Title: Elementary Linear Algebra
1Elementary Linear Algebra
2Contents
- General Linear Transformations
- Kernel and Range
- Inverse Linear Transformations
- Matrices of General Linear Transformations
- Similarity
- Isomorphism
3Linear Transformation
- Definition
- If T V ? W is a function from a vector space V
into a vector space W, then T is called a linear
transformation from V to W if for all vectors u
and v in V and all scalars c - T (u v) T (u) T (v)
- T (cu) cT (u)
- In the special case where V W, the linear
transformation T V ? V is called a linear
operator on V.
4Linear Transformation
- Example (Zero Transformation)
- The mapping T V ? W such that T(v) 0 for
every v in V is a linear transformation called
the zero transformation. - Example (Identity Operator)
- The mapping I V ? I defined by I (v) v is
called the identity operator on V.
5Orthogonal Projections
- Suppose that W is a finite-dimensional subspace
of an inner product space V then the orthogonal
projection of V onto W is the transformation
defined by - T (v) projWv
- If S w1, w2, , wr is any orthogonal basis
for W, then T (v) is given by the formula - T (v) projWv ?v, w1? w1 ?v, w2? w2
?v, wr? wr
6Orthogonal Projections
- This projection a linear transformation
- T(u v) T(u) T(v)
- T(cu) cT(u)
7A Linear Transformation from a Space V to Rn
- Let S w1, w2, , wn be a basis for an
n-dimensional vector space V, and let - (v)s (k1,, k2,, , kn)
- be the coordinate vector relative to S of a
vector v in V thus v k1w1 k2w2 kn wn
8A Linear Transformation from a Space V to Rn
- Define T V ? Rn to be the function that maps v
into its coordinate vector relative to S that
is, - T (v) (v)s (k1,, k2,, , kn)
- Then the function T is a linear transformation
- Let u c1w1 c2w2 cn wn and v d1w1
d2w2 dn wn - Check if (u v)s (u)s (v)s and (ku)s
k(u)s
9A Linear Transformation from Pn to Pn1
- Let p p(x) c0 c1x cnx n be a
polynomial in Pn , and define the function T Pn
? Pn1 by - T (p) T (p(x)) xp(x) c0x c1x2 cnx
n1 - The function T is a linear transformation
- For any scalar k and any polynomials p1 and p2 in
Pn we have - T (p1 p2) T (p1(x) p2 (x)) x (p1(x) p2
(x)) x p1(x) x p2 (x) T (p1) T (p2) - T (k p) T (k p(x)) x (k p(x)) k (x p(x)) k
T(p)
10A Linear Transformation Using an Inner Product
- Let V be an inner product space and let v0 be
any fixed vector in V. Let T V ? R be the
transformation that maps a vector v into its
inner product with v0 that is, - T (v) ?v, v0?
- From the properties of an inner product
- T (u v) ?u v, v0? ?u, v0? ?v, v0?
- T (k u) ?k u, v0? k ?u, v0? kT (u)
- Thus, T is a linear transformation.
11Example
- Let TMnn ?R be the transformation that maps an n
n matrix into its determinant that is, - T (A) det (A)
- If ngt1, then this transformation does not satisfy
either of the properties required of a linear
transformation.
12Example
- For example, we saw Example 1 of Section 2.3 that
- det (A1A2) ? det (A1) det (A2)
- in general.
- Moreover, det (cA) C n det (A), so
- det (cA) ? c det (A)
- in general.
- Thus, T is not linear transformation.
13Properties of Linear Transformation
- If T V ? W is a linear transformation, then
for any vectors v1 and v2 in V and any scalars c1
and c2, we have - T (c1v1 c2v2) T (c1v1) T (c2v2) c1T (v1)
c2T (v2) - More generally, if v1 , v2 , , vn are vectors in
V and c1 , c2 , , cn are scalars, then - T (c1v1 c2v2 cnvn ) c1T (v1) c2T (v2)
cnT (vn)
14Properties of Linear Transformation
- The above equation is sometimes described by
saying that linear transformations preserve
linear combinations.
