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CS 1502 Formal Methods in Computer Science

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Every Steeler is taller than anyone who is the same size as Jim. ... Some Steeler is not taller than Jim. x (Steeler(x) Taller(x, jim) ... – PowerPoint PPT presentation

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Title: CS 1502 Formal Methods in Computer Science


1
CS 1502 Formal Methods in Computer Science
  • Lecture Notes 14
  • Translations
  • Mixed Quantifiers

2
Informal Proof
  • Prove that if the square of an integer is even,
    then so is that integer.
  • Proving the contrapositive is easier If an
    integer is not even, then its square isnt even
    either.
  • Let n be an integer. Assume Even(n), i.e.,
    Odd(n). Then we can express n as 2m 1 for some
    m. But we see that nn 2(2mm 2m) 1,
    showing that nn is odd. Thus, we have shown
    Even(n) ? Even(nn)

3
Translations
  • Every Steeler is taller than Jim.
  • ?x (Steeler(x) ? Taller(x, jim))
  • Every Steeler is taller than anyone who is the
    same size as Jim.
  • ?x Steeler(x) ? ?y (SameSize(y, jim) ? Taller(x,
    y))

4
Translations
  • Some Steeler is taller than Jim.
  • ?x (Steeler(x) ? Taller(x, jim))
  • Some Steeler is taller than anyone who is the
    same size as Jim.
  • ?x Steeler(x) ? ?y (SameSize(y, jim) ? Taller(x,
    y))

5
Translations
  • Some Steeler is not taller than Jim.
  • ?x (Steeler(x) ? ?Taller(x, jim))
  • Some Steeler is not taller than someone who is
    the same size as Jim.
  • ?x Steeler(x) ? ?y (SameSize(y, jim) ?
    ?Taller(x, y))

6
Translations
  • No Steeler is taller than Jim.
  • ?x (Steeler(x) ? ?Taller(x, jim))
  • No Steeler is taller than somebody who is the
    same size as Jim.
  • ?x Steeler(x) ? ??y(SameSize(y, jim) ? Taller(x,
    y))

7
Orders of Quantifiers
  • ?x ?y P(x,y) is logically equivalent to ?y ?x
    P(x,y)
  • ?x ?y P(x,y) is logically equivalent to
  • ?y ?x P(x,y)
  • ?x ?y P(x,y) is not logically equivalent to ?y ?x
    P(x,y)

8
A Gotcha (before moving on)
  • Suppose a world has 4 cubes, all in the same row
    (a,b,c,d)
  • Is the following true of that world?
  • all x all y ((Cube(x) Cube(y)) ?
  • (LeftOf(x,y) v RightOf(x,y)))
  • No! Can infer LeftOf(a,a) v RightOf(a,a) (same
    for b,c,d)
  • Want all x all y ((Cube(x) Cube(y) x ! y) ?
  • (LeftOf(x,y) v RightOf(x,y)))

9
Translation
  • ?x ?y P(x,y)For each x there is a y such that
    P(x,y).

y
x
10
Translation
  • ?x ?y P(x,y)There is a special x such that for
    all y, P(x,y).

11
Prenex Normal Form
  • Sentence containing no quantifiers at all, or
  • A sentence of the form Q1x1
    Q2x2 Qnxn P
  • where Qi are either the universal or
    existential quantifier, xi are variables and wff
    P is free of quantifiers.

12
Conversion to Prenex Normal Form
  • Replace implications (whose left- or right-hand
    sides include quantifiers) (A ? B) by ?A ? B
  • Move ? inwards until there are no quantifiers
    in the scope of a negation
  • Rename variables so each separate variable has
    its own name
  • Move quantifiers to the front of the sentence,
    without changing their order

13
Example
?x(C(x) ? ?y(T(y) ? L(x,y))) ? ?y(D(y) ?
B(x,y)) ?x?(C(x) ? ?y(T(y) ? L(x,y))) ?
?y(D(y) ? B(x,y)) ?x? ?y(C(x) ? T(y) ? L(x,y))
? ?y(D(y) ? B(x,y)) ?x?y?(C(x) ? T(y) ?
L(x,y)) ? ?z(D(z) ? B(x,z)) ?x?y?z?(C(x) ?
T(y) ? L(x,y)) ? (D(z) ? B(x,z)) If you want to
restore the conditional ?x?y?z(C(x) ? T(y) ?
L(x,y)) ? (D(z) ? B(x,z))
14
Translation
All cubes are to the left of something large.
?x Cube(x) ? x is to the left of something
large
?x Cube(x) ? ?y (Large(y) ? LeftOf(x,y))
Some cube is to the left of everything large.
?x Cube(x) ? x is to the left of everything
large
  • ?x Cube(x) ? ?y Large(y) ? LeftOf(x,y)

15
Translation
  • Taken(x,y) means x has taken class y
  • Domain of discourse for x is all (Pitt) students
  • Domain of discourse for y is all (Pitt) CS
    classes
  • Continued

16
  • exist x exist y Taken(x,y)
  • A student has taken a CS class
  • exist x all y Taken(x,y)
  • A student has taken all the CS classes
  • all x exist y Taken(x,y)
  • Each student has taken some CS class
  • exist y all x Taken(x,y)
  • There is a CS class that all students have taken
  • all y exist x Taken(x,y)
  • Each CS class has been taken by at least one
    student

17
Translation
  • Everyone ate a sandwich
  • Ate(x,y) DoD of x is all people DoD of y is all
    sandwiches
  • Most natural everyone ate their own sandwich
    all x exist y Ate(x,y)
  • But perhaps it was one huge sandwich exist y all
    x Ate(x,y)

18
What do these sentences mean?
  • exist y (Small(y) all x (Small(x) ? yx))
  • There is exactly one small thing!
  • all x all y ((Small(x) Small(y)) ? yx)
  • There is at most one small thing
  • T if there are 0 or 1 small things (try it in TW)

19
Valid Arguments?
YES! All Are Valid
  • exists y (Tet(y) all x (Cube(x) ?
    SameSize(y,x)))
  • ---
  • all x (Cube(x) ? exists y (Tet(y)
    SameSize(y,x)))
  • exists y (Girl(y) all x (Boy(x)? Likes(x,y)))
  • ---
  • all x (Boy(x) ? exists y (Girl(y) Likes(x,y)))
  • exists y all x (x ! y ? Adjoins(x,y))
  • ---
  • all x exists y (x ! y ? Adjoins(x,y))

20
Valid Arguments?
No! All Are Invalid!!
  • all x (Cube(x) ? exists y (Tet(y)
    SameSize(y,x)))
  • ---
  • exists y (Tet(y) all x (Cube(x) ?
    SameSize(y,x)))
  • all x (Boy(x) ? exists y (Girl(y) Likes(x,y)))
  • ---
  • exists y (Girl(y) all x (Boy(x)? Likes(x,y)))
  • all x exists y (x ! y ? Adjoins(x,y))
  • ---
  • exists y all x (x ! y ? Adjoins(x,y))

21
Translations with Function Symbols
  • Domain of discourse people
  • Every person has exactly one mother, who is older
    than he or she. With a function
  • all x OlderThan(mother(x),x)
  • With a predicate?
  • all x exist y (MotherOf(y,x) OlderThan(y,x)
    all z (MotherOf(z,x) ? yz))
  • Moral use a function when appropriate

22
Proofs with Multiple Quantifiers
?x (P(x) ??y F(y,x))?x ?y (F(y,x) ?L(y,x))?x
(P(x) ? ?y L(y,x))
23
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