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Fire Dynamics I

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Carleton University, 82.575 (CVG7300), Fire Dynamics I, Winter 2002, Lecture # 5 ... For 89 mm batt insulation with (R12) R = 12 ft2 F h Btu-1 = 2.10 m2 K W-1 ... – PowerPoint PPT presentation

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Title: Fire Dynamics I


1
Fire Dynamics I
  • Lecture 5
  • Heat Transfer
  • Conduction
  • Jim Mehaffey
  • 82.575 or CVG7300

2
  • Heat Transfer Convection Radiation
  • Outline
  • Steady-state conduction
  • Transient conduction
  • Numerical Methods

3
  • Heat Transfer by Conduction
  • Heat transfer from regions of high temp to
    regions of lower temp within solids
  • Important
  • in ignition and spread of flame over combustible
    solids, and
  • in fire resistance of combustible or
    noncombustible building elements

4
  • Heat Transfer by Conduction
  • Satisfies Fourier laws
  • Eqn (5-1)

5
  • k -Thermal Conductivity
  • Materials with large k are good thermal (and
    often electrical) conductors
  • Materials with small k are good thermal (and
    often electrical) insulators
  • k is temperature dependent

6
  • k -Thermal Conductivity (1)
  • At temperatures found in Canadian climates

7
  • k -Thermal Conductivity (3)
  • At elevated temperatures associated with fire

8
  • Steady-state Conduction
  • Consider 1-D heat flow through a wall of
    thickness L
  • Surfaces at temperatures Th Tc with Th gt Tc
  • For example exterior
  • wall in the winter

9
  • Steady-state Conduction
  • Fouriers Law of heat conduction (1-D)
  • Eqn (5-2)
  • is constant (independent of x and t)
  • Integrating over thickness of wall assuming k is
    independent of temperature
  • Eqn (5-3)
  • Heat transfer governed by k / L

10
  • Steady-state Conduction
  • Integrating to depth x
  • Tx Th - x / k
  • or
  • Tx Th - (Th - Tc) x / L Eqn (5-4)
  • Tx

11
  • Convection and Steady-state Conduction
  • On hot side of wall, gas temperature is Th and
    convective heat transfer coefficient is hh
  • On cold side of wall, gas temperature is Tc and
    convective heat transfer coefficient is hc
  • Surfaces temperatures are T1 (hot side) T2
    (cold side)

12
  • Convection and Steady-state Conduction
  • hh (Th - T1) k / L (T1 - T2) hc(T2 -
    Tc)
  • Th - T1 / hh
  • or T1 - T2 L / k
  • T2 - Tc / hc
  • adding Th - Tc 1/hh L/k 1/hc
  • or Eqn (5-5)

13
  • Convection and Steady-state Conduction
  • For a wall containing 3 layers with properties
    (k1, L1), (k2, L2) and (k3, L3)
  • Th - Tc 1/hh L1/k1 L2/k2
    L3/k3 1/hc
  • Eqn (5-6)

14
  • Analogy between Electrical Thermal Resistance
  • Resistors in Series
  • V
  • R1 R2
    R3 R4
    R5
  • 1/hh L1/k1 L2/k2
    L3/k3 1/hc
  • ?T

15
  • Thermal Resistance
  • R 1 / h (m2 K W-1) fluid to solid
  • R L / k (m2 K W-1) across a solid
  • In Imperial units R (ft2 F h Btu-1)
  • 1.0 ft2 F h Btu-1 0.176 m2 K W-1
  • For 89 mm batt insulation with (R12)
  • R 12 ft2 F h Btu-1 2.10 m2 K W-1

16
  • Analogy between Electrical Thermal Resistance
  • Resistors in Parallel
  • Not a bad approximation if
  • thermal resistors are thermally isolated

17
  • Transient Conduction - Fire Exposure
  • 1-D partial differential equation
  • Eqn (5-7)

18
  • Transient Conduction - Fire Exposure
  • 3-D partial differential equation
  • Eqn (5-8)

19
  • Transient Conduction - Fire Exposure
  • For many applications we can assume
  • k ? k (T)
  • 1-D transient equation can be written
  • Eqn (5-9)

20
  • k -Thermal Conductivity (1)
  • At temperatures found in Canadian climates

21
  • k -Thermal Conductivity (3)
  • At elevated temperatures associated with fire

22
  • Thermally Thin Solid - Transient Heating
  • ? ? Thin solid at To is
    suddenly immersed in gas current at T?
  • T? T T? Assume
    convective heating on on both surfaces (Area
    2A)
  • ? ? Use lumped thermal
    capacity L analysis
  • Volume V A L

