Title: Relational Query Optimization
1Relational Query Optimization
2Query Blocks Units of Optimization
- An SQL query is parsed into a collection of query
blocks - An SQL query with no nesting and exactly one
SELECT, FROM, WHERE, GROUP BY, and HAVING
clause. - WHERE is in conjunctive normal form.
3Query Blocks Units of Optimization
- Nested blocks are usually treated as calls to a
subroutine, made once per outer tuple. - Optimization is one block at a time.
SELECT S.sname FROM Sailors S WHERE S.age IN
Reference to nested block
SELECT S.sname FROM Sailors S WHERE S.age IN
(SELECT MAX (S2.age) FROM Sailors
S2 GROUP BY S2.rating)
SELECT MAX (S2.age) FROM Sailors S2
GROUP BY S2.rating
Nested block
Outer block
4Query Block
- For each block, the plans considered are
- All available access methods
- for each relation in FROM clause.
- All left-deep join trees
- all ways to join the relations one-at-a-time,
with inner relation in FROM clause, considering
all relation permutations and join methods.
5Cost Estimation
- For each plan considered, must estimate cost
- Must estimate cost of each operation in plan
tree. - Depends on input cardinalities.
- Depends on algorithm (sequential scan, index
scan). - Must also estimate size of result for each
operation. - Use information about the input relations.
- Must make assumptions about effect of predicates.
- Cost of plan sum of cost of each operator in
tree.
6Size Estimation and Reduction Factors
SELECT attribute list FROM relation list WHERE
term1 AND ... AND termk
- Goal Estimate result size !
7Size Estimation and Reduction Factors
SELECT attribute list FROM relation list WHERE
term1 AND ... AND termk
- Consider a query block
- Given maximum tuples in result
- product of cardinalities of relations in FROM
clause. - Reduction factor (RF) associated with each term
- reflects impact of term in reducing result size.
- Result size
- product of cardinalities of involved relations
(FROM) product of reduction factors (WHERE).
8Assumptions
- Uniform distribution of values in domain
- Independent distribution of values in different
columns. - For selections and joins, assume independence of
predicates.
9Reduction Factors
- Reduction factor (RF) associated with each term
- Term colvalue has
- RF 1/NKeys(I), given index I on col
- Term col1col2 has
- RF 1/MAX(NKeys(I1), NKeys(I2))
- Term colgtvalue has
- RF (High(I)-value)/(High(I)-Low(I))
10Reduction Factors
- Column value. - Given the index I on
column, assume uniform distribution. - 1/Nkeys(I).
- Otherwise, fixed reduction factor 1/10
- Column1 column2 - Given indexes I1 and I2 on
column1 and column2, assuming each key value in
I1 (smaller one) has a matching value in I2. - 1/MAX(Nkeys(I1), Nkeys(I2)).
- One index I, 1/Nkeys(I)
- otherwise, 1/10
- Column gt values - Given an index I on column,
arithmetic type. - High(I) value / High(I) Low(I).
- Not arithmetic type, or no index.
- A fraction Less than half is arbitrarily chosen.
- Column IN (list of values) - reduction factor
for (column value) number of items in list.
11 More on Estimation
- Uniform distribution is not accurate since real
data is not uniformly distributed. - Histogram a data structure maintained by a DBMS
to approximate a data distribution.
12Estimation
- Equi-width divide range of column values into
subranges (buckets). Assuming the distribution
within the histogram bucket is uniform. - Equi-depth number of tuples within each bucket
is equal (almost). - Compressed equi-depth maintain separate counts
for a small number of very frequent values, and
maintain equi-depth histogram to cover the
remaining values.
5.0
5.0
5.0
9.0
Equiwidth
Equidepth
2 3 3 1 2 1 3 4 8 2 0 1 2 4 9
2.67
2.25
2.5
1.33
1.0
1.75
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
Bucket 1 2 3 4 5 Count 8 4 15 3
15
Bucket 1 2 3 4 5 Count 9 10 10 7
9
13Relational Algebra Equivalences
- Allow us to choose different join orders
- Allow us to push selections and projections
ahead of joins.
14Relational Algebra Equivalences
Combine several selections into one selection.
Evaluate conjunctive condition to each of the
tuple.
Separate conjunctions into smaller selection
operations, Able to combine as Join.
(Commute)
15Relational Algebra Equivalences
(Cascade)
Where ai ? ai1 for i 1n-1.
16Relational Algebra Equivalences
(Associative)
R (S T) (R S) T
(Commute)
(R S) (S R)
- When join several relations, we are free to
join the relations in any order we choose.
17Selects, Projects and Joins
- Case1 A projection commutes with a selection
that only uses attributes retained by the
projection. - ?a (?c(R)) ? ?c (?a(R))
- Case2 Combine a selection with a cross-product
to form a join. R c S ? ?c (R?S) - Case3 A selection on just attributes of R
commutes with Join. i.e., (R S)
(R) S
18Selects, Projects and Joins
- Selection and Joins
- ?c1?c2 ?c3 (R S) ? ?c1(?c2 (R) ?c3 (S))
- Project and Joins ?a (R?S) ? ?a1 (R) ? ?a2 (S)
?a (R c S) ? ?a1 (R) c ?a2 (S)
(Where c appear in a)
19Enumeration of Alternative Plans
- There are two main cases
- Single-relation plans
- Multiple-relation plans
20Single Relation Plans
- Queries over a single relation combination of
selects, projects, and aggregate operations - Main decision Which access path for retrieving
tuples. - Most selective access path (file scan / index) if
only single operator considered. - The different operations essentially carried out
together. - e.g., if an index is used for a selection,
projection is done for each retrieved tuple, and
the resulting tuples are pipelined into the
aggregate computation.
