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Waves Chapter 16

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n = number of moles of gas. T = absolute temperature degrees kelvin ... Na = Avogadro's number 6.022E 23 atoms/mole. PV = N Kb T. Kb = Boltzman's constant R/Na ... – PowerPoint PPT presentation

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Title: Waves Chapter 16


1
Waves Chapter 16 17
  • PHYS 2326-25

2
Concepts to Know
  • Mass per Unit Length
  • Bulk Modulus
  • Youngs Modulus
  • Ratio of Heat Capacities
  • Ideal Gas
  • Pressure
  • Gas Constant
  • Molecular Mass
  • Absolute Temperature

3
Transverse Wave
  • A wave on a string is usually transverse.
    Examples include plucking or strumming a guitar
    or banjo.
  • Eqn 16.18 provides the basis for transverse waves
    on a string

4
General Expression
  • All mechanical wave speeds follow a general
    expression
  • For a string the elastic property was the tension
    T and the inertial property of the medium was the
    mass per unit length
  • See section 12.4 for review information

5
Bulk ModulusSound Waves in Liquid or Gas (fluid)
  • Speed of sound in a medium depends upon the
    compressibility and density of the medium
  • B bulk modulus (elastic property)
  • ? density (inertial property)

6
Youngs ModulusSound Waves in a Solid
  • For longitudinal waves in a solid material
  • Y Youngs modulus (elastic property)
  • ? density (inertial property)

7
Ideal Gas Law
  • Chapter 19.5 is the ideal gas law this is
    covered in the other semester
  • PV nRT (eqn 19/8)
  • P pressure in pascals (N/m2)
  • R universal gas constant 8.314 J/molk or
    0.08206 Latm / molK for Volume in liters and
    pressure in earth atmospheres
  • n number of moles of gas
  • T absolute temperature degrees kelvin

8
  • PV nRT N/Na RT where
  • N number of molecules
  • Na Avogadros number 6.022E23 atoms/mole
  • PV N Kb T
  • Kb Boltzmans constant R/Na
  • 1.38E-23 J/K

9
Longitudinal Wavein an Ideal Gas
  • It is a pressure wave
  • B bulk modulus change in pressure /
    fractional change in volume
  • for an ideal gas relationship (for adiabatic
    condition) is pV? constant
  • ? cp/cv specific heat at constant pressure
    divided by the specific heat at constant volume
  • adiabatic activity where no heat enters or
    leaves
  • Bad ?p so
  • M molecular mass (28.8 avg. for air)

10
Speed of Sound in AirAssuming Ideal Gas
  • v 348m/s or 1148 ft/s
  • The eqn below 17.1, v(331) sqrt(1Tc/273) m/s
  • comes from this

11
Energy in the Wave(String)
  • Chapter 16.5 energy transfer per unit time in a
    string by a sinusoidal wave

12
Sound Pressure Energy
  • Like the transverse wave in a string, sound waves
    also have energy.
  • Rather than an transverse amplitude A we have a
    longitudinal displacement smax

13
Sound Pressure Energy
  • Like the transverse wave in a string, sound waves
    also have energy.
  • Rather than an transverse amplitude A we have a
    longitudinal displacement smax
  • For a solid we have

14
Example 1
  • A mass of 2kg is suspended on a string of length
    2m and mass 10g. Find a) speed of a transverse
    wave, b) the fundamental frequency (assuming the
    wavelength is twice the length of the string, c)
    the power transferred up and down the string
    while vibrating with an amplitude of 2cm

15
Example 1
  • Given M 2kg, L 2m, m 0.1kg, ? 4m, A
    0.02m
  • Force F mg (gravity, g 9.78m/s2)
  • µ m/L (mass/length), v sqrt(F/µ) m/s
  • v f?, ? 2pf, Pav ½ sqrt(µF) ?2 A2
  • F (2kg)(9.78m/s2) 19.6 N
  • µ m/L 0.1/2 0.005 kg/m
  • v v sqrt(F/µ) sqrt(19.6/0.05) 19.8m/s
  • b) frequency f v/ ? 19.8/4 4.95 Hz

16
Example 1
  • ? 2 pf 31.1 r/sec
  • Pav ½ sqrt(0.05 19.6) (31.1)2 (0.02)2
  • 0.192 W

17
Example 2
  • At what temeprature C is the speed of sound in
    air equal to 345 m/s. Assume air is an ideal gas
    with molecular weight of 28.8g/mole and that air
    is diatomic so ?1.40.
  • M28.8E-3 kg/mole
  • R 8.315 J/mole K
  • v 345
  • Note Tc Tk 273.15
  • v sqrt (?RT/M)

18
Example 2
  • rearranging the v eqn,
  • T M v2 / ? R 28.8 (345)2 / (1.4 8.315)
  • 294.5 degrees K
  • converting to centegrade
  • 294.5 273.15 21.2 degrees C
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