Title: COE 341: Data
1COE 341 Data Computer Communications
(T062)Dr. Marwan Abu-Amara
2Encoding and Modulation Techniques
3Digital Analog Signaling
- Digital signaling
- Data source g(t) encoded into digital signal x(t)
- g(t) may be analog (e.g. voice) or digital (e.g.
file) - x(t) dependent on coding technique, chosen to
optimize use of transmission medium - Conserve bandwidth or minimize errors
- Analog signaling
- Based on continuous constant frequency signal,
carrier signal (i.e. A cos(2?fct?) or A
sin(2?fct?)) - Carrier signal frequency chosen to be compatible
with transmission medium - Data transmitted by carrier signal modulation by
manipulating A, fc, and/or?
4Analog Signaling
- Modulation
- Process of encoding source data onto a carrier
signal with frequency fc - Operation on one or more of three fundamental
frequency-domain parameters amplitude,
frequency, and phase - Input signal m(t)
- Can be analog or digital
- Called modulating signal or baseband signal
- Modulated signal s(t) is result of modulating
carrier signal called bandlimited or bandpass
signal - Location of bandwidth on spectrum related to
carrier frequency fc
5Baseband vs. Bandpass Signals
- Baseband Signal
- Spectrum not centered around non zero frequency
- May have a DC component
- Bandpass Signal
- Does not have a DC component
- Finite bandwidth around or at fc
6Encoding and Modulation Remarks
- Encoding is simpler and less expensive than
modulation - Encoding into digital signals allows use of
modern digital transmission and switching
equipment - Basis for Time Division Multiplexing (TDM)
- Modulation shifts baseband signals to a different
region of the frequency spectrum - Basis for Frequency Division Multiplexing (FDM)
- Unguided media and optical fibers can carry only
analog signals
7Encoding Techniques
- Digital data, digital signal
- Simple and inexpensive equipment
- Analog data, digital signal
- Data needs to be converted to digital form
- Digital data, analog signal
- Take advantage of existing analog transmission
media - Analog data, analog signal
- Transmitted as baseband signal easily and cheaply
8Digital Data, Digital Signal
- Digital signal
- Sequence of discrete, discontinuous voltage
pulses - Each pulse is a signal element
- Binary data encoded into signal elements
- Unipolar signal
- All signal elements have same sign (e.g. 0 5 V,
1 10 V ? DC content) - Polar signal
- One logic state represented by positive voltage
the other by negative voltage (e.g. 0 5 V, 1
-5 V ? ideally Zero DC content)
9Digital Data, Digital Signal
- Mark and Space
- Binary 1 and Binary 0 respectively
- Duration or length of a bit (Tb)
- Time taken for transmitter to emit the bit
- Data rate, R ( 1/Tb)
- Rate of data transmission in bits per second
(bps) - Duration of a Signal Element (Ts)
- Minimum signal pulse duration
- Modulation (signaling) rate (1/Ts)
- Rate at which the signal level changes with time
- Measured in bauds signal elements per second
10Digital Data, Digital Signal
- Data rate 1/1ms
- 1 M bps
- Signaling Rate for NRZI 1/1ms
- 1 M bauds
- Signaling Rate for Manchester 1/0.5ms
- 2 M bauds
Tb
Ts
Ts
11Interpretation of the Received Signal
12Interpreting Digital Signal at Receiver
- Receiver need to know
- Timing of bits - when they start and end
- Signal level
- Sampling comparison with a threshold value
- Factors affecting successful interpretation of
signals signal to noise ratio, data rate,
bandwidth - Increase in data rate increases bit-error-rate
(BER) - Increase in SNR decreases BER
- Increase in bandwidth allows for increase in data
rate
13Comparison of Encoding Schemes
- Encoding scheme
- Mapping from data bits to signal elements
- Signal Spectrum
- Lack of high frequencies reduces required
bandwidth - Lack of dc component allows ac coupling via
transformer ? providing isolation reducing
interference - Transfer function of a channel is worse near the
band edges - ? Concentrate power in the middle of the
bandwidth - Clocking
- Synchronizing transmitter and receiver
- Sync mechanism based on signal
- can be built into signal encoding
14Comparison of Encoding Schemes