15Theorem
- Theorem 8.1
- If T V ? W is a linear transformation, then
- T(0) 0
- T(-v) -T(v) for all v in V
- T(v w) T(v) T(w) for all v and w in V
16Finding Linear Transformations from Images of
Basis
- If T V ? W is a linear transformation, and if
v1 , v2 , , vn is any basis for V, then the
image T (v) of any vector v in V can be
calculated from the images - T (v1), T (v2), , T (vn)
- of the basis vectors.
- This can be done by first expressing v as a
linear combination of the basis vectors, say - v c1 v1 c2 v2 cn vn
- and then the transformation becomes
- T (v) c1 T (v1) c2 T (v2) cn T (vn)
- A linear transformation is completely determined
by its images of any basis vectors.
17Example
- Consider the basis S v1 , v2 , v3 for R3 ,
where - v1 (1,1,1), v2 (1,1,0), and v3 (1,0,0).
- Let T R3 ? R2 be the linear transformation
such that - T (v1) (1,0), T (v2) (2,-1), T (v3) (4,3).
- Find a formula for T (x1, x2, x3) then use this
formula to compute T (2, -3, 5).
18Example
- Solution
- Let x c1v1 c2v2 c3v3, or (x1, x2 , x3) c1
(1,1,1) c2 (1,1,0) c3 (1,0,0), then we have - c1 c2 c3 x1
- c1 c2 x2
- c1 x3
- which yields c1 x3 , c2 x2 x3 , c3
x1 x2 - Thus, x (x1, x2, x3) x3(1,1,1) (x2
x3)(1,1,0) (x1 x2)(1,0,0) - x3v1 (x2 x3 )v2 (x1 x2 )v3
- That is, T (x) T (x1, x2, x3) x3 T (v1) (x2
x3) T (v2) (x1 x2) T (v3) - x3(1,0) (x2 x3)(2,-1)
(x1 x2)(4,3) (4x1 2x2 x3 , 3x1 4x2
x3) - From this formula we obtain T (2 , -3 , 5 ) (9,
23).
19Composition of T2 with T1
- Definition
- If T1 U ? V and T2 V ? W are linear
transformations, the composition of T2 with T1,
denoted by T2 ? T1 (read T2 circle T1 ), is
the function defined by the formula - (T2 ? T1 )(u) T2 (T1 (u))
- where u is a vector in U.
20Composition of T2 with T1
- Theorem 8.1.2
- If T1 U ? V and T2 V ? W are linear
transformations, then (T2 ? T1 ) U ? W is
also a linear transformation.
21Remark
- The compositions can be defined for more than two
linear transformations. - For example, if T1 U ? V and T2 V ? W ,and
T3 W ? Y are linear transformations, then the
composition T3 ? T2 ? T1 is defined by (T3 ?
T2 ? T1 )(u) T3 (T2 (T1 (u)))
22Kernel and Range
- Recall
- If A is an m?n matrix, then the nullspace of A
consists of all vector x in Rn such that Ax 0. - The column space of A consists of all vectors b
in Rm for which there is at least one vector x in
Rn such that Ax b. - The nullspace of A consists of all vectors in Rn
that multiplication by A maps into 0. (in terms
of matrix transformation) - The column space of A consists of all vectors in
Rm that are images of at least one vector in Rn
under multiplication by A. (in terms of matrix
transformation)
23Kernel and Range
- Definition
- If T V ? W is a linear transformation, then
the set of vectors in V that T maps into 0 is
called the kernel of T it is denoted by ker(T). - The set of all vectors in W that are images
under T of at least one vector in V is called the
range of T it is denoted by R(T).
