Title: Chapter 14 Chemical Kinetics
1Chapter 14Chemical Kinetics
CHEM 160September 13, 2006
2Factors that Affect Reaction Rates
- Kinetics is the study of how fast chemical
reactions occur. - There are 4 important factors which affect rates
of reactions - reactant concentration,
- temperature,
- action of catalysts, and
- surface area.
- Goal to understand chemical reactions at the
molecular level.
3Reaction Rates
- Speed of a reaction is measured by the change in
concentration with time. - For a reaction A ? B
- Suppose A reacts to form B. Let us begin with
1.00 mol A.
4Reaction Rates
5Reaction Rates
- At t 0 (time zero) there is 1.00 mol A (100 red
spheres) and no B present. - At t 20 min, there is 0.54 mol A and 0.46 mol
B. - At t 40 min, there is 0.30 mol A and 0.70 mol
B. - Calculating,
6Reaction Rates
- For the reaction A ? B there are two ways of
measuring rate - the speed at which the products appear (i.e.
change in moles of B per unit time), or - the speed at which the reactants disappear (i.e.
the change in moles of A per unit time).
7Reaction Rates
- Change of Rate with Time
- For the reaction A ? B there are two ways of
- Most useful units for rates are to look at
molarity. Since volume is constant, molarity and
moles are directly proportional. - Consider
- C4H9Cl(aq) H2O(l) ? C4H9OH(aq) HCl(aq)
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9Reaction Rates
- Change of Rate with Time
- C4H9Cl(aq) H2O(l) ? C4H9OH(aq) HCl(aq)
- We can calculate the average rate in terms of the
disappearance of C4H9Cl. - The units for average rate are mol/Ls or M/s.
- The average rate decreases with time.
- We plot C4H9Cl versus time.
- The rate at any instant in time (instantaneous
rate) is the slope of the tangent to the curve. - Instantaneous rate is different from average
rate. - We usually call the instantaneous rate the rate.
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11Reaction Rates
- Reaction Rate and Stoichiometry
- For the reaction
- C4H9Cl(aq) H2O(l) ? C4H9OH(aq) HCl(aq)
- we know
- In general for
- aA bB ? cC dD
12Concentration and Rate
- In general rates increase as concentrations
increase. - NH4(aq) NO2-(aq) ? N2(g) 2H2O(l)
13Concentration and Rate
- For the reaction
- NH4(aq) NO2-(aq) ? N2(g) 2H2O(l)
- we note
- as NH4 doubles with NO2- constant the rate
doubles, - as NO2- doubles with NH4 constant, the rate
doubles, - We conclude rate ? NH4NO2-.
- Rate law
- The constant k is the rate constant.
14Concentration and Rate
- Exponents in the Rate Law
- For a general reaction with rate law
- we say the reaction is mth order in reactant 1
and nth order in reactant 2. - The overall order of reaction is m n .
- A reaction can be zeroth order if m, n, are
zero. - Note the values of the exponents (orders) have to
be determined experimentally. They are not
simply related to stoichiometry.
15Concentration and Rate
- Using Initial Rates to Determines Rate Laws
- A reaction is zero order in a reactant if the
change in concentration of that reactant produces
no effect. - A reaction is first order if doubling the
concentration causes the rate to double. - A reacting is nth order if doubling the
concentration causes an 2n increase in rate. - Note that the rate constant does not depend on
concentration.
16The Change of Concentration with Time
- First Order Reactions
- Goal convert rate law into a convenient equation
to give concentrations as a function of time. - For a first order reaction, the rate doubles as
the concentration of a reactant doubles.
17The Change of Concentration with Time
- First Order Reactions
- A plot of lnAt versus t is a straight line with
slope -k and intercept lnA0. - In the above we use the natural logarithm, ln,
which is log to the base e.
18The Change of Concentration with Time
19The Change of Concentration with Time
- Second Order Reactions
- For a second order reaction with just one
reactant - A plot of 1/At versus t is a straight line with
slope k and intercept 1/A0 - For a second order reaction, a plot of lnAt vs.
t is not linear.
20The Change of Concentration with Time
Second Order Reactions
21The Change of Concentration with Time
- Half-Life
- Half-life is the time taken for the concentration
of a reactant to drop to half its original value. - For a first order process, half life, t½ is the
time taken for A0 to reach ½A0. - Mathematically,
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23The Change of Concentration with Time
- Half-Life
- For a second order reaction, half-life depends in
the initial concentration
24Temperature and Rate
- The Collision Model
- Most reactions speed up as temperature increases.
(E.g. food spoils when not refrigerated.) - When two light sticks are placed in water one at
room temperature and one in ice, the one at room
temperature is brighter than the one in ice. - The chemical reaction responsible for
chemiluminescence is dependent on temperature
the higher the temperature, the faster the
reaction and the brighter the light.
25Temperature and Rate
- The Collision Model
- As temperature increases, the rate increases.
