Exp' 23 Determination of a Rate Law p' 267 - PowerPoint PPT Presentation

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Exp' 23 Determination of a Rate Law p' 267

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... for this reaction, we determine that log(rate) = plog[I-] C (y=mx b) ... A.4. Rapidly add solution B (H2O2) to the solution in test tube A. Start timing. ... – PowerPoint PPT presentation

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Title: Exp' 23 Determination of a Rate Law p' 267


1
Exp. 23 Determination of a Rate Law

p. 267
  • To determine the rate law for a chemical
    reaction.
  • To utilize a graphical analysis of the
    experimental data.

2
Exp. 23 Introduction
  • The rate of a chemical reaction is determined by
    a number of factors (Exp. 22)
  • Nature of reactants
  • Temperature
  • Presence of a catalyst
  • R of the reactants
  • Surface area of the reactants.

3
Exp. 23 Introduction
  • You can observe the rate as
  • a change in of one of the reactants or
    products per unit of time
  • the volume of gas produced per unit of time
  • Change in color (T) per unit of time

4
Exp. 23 Introduction
  • For the reaction A2 2B2 ? 2AB2
  • the rate of the reaction is related to the
    initial concentration of each reactant. This is
    called the rate law for the reaction and is
    written rate kA2pB2q
  • The rate constant is k which relates the rate of
    a reaction to the initial concentrations of
    reactants. It varies with temperature and is
    independent of reactant concentrations.

5
Exp. 23 Introduction
  • A study of reaction kinetics involves determining
    the values of k, p, and q.

6
Exp. 23 Introduction
  • In this experiment, you will determine p, q, and
    k for the following reaction
  • 2I-(aq) H2O2(aq) 2H3O(aq) ? I2(aq) 4H2O(l)
  • Where rate kI-pH2O2qH3Or
  • The addition of a buffer controls the speed of
    the reaction, minimizing the contribution of the
    H3O.
  • The rate law becomes kI-pH2O2q

7
Exp. 23 Introduction
  • Determination of p, the order of the reaction
    with respect to I-
  • H2O2 and H3O are maintained constant by an
    excess of H2O2 and a buffer.
  • By taking the logarithmic form of the rate law
    for this reaction, we determine that log(rate)
    plogI-C (ymx b). So, a plot of log(rate)
    vs. log I- produces a line with a slope p (fig.
    p. 268)

8
Exp. 23 Introduction
  • Determination of q, the order of the reaction
    with respect to H2O2
  • I- and H3O are maintained constant by an excess
    of KI and a buffer.
  • A second plot, of log(rate) vs. logH2O2
    produces a straight line with a slope equal to q
    (see the figure on p. 268).

9
Exp. 23 Procedural Notes
  • A.1. You will be using 150 mm test tubes.
    Clean your glassware, but do not dry with paper
    towels.
  • A.2. Follow Table 23.1
  • A.4. Rapidly add solution B (H2O2) to the
    solution in test tube A. Start timing. Watch
    for the sudden appearance of deep blue color.
    Stop timer. Be patient, this may take as long as
    3 minutes.

10
Exp. 23 Report Sheet
  • Questions 1, 3, 5
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