- Error detection
- Can be built into signal encoding
- Signal interference and noise immunity
- Some codes are better than others
- Cost and complexity
- Higher signal rate ( thus data rate) lead to
higher costs - Some codes require signal rate greater than data
rate
15Encoding Schemes
- Nonreturn to Zero-Level (NRZ-L)
- Nonreturn to Zero Inverted (NRZI)
- Bipolar AMI (alternate mark inversion)
- Pseudoternary
- Manchester
- Differential Manchester
16Nonreturn to Zero-Level (NRZ-L)
- Two different voltages for 0 and 1 bits
- Voltage constant during bit interval
- no transition, no return to zero voltage
- e.g. Absence of voltage for zero, constant
positive voltage for one - More often, negative voltage for one value (1)
and positive for the other (0) - Used to generate or interpret digital data by
terminals - An example of absolute encoding
- Encoding data as a signal level
17Nonreturn to Zero Inverted (NRZI)
- Nonreturn to zero inverted on ones
- Constant voltage pulse for duration of bit
- Data encoded as presence or absence of signal
transition at beginning of bit time - Transition (low to high or high to low) denotes a
binary 1 - No transition denotes binary 0
- An example of differential encoding
- Info to be transmitted represented as changes
between successive signal elements
18NRZ
()ve
()ve
Transition Denotes one
19NRZ pros and cons
- Pros
- Easy to engineer
- Make good use of bandwidth
- Cons
- Large dc component
- Lack of synchronization capability
- No signal transitions for long strings of 0s or
1s - Used for magnetic recording
- Not often used for signal transmission
20Differential Encoding
- Data represented by signal transitions rather
than signal levels - Advantages
- With noise, signal transitions are detected more
easily than signal levels - In complex transmission layouts, it is easy to
accidentally lose sense of polarity
RX
- Effect of swapping terminals on
- NRZ-L
- NRZI
_
21NRZ pros and cons
22Multilevel Binary
- Use more than two signaling levels
- Bipolar-AMI (Alternate Mark Inversion)
- zero represented by no line signal
- one represented by positive or negative pulse
- one pulses alternate in polarity
- No loss of sync if a long string of ones (zeros
still a problem) - No net dc component
- Lower bandwidth
- Easy error detection
23Pseudoternary
- One represented by absence of line signal
- Zero represented by alternating positive and
negative - No advantage or disadvantage over bipolar-AMI
24Bipolar-AMI and Pseudoternary
All Single Pulse Errors- Detected
Double Pulse Error- Undetected
Adding
Canceling
Double Pulse Error- Detected
25Trade Off for Multilevel Binary
- Not as efficient as NRZ
- Each signal element only represents one bit
- Date RateR1/TB
- In a 3 level system could represent log23 1.58
bits - Receiver must distinguish between three levels
(A, -A, 0) - Requires approximately 3dB more signal power for
same probability of bit error
26Theoretical Bit Error Rate for Various Encoding
Schemes
27Biphase
- Manchester
- Transition in middle of each bit period
- Transition serves as clock and data
- High to low represents zero
- Low to high represents one
- Used by IEEE 802.3 (Standard for baseband coaxial
cable twisted pair CSMA/CD bus LANs) - Differential Manchester
- Mid bit transition is clocking only
- Transition at start of a bit period represents
zero - No transition at start of a bit period represents
one - Note this is a differential encoding scheme
- Used by IEEE 802.5 (Token ring LAN)
28Manchester Encoding
29Differential Manchester Encoding
30(No Transcript)
31Biphase Pros and Cons
- Pros
- Synchronization on mid bit transition (self
clocking) - No dc component
- Error detection
- Absence of expected transition
- Con
- At least one transition per bit time and possibly
two - Maximum modulation rate is twice NRZ
- Requires more bandwidth
32Modulation (Signaling) Rate
- Data rate (R)
- Bits per second, or bit rate
- 1/Tb, where Tb is bit duration
- Modulation rate (D)
- Rate at which signal elements generated
- Measured in Baud
- Modulation Rate D R k
- R data rate in bps
- M signaling levels used ? L bits/signal