26Temperature and Rate
- The Collision Model
- Since the rate law has no temperature term in it,
the rate constant must depend on temperature. - Consider the first order reaction CH3NC ? CH3CN.
- As temperature increases from 190 ?C to 250 ?C
the rate constant increases from 2.52 ? 10-5 s-1
to 3.16 ? 10-3 s-1. - The temperature effect is quite dramatic. Why?
- Observations rates of reactions are affected by
concentration and temperature.
27Temperature and Rate
- The Collision Model
- Goal develop a model that explains why rates of
reactions increase as concentration and
temperature increases. - The collision model in order for molecules to
react they must collide. - The greater the number of collisions the faster
the rate. - The more molecules present, the greater the
probability of collision and the faster the rate.
28Temperature and Rate
- The Collision Model
- The higher the temperature, the more energy
available to the molecules and the faster the
rate. - Complication not all collisions lead to
products. In fact, only a small fraction of
collisions lead to product. - The Orientation Factor
- In order for reaction to occur the reactant
molecules must collide in the correct orientation
and with enough energy to form products.
29Temperature and Rate
- The Orientation Factor
- Consider
- Cl NOCl ? NO Cl2
- There are two possible ways that Cl atoms and
NOCl molecules can collide one is effective and
one is not.
30Temperature and Rate
The Orientation Factor
31Temperature and Rate
- Activation Energy
- Arrhenius molecules must posses a minimum amount
of energy to react. Why? - In order to form products, bonds must be broken
in the reactants. - Bond breakage requires energy.
- Activation energy, Ea, is the minimum energy
required to initiate a chemical reaction.
32Temperature and Rate
- Activation Energy
- Consider the rearrangement of methyl isonitrile
- In H3C-N?C, the C-N?C bond bends until the C-N
bond breaks and the N?C portion is perpendicular
to the H3C portion. This structure is called the
activated complex or transition state. - The energy required for the above twist and break
is the activation energy, Ea. - Once the C-N bond is broken, the N?C portion can
continue to rotate forming a C-C?N bond.
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34Temperature and Rate
- Activation Energy
- The change in energy for the reaction is the
difference in energy between CH3NC and CH3CN. - The activation energy is the difference in energy
between reactants, CH3NC and transition state. - The rate depends on Ea.
- Notice that if a forward reaction is exothermic
(CH3NC ? CH3CN), then the reverse reaction is
endothermic (CH3CN ? CH3NC).
35Temperature and Rate
- Activation Energy
- How does a methyl isonitrile molecule gain enough
energy to overcome the activation energy barrier? - From kinetic molecular theory, we know that as
temperature increases, the total kinetic energy
increases. - We can show the fraction of molecules, f, with
energy equal to or greater than Ea is - where R is the gas constant (8.314 J/molK).
36Temperature and Rate
Activation Energy
37Temperature and Rate
- The Arrhenius Equation
- Arrhenius discovered most reaction-rate data
obeyed the Arrhenius equation - k is the rate constant, Ea is the activation
energy, R is the gas constant (8.314 J/K-mol) and
T is the temperature in K. - A is called the frequency factor.
- A is a measure of the probability of a favorable
collision. - Both A and Ea are specific to a given reaction.
38Temperature and Rate
- Determining the Activation Energy
- If we have a lot of data, we can determine Ea and
A graphically by rearranging the Arrhenius
equation - From the above equation, a plot of ln k versus
1/T will have slope of Ea/R and intercept of ln
A.
39Temperature and Rate
40Temperature and Rate
- Determining the Activation Energy
- If we do not have a lot of data, then we
recognize
41Reaction Mechanisms
- The balanced chemical equation provides
information about the beginning and end of
reaction. - The reaction mechanism gives the path of the
reaction. - Mechanisms provide a very detailed picture of
which bonds are broken and formed during the
course of a reaction. - Elementary Steps
- Elementary step any process that occurs in a
single step.
42Reaction Mechanisms
- Elementary Steps
- Molecularity the number of molecules present in
an elementary step. - Unimolecular one molecule in the elementary
step, - Bimolecular two molecules in the elementary
step, and - Termolecular three molecules in the elementary
step. - It is not common to see termolecular processes
(statistically improbable).
43Reaction Mechanisms
- Multistep Mechanisms
- Some reaction proceed through more than one step
- NO2(g) NO2(g) ? NO3(g) NO(g)
- NO3(g) CO(g) ? NO2(g) CO2(g)
- Notice that if we add the above steps, we get the
overall reaction - NO2(g) CO(g) ? NO(g) CO2(g)
44Reaction Mechanisms
- Multistep Mechanisms
- If a reaction proceeds via several elementary
steps, then the elementary steps must add to give
the balanced chemical equation. - Intermediate a species which appears in an
elementary step which is not a reactant or
product.
45Reaction Mechanisms
- Rate Laws for Elementary Steps
- The rate law of an elementary step is determined
by its molecularity - Unimolecular processes are first order,
- Bimolecular processes are second order, and
- Termolecular processes are third order.