24Examples
- If TA Rn ? Rm is multiplication by the m?n
matrix A, then the kernel of TA is the nullspace
of A and the range of TA is the column space of
A. - Let T V ? W be the zero transformation. Since T
maps every vector in V into 0, it follows that
ker(T) V. Moreover, since 0 is the only image
under T of vectors in V, we have R(T) 0. - Let I V ? V be the identity operator. Since I
(v) v for all vectors in V, every vector in V
is the image of some vector thus, R(I) V.
Since the only vector that I maps into 0 is 0, it
follows ker(I) 0.
25Example
- Let T R3 ? R3 be the orthogonal projection on
the xy-plane. The kernel of T is the set of
points that T maps into 0 (0,0,0) these are
the points on the z-axis. - Since T maps every points in R3 into the
xy-plane, the range of T must be some subset of
this plane. But every point (x0 ,y0 ,0) in the
xy-plane is the image under T of some point. Thus
R(T) is the entire xy-plane.
26Example
- Let T R2 ? R2 be the linear operator that
rotates each vector in the xy-plane through the
angle ?. - Since every vector in the xy-plane can be
obtained by rotating through some vector through
angle ?, we have R(T) R2. - The only vector that rotates into 0 is 0, so
ker(T) 0.
27Properties of Kernel and Range
- Theorem 8.2.1
- If T V ? W is linear transformation, then
- The kernel of T is a subspace of V.
- The range of T is a subspace of W.
- Definition
- If T V ? W is a linear transformation, then the
dimension of the range of T is called the rank of
T and is denoted by rank(T). - The dimension of the kernel is called the nullity
of T and is denoted by nullity(T).
28Properties of Kernel and Range
- Theorem 8.2.2
- If A is an m?n matrix and TA Rn ? Rm is
multiplication by A, then - nullity (TA) nullity (A)
- rank (TA) rank (A)
29Example
- Let TA R6 ? R4 be multiplication byFind
the rank and nullity of TA - In Example 1 of Section 5.6 we showed that rank
(A) 2 and nullity (A) 4. (use reduced
row-echelon form, etc.) - Thus, from Theorem 8.2.2, rank (TA) 2 and
nullity (TA) 4.
30Example
- Let T R3 ? R3 be the orthogonal projection on
the xy-plane. - From Example 4, the kernel of T is the z-axis,
which is one-dimensional and the range of T is
the xy-plane, which is two-dimensional. - Thus, nullity (T) 1 and rank (T) 2.
31Dimension Theorem for Linear Transformations
- Theorem 8.2.3
- If T V ? W is a linear transformation from an
n-dimensional vector space V to a vector space W,
then - rank(T) nullity(T) n
- Remark
- In words, this theorem states that for linear
transformations the rank plus the nullity is
equal to the dimension of the domain.
32Dimension Theorem for Linear Transformations
- Example
- Let T R2 ? R2 be the linear operator that
rotates each vector in the xy-plane through an
angle ?. We showed that ker(T) 0 and R(T)
R2. - Thus, rank(T) nullity(T) 2 0 2.
33One-to-One Linear Transformation
- Definition
- A linear transformation T V ? W is said to be
one-to-one if T maps distinct vectors in V into
distinct vectors in W.
34One-to-One Linear Transformation
- Examples
- If A is an n?n matrix and TA Rn ? Rn is
multiplication by A, then TA is one-to-one if and
only if A is an invertible matrix (Theorem
4.3.1). - Let T Pn ? Pn1 be the linear transformation T
(p) T(p(x)) xp(x). If p p(x) c0 c1 x
cn xn and q q(x) d0 d1 x dn xn are
distinct polynomials, then they differ in at
least one coefficient. Thus, T (p) c0 x c1
x2 cn xn1 and T (q) d0 x d1 x2 dn
xn1 also differ in at least one coefficient.
Thus, T is one-to-one, since it maps distinct
polynomials p and q into distinct polynomials T
(p) and T (q).