element log2 M - k signal elements per bit signal trans./bit
trans. 1/L - In General, Modulation Rate D R k R/log2 M
33Modulation (Signaling) Rate
k1
k2
So, for Manchester ? D k?R 2/Tb
34Scrambling
- Use scrambling to replace sequences that would
produce constant voltage - Filling sequence
- Must produce enough transitions to sync
- Must be recognized by receiver and replace with
original - Same length as original
- Not be likely to be generated by noise
- No dc component
- No long sequences of zero level line signal
- No reduction in data rate
- Error detection capability
35B8ZS
- Bipolar With 8 Zeros Substitution
- Based on bipolar-AMI
- If octet of all zeros and last voltage pulse
preceding was positive encode as 000-0- - If octet of all zeros and last voltage pulse
preceding was negative encode as 000-0- - Causes two violations of AMI code
- Unlikely to occur as a result of noise
- Receiver detects and interprets as octet of all
zeros
36HDB3
- High Density Bipolar 3 Zeros
- Based on bipolar-AMI
- String of four zeros replaced with one or two
pulses
37B8ZS and HDB3
38Digital Data, Analog Signal
- Transmission of digital data through public
telephone network - Public telephone system
- 300Hz to 3400Hz
- Use modem (modulator-demodulator)
- Encoding techniques modify one of three
characteristics of carrier signal - Amplitude gt Amplitude shift keying (ASK)
- Frequency gt Frequency shift keying (FSK)
- Phase gt Phase shift keying (PSK)
- Resulting signal has a bandwidth centered on
carrier frequency
39Digital Data, Analog Signal
40Amplitude Shift Keying (ASK)
- Binary values represented by different amplitudes
of carrier - Usually, one amplitude is zero
- i.e. presence and absence of carrier is used
- For a carrier signal resulting signal is
41Amplitude Shift Keying (ASK)
- Inefficient up to 1200bps on voice grade lines
- Used to transmit digital data over optical fiber
42Frequency Shift Keying (FSK)
- Binary values represented by two different
frequencies near carrier frequency - Resulting signal is
- f1 and f2 are offset from carrier frequency fc by
equal but opposite amounts
43Frequency Shift Keying (FSK)
- Less susceptible to error than ASK
- Up to 1200bps on voice grade lines
- Used for high frequency (3 to 30 MHz) radio
transmission - Even higher frequencies on LANs using coaxial
cables
44FSK
Df
fc
Df
f2
f1
45Frequency Shift Keying (FSK)
- Full-duplex transmission over voice grade line
- In one direction fc is 1170 Hz with f1 and f2
given by 11701001270 Hz and 11701001070 Hz - In other direction fc is 2125 Hz with f1 and f2
given by 21251002225 Hz and 21251002025 Hz
46Phase Shift Keying (PSK)
- Binary PSK Phase of carrier signal is shifted to
represent different values - Phase shift of 180o
- Differential PSK Two-phase system with
differential PSK - Phase shift relative to previous bit transmitted
rather than some constant reference signal - Binary 0 represented by sending a signal burst of
same phase as previous signal burst - Binary 1 represented by sending a signal burst of
opposite phase as previous signal burst
47BPSK
48Differential PSK (DPSK)
- Phase shifted relative to previous signal
element rather than some reference signal
- 1 Reverse phase 0 Do not reverse phase
- (A form of differential encoding)
- Advantage
- - No need for a reference oscillator at RX to
determine absolute phase
49Quadrature PSK (QPSK)
- More efficient Bandwidth use by each signal
element representing more than one bit - Shifts of ?/2 (90o)
- Resulting signal is
- Each signal element represents two bits
50Quadrature PSK (QPSK)
51Quadrature Amplitude Modulation (QAM)
Constellation
- An extension of the QPSK just described
- Combines both ASK and PSK
- For example, ASK with 2 levels and
- PSK with 4 levels give 4 x 2 i.e. 8-QAM
- Up to M256 is possible
- Large bandwidth savings
- But some susceptibility to
- noise
- QAM used on asymmetric
- digital subscriber line
- (ADSL) and some wireless
- systems
M8, L 3
52QAM
- One stream is ASK modulated on a carrier of
frequency fc - Other stream is ASK modulated on a carrier of
frequency fc shifted by 90o - The two modulated signals are combined together
