Title: Collisions in 1D
1Collisions in 1-D
- For next time
- Read Chapter 7, Section 4
- Homework
- SP 68, SP 69, SP 72
2Announcement
- Homework solutions are available at Cards N
Copies.
3The two cars lock bumpers after the collision.
30 m/s
0 m/s
1200 kg
1200 kg
elastic inelastic maximally inelastic
Is the final kinetic energy of the system zero?
4SP 65
A boxcar travelling at 10 m/s approaches a string
of 4 identical boxcars sitting stationary on the
track. The moving boxcar collides and links with
the stationary cars and the five move off
together along the track. What is the final
speed of the five cars immediately after the
collision? (You may take the mass of each boxcar
to be 18537 kg.)
5SP 65
mcar 18,537 kg
6Work-Energy theorem is TRUE... just USELESS.
30 m/s
30 m/s
KE 1,080,000 J
1200 kg
1200 kg
v0
maximallyinelastic
KE 0 J
10 m/s
10 m/s
inelastic
KE 120,000 J
elastic
KE 1,080,000 J
7Tarzan Swing
Impulse-momentum theorem is TRUE just USELESS.
v ?
8Some collisions look like explosions
An astronaut is motionless in outer space. Upon
command, the propulsion unit strapped to his back
ejects some gas with a velocity of 32 m/s, and
the astronaut recoils with a velocity of -0.30
m/s. After the gas is ejected, the mass of the
astronaut is 160 kg. What is the mass of the
ejected gas?
9Some collisions look like explosions
Conservation of Energy or Conservation of
Momentum?
pi 0
pi pf
0 (160 kg)(-0.30 m/s) mg(32 m/s)
mg 1.5 kg
pf (160 kg)(-0.30 m/s) mg(32 m/s)
10Momentum is conserved during a collision
What does this mean?
- Total momentum for the system adds up to zero
before and after the collision. - Total momentum for the system stays the same
before and after the collision.
11Basic collision problem
12What if they stick?
13Sometimes it appears that momentum is not
conserved
14m 1 kg
h 5 m
15Ei mgh Ei 50 J
m 1 kg
h 5 m
50 J 1/2 mv2 v2 100 v 10 m/s
v 10 m/s
16m 1 kg
h 5 m
v 0 m/s
17What about the momentum?
v 10 m/s
Where does the energy go?
v 0 m/s
18pi pf 10 kg m/s 0 kg m/s huh?
pi 10 kg m/s
pf 0 kg m/s
19Need to include everything that bumps in our
system.
mbvib ME(0) (mb ME)vf 10 kg m/s 6 x 1024
kg vf
vf 2 x 10-24 m/s
pi 10 kg m/s
pf 0 kg m/s
20What about the energy of the Earth?
vf 2 x 10-24 m/s
Ef 1/2 mv2 Ef 1/2 (6 x 1024 kg) (2 x 10-24
m/s)2 Ef 1.2 x 10-23 J Ei 50 J
pi 10 kg m/s
pf 0 kg m/s
21Practice problem (SP 76)
2 kg
1.25 m
KE 25 J
4 kg
22SP 65 (with a twist)
A boxcar traveling at 10 m/s approaches a string
of 4 identical boxcars sitting stationary on the
track. The moving boxcar collides and links with
the stationary cars and the five move off
together along the track. What is the final
speed of the five cars immediately after the
collision? (You may take the mass of each boxcar
to be 18537 kg.)
23mcar 18,537 kg
24What if the first car bounces?
mcar 18,537 kg
25Help with tutorial homework
Galilean transformation
26Help with tutorial homework
Galilean transformation