Title: Section 2'6: Infinite Sets
1Section 2.6 Infinite Sets
- Dr. Fred Butler
- Math 121 Fall 2004
2Review of One-to-One Correspondences
- Recall that a one-to-one correspondence between
two sets A and B is a way of pairing up every
element in A with exactly one element in B. - For example
- S Maryland, Pennsylvania, West Virginia
- C Charleston, Annapolis, Harrisburg
3Proper Subsets Review
- Also recall that the set B is a proper subset of
the set A if and only if all the elements of the
set B are elements of the set A, and the set B ?
A. - If A 1, 3, 5, 7, 9, 11, then
- B 11, 3, 7
- is a proper subset, but
- C 3, 1, 9, 11, 7, 5
- is not a proper subset (because C A).
4Infinite Sets
- An infinite set is a set that can be placed in
one-to-one correspondence with a proper subset of
itself. - Note the importance of the word proper in the
above definition. - If it werent in the definition, we could use the
fact that any set A is a subset of itself, and we
could easily give a one-to-one correspondence
between A and itself. - In this case, every set would be infinite!
5The Set of Natural Numbers is Infinite
- Consider the set N1,2,3,4, of natural
numbers. - Let S2,3,4,5,, which is a proper subset of N
(since 1 is not in S). - N 1, 2, 3, 4, 5, 6,
- S 2, 3, 4, 5, 6, 7,
- The general way of pairing elements in N with
elements in S is n?n1. - This shows that N is infinite.
6The General Term of an Infinite Set
- The general term of a set is a formula involving
n, such that when 1 is substituted for n we get
the first term of the set, when 2 is substituted
for n we get the second term of the set, etc. - When showing that the set A is infinite, we need
to demonstrate a one-to-one correspondence
between A and a proper subset of A by showing how
to pair the general terms of the two sets.
7An Example of Finding the General Term
- Consider the set
- 4, 9, 14, 19, .
- How can we find a formula for the general term of
this set? - In 4, 9, 14, 19, , we note that
- 1. 9 4 5
- 2. 14 9 5
- 3. 19 14 5
- etc.
- The difference between each successive term is 5.
- This means that the general term looks like 5na
for some number a.
8An Example of Finding the General Term contd.
- The general term looks like 5na for some a.
- The first term is 4, so for n1 we must have 4
5(1) a. - Thus a -1, and the general term is 5n1.
- So our list looks like
- 4, 9, 14, 19, , 5n-1,
9Class Question 1.7
- What is the general term of the set
- 4, 6, 8, 10, 12, 14, 16, ?
- 1. 2n 2. 2n2 3. 2n4
10The Set of Even Numbers is Infinite
- Consider the set
- E 2, 4, 6, 8, , 2n,
- of even numbers.
- Consider the proper subset
- S 4, 6, 8, 10, , 2n2,
- obtained by removing 2 from E.
11The Set of Even Numbers is Infinite contd.
- Then the desired one-to-one correspondence is
given by - E 2, 4, 6, 8, , 2n,
-
- S 4, 6, 8, 10, , 2n2,
, - where we pair the general term 2n in E with the
general term 2n2 in S. - This correspondence shows E is infinite.
12Countable Sets
- A set is countable if it is finite, or if it can
be placed in one-to-one correspondence with the
set of counting numbers. - For example, 1, 2, 5, 6, 8, a, is countable
because it is finite. - So is the empty set Ø.
- N 1, 2, 3, 4, 5, 6, is also countable.
13Another Example of a Countable Set
- We will now show that the set of the odd counting
numbers - O 1, 3, 5, 7, 9, 11,
- is countable, by finding a one-to-one
correspondence between O and N. - Using the methods described earlier, we can see
that the general term of O is - 2n 1, because
- 2(1) 11, 2(2) 13, 2(3) 15, etc.
14An Example of a Countable Set contd.
- So we have the one-to-one correspondence
- N 1, 2, 3, 4, 5, , n,
- O 1, 3, 5, 7, 9, , 2n1,
- which in general sends n to 2n1.
- We have established a one-to-one correspondence
between N and O, which shows that O is countable.