and transmitted - Transmitted signal can be expressed as
53Multilevel PSK (MPSK)
- Can use more phase angles and even have more than
one amplitude! - For example, 9600 bps modems use 12
phase angles, four of which have 2
amplitudes - Gives 16 different signal elements ? M
16 and L log2 (16) 4 bits - Every signal element carries 4 bits
(Data sent 4 bits at a time) - Baud rate is only 9600/4 2400 bauds (OK for a
voice grade line) - Complex signal encoding allows high data rates to
be sent on voice grade lines having a limited
bandwidth
54Data Rate Modulation Rate
- In general
- D modulation rate (signals per second or bauds)
- R data rate (bits per second)
- M number of different signal elements
- L number of bits per signal element
- With line signaling speed of 2400 baud
- For NRZ-L, data rate is 1/Tb
- For PSK, using L16 different combinations of
amplitude and phase, data rate is 9600 bps, R
4/Tb - For bi-phase, Data rate is 2/Tb
55Performance of D/A Modulation Schemes
- Performance of digital-to-analog techniques
depends on the definition of the bandwidth of the
modulated signal - Bandwidth of modulated signal depends on factors
such as Filtering technique used to create the
band-pass signal - ASK and PSK bandwidth directly related to bit
rate - Transmission bandwidth BT for ASK and PSK is
- R is data rate
- r is related to filtering technique 0lt r lt1
- Transmission bandwidth BT for FSK is
- where the delta for offset from the carrier
frequency
56Performance of D/A Modulation Schemes
- With multilevel signaling, bandwidth can improve
significantly - In the presence of noise, bit error rate of PSK
and QPSK are about 3dB superior to ASK and FSK
(as shown in Figure 5.4)
57Bandwidth Efficiency
- Bandwidth efficiency is the ratio of data rate to
transmission bandwidth, R/BT
r 0 r 0.5 r 1
ASK 1.0 0.67 0.5
FSK (wideband ?F gtgt R) 0 0 0
FSK (narrowband ?F ? fc) 1.0 0.67 0.5
PSK 1.0 0.67 0.5
MPSK M4, L2 2.0 1.33 1.0
MPSK M8, L3 3.0 2.00 1.5
MPSK M16, L4 4.0 2.67 2.0
MPSK M32, L5 5.0 3.33 2.5
58Bandwidth Efficiency Bit Error Rate
- The bit error rate (BER) can be reduced by
increasing Eb/N0 - Bit error rate can be reduced by decreasing
bandwidth efficiency - Increasing bandwidth
- Decreasing data rate
- N0 is the noise power density in watts/hertz.
Hence, the noise in a signal with bandwidth BT,,
NN0 BT
59Bandwidth Efficiency Bit Error Rate
- For multi-level signaling, replace R with D
60Example
- What is the bandwidth efficiency for FSK, ASK,
PSK, and QPSK for a bit error rate of 10-7 on a
channel with an SNR of 12dB ? - Recall that Bandwidth efficiency is the ratio of
R/BT
61Example
- For FSK ASK, Eb/N0 14.2dB
- ? (R/BT)dB 2.2 dB, R/BT 0.6
- For PSK, Eb/N0 11.2dB
- ? (R/BT)dB 0.8 dB, R/BT 1.2
- For QPSK, DR/2 (biphase) ? R/BT 2.4
62Analog vs. Digital Signaling Bandwidth Req.
- For digital signaling, bandwidth requirement is
approximated to be - For NRZ, D R
63Analog Data, Digital Signal
- Digitization
- Conversion of analog data into digital data
- Digital data can be transmitted using NRZ-L
- Digital data can be transmitted using code other
than NRZ-L - Digital data can then be converted to analog
signal - Analog to digital conversion done using a codec
- Pulse code modulation
- Delta modulation
64Pulse Code Modulation (PCM)
- Sampling Theorem If a signal is sampled at
regular intervals at a rate higher than twice the
highest signal frequency, the samples contain all
the information of the original signal - Signal maybe constructed from samples using a
low- pass filter - Voice data limited to below 4000Hz
- Require 8000 sample per second
- Analog samples (Pulse Amplitude Modulation, PAM)
- Each sample assigned digital value
65Quantization
Levels are numbered 0 to 15
n 4 bits ? 24 16 Quantization levels
PAM Sample
Analog signal is band-limited with bandwidth B
Quantization Error
Transmitted Serial Code representing the PAM
Samples
Sampling rate 2B
Each PAM sample is assigned the number of the
nearest quantization level and its digital code
is transmitted
Must finish sending the n bits of the code before
the next sample is due!
