THE MOLE - PowerPoint PPT Presentation

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THE MOLE

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... is also referred to as Avogadro's number, NA. 1 mole = NA= n = 6.022 x ... 100.0g K (1 mole K / 39.1 g K) (6.022x1023 K-atoms/1 mole K) = 1.540 x 10 24 K-atoms. ... – PowerPoint PPT presentation

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Title: THE MOLE


1
THE MOLEn
  • The mole term is similar to the dozen term.
  • Just as a dozen represents 12 the mole
    represents 6.022 x 1023. A very large amount.
  • This is due to atoms molecules being very small.
  • The mole is also referred to as Avogadros
    number, NA
  • 1 mole NA n 6.022 x 1023 particles
  • Particles could be atoms, molecules, ions,
    electrons, even eggs.

2
THE MOLE ATOMIC MASS
  • The atomic mass (weight) is measured in reference
    to the mole.
  • The atomic mass is also known as the MOLAR MASS.
  • The atomic mass mass of an element DIVIDED by 1
    mole of that element.
  • Atomic mass mass/mole or m/n.
  • Units for atomic mass is grams per mole or g/mol.
  • For example
  • H 1.008 amu
  • 1.008 g/mol
  • 6.022 x 1023 atoms
  • 1 molar mass

3
CALCULATIONS INVOLING THE MOLE.
  • Fill in the blank.
  • A mole of oxygen atoms contain _______ atoms and
    weighs ______ grams.
  • A mole of oxygen contains _____ molecules and
    ____ atoms and weighs _______ grams.
  • A mole of fluorine atoms contain _________ atoms
    and weighs _____grams.
  • A mole of fluorine contains __________ molecules
    and ________ atoms and weighs ______ grams.

6.022 x 1023
6.022 x 1023
15.999
19.00
6.022 x 1023
6.022 x 1023
2(6.022 x 1023 )
12.044 x 1023
31.998 or 2(15.999)
38.00
4
CALCULATIONS INVOLING THE MOLE.
  • How many atoms of Mg are contained in 15.0 grams
    of Mg?
  • Answer
  • 15.0 g (1 mole/24.3g)
  • 0.617 moles.
  • then
  • 0.617 mol (6.022 x 1023 atoms/ 1 mole) 3.72 x
    1023 atoms.
  • Dimensional Analysis Approach.
  • How many moles of Mg are contained in 15.0 grams
    of Mg?
  • Answer
  • 15.0 g (1 mole/24.3g)
  • 0.617 moles.
  • Remember if g is on top originally then inside
    the parenthesis it must go on the bottom.

5
MOLAR MASS FOR COMPOUNDS
  • The molar mass of any substance is the mass in
    grams for one mole of that substance.
  • H2SO4 contains 2-H atoms, 1-S atoms 4-O atoms.
    Each of those atoms contribute mass to the whole
    compound.
  • 2H 1S 4O H2SO4
  • so
  • 2(1.008 g/mol) 1(32.06 g/mol) 4(15.99 g/mol)
  • 98.04 g/mol
  • Calculate the molar mass of the following
    compounds.
  • 1. K3PO4
  • 2. Ca(OH)2
  • 3. (NH4)2SO3
  • 4. SrCl2 . 6H2O
  • answer on next page.

6
MOLAR MASS FOR COMPOUNDS
  • Answer to molar mass question.
  • 1. 3K P 4O
  • 212 g/mol
  • 2. Ca 2O 2H
  • 74 g/mol
  • 3. 2N 8H S 3O
  • 116 g/mol
  • 4. Sr 2Cl 12H 6O
  • 267 g/mol
  • Word Problems
  • How many grams does one molar mass of BaCO3
    weigh?

Answer 197 g/mol
7
CALCULATIONS INVOLING THE MOLE for COMPOUNDS.
  • How many atoms are in 6.34 g of (NH4)3PO4
  • Answer
  • 3N 12H P 4O 149 /mol
  • then
  • 6.34 g (1 mole/149 g)
  • 0.0426 moles.
  • then
  • 0.0426 mol (6.022 x 1023 formula units/ 1 mole)
    (20 atoms/1 formula unit) 5.12 x 1023 atoms.
  • Dimensional Analysis Approach.
  • How many grams of NH4NO3 are contained in 3.15
    moles of NH4NO3?
  • Answer
  • 2N 4H 3O 80 g/mol
  • 3.15 mol (80 g/mol)
  • 252 g
  • Remember if mol is on top originally then
    inside the parenthesis it must go on the bottom.

8
Challenge MOLE problems.
What mass of sodium will contain the same number
of atoms as 100.0 g of potassium? 100.0g K (1
mole K / 39.1 g K) (6.022x1023 K-atoms/1 mole K)
1.540 x 10 24 K-atoms. Now
since atoms of K atoms of Na 1.540x1024 atoms
Na (1 mol/ 6.02 x1023 atoms) (22.98 g/ 1 mol)
58.77 g of Na
9
Challenge MOLE problems.
A solution of sulfuric acid contained 65 H2SO4
by mass and had a density of 1.56 g/mL. How
many moles of acid are present in 1.00 L of the
solution? 1.00L (1000 mL/1L) 1000 mL of
solution dV m 1000 mL (1.56 g/mL) 1560
g of solution but only 65 of the solution is
H2SO4 therefore 65 (x / 1560 g) 100 so x
mass of H2SO4 1014 g 1014 g H2SO4 (1 mole /
98.04 g) 10.3 moles
10
PRACTICE PROBLEM 10
  • 1. What is the molar mass of Fe(NO2)3.6H2O
  • 2. How many moles are contained in 750.0 g of
    Fe(NO2)3?
  • 3. How many grams of iron are contained in 0.097
    mol of Fe2(CO3)3?
  • 4. How many atoms are contained in 25.0 g of
    nitrogen (N2)?
  • 5. How many grams of potassium nitrite will
    contain 6.78 x 1024 potassium atoms?
  • 6. If 25.0 g of calcium chloride reacted with
    25.0 g of sodium carbonate, how many moles of
    each will be reacting?

301.9 g/mol
3.868 mol
11 g
1.07 x 1024 N-atoms
957 g
CaCl2 0.225 mol Na2CO3 0.236 mol
11
GROUP STUDY PROBLEM 10
  • ______1. What is the molar mass of Ba(NO3)2.4H2O
  • a) 185.0 b) 261.0 c) 333.3 d) 1044
  • ______2. How many moles are contained in 54.78g
    of Cu(NO3)2?
  • a) 0.2921mol b) 3.424mol c) 187.5mol d)
    0.399
  • ______3. Which contains the larger number of
    molecules?
  • a) 125.0 g HCl b) 15.0 g C6H12O6 c)
    170.0 g of I2
  • ______4. How many grams of silver are contained
    in 0.754 mol of AgNO3?
  • a) 0.488 g b) 81.3 g c) 128g d) 170g
  • ______5. 7.0 g of nitrogen (N2) contains
  • a) 7.0 atoms of N c) 3.0 x 1023 atoms
    of N
  • b) 0.25 mole of N d) 7.0 atomic
    masses of N
  • ______6. How many atoms are in 56.9 g of
    potassium nitrite?
  • ______7. If 16.054 g of calcium chloride reacted
    with 25.004 g of sodium carbonate, how many moles
    of each will be reacting?
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