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Lecture 25 Complex Power

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... power is delivered to the load at a specified interface voltage magnitude ... sum of the complex power absorbed by each two-terminal element in the circuit. ... – PowerPoint PPT presentation

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Title: Lecture 25 Complex Power


1
Lecture 25Complex Power
  • ECE 205
  • Prof. Ali Keyhani

2
Complex Power
  • In power circuit analysis phasor magnitudes
    are expressed in terms of root mean square (rms)
    values

Complex power Product of the voltage phasor
times the conjugate of the current phasor
3
Complex Power
4
Complex Power
  • Power Triangle

5
Example 1
  • Determine the average power, reactive power
    and apparent power for the given voltage and
    current.

6
Complex Power
Since
We have
Reactive Power positive inductive load, lagging
power factor Reactive Power negative capacitive
load, leading power factor
7
Example 2
  • At 480V, a load draws 300kVA of apparent power
    with p.f. 0.9 lagging, what is the active,
    reactive, and complex power of the load?

8
Example 2
  • Solution

Q gt 0 because p.f. is lagging
9
Example 3
  • Consider a 480V, 180kVA load with pf 0.0
    leading, what is the active, reactive, and
    complex power of the load?

10
Example 3
  • Solution

Q lt 0 because p.f. is leading.
11
Load Flow
  • Load Flow Adjust the source so that a
    required complex power is delivered to the load
    at a specified interface voltage magnitude
  • Conservation of complex power
  • In a linear circuit operating in steady state
    the sum of the complex powers produced by each
    independent source is equal to the sum of the
    complex power absorbed by each two-terminal
    element in the circuit.

12
Example 4
  • Source textbook
  • Compute the complex power absorbed by each
    branch of the circuit. Also calculate the power
    produced by the source.

13
Example 4
  • Solution

14
Example 5
  • Calculate the complex power delivered by each
    source.

15
Example 5
  • Solution
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