uniform Circular Motion
  • Trajectory is a circle, so
  • ri ri r
  • Use definitions of a, v
  • Dv a Dt, Dr v Dt
  • If Dq small,
  • Dv v Dq, Dr r Dq, so
  • aDt vDq, Dr, vDtr Dq
  • Divide a/v v/r, or
  • a v2 / r

18
Clicker question (vectors)A man walks 30 m
north, then 40 m east. The magnitude of his
total displacement is (in m)
  1. 10
  2. 30
  3. 40
  4. 50
  5. 70

19
Clicker Question relative motionA UA student is
driving (horizontally) 40 m/s in a convertible
when 1 cm diameter hail starts to fall,
vertically at 30 m/s.The speed with which the
hail strikes her is
  1. 30 m/s
  2. 40 m/s
  3. 50 m/s
  4. 60 m/s
  5. 70 m/s
Write a Comment
User Comments (0)
About PowerShow.com