66Pulse Code Modulation (PCM)
- 4 bit system gives 16 levels
- Quantized
- Quantizing error or noise
- Approximations mean it is impossible to recover
original exactly - SNR for quantizing error is
- For each additional bit used for quantizing, SNR
increases by about 6 dB or a factor of 4 - 8 bit sample gives 256 levels
- Quality comparable with analog transmission
- 8000 samples per second of 8 bits each gives
(8000?8) 64 kbps
67PCM Example
- Suppose that we want to code an analog signal
that has voltage levels 0-5v using 2-bit PCM - Then, we divide the the voltage level in four
intervals such that the size of each interval is
5/41.25 - 0-1.25, 1.25-2.5, 2.5-3.75, 3.75-5
- We choose the values to be in the middle of each
interval - Selected values are 0.625, 1.875, 3.125, 4.375
- This guarantees that the maximum quantization
error is ½5/40.625 - and quantization SNR 6 x 2 1.76 13.76 dB
68Nonlinear Encoding
- Absolute error for each sample is the same
regardless of signal level - Lower amplitude values are relatively more
distorted - Solution is to make quantization levels not
evenly spaced - Greater number of quantization steps for lower
amplitudes and smaller number of steps for higher
amplitudes - Reduces overall signal distortion
69Effect of Nonlinear Coding
70Companding
- Effect of nonlinear coding can also be reduced by
companding - Compressing-expanding
- More gain to weak signals than to strong signals
on input - Reverse operation at output
71Example (Problem 5-20)
- Consider an audio signal with spectral components
in the range of 300 to 3000 Hz. Assuming a
sampling rate of 7000 samples per second will be
used to generate the PCM signal. - For SNR 30 dB, what is the number of uniform
quantization levels needed? - (SNR)dB 6.02 n 1.76 30 dB
- n (30 1.76)/6.02 4.69
- Rounded off, n 5 bits ? 25 32 quantization
levels - What data rate is required?
- R 7000 samples/sec ? 5 bits/sample 35 Kbps
72Delta Modulation
- Analog input is approximated by a staircase
function - Move up or down one level (?) at each sample
interval - Binary behavior
- Function moves up or down at each sample interval
- A bit stream produced approximates derivative of
analog signal rather than its amplitude - Produce a 1 if stair function is to go up
- Produce a 0 if stair function is to go down
73Delta Modulation - example
74Delta Modulation - Operation
- Analog input compared to most recent value of
approximating staircase function - If value exceeds staircase function, generate a 1
- Otherwise generate a 0
- Output of DM process is a binary sequence to be
used for reconstructing staircase function - Reconstructed stair function is smoothed by a low
pass filter to reconstruct approximated analog
signal
75Delta Modulation - Operation
76Delta Modulation
- Two important parameters in DM scheme
- Size of step assigned to each binary digit d
- Must be chosen to produce a balance between two
types of errors or noise - If waveform changes slowly, quantizing noise
increases with increase in d - If waveform changes rapidly, slope overload noise
increases with decrease in d - Increasing sampling rate
- improves the accuracy of the scheme
- Increases data rate
- Principal advantage of DM is implementation
simplicity - PCM has better SNR at same data rate
77CODEC - Performance
- Good voice reproduction
- PCM - 128 levels (7 bit)
- Voice bandwidth 4 KHZ
- Data rate should be 8000 x 7 56 kbps for PCM
- Bandwidth requirement
- Digital transmission requires 56 kbps for 4 KHz
analog signal - Using Nyquist theorem, this signal requires in
the order of 28 KHz of Bandwidth, (C/256/2)
78CODEC - Performance
- A common PCM scheme for color TV uses 10-bit
codes - For bandwidth4.6 MHz ? 92 Mbps (i.e. 24.610)
- Digital techniques continue to grow in popularity
- Repeaters used with no additive noise
- Time-division multiplexing (TDM) is used for
digital signals with no intermodulation noise - Use more efficient digital switching techniques
- More efficient codes are used to reduce required
bit rate
79Analog Data, Analog Signals
- Modulation
- Combining an input signal m(t) and a carrier at
frequency fc to produce signal s(t) with
bandwidth centered on fc - Why modulate analog signals?
