Title: Waves
1Waves
2Periodic Motion
- Repeat in a regular cycle
- Examples
- Period T
- Time required to complete one cycle
- Frequency f
- Cycles that occur in one second
- Frequency is in hertz, Hz, which is 1/sec
3Periodic Motion
- Springs as periodic motion
- Always tries to return to equilibrium
- Hookes Law
- F-kx
- Potential Energy in a Spring
- PEsp1/2 kx2
4Periodic Motion
- Pendulum as simple harmonic motion
- Always tries to return to equilibrium
Distance from equilibrium as a function of time
http//www.phy.ntnu.edu.tw/ntnujava/index.php?topi
c11
5Wave Properties
- Types of Waves and Measuring Waves
6Wave Properties
Maximum distance from equilibrium
7Wave Properties
Distance from Crest to Trough (or from low peak
to high peak)
8Wave Properties
9Wave Properties
- Period/frequency
- Essentially the same variable, just inverted
- T 1/f Seconds per cycle
- f 1/T Cycles per second
- (just remember frequency always has 1 sec as the
denominator)
Cycles per second and seconds per cycle Crash
10Wave Properties
- Phase
- A way to describe the relationship between two
points on waves
¼ of the distance from the other wave
¼ x 360 90 degrees out of phase
11Wave Properties
- Equations
- Frequency f 1/T
- Wavelength ? v/f
- flambda v f ? (speed or velocity of a wave)
¼ wavelength
meters
x(meters)
t(seconds)
12Wave Properties
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14Problems
- In Class
- Pg 397
- 64, 65, 66, 67, 68, 69, 71, 73, 75, 76, 77, 79,
80 - Homework
- Pg 398
- 81, 82, 88, 89, 90, 97, 102
15Wave Behavior
- Multiple waves, multiple boundaries
16Wave Behavior
- Multiple waves can exist in the same place at the
same time. - Multiple particles cannot exist in the same place
at the same time - Note This is where the dilemma occurs when
waves and particles are not clearly separated.
17Boundaries
- Incident waves
- Waves that strike the boundary
- Reflected waves
- Waves that return from the boundary
Boundary
18Reflected Waves
- Fixed/Rigid
- Inverted reflection
- Loose
- Non-inverted reflection
- No end
- No reflection
- Reflected waves do not change speed (ever).
Speed is a function of the medium.
http//www.phy.ntnu.edu.tw/ntnujava/index.php?topi
c11
19Principle of superposition
- The displacement of the medium caused by two or
more waves is the algebraic sum of the
displacements caused by the individual waves. - Interference The result of the superposition of
two or more waves.
20Interference
- Constructive
- Result is bigger
- Destructive
- Result is smaller
21Interference
- Node Has zero displacement, does not move at
all. - Antinode Has maximum displacement.
What is the pattern? ( of nodes vs. antinodes)
22Standing Wave
- Standing wave Appears to be standing still. Is
the interference of two or more waves.
23Waves in two dimensions
24Waves in two dimensions
- Wave front A line that represents the crest or
peak of a wave in 2D. Can be any shape (e.g.
straight, circular, etc.).
25Law of reflection
- Law of reflection
- The angle of incidence is equal to the angle of
reflection
26Refraction
- Refraction The change in the direction of waves
at the boundary between different media. - Examples are echoes and rainbows
27Rules to Remember
- Speed of a wave only changes when the medium
changes (i.e. water depth changes or wave crosses
a boundary into a different medium). - Speed will not change because of wavelength or
frequency - Frequency only changes when the source changes
- Frequency will never change when the wave crosses
a boundary
28Read the Graph
- Maximum Speed, Zero Force, No Acceleration
Equilibrium Point - Maximum Displacement, Maximum Amplitude, Maximum
Force, Zero Velocity, No Motion
29Things you need to know
- EPEKE
- Work is Energy - work done is equivalent to the
change in potential energy - All lengths need to be in meters
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31Problems
- Consider a 10.0-kg pendulum clock that has a
period of 1s on Earth. If the clock is moved to a
location where it weighs 98 N, how many minutes
will the minute hand move in 1 h? - Write the equation for Earth
- Write the equation for the new location
- Set up the ratios
32Problems
- Spring A with a spring constant of 253 N/m is
stretched by a distance of 18.0 cm when a block
is suspended from its end. An object is suspended
from another spring B with a spring constant of
169 N/m. If the elastic potential energy in both
the springs is the same, how far does spring B
stretch? - Two parts
- Find k with F-kx
- Compare with PE ½ kx2
33Problems
- A 150-g object subject to a restoring force F
kx is undergoing simple harmonic motion. Shown
below is a plot of the potential energy, PE, of
the object as a function of distance, x, from its
equilibrium position. The object has a total
mechanical energy of 0.3 J.