46Reaction Mechanisms
Rate Laws for Elementary Steps
47Reaction Mechanisms
- Rate Laws for Multistep Mechanisms
- Rate-determining step is the slowest of the
elementary steps. - Therefore, the rate-determining step governs the
overall rate law for the reaction. - Mechanisms with an Initial Fast Step
- It is possible for an intermediate to be a
reactant. - Consider
- 2NO(g) Br2(g) ? 2NOBr(g)
48Reaction Mechanisms
- Mechanisms with an Initial Fast Step
- 2NO(g) Br2(g) ? 2NOBr(g)
- The experimentally determined rate law is
- Rate kNO2Br2
- Consider the following mechanism
49Reaction Mechanisms
- Mechanisms with an Initial Fast Step
- The rate law is (based on Step 2)
- Rate k2NOBr2NO
- The rate law should not depend on the
concentration of an intermediate (intermediates
are usually unstable). - Assume NOBr2 is unstable, so we express the
concentration of NOBr2 in terms of NOBr and Br2
assuming there is an equilibrium in step 1 we have
50Reaction Mechanisms
- Mechanisms with an Initial Fast Step
- By definition of equilibrium
- Therefore, the overall rate law becomes
- Note the final rate law is consistent with the
experimentally observed rate law.
51Catalysis
- A catalyst changes the rate of a chemical
reaction. - There are two types of catalyst
- homogeneous, and
- heterogeneous.
- Chlorine atoms are catalysts for the destruction
of ozone. - Homogeneous Catalysis
- The catalyst and reaction is in one phase.
52Catalysis
- Homogeneous Catalysis
- Hydrogen peroxide decomposes very slowly
- 2H2O2(aq) ? 2H2O(l) O2(g)
- In the presence of the bromide ion, the
decomposition occurs rapidly - 2Br-(aq) H2O2(aq) 2H(aq) ? Br2(aq)
2H2O(l). - Br2(aq) is brown.
- Br2(aq) H2O2(aq) ? 2Br-(aq) 2H(aq) O2(g).
- Br- is a catalyst because it can be recovered at
the end of the reaction.
53Catalysis
- Homogeneous Catalysis
- Generally, catalysts operate by lowering the
activation energy for a reaction.
54Catalysis
55Catalysis
- Homogeneous Catalysis
- Catalysts can operate by increasing the number of
effective collisions. - That is, from the Arrhenius equation catalysts
increase k be increasing A or decreasing Ea. - A catalyst may add intermediates to the reaction.
- Example In the presence of Br-, Br2(aq) is
generated as an intermediate in the decomposition
of H2O2.
56Catalysis
- Homogeneous Catalysis
- When a catalyst adds an intermediate, the
activation energies for both steps must be lower
than the activation energy for the uncatalyzed
reaction. The catalyst is in a different phase
than the reactants and products. - Heterogeneous Catalysis
- Typical example solid catalyst, gaseous
reactants and products (catalytic converters in
cars). - Most industrial catalysts are heterogeneous.
57Catalysis
- Heterogeneous Catalysis
- First step is adsorption (the binding of reactant
molecules to the catalyst surface). - Adsorbed species (atoms or ions) are very
reactive. - Molecules are adsorbed onto active sites on the
catalyst surface.
58Catalysis
59Catalysis
- Heterogeneous Catalysis
- Consider the hydrogenation of ethylene
- C2H4(g) H2(g) ? C2H6(g), ?H -136 kJ/mol.
- The reaction is slow in the absence of a
catalyst. - In the presence of a metal catalyst (Ni, Pt or
Pd) the reaction occurs quickly at room
temperature. - First the ethylene and hydrogen molecules are
adsorbed onto active sites on the metal surface. - The H-H bond breaks and the H atoms migrate about
the metal surface.
60Catalysis
- Heterogeneous Catalysis
- When an H atom collides with an ethylene molecule
on the surface, the C-C ? bond breaks and a C-H ?
bond forms. - When C2H6 forms it desorbs from the surface.
- When ethylene and hydrogen are adsorbed onto a
surface, less energy is required to break the
bonds and the activation energy for the reaction
is lowered. - Enzymes
- Enzymes are biological catalysts.
- Most enzymes are protein molecules with large
molecular masses (10,000 to 106 amu).
61Catalysis
- Enzymes
- Enzymes have very specific shapes.
- Most enzymes catalyze very specific reactions.
- Substrates undergo reaction at the active site of
an enzyme. - A substrate locks into an enzyme and a fast
reaction occurs. - The products then move away from the enzyme.
62Catalysis
- Enzymes
- Only substrates that fit into the enzyme lock can
be involved in the reaction. - If a molecule binds tightly to an enzyme so that
another substrate cannot displace it, then the
active site is blocked and the catalyst is
inhibited (enzyme inhibitors). - The number of events (turnover number) catalyzed
is large for enzymes (103 - 107 per second).
63Catalysis
Enzymes
64End of Chapter 14Chemical Kinetics