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Expressing Concentration

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... results: Nitrogen 0.50 mol; oxygen 0.50 mol; nitrogen monoxide 0.020 mol. ... 0.053 mol; carbon dioxide 0.053 mol; water 0.047 mol; carbon monoxide 0.047 mol. ... – PowerPoint PPT presentation

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Title: Expressing Concentration


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Expressing Concentration
  • Solute the dissolved particles in a solution.
  • Solvent the dissolving medium in a solution.

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Expressing Concentration
  • Molarity (M) of moles of solute
  • liters of
    solution
  • Molarities are often expressed as a number within
    brackets 5.0 ? 5.0 M, or 5.0 moles/L.
  • Molality (m) moles of solute moles
    solute
  • kilogram of solvent
    1000 g of solvent
  • Mole fraction Xa moles solute

  • Total moles of solute solvent

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EXAMPLE 1
  • 45.0g of NaOH are dissolved in 4953g of water.
    Express the molarity, molality, and mole fraction
    of this NaOH solution.

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EXAMPLE 2
  • Some students wish to make 800.0 mL of 5.50 M
    solution of sulfuric acid using dry sulfuric acid
    and water. What must they do?

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Communicating Equilibrium
  • What is a concise way to communicate the degree
    toward which a state of equilibrium lies toward
    the reactants vs. the products?

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Equilibrium Constants
  • Keq The ratio of product concentrations to
    reactant concentrations, with each concentration
    raised to a power given by the number of moles of
    that substance in the balanced chemical equation.

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Equilibrium Constant
  • aA bB ? cC dD
  • Keq Cc x Dd
  • Aa x Bb
  • If Keq gt1, products are favored at equilibrium
  • If Keq lt1, reactants are favored at equilibrium.

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EXAMPLE 3
  • Write an expression for the equilibrium constant
    for each of the following
  • 4H2(g) CS2(g) ? CH4(g) 2H2S(g)
  • 2NO(g) O2(g) ? 2NO2(g)

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EXAMPLE 4
  • At high temperature, the following system reaches
    equilibrium
  • N2(g) O2(g) ? 2NO(g)
  • An analysis of the equilibrium mixture in a
    1.00-L flask gives the following results
    Nitrogen 0.50 mol oxygen 0.50 mol nitrogen
    monoxide 0.020 mol. Calculate Keq for this
    reaction.

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EXAMPLE 5
  • At 750oC, the following system reaches
    equilibrium
  • H2(g) CO2(g) ? H2O(g) CO(g)
  • An analysis of the equilibrium mixture in a
    1.00-L flask gives the following results
    hydrogen 0.053 mol carbon dioxide 0.053 mol
    water 0.047 mol carbon monoxide 0.047 mol.
    Calculate Keq AND the change in free energy for
    this reaction.
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