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Sample Mean

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Let the CDF of Zn=nMn be Gn(z). Then. its cdf. Example 11.1 If Xi ~ N(m, 2), then ... using CLT, a 100(1 )% confidence interval of m can be specified to choose ... – PowerPoint PPT presentation

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Title: Sample Mean


1
Chapter 10
2
Sample Mean
  • Definition Sample Mean
  • Assume EXi m for all i, then
  • EMn m
  • Hence, Mn is an unbiased estimate of m.
  • If Var(Xi) ?2 for all i, then
  • Convergence in probability
  • Since Mn converges to m in probability, it is a
    consistent estimator of m.
  • It can be shown that
  • Var(Mn) ?2/n
  • Thus one may work on a normalized random variable
  • Clearly, EYn 0, Var(Yn) 1

3
Sample Mean (Contd)
  • Let the CDF of ZnnMn be Gn(z). Then
  • its cdf
  • Example 11.1 If Xi N(m, ?2), then nMn N(nm,
    n?2). Let ?(x) be the cdf of the standard
    uni-variate normal density N(0,1). Then
  • and Fn(y) ?(y). Note that Fn(y) is independent
    of n. If Xi is not normal, however, Fn(y) will be
    dependent on n.
  • Example 11.2 Recall that
  • Substitute Yn, we have
  • Let Then
  • If Xis N(0,1), and ? ?,
  • Above bound is loose. For example, if n 3, then

4
Central Limit Theorem
  • Theorem (CLT) Let X1, X2, , Xn be iid random
    variables with finite mean m and variance ?2.
    Denote
  • Then
  • Significance of CLT
  • Even is unknown,
  • can be
    approximated by for n gt 30.
  • Example 11.3 A channel has bit error probability
    p. Use CLT to estimate P(more than k bits are
    incorrect when n bits are transmitted)
  • Solution Denote Xi 1 if bit i is received in
    error, 0 if correct. Then Xi Bernoulli(p).
    Thus, EXi p, Var(Xi) p(p-1). Hence

5
Confidence Interval
  • Since
  • using CLT, a 100(1??)
    confidence interval of m can be specified to
    choose appropriate value of y such that
  • where ? is determined by user.
  • To determine y, solve y?/2 s.t.
  • The length of
  • is
  • Example 11.5 Let X1, X2, , Xn be i.i.d. with
    variance ?2 2. If M100 7.129. Find the 93
    confidence interval of EXi m.
  • Solution Look-up in table 11.1.
  • 1?? 0.93, y?/2 1.812. The confidence interval
    is
  • In other words,
  • M 7.129 ? 0.2563 with 93 probability.

6
Sample Variance
  • In calculating confidence interval, we assume the
    variance ?2 is known. When ?2 is unknown, we need
    to estimate the sample variance
  • a) ES2 ?2 unbiased est.
  • b) consistent est.
  • Given the sample variance, during estimation of
    the confidence interval of m, we use S2 in lieu
    of ?2. The remaining steps are still the same.
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