21Single Relation Plans without Index
? s.rating, COUNT()(HAVING COUNT
DISTINCT(S.sname) gt 2(GROUP Bys.rating(
?s.rating, S.sname ( ? s.ratinggt5 ? S.age20
(Sailors)))))
SELECT S.rating, COUNT() FROM Sailors S WHERE
S.rating gt 5 AND S.age 20 GROUP BY
S.rating HAVING COUNT DISTINCT (S.sname) gt 2
Sailors 500 pages
- File scan to retrieve tuples and apply the
selections and projections. - Writing out tuples after the selections and
projections. - Sorting these tuples to implement the GROUP BY
clause. - Then GROUP BY and HAVING are done
on-the-fly. - e.g., Cost Cost1(scan) cost2 (writing
ltS.rating, S.snamegt pairs) cost3
(sorting as per the GROUP BY clause).
cost1 500 pages - cost2 500 ratio of tuple size RFs
20 pages ratio of tuple size pair size /
tuple size 0.8 - RF(s.ratinggt5) 0.5 RF(S.age20) 0.1
- cost3 3Npages 60 (assuming two
passes)
22Single-Relation Plans with Index
- Single-index access path
- When several indexes match the selection
conditions, choose the most selective access
path. - Multiple-index access path
- Several indexes using Alternatives (2) or (3) for
data entries match the selection condition. - Retrieve rids using them individually.
- Intersect result set. Sort by page id.
- Sorted-index access path
- Grouping attributes is a prefix of a tree index.
- Using index to retrieve tuples in order required
by GROUP BY - Index-only access path
- All attributes mentioned in the query are
included in the search key for some dense index
on the relation in the FROM clause. - Index-only scan to compute the answer.
23Single-Relation Plans with Index
- Index I on primary key matches selection
- Cost is Height(I)1 for a B tree, about 1.21
for hash index. - Clustered index I matching one or more selects
- (NPages(I)NPages(R)) product of RFs of
matching selects. - Non-clustered index I matching one or more
selects - (NPages(I)NTuples(R)) product of RFs of
matching selects. - Sequential scan of file
- NPages(R).
24Single-Relation Example
SELECT S.sid FROM Sailors S WHERE S.rating8
- Sailors 500 pages, 80 tuples/page
- Case2 index on rating.
- Clustered index (1/NKeys(I))
(NPages(I)NPages(S)) (1/10) (50500) pages
Unclustered index (1/NKeys(I))
(NPages(I)NTuples(S)) (1/10) (5040000)
pages - Case3 index on sid.
- Would have to retrieve all tuples/pages. With a
clustered index, the cost is 50500, with
unclustered index, 5040000. - Case4 file scan
- We retrieve all file pages (500).
25Queries Over Multiple Relations
- As the number of joins increases, the number of
alternative plans grows rapidly - We need to restrict search space !
26Queries Over Multiple Relations
- Fundamental decision in System R (IBM)
- Only left-deep join trees are considered.
- Left-deep trees can generate all fully pipelined
plans. - Intermediate results not written to temporary
files. - Not all left-deep trees are fully pipelined
(e.g., SM join).
27Enumeration of Left-Deep Plans
- Left-deep plans differ in
- the order of relations,
- the access method for each relation, and
- the join method for each join.
28Enumeration of Left-Deep Plans
- Enumerated using N passes (if N relations
joined) - Pass 1 Find best 1-relation plan for each
relation. - Pass 2 Find best way to join result of each
1-relation plan (as outer) to another relation.
(All 2-relation plans.) - Pass N Find best way to join result of a
(N-1)-relation plan (as outer) to the Nth
relation. (All N-relation plans.) - For each subset of relations, retain
- Cheapest plan overall, plus
- Cheapest plan for each interesting
order of the tuples.
B
A
C
D
Pass 1
Pass 2
Pass 3
29Enumeration of Left-Deep Plans Pass 1
- Identify selection terms in WHERE clause that
mention only attributes of A. (perform access of
A, before Join) - Identify attributes of A not mentioned in SELECT
or WHERE (project out when first access of A,
before Join) - Keep cheapest overall plan for fetching all
tuples - a file scan
- Keep cheapest plan with tuples in search key
order - B tree index
30Left-Deep Plans All 2-relation Plans
- Each of the single-relation plan from Pass 1 as
the outer relation, and every other relation as
the inner relation. - Examine WHERE clauses
- Selections involving only attributes of inner
relation (apply before Join). - Selections defining the Join.
- Selections involving attributes of other
relations (apply after Join). - Only selections that are really applied before
the join are those that match the chosen access
paths for A and B. - Depending on the Join algorithm chosen, the cost
may include materializing the outer relation.
31Enumeration of Plans (Contd.)
- ORDER BY, GROUP BY, aggregates etc. handled as a
final step, using either an interestingly
ordered plan or an additional sorting operator. - An N-1 way plan is not combined with another
relation unless join condition between them - avoid Cartesian products if possible.
- In spite of pruning plan space, this approach is
still exponential in