Estimating the Difference Between Two Means

1
Estimating the Difference Between Two Means

• Given two independent random samples, a point
  estimate the difference between µ1 and µ2 is
  given by the statistic
• We can build a confidence interval for µ1 - µ2
  (given s12 and s22 known) as follows

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Example 9.9 Page 289

• Find a 96 Confidence Interval
• xbarA 36 mpg sA 6 nA 50
• xbarB 42 mpg sB 8 nB 75
• a0.04 a/2 0.02 Z0.02 2.055

Calculations 6 2.055 sqrt(64/75 36/50) lt
µB - µA lt 6 2.055 sqrt(64/75
36/50) Results 3.4224 lt µB - µA lt 8.5776
96 CI is (3.4224, 8.5776)
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Differences Between Two Means Variances Unknown

• Case 1 s12 and s22 unknown but equal
• Page 291
• Where,
• Note v n1 n2 -2

4
Differences Between Two Means Variances Unknown
(Page 293)

• Case 2 s12 and s22 unknown and not equal
• Where,
• WOW!

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Estimating µ1 µ2

• Example (s12 and s22 known)
• A farm equipment manufacturer wants to compare
  the average daily downtime of two sheet-metal
  stamping machines located in two different
  factories. Investigation of company records for
  100 randomly selected days on each of the two
  machines gave the following results
• x1 12 minutes x2 10 minutes
• s12 12 s22 8
• n1 n2 100
• Construct a 95 C.I. for µ1 µ2

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Solution

• 95 CI Z.025 1.96
• (12-10) 1.96sqrt(12/100 8/100) 2 0.8765
• 1.1235 lt µ1 µ2 lt 2.8765
• Interpretation If CI contains 0, then µ1 µ2
  may be either positive or negative (cant say
  that one is larger than the other) however,
  since the CI for µ1 µ2 is positive, we conclude
  µ1 must be larger than µ2 .

7
µ1 µ2 si2 Unknown

• Example (s12 and s22 unknown but equal)
• Suppose the farm equipment manufacturer was
  unable to gather data for 100 days. Using the
  data they were able to gather, they would still
  like to compare the downtime for the two
  machines. The data they gathered is as follows
• x1 12 minutes x2 10 minutes
• s12 12 s22 8
• n1 18 n2 14
• Construct a 95 C.I. for µ1 µ2

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Solution

• Governing Equations
• Calculations
• t0.025,30 2.042 sp2
  ((1712)(138))/30 10.267 sp 3.204
• 2 2.0423.204sqrt(1/18 1/14) 2 2.3314
• -0.3314 lt µ1 µ2 lt 4.3314
• Interpretation
• Since this CI contains 0, we cant conclude µ1 gt
  µ2 .

9
Paired Observations

• Suppose we are evaluating observations that are
  not independent
• For example, suppose a teacher wants to compare
  results of a pretest and posttest administered to
  the same group of students.
• Paired-observation or Paired-sample test
• Example murder rates in two consecutive years
  for several US cities. Construct a 90 confidence
  interval around the difference in consecutive
  years.

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Calculation of CI for Paired Data

• Example 9.12 We have 20 pairs of values. We
  calculate the difference for each pair. We
  calculate the sample standard deviation for the
  difference values. The appropriate equations are
• µd µ1 µ2
• Based on the data in Table 9.1 Dbar -0.87
  Sd 2.9773 n20
• We determine that a (1-0.05)100 CI for µd is
  -2.2634 lt µd lt 0.5234

Interpretation If CI contains 0, then µ1 µ2
may be either positive or negative (cant say
that one is larger than the other). Since this
CI contains 0, we conclude there is no
significant difference between the mean TCDD
levels in the fat tissue.
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C.I. for Proportions

• The proportion, P, in a binomial experiment may
  be estimated by
• where X is the number of successes in n trials.
• For a sample, the point estimate of the parameter
  is
• The mean for the sample proportion is
• and the sample variance

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C.I. for Proportions

• An approximate (1-a)100 confidence interval for
  p is
• Large-sample C.I. for p1 p2 is
• Interpretation If the CI contains 0

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Example 9.16 Page 304

1. If the C.I. for p1 p2 (-0.0017, 0.0217), is
   there reason to believe there is a significant
   decrease in the proportion defectives using the
   new process?
2. What if the interval were (0.002, 0.022)?
3. What if the interval were (-0.900, -0.700)?