Payback Period Analysis

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Payback Period Analysis

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Title: Payback Period Analysis


1
Payback Period Analysis Life-Cycle Cost
  • Engineering Economics

Lecture 5 24 August, 2007
2
So far -
  • Compound interest/equivalence
  • PW and AW analysis techniques
  • MARR
  • EAC, AOC, CR costs
  • Selecting alternatives using AW analysis

3
This week -
  • Example - AW analysis
  • Payback Period Analysis
  • Conventional
  • Discounted
  • Life Cycle Costs
  • Acquisition phase
  • Operation phase

4
2005 exam Q4
  • A company is evaluating two alternative methods
    of producing one of its product lines.
  • Method A costs 80,000 initially and will have a
    15,000 salvage value after 3 years. The
    operating cost of this method will be 30,000 per
    year.
  • Method B will have an initial cost of 120,000,
    an operating cost of 8,000 per year and a
    40,000 salvage value after its operating life of
    2 years.
  • At an interest rate of 18, which method should
    be used?

5
18 Table
6
Solution
7
Payback Period Analysis
  • Two forms for this method
  • Conventional Payback Period (zero interest rate)
  • Discounted Payback Period (uses an interest rate)
  • Payback is the period of time it takes for the
    cash flows to recover the initial investment.
  • It is useful in providing the initial screening
    for a number of alternatives.
  • What is the relationship between the payback
    period and the actual useful life of an item?

8
Example
  • An organisation leases 4 x 2 Mbps point-to-point
    digital service to interconnect its private
    network in 5 buildings in the CBD from the local
    telecom carrier for 52,000 per annum.
  • The organisation decided to install and operate
    its own digital microwave radio links for the
    capital investment of 140,000
  • The annual licence fee 1,500 and maintenance
    contract 4,800 will be ongoing expenses.

9
Network Diagram
2
3
2Mbps
2Mbps
1
2Mbps
2Mbps
5
4
10
Conventional Payback Period
  • The conventional payback period for the capital
    investment would be
  • np 140,000 / 52,000 2.7 years
  • This method is very simple and can be give very
    misleading results.
  • It may be acceptable as a rough indication only
    but not as a business evaluation tool.

11
Questions to be asked
  • What is the revenue or benefit that the
    organisation gets from this service ?
  • Where will the organisation get the 140,000
    initial investment from ?
  • What is the useful life of the equipment ?
  • Are there any other costs or factors that need to
    be considered ?

12
Possible Answers
  • Having the private links, the organisation will
    not have to pay 52,000 a year for connectivity.
  • If the organisation borrowed the money, it will
    have to pay interest. Even if the organisation
    had the money, it can earn interest on it.
    (Opportunity Cost)
  • The useful life has to be significantly longer
    than the payback period (typically 10 to 15
    years)
  • System design, permits and licences,
    installation, commissioning, and maintenance must
    be considered.

13
Discounted Payback Period
  • An interest rate i gt 0 is used for this
    calculation.
  • There is a logical linkage between this method
    and the breakeven analysis.
  • The analysis produces a payback period np that is
    the estimated time, usually in years, it will
    take for the estimated revenues and other
    economic benefits to recover the initial
    investment and a stated rate of return.

14
Discounted Payback Approach
  • Find the value of np such that

where P is the initial investment, NCF is the
estimated net cash flow for each year t as
determined by the equation
NCF cash inflows - cash outflows
15
Calculations
  • Given the requirement 0 - P ?NCFt(P/F,i,t)
  • and in this simple case
  • ?NCFt(P/F,i,t) A(P/A,i,t)
  • for P 140,000, A 52,000 and i 0.1 (10)
  • gt 0 52,000 (P/A,10,n)
  • gt (P/A,i,n) 2.692
  • the number of years (n) is 3.29 years
  • derived by trial and error using Excel or by
    interpolation using the 10 table

16
10 Table
17
Comments
  • Even if the organisation did not have to borrow
    the 140,000 an interest rate must be considered.
  • The discounted cash flow method show that the
    payback period is much longer than that obtained
    using the conventional method.
  • The ongoing licence and maintenance fees must not
    be forgotten.

18
Cost Elements
  • System engineering
  • Permits and licences
  • Capital investment (equipment)
  • Installation and commissioning
  • Annual maintenance
  • Annual licences
  • Salvage/Disposal

19
Payback Method - Summary
  • Payback is only a rough estimator of desirability
  • Use as an initial screening method
  • Avoid using this method as a primary analysis
    technique for selection projects
  • Totally avoid the no-return payback period

20
Payback Method - Summary
  • The No-return method
  • Does not employ the time value of money
  • Disregards all cash flows past the payback time
    period
  • If used, can lead to conflicting selections when
    compared to more technically correct methods like
    present worth!

21
Life Cycle Costs ( LCC )
22
Life Cycle Costs (LCC)
  • Extension of the Present Worth method
  • Used for projects over their entire life span
    where cost estimates are employed
  • Used for
  • Military/Defense Projects
  • New Product Lines
  • Large construction projects

23
Phases of Life Cycle
  • Needs Assessment Phase
  • Conceptual Design Phase
  • Detailed Design Phase
  • Production/Construction Phase
  • Operation (upgrading to extend) Phase
  • Retirement/Disposal Phase

24
Life Cycle Two General Phases
Cost-
Cumulative Life Cycle Costs
Time
Acquisition Phase
Operation Phase
25
The Design Phase
  • The design phase is the most critical phase in
    the system engineering process.
  • If not managed correctly, it can lead to some
    undesired outcomes
  • There will always be changes during the design
    phase, the amount of which can be attributed to
    the phases preceding it.

26
LCC Impact of Design Changes
  • Cost of a design change tends to multiply by 10
    with each phase
  • Any design changes that might occur late in the
    life cycle drastically increase the total life
    cycle costs!
  • Design freeze period

27
LCC Acquisition Phase
Rule About 80 of LCC are locked in by the end
of the Acquisition Phase. Emphasis is on good
design!
Costs -
Needs Assessment
Conceptual Design
Detailed Design
Acquisition Phase
28
Life-Cycle Costs Purpose
  • Make as explicit as possible the relationship of
    costs over the total life span of a
    product/system
  • Design Process Objective
  • Minimize the life-cycle costs
  • And meet other performance requirements
  • By making correct trade-offs between costs in the
    acquisition phase and costs during the operations
    phase

29
Life-Cycle Costs Warning
  • Beware of introducing certain cost- cutting
    measures in the acquisition phase and early
    production phase
  • Such cost-cutting measures could impact the
    future operations and degrade safety or require
    modifications later on
  • These cost-cutting measures can be misleading and
    dangerous!

30
Life-Cycle Costs Warning
  • Engineers have a ethical and moral responsibility
    to ensure that designs are
  • Economically sound
  • Functional
  • Safe
  • Perform as expected

31
LCC of the Microwave System
  • For Microwave example
  • Useful life 10 years
  • Interest rate 10
  • Initial costs 153,000
  • Recurring costs 8,800 per annum
  • Salvage value 0
  • Total PW 207,072
  • Total PW for carrier-provided service 346,717
  • Refer to the spreadsheet example Microwave
    Example also includes AW analysis.

32
References
  • Blank, L., Tarquin, A., Engineering Economy,
    McGraw-Hill, 5/e (Chapter 5)

Thanks for your attention
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