15The Cardinal Number ?0
- Any infinite set that can be placed in one-to-one
correspondence with the counting numbers has
cardinal number ?0, pronounced aleph-null. - Said another way, any countable infinite set has
cardinal number ?0. - This symbol is made up of ?, the first letter of
the Hebrew alphabet, with a 0 subscript. - This definition immediately gives us that the
cardinal number of the set N of counting numbers
is ?0.
16The Cardinal Number of the Odd Counting Numbers
- In establishing a one-to one correspondence
between the odd counting numbers - O 1, 3, 5, 7, 9, 11,
- and the counting numbers
- N 1, 2, 3, 4, 5, 6, ,
- we have also shown that the set O has cardinal
number ?0.
17Other Sets with Cardinality ?0
- It can be shown (although we will not do so) that
the set of integers - Z , -3, -2, -1, 0, 1, 2, 3, ,
- and the set of rational numbers
- Q p/q p e Z, q e Z, and q ? 0
- (the set of all fractions), also both have
cardinality ?0. - These sets both seem to be much bigger than the
set of counting numbers N, but in terms of
cardinal numbers they are the same size!
18Cardinal Numbers and Unions
- Recall the formula for finite sets A and B
- n(A U B) n(A) n(B) n(A n B).
- Recall that two sets A and B are disjoint if they
have no elements in common (in which case n(A n
B) 0). - So when A and B are finite disjoint sets, the
above formula becomes - n(A U B) n(A) n(B).
19Cardinal Numbers and Unions contd.
- If A1,2,3 and B7,8,9,10,11, then A and B
are disjoint, - A U B 1,2,3,7,8,9,10,11,
- and
- n(A U B) 8 3 5 n(A) n(B).
- However, if A1,2,3,4 and B2,4,6,8,10, then
A and B are not disjoint, - A U B1,2,3,4,6,8,10,
- and
- n(A U B) 7 ? n(A) n(B).
20Cardinal Numbers and Unions contd.
- The formula
- n(A U B) n(A) n(B)
- for A and B finite disjoint sets is saying that
the cardinal number of the union of A and B is
just the sum of the cardinal numbers of A and B. - We will now see that strange things happen when
we try to apply this formula to infinite sets.
21A Paradox
- Earlier, we showed that the cardinal number of
the set of odd counting numbers O1,3,5,7,9,
is ?0. - In a similar fashion, we can show that the
cardinal number of the set of even counting
numbers E2,4,6,8,10, is also ?0. - Finally, we know that the cardinal number of the
set of counting numbers N1,2,3,4,5, is ?0.
22A Paradox contd.
- We have that O1,3,5,7,9, and E2,4,6,8,10,
are disjoint sets, and - O U E 1,3,5,7,9, U 2,4,6,8,10
- 1,2,3,4,5,6, N.
- Applying the formula
- n(N) n(OUE) n(O) n(E),
- we get that
- ?0 ?0 ?0 !
23An Infinite Set with Cardinality Bigger than ?0
- The set R of real numbers includes the counting
numbers, integers, rational numbers, irrational
numbers (things like v2), and even transcendental
numbers (things like p). - Georg Cantor, the mathematician responsible for
all of this work on infinite sets, proved that R
has cardinal number bigger than ?0. - We will discuss irrational numbers, p, and the
set of real numbers R later in the course.
24Lecture Summary
- An infinite set is a set that can be placed in
one-to-one correspondence with a proper subset of
itself. - We need to demonstrate such a one-to-one
correspondence by showing how to pair the general
terms of the two sets. - A set is countable if it is finite, or if it can
be placed in one-to-one correspondence with the
set of counting numbers.
25Lecture Summary contd.
- An infinite set that can be placed in one-to-one
correspondence with the counting numbers have
cardinal number ?0, pronounced aleph-null. - The set R of real numbers is an infinite set that
has cardinality bigger than ?0 .
26Homework
- Do problems from Section 2.6 of the textbook.
- HW Quiz 1 is due Wednesday, Sep. 8, in Web CT by
1100 PM. - Study for Unit 1 Exam, held Thursday Sep. 09 and
Friday Sep. 10.