Title: Diploid Mapping 2point cross
1Diploid Mapping (2-point cross)
a b X a a b b
wildtype albino/bent bent albino 110
125 370 395 1000 total
recombinants parentals
( recombinance) distance between a--b
110 125 / 1000 0.235 x 100 23.5 or 23.5
cM
2Three - Point Cross
- determine gene order distance between 3 linked
genes - make a trihybrid and do a test cross
- determine parental types (2 most abundant)
nonrecombinants - 2) determine gene order look at double mutant
recombinants - (2 least abundant). The one allele type that
is different from one - of the parents would be the gene in the middle
- 3) diagram all of the offsprings genotypes
- 4) determine distance between a -- b
- single crossover single crossover double
crossover double crossover - total of
offspring - 5) determine distance between b -- c
- (use same formula but different single
crossover values)
3wt
abc X aabbcc
- albino, bent, crazy
- wildtype
- albino, bent
- crazy
- bent
- albino, crazy
- bent, crazy
- albino
- 1000 total
a - c 93 87 10 7 19.7 cM 1000
b - a 56 50 10 7 12.3 cM 1000
b - c 93875650107107 32.0 cM
1000
4Double-Cross Over
the closer the genes, the lower the double
recombinance
observed double cross-over total of double
cross-overs total offspring
expected double cross-over (freq. b--a) X (freq.
a--c)
0.123 X 0.197 0.024
10 7 / 1000 0.017
5Chromosome Interference
cross-overs in one region dec. the prob. of
second cross-over
Coefficient of coincidence observed double
recomb. expected double recomb.
one cross-over event reduces chance of second
cross-over event
Interference 1 - 0.017 0.29
0.024
6- Find parental types, single and double
recombinants, - Determine the order of the genes and distance
- between them
- Determine if there is interference between the
two - cross-over events
abc X aabbcc
- 880 albino, crazy
- 887 bent
- 64 albino
- 67 bent, crazy
- 49 albino, bent
- 46 crazy
- 3 abino, bent, crazy
- 4 wildtype
- 2000 total