Title: NMR Spectroscopy Chapter 13
1NMR SpectroscopyChapter 13
2Contents of Chapter 13
- Proton NMR Spectroscopy
- Number of Signals and Position of Resonance
- Chemical Shifts and Splitting of Signals
- Coupling Constants
- 13C NMR Spectroscopy
- Advanced NMR Techniques
3Introduction to NMR Spectroscopy
4Effective Magnetic Field
- Exact energy at which various protons flip
depends on effective rather than applied magnetic
field - Diamagnetic shielding caused by electrons
diminishes effective field - Deshielding caused by electronegative groups
pulls electrons away from nuclei and makes nuclei
feel stronger effective magnetic fields - Neighboring hydrogens enhance and diminish
applied field leading to signal multiplicity
5Shielding and Deshielding
6The Number of Signals in the 1H NMR Spectrum
7Signals vs. Lines or Peaks
- Each set of equivalent hydrogens makes one signal
- Each signal appears as a set of one or more
lines or peaks - The number of peaks produced by one signal is
called its multiplicity
8The Position of the 1H NMR Signals
- Tetramethylsilane (TMS) is used as reference
standard because its protons are shielded more
than protons in almost all other organic compounds
9The Chemical Shift
- The chemical shift is measured in Hz (i.e.
frequency units) or ppm downfield from the TMS
signal - Typically these differences are reported in parts
per million, ppm
10The Chemical Shift
- The advantage of measuring chemical shift in ppm
is that signal positions are independent of the
frequency of the spectrometer - Coupling constants are measured in Hz rather than
ppm for the same reason
11Characteristic Values of Chemical Shifts
- Its useful to know that acetone Hs a to
carbonyl normally show up at about 2.1 ppm
12Chemical Shifts
- Note that d for a CH3 (0.9 ppm) is farther
upfield than for a CH2 (1.3 ppm) which is upfield
of CH (1.4 ppm) - In all illustrations in our textbook, protons are
labeled a, b, c etc. beginning with the proton
farthest upfield
13Splitting of Signals
- Signal splitting is described by the N1 Rule
- N is the number of equivalent protons bonded to
the adjacent carbon
14Splitting of Signals
- It is important to remember that it is the number
of proton on the adjacent carbon which determines
the multiplicity NOT the number of protons giving
rise to the signal - In CH3CHCl2, the methyl signal at ? 2.8 is
split into a doublet by the single proton on the
adjacent carbon
15Splitting of Signals
16Splitting of Signals
- Equivalent protons never split each other
17Deshielding and Splitting Analogy
- Protons like gangs which make peaks to kill rival
gang members living in carbon house next door - Every hydrogen in identical chemical situation is
in same gang even if it lives in different house - Gang makes n1 peaks to kill n rival gang members
and have one spare peak left over - If one gang lives next door to two or more gangs
it gets confused about how many peaks to make and
makes multiple peaks
18Deshielding and Splitting Analogy
- All peaks for a single gang stored in same
location-2 sets of peaks stored in same spot
merge and become one set of peaks - Electronegative landlords suck electrons (money)
from gangs to pay the rent - Rental office is downtown (downfield) at higher
numbered address, furthest from waterfront (TMS),
which has lowest ppm address number (0) - Gang which runs rental office furthest downtown
19Deshielding and Splitting Analogy
- Poorer gangs which live closer to the rental
office (lectronegative group) store their peaks
downtown since they cant afford an uptown crib - Gangs with less members per house are poorer than
gangs with more members in a house, so they store
peaks further downtown
20Splitting of Signals
21Splitting of Signals
- Nonequivalent protons split each other if they
are on adjacent carbons, i.e. separated by 3 s
bonds - Protons separated by 4 bonds will split if one of
the bonds is a double or triple bond
22Splitting of Signals
- The spectrum of isopropyl butanoate shows five
signals
23Splitting of Signals
24Coupling Constants
- The distance between two peaks in a split NMR
signal is called the coupling constant and is
symbolized by Jab - The signals of coupled protons have the same
coupling constant, i.e. Jab Jba
25Coupling Constants
- The magnitude of the coupling constant is
independent of the frequency of the spectrometer - The frequency difference between split peaks in a
60 MHz spectrum is the same as the frequency
difference between the same peaks in a 300 MHz
spectrum - In the latter case the peaks appear closer
together because while the Hz difference is the
same, it represents a smaller fraction of the
spectrometer frequency
26Coupling Constants
27Coupling Constants
- For complex splitting patterns, a splitting
diagram is used
28Coupling Constants
- Note the difference between a quartet and a
doublet of doublets
29Coupling Constants
- For 1-chloro-3-iodopropane, Jab Jac and what
should have been a triplet of triplets collapses
into a simple quintet
30Coupling Constants
- Always do highest multiplicity splitting first
31Integration of NMR Signals
- For 1H NMR spectra, the area under each
resonance peak is proportional to the number of
protons that absorb at that particular energy
32Integration of NMR Signals
- Height of integration line is proportional to the
area under the peak - If you are given a molecular formula its best to
calculate the total Hs divided by the total
units of integration height, H/U and use this to
calculate number of Hs in each signal. - In previous slide H/U 11H/8.6U 1.28 H/U
- Signal a is 7 U tall and 1.28 x 7 8.96 H (ie. 9
H) - Signal b is 1.6 U tall, 1.6 U x 1.28 H/U 2 H
3313C NMR Spectroscopy
- Alkyl 0 60 ppm
- C-O 50 80 ppm
- CC/Ph 100-170 ppm
- Amide/ester/acid 175
- Aldehyde lt 200 ppm
- Ketone gt 200 ppm
3413C NMR Spectroscopy
When the 13C spectrum is taken with
spin-coupling, only H atom bonded to the C atoms
split signals
3513C DEPT NMR spectrum of Citronellal
36COSY Spectrum of Ethyl Vinyl Ether
37Unsaturation Analysis
- Whenever a molecular formula for an unknown
compound is given an unsaturation analysis should
be done - First rewrite formula so that each halogen
replaced by an H and each N atom removes an H
from formula - Write rmaining formula ignoring all O atoms and
NH groups (both have two bonds) - Calculate Hs missing from CnH2n2 sat formula
- Each missing pair of Hs 1 unit of unsaturation
- Aromatic ring 4 units of unsaturation
381H NMR Alkyl Group Patterns
391H NMR Alkyl Group PatternsMethyl and t-Butyl
Groups
401H NMR Alkyl Group PatternsEthyl Group
411H NMR Alkyl Group PatternsPropyl Group
421H NMR Alkyl Group PatternsButyl Group
431H NMR Alkyl Group PatternsIsopropyl Group
441H NMR Alkyl Group Patternsn-Butyl Group
451H NMR Alkyl Group Patternssec-Butyl Group
461H NMR Alkyl Group PatternsPhenyl Group
471H NMR Alkyl Group Patterns1,4-Disubstituted
Aromatics