Oscillations SHM - PowerPoint PPT Presentation

1 / 19
About This Presentation
Title:

Oscillations SHM

Description:

... What is the spring constant of the car's springs, assuming they act as a ... A small insect of mass 0.30 g is caught in a spiderweb of negligible mass. ... – PowerPoint PPT presentation

Number of Views:39
Avg rating:3.0/5.0
Slides: 20
Provided by: nbd4
Category:
Tags: shm | act | caught | in | oscillations | the

less

Transcript and Presenter's Notes

Title: Oscillations SHM


1
Oscillations - SHM
  • Chapter 13

2
Oscillations
  • In general an oscillation is simply aback and
    forth motion
  • Since the motion repeats itself, it is called
    periodic
  • We will look at a special type of oscillation -
    SHM

3
Simple Harmonic Motion
  • SHM is a result of the restoring force varying
    linearly with the displacement.
  • In other words if you double the distance moved
    by the oscillator, there will be twice as much
    force trying to return it to its natural state

4
SHM
  • A mass on a spring is the prime example of SHM
    since the force that restores it to its
    equilibrium position is directly proportional to
    the amount by which the spring is stretched.

5
(No Transcript)
6
Hooks Law
  • The law that governs how spring stretches
  • F -kx
  • F force exerted by the spring (N)
  • x the amount by which he string is stretched or
    compressed (m)
  • k spring constant. A measure of how stiff the
    spring is (N/m)
  • A small spring has a k 200 N/m
  • the neg. sign indicate that displacement
    and force is in opposite direction

7
Mass Oscillating on a Spring
(2)
(1)
(3)
(4)
8
(5)
(6)
(7)
9
New formula
  • Since acceleration is not constant our Big 4
    Equations do not work
  • F ma is still ok but a is always changing
  • Calculating period
  • T does not depend on amplitude does this make
    sense?
  • Frequency

10
SHM - Example
  • Many skyscrapers use huge oscillating blocks of
    concrete to help reduce the oscillation of the
    building itself. In one such building the
    3.73x105 kg block completes one oscillation in
    6.80 s. What is the spring constant for this
    block?

11
Additional Problems
  • A block of mass 1.5 kg is attached to the end of
    a vertical spring of force constant k300 N/m.
    After the block comes to rest, it is pulled down
    a distance of 2.0 cm and released.(a) What is
    the frequency of the resulting oscillations?(b)
    What are the maximum and minimum amounts of
    stretch of the spring during the oscillations of
    the block?
  • When a family of four people with a mass of 200
    kg step into their 1200 kg car, the car's springs
    compress 3 cm. (a) What is the spring constant
    of the car's springs, assuming they act as a
    single spring?(b) What are the period and
    frequency of the car after hitting a bump?
  • A small insect of mass 0.30 g is caught in a
    spiderweb of negligible mass. The web vibrates
    with a frequency of 15 Hz.(a) Estimate the value
    of the spring constant for the web.(b) At what
    frequency would you expect the web to vibrate if
    an insect of mass 0.10 g were trapped?

12
Energy Involved with SHM
  • Lets look at a similar situation but concentrate
    on the energy of the object
  • Energy stored in a spring (potential energy)
  • U PE ½ kx2

13
Energy of SHM
2
1
3
4
14
Energy Formula
  • If total energy PE KE
  • ½ kx2 ½ mv2
  • Then Total energy PE (max) (KE 0)
  • ½ kx2max
  • Remember X(max) Amplitude

15
Velocity
  • If we combine all our formulas
  • Which is useful when we solve for v

16
Simple Pendulum
  • Is this motion SHM?

17
Pendulums
  • Weight is broken into components
  • Y component tension of rope
  • X component restoring force ( brings the
    pendulum back resting position)
  • F -mg(sin?) (neg. because it acts opp to
    displacement)
  • If the angle is small and measured in radians the
    sin of angle basically equals the angle itself
    (only if ? lt 15)
  • Therefore F-mg?

18
  • Now the arc length x is given by
  • XL?
  • Which means that we can replace the angle In the
    force formula with x/L
  • F -mg (x/L)
  • F (mg/L)x
  • The formulas is just F -kx with the mg/L taking
    the place of k
  • Therefore we do have SHM

19
Period of a Pendulum
  • Period of a Spring
  • Replace the k with mg/L
  • Period of a pendulum
Write a Comment
User Comments (0)
About PowerShow.com