35Theorems
- Theorem 8.3.1 (Equivalent Statements)
- If T V ? W is a linear transformation, then the
following are equivalent. - T is one-to-one
- The kernel of T contains only zero vector that
is, ker(T) 0 - Nullity(T) 0
36Theorems
- Theorem 8.3.2
- If V is a finite-dimensional vector space and T
V ? V is a linear operator, then the following
are equivalent. - T is one-to-one
- ker(T) 0
- Nullity(T) 0
- The range of T is V that is, R(T) V
37Example
- Let TA R4 ? R4 be multiplication
byDetermine whether TA is one to one. - Solution
- det(A) 0, since the first two rows of A are
proportional ? A is not invertible? TA is not
one-to-one.
38Inverse Linear Transformations
- If T V ? W is a linear transformation, then the
range of T denoted by R (T), is the subspace of W
consisting of all images under T of vectors in V.
- If T is one-to-one, then each vector w in R(T) is
the image of a unique vector v in V. - This uniqueness allows us to define a new
function, call the inverse of T, denoted by T 1,
which maps w back into v. - The mapping T 1 R (T) ? V is a linear
transformation. Moreover, - T 1(T (v)) T 1(w) v
- T 1(T (w)) T 1(v) w
39Inverse Linear Transformations
- If T V ? W is a one-to-one linear
transformation, then the domain of T 1 is the
range of T. - The range may or may not be all of W (one-to-one
but not onto). - For the special case that T V ? V, then the
linear transformation is one-to-one and onto.
40Example (An Inverse Transformation)
- Let T R3 ? R3 be the linear operator defined by
the formula - T (x1, x2, x3) (3x1 x2, -2x1 4x2 3x3, 5x1
4 x2 2x3). - Determine whether T is one-to-one if so, find T
-1(x1,x2,x3) .
41Example (An Inverse Transformation)
42Theorem
- Theorem 8.3.3
- If T1 U ? V and T2 V ? W are one to one
linear transformation then - T2 ? T1 is one to one
- (T2 ? T1)-1 T1-1 ? T2-1
43Matrices of General Linear Transformations
- Remark
- If V and W are finite-dimensional vector spaces
(not necessarily Rn and Rm), then any
transformation T V ? W can be regarded as a
matrix transformation. - The basic idea is to work with coordinate
matrices of the vectors rather than with the
vectors themselves.
44Matrices of Linear Transformations
- Suppose V and W are n and m dimensional vector
space and B and B? are bases for V and W, then
for x in V, the coordinate matrix xB will be a
vector in Rn, and coordinate matrix T(x) B?
will be a vector in Rm .
45Matrices of Linear Transformations
- If we let A be the standard matrix for this
transformation, then A xB T (x)B? - The matrix A is called the matrix for T with
respect to the bases B and B?
46Matrices of Linear Transformations
- Let B u1, , un be a basis for the
n-dimensional space V and B? u1, , um be a
basis for the m-dimensional space W. - Consider an m?n matrix such that A xB
T(x)B? holds for all vectors x in V.
47Matrices of Linear Transformations
- That is, A xB T(x)B? has to hold for the
basis vectors u1, , un. - Thus, we need
- A u1B T(u1)B? ,
- A u2B T(u2)B? , , A unB T(un)B?
- Since
- u1B e1 , u2B e2 , , unB en
48Matrices of Linear Transformations
- We have
- Thus, , which is the matrix for T w.r.t. the
bases B and B?, and denoted by the symbol TB?,B
49Matrices of Linear Transformations
Basis for the image space
Basis for the domain
50Matrices for Linear Operators
- In the special case where V W, the resulting
matrix is called the matrix for T with respect to
the basis B and denoted by TB rather than
TB,B. - If B u1, , un , then we have
- and
- That is, the matrix for T times the coordinate
matrix for x is the coordinate matrix for T(x).
51Example
- Let T P1 ? P2 be the transformations defined
by - T (p(x)) xp(x).
- Find the matrix for T with respect to the
standard bases, - B u1, u2 and B? v1, v2, v3,
- where u1 1, u2 x v1 1, v2 x , v3 x2
- Solution
- T(u1) T(1) (x)(1) x and T(u2)
T(x) (x)(x) x2 - T (u1)B 0 1 0T T (u2)B 0 0 1T
- Thus, the matrix for T w.r.t. B and B is
52Example
- Let T R2 ? R3 be the linear transformation
defined by - Find the matrix for the transformation T with
respect to the bases B u1,u2 for R2 and B?
v1,v2,v3 for R3, where - Solution
53Example
54Theorems
- Theorem 8.4.1
- If T Rn ? Rm is a linear transformation and if
B and B? are the standard bases for Rn and Rm,
respectively, then - TB?,B T
- Theorem 8.4.2
- If T1 U ? V and T2 V ? W are linear
transformations, and if B, B?? and B? are bases
for U, V and W, respectively, then - T2 ? T1B,B T2 B,BT1 B,B
- Theorem 8.4.3
- If T V ? V is a linear operator and if B is a
basis for V then the following are equivalent - T is one to one
- TB is invertible
- Moreover, when these equivalent conditions hold
- T-1B TB-1
55Indirect Computation of a Linear Transformation
- An indirect procedure to compute a linear
transformation - Compute the coordinate matrix xB
- Multiply xB on the left by TB?,B to produce
T (x)B? - Reconstruct T (x) from its coordinate matrix T
(x)B?
56Example
- Let T P2 ? P2 be linear operator defined by
T(p(x)) p(3x 5), that is, T (co c1x c2x2)
co c1(3x 5) c2(3x 5)2 - Find TB with respect to the basis B 1, x,
x2 - Use the indirect procedure to compute T (1 2x
3x2) - Check the result by computing T (1 2x 3x2)
57Example
- Solution
- Form the formula for T,
- T(1) 1, T(x) 3x 5, T(x2) (3x 5)2 9x2
30x 25 - Thus,
58Example
- The coordinate matrix relative to B for vector p
1 2x 3x2 is - pB 1 2 3T.
- Thus, T (1 2x 3x2)B T (p)B TB pB
? T (1 2x 3x2) 66 84x 27x2 - By direction computation
- T (1 2x 3x2) 1 2(3x 5) 3(3x 5)2
- 1 6x 10 27x2 90x 75
- 66 84x 27x2
59Similarity
- The matrix of a linear operator T V ? V depends
on the basis selected for V that makes the matrix
for T as simple as possible a diagonal or
triangular matrix.
60Simple Matrices for Linear Operators
- Consider the linear operator T R2 ? R2 defined
by - and the standard basis B e1, e2 for R2.
- The matrix for T with respect to this basis is
the standard matrix for T that is, TB T
T(e1) T(e2). - Since T (e1) 1 -2T, T (e2) 1 4T, we have
61Simple Matrices for Linear Operators
- However, if u1 1 1T, u2 1 2T, then the
matrix for T with respect to the basis B? u1,
u2 is the diagonal matrix - This matrix is simpler in the sense that
diagonal matrices enjoy special properties that
more general matrices do not!
62Theorem
- Theorem 8.5.1
- If B and B? are bases for a finite-dimensional
vector space V, and if I V ? V is the identity
operator, then IB,B? is the transition matrix
from B? to B. - Remark
I
V
V
v
v
Basis B?
Basis B
IB,B? is the transition matrix from B? to B.
63Theorem
- Theorem 8.5.2
- Let T V ? V be a linear operator on a
finite-dimensional vector space V, and let B and
B? be bases for V. Then - TB? P-1 TB P
- where P is the transition matrix from B? to B.
- Remark
I
I
T
v
v
T(v)
T(v)
V
V
V
V
Basis B?
Basis B?
Basis B
Basis B
TB? IB?,BTBIB,B? P-1 TB P
64Example
- Let T R2 ? R2 be defined byFind the matrix T
with respect to the standard basis B e1, e2
for R2, then use Theorem 8.5.2 to find the matrix
of T with respect to the basis B? u1?, u2?,
where u1? 1 1T and u2? 1 2T.
65Example
- Solution
- By inspection, u1? e1 e2 and u2? e1 2 e2,
? u1?B 1 1T and u2?B 1 2T.
66Definitions
- Definition
- If A and B are square matrices, we say that B is
similar to A if there is an invertible matrix P
such that B P-1AP - Definition
- A property of square matrices is said to be a
similarity invariant or invariant under
similarity if that property is shared by any two
similar matrices.
67Similarity Invariants
68Determinant of A Linear Operator
- Two matrices representing the same linear
operator T V ? V with respect to different
bases are similar. - For any two bases B and B? we must have
- det(TB) det(TB?)
- Thus we define the determinant of the linear
operator T to be - det(T) det(TB)
- where B is any basis for V.
69Determinant of A Linear Operator
- Example
- Let T R2 ? R2 be defined by
70Eigenvalues of a Linear Operator
- A scalar l is called an eigenvalue of a linear
operator T V ? V if there is a nonzero vector x
in V such that Tx lx. The vector x is called an
eigenvector of T corresponding to l. - Equivalently, the eigenvectors of T corresponding
to l are the nonzero vectors in the kernel of lI
T. This kernel is called the eigenspace of T
corresponding to l.
71Eigenvalues of a Linear Operator
- If V is a finite-dimensional vector space, and B
is any basis for V, then - The eigenvalues of T are the same as the
eigenvalues of TB . - A vector x is an eigenvector of T corresponding
to TB if and only if its coordinate matrix xB
is an eigenvector of TB corresponding to l.
72Example
- Find the eigenvalues and bases for the
eigenvalues of the linear operator T P2 ? P2
defined by - T (a bx cx2) -2c (a 2b c)x (a
3c)x2
73Example
- Solution
- The matrix for T with respect to the standard
basis B 1, x, x2 is - The eigenvalues of T are l 1 and l 2
- The eigenvectors of TB are
- l 2 l 1
- Thus, the eigenvectors of T are p1 -1 x2 , p2
x , p3 -2 x x2 - Check T (p1) 2p1, T (p2) 2p2 and T (p3) p3
74Example
- Let T R3 ? R3 be the linear operator given
byFind a basis for R3 relative to which the
matrix for T is diagonal. - Solution
- det(lI - A) l3 - 5l2 8l - 4 (l-2)(l-2)(l-1)
75Onto Transformations
- Definitions
- Let V and W be real vector spaces. We say that
the linear transformation T V ? W is onto if
the range of T is W. - An onto transformation is also said to be
surjective or to be a surjection. For a
surjective mapping, the range and the codomain
coincide. - If a transformation T V ? W is both one-to-one
(also called injective or an injection) and onto,
then it is a one-to-one mapping to its range W
and so has an inverse T-1 W ? V.
76Onto Transformations
- Theorem 8.6.1 (Bijective Linear Transformation)
- Let V and W be finite-dimensional vector spaces.
If dim(V) ? dim(W), then there can be no
bijective linear transformation from V to W.
77Isomorphisms
- Definition
- An isomorphism between V and W is a bijective
linear transformation from V to W. - Theorem 8.6.2 (Isomorphism Theorem)
- Let V be a finite-dimensional real vector space.
If dim(V) n, then there is an isomorphism from
V to Rn. - Example
- The vector space P3 is isomorphic to R4, because
the transformation - T(a bx cx2 dx3) (a,b,c,d)
- is one-to-one, onto, and linear.
78Isomorphisms between Vector Spaces
- Theorem 8.6.3 (Isomorphism of Finite-Dimensional
Vector Spaces) - Let V and W be finite-dimensional vector spaces.
If dim(V) dim(W), then V and W are isomorphic.
79Isomorphisms between Vector Spaces
- Example (An Isomorphism between P3 and M22)
- Because dim(P3) 4 and dim(M22) 4, these
spaces are isomorphic. - We can find an isomorphism T P3 ? M22
- This is one-to-one and onto linear
transformation, so it is an isomorphism between
P3 and M22.