a. What is the farthest the object moves along
the x-axis in the positive direction? Explain
your reasoning. b. What is the objects potential
energy when its displacement is 4.0 cm from its
quilibrium position? c. Determine the objects
kinetic energy when its position is x 8.0
cm. d. What is the objects speed at x 0.0 cm?
34Answer
- a. Answer 10.0 cm or 0.100 m. The total
mechanical energy is E 0.3 J, and total
mechanical energy is given by E KE PE. Since
the maximum potential energy cannot be greater
than the total mechanical energy, the maximum
potential energy is also 0.3 J. From the graph,
PE 0.3 J at x 10.0 cm. Hence the maximum
possible position in the x-direction is 10.0 cm
or 0.100 m. The particle stops at this point
(i.e. the kinetic energy KE 0 at this point)
because all of the energy is in the form of
potential energy. - b. PE 0.05 J
- Method 1
- Read off the value from the graph PE 0.05 J
- Method 2
- Since the restoring force is given by Hookes law
F kx, we can use the following equation for
the potential energy of simple harmonic motion - PEsp ½ kx2
- The maximum value of potential energy is PEmax
0.3 J. This occurs at a distance of xmax 10.0
cm 0.100 m. Use these values to determine the
value of the spring constant k - k 2PEmax/(x max2) 2(0.3J)/(0.100m)2 60M/n
- Then, to determine the value of PE at x 14.0 cm
0.040 m - PEsp ½ kx2 ½ (60N/m)(0.040m)2 0.05J
35Answer
- c. 0.1 J
- Method 1
- Read off the value from the graph PE 0.2 J
The total mechanical energy is the sum of kinetic
energy and potential energy - E KE PE
- Find the kinetic energy
- KE E PE 0.3 J 0.2 J 0.1 J
- Method 2
- Use the value of the spring constant k found in
part b - k 60 N/m
- Determine the value of PE at x 28.0 cm 20.080
m - PEsp ½ kx2 (60N/m)(20.080m)2 0.2J
- Then, find the kinetic energy
- E KE PE
- KE E PE
- 0.3 J 0.2 J 0.1 J
- d. 2 m/s
- At x 0.0cm,PEsp ½ kx2 0
- E KE PE KE 0
- so
36Problem
- Read the graph
- Given the incident wave travels at 1.0m/s
- How much time has passed in graph b?
- How far has the transmitted wave traveled in that
time? - What is the velocity of the transmitted wave in
graph b?
37Problem
- Given 3 nodes and 2 antinodes in a 2-meter span
- What happens when the frequency is doubled?
- What is the wavelength?
- Does the velocity change if the frequency
changes? - Write an equation relating the first frequency
and wavelength to the second frequency and
wavelength.
38Wave table or Ripple tank
39Problems
- In Class
- Pg 391
- 27, 28, 29, 30,
- Homework
- Pg 398
- 84, 85, 86, 87, 91, 93
40Boundaries
- Fixed
- Loose
- No end
- Incident waves
- Reflected waves Do waves slow down after
reflection? - Principle of superposition
- Wave interference
- Node
- Antinode
- Standing waves
- 2-D reflection
- 2-D refraction
- Normal
- Law of reflection angle of incidence is equal
to angle of reflection
http//phet.colorado.edu/simulations/sims.php?sim
Wave_on_a_String
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49Is it hot in here?
50Elements
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