- Higher frequency may be needed for effective
transmission - For unguided transmission, impossible to send
baseband signals as required antennas would be
kilometers in diameter - Permits frequency division multiplexing
- Types of modulation
- Amplitude
- Frequency
- Phase
80Analog Modulation
Amplitude Modulation (AM)
Angle Modulation (Phase, PM)
Angle Modulation (Frequency, FM)
81Amplitude Modulation
- Simplest form of modulation
- Accos 2pfct is the carrier,
- and x(t) Amcos 2pfmt is the input modulating
signal - Modulated signal expressed as
- na is the modulation index (? 1)
-
- Added 1 is a DC component to prevent loss of
information there will always be a carrier - Scheme is known as double sideband transmitted
carrier (DSBTC)
Amplitude of modulated wave
Portion of the modulating signal
82Amplitude Modulation - Example
- Given the amplitude-modulating signal x(t)Amcos
2pfmt , find s(t) - Resulting signal has three components
- At the original carrier frequency fc
- A pair of additional components each
- spaced fm Hz from the carrier
- Envelope of resulting signal is 1na x(t)
- With na lt1, envelope is exact reproduction of the
modulating signal, - So it can be recovered at receiver
- With na gt1, envelope crosses the time axis and
information is lost
Ac
Am/2
Am/2
fc
fm
fm
83Amplitude Modulation - Examples
MatLab Simulations
Modulating Signal
Carrier
Envelope
Modulated Signal
na 0.5/1 0.5
(10.5cos2pit) (1nacos2pit)
84Amplitude Modulation - Example
na 1/1 1
85Amplitude Modulation - Example
na 2/1 2 (gt1)
86Spectrum of an AM signal
Modulating Signal having a single Frequency, fm
87Spectrum of an AM signal
Modulating Signal having a finite Bandwidth, B
- Spectrum of AM signal is original
- carrier plus spectrum of original
- signal translated on both sides of fc
- Portion of spectrum f gt fc is
- upper sideband
- Portion of spectrum f lt fc is
- lower sideband
- Example voice signal 300-3000Hz
- With fc 60 KHz
- Upper sideband is 60.3-63 KHz
- Lower sideband is 57-59.7 KHz
- Bandwidth Requirement 2B
88Amplitude Modulation
- Total transmitted power Pt in modulated s(t) is
given by - Pc is transmitted power in carrier
- na should be maximized (but lt1) to allow most of
signal power to carry information - Modulated signal contains redundant information
- Only one of the sidebands is enough to restore
modulating signal - Possible ways to economize on transmitted power
- SSB single sideband, eliminates one sideband and
carrier, saves on BW ( B) - DSBSC double sideband suppressed carrier,
carrier is not transmitted, no saving on BW (
2B) - Suppressing the carrier may not be OK in some
applications, e.g. ASK, where the carrier can
provide TX-RX synchronization.
89DSBSC Double Sideband Suppressed Carrier -
Example
Suppressed Carrier
90Angle Modulation
- Includes
- Frequency modulation (FM) and
- Phase modulation (PM) as special cases
- Modulated signal is given by
- Phase modulation (PM)
- Instantaneous Phase is proportional to modulating
signal - np is phase modulation index
- Frequency modulation (FM)
- Instantaneous frequency deviation is proportional
to modulating signal - i.e. Derivative of f is proportional to
modulating signal - nf is frequency modulation index
Total Angle
91Angle Modulation
- The total phase angle of s(t) at any instant is
2pfctf(t) - Instantaneous phase deviation from carrier is
f(t) - Instantaneous angular frequency, , can be
defined as the rate of change of total phase - So, for the modulated signal, s(t)
- Phase Modulation (PM)
- f(t) npx(t), instantaneous phase deviation from
carrier is directly proportional to x(t) - Frequency Modulation (FM)
- f(t) is proportional to x(t). So, instantaneous
frequency deviation from carrier frequency is
proportional to x(t).
92Phase Modulation (PM)- Example
- Derive an expression for a phase-modulated signal
s(t) with Ac 5V, given the modulating signal - x(t) 3 sin 2pfmt
- We know that s(t)
- For PM, f (t) is given by
- Then s(t) is
- Instantaneous frequency of s(t) is
Note Frequency variations in s(t) lead x(t)
amplitude variations by 90?
93Frequency Modulation FM
- Peak frequency deviation DF is given by
-
- Where Am is the peak value of the modulating
signal x(t) - An increase in the amplitude Am of x(t) increases
DF, which increases the bandwidth requirement BT - But average power level of the FM modulated
signal is fixed at AC2/2, (does not increase with
Am) - In Amplitude Modulation, Am affects the power in
the AM signal, but does not affect the bandwidth
94Frequency Modulation - Example
- Derive an expression for a frequency-modulated
signal s(t) with Ac 5V, given the modulating
signal - x(t) 3 sin 2pfmt
- We know that s(t)
- For FM, f(t) is given by
- Then s(t) is
- We have
- Substituting for DF we get
But frequency varies as f, i.e. as sin not as
cos !!
95Bandwidth Requirement
- All AM, FM, and PM result in a modulated signal
whose bandwidth is centered at fc - Let B be the bandwidth of the modulating signal
- For AM, BT 2B
- Angle modulation includes a term of the form
cos(cos()) which is a nonlinear term producing
a wide range of frequencies fcfm, fc2fm,
(the Bessel function) - i.e. Theoretically, an infinite bandwidth is
required to transmit an FM or PM signal
96Practical Bandwidth Requirement for Angle
Modulation
- Carsons Rule of thumb
- For FM, BT 2DF 2B
- Both FM and PM require greater bandwidth than AM