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2'6 More Related Rates

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A man (6 ft) walks away from a lamp post (15 ft) at 5 ft/sec. ... Dif: ds/dt = 2/3 dm/dt. So ds/dt = 2/3 (5) = 10/3 ft/sec. d(m s)/dt = dm/dt ds/dt = 5 10/3 ... – PowerPoint PPT presentation

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Title: 2'6 More Related Rates


1
2.6 More Related Rates
  • November 5

2
Example 4
  • A man (6 ft) walks away from a lamp post (15 ft)
    at 5 ft/sec. How fast is his shadow lengthening?
    How fast is the shadow's tip moving?

3
Example 4
  • Given dm/dt 5
  • Find ds/dt and d(ms)/dt dm/dt ds/dt
  • Eqn By ?s we know
  • man's ht shadow length
  • lamp's ht dist. lamp to shadow tip
  • So 6/15 s/(ms) and
  • S 2m/3 or m 3s/2

4
Example 4
  • S 2m/3
  • Dif ds/dt 2/3 dm/dt
  • So ds/dt 2/3 (5) 10/3 ft/sec
  • d(ms)/dt dm/dt ds/dt 5 10/3
  • 25/3 ft/sec

5
Example 5
  • A plane (alt. 4000 ft) is flying west at 700
    ft/s. A searchlight, under its path, tracks it.
  • How fast is the light pivoting when the plane is
    1000 ft east, overhead, 5000 ft west?
  • (see CiM)

6
Example 5
  • Given dx/dt -700
  • Find d?/dt when x 1000
  • Eqn tan? x/4000
  • Dif sec2? d?/dt 1/4000 dx/dt
  • Note when x 1000, tan? 1/4
  • So ? tan-1(1/4) 0.245 radians

7
Example 5
  • sec2? d?/dt 1/4000 dx/dt
  • sec2 (0.245) d?/dt 1/4000 (-700)
  • d?/dt (-7/40)cos2(0.245)
  • d?/dt -0.165 radians/sec

8
Add to 17
  • p. 146
  • 21,22,24,25,28, 31,32,33,39,42
  • (have 16 ready tomorrow)
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