23
  • Thermally Thin Solid - Transient Heating
  • Volume of solid is V A L
  • Energy absorbed during time dt 2 A h (T? -T) dt
  • Corresponding increase in internal energy ? c V
    dT
  • ? 2 A h (T? -T) dt ? c V dT
    Eqn (5-10)
  • If h T? are independent of t, integrate Eqn
    (5-10)
  • (T? -T) (T? -To) exp - 2 h t / (L ? c)
    Eqn (5-11)
  • Lumped thermal capacity assumption is valid
    provided
  • Biot Number Bi hL/k ? 0.2

24
  • Transient Conduction
  • Semi-finite solid
  • Assume solid is initially at To
  • At t 0 surface is suddenly increased to T? by
    application of heat
  • Solve Eqn (5-9) subject to initial condition
    two boundary conditions

Heat
x
25
  • Transient Conduction
  • Solution
  • (T - To) (T? - To)
  • (T? - To) Eqn (5-12)
  • Where the error function is
  • Eqn (5-13)
  • Fourier number ? t / x2

26
  • Error Function (1)

27
  • Error Function

28
  • Depth of Penetration of Heat
  • L Depth at which (T - To) is 0.5 of (T? - To)
  • (T - To) 0.005 (T? - To)
  • 0.005
  • ? 2
  • Eqn (5-14)

29
  • Thermally Thick Solid
  • A solid is considered thermally thick
    (semi-infinite approximation is okay) if
  • Thickness ?
  • is a measure of depth of penetration of
    heat
  • _____________________________________________
  • Some researchers claim it is okay to assume a
    solid is semi-infinite if
  • Thickness ?
  • (T - To) 0.157 (T? - To)

30
  • k -Thermal Diffusivity (3)
  • At elevated temperatures associated with fire

31
  • Depth of Penetration of Heat

32
  • Transient Conduction
  • Semi-finite solid
  • Assume solid is initially at To
  • For t ? 0, heat flux q (W m-2) absorbed at
    surface
  • Solve Eqn (5-9) subject to initial condition
    two boundary conditions

q
x
33
  • Transient Conduction
  • Solution
  • (T - To) q -
    Eqn (5-15)
  • Surface temperature (x0) is Ts
  • (Ts - To) q
    Eqn (5-16)
  • thermal inertia (J m-2 s1/2 K-1)

34
  • k -Thermal Inertia (3)
  • At elevated temperatures associated with fire

35
  • Transient Conduction
  • q Semi-finite solid
  • radiant heating
  • convective
  • cooling
  • Assume solid and air initially at To
  • For t ? 0, radiant flux q (W m-2) absorbed at
    surface which begins to undergo convective
    cooling h(Ts-To)
  • Solve Eqn (5-9) subject to initial condition
    two boundary conditions

x
36
  • Transient Conduction
  • Solution
  • Surface temperature (x0) is Ts
  • Eqn (5-17)

37

38

39
  • Eqn (5-17)
  • For small times (t ?0) (see page 5-33)
  • Eqn (5-16)
  • For long times (t ??)
  • Eqn (5-18)
  • which is bound but independent of k, ? and c

40
  • Transient Conduction
  • T? Semi-finite solid
  • Convective
  • heating
  • Assume solid is initially at To
  • At t 0, solid is brought in contact with a gas
    T? and experiences convective heating h(T? -Ts)
  • Solve Eqn (5-9) subject to initial condition
    two boundary conditions

x
41
  • Transient Conduction
  • Solution
  • Surface temperature (x0) is Ts
  • Eqn (5-19)

42
  • For small times (t ?0)
  • Eqn (5-20)
  • or
  • see pages 3-33 and 3-39
  • For long times (t ??)
  • TS T? Eqn (5-21)
  • which is bound but independent of k, ? and c

43
  • Effect of Thermal Inertia on
  • Surface Temperature Eqn (5- 19)
  • Assume h 25 W m-2 K-1

44
  • Effect of Thermal Inertia on
  • Surface Temperature Eqn (5- 19)

45
  • Summary - Conduction
  • Steady-state conduction governed by k / L
  • e.g. thermal insulation
  • Penetration depth governed by
  • e.g. fire resistance
  • Surface temperature governed by
  • e.g. ignition and flame spread

46
  • Numerical Methods
  • Analytical solution yielding algebraic expression
    (temperature) not possible if
  • Boundary conditions are nonlinear (radiation)
  • Thermal properties are temperature dependent
  • k k(T) ? ? (T) c c(T) Q ? 0
  • Conduction is 2-D or 3-D
  • Must resort to numerical (computer) solution of
    heat conduction equation

47
  • References
  • 1. D. Drysdale, An Introduction to Fire
    Dynamics,Wiley, 1999, Chap 1
  • 2. J.A. Rockett and J.A. Milke, Conduction of
    Heat in Solids Section 1 / Chapter 2, SFPE
    Handbook, 2nd Ed. (1995)
  • 3. 5. T.Z. Harmathy and J.R. Mehaffey,
    Post-Flashover Compartment Fires,
    Fire and Materials Vol 7, 49-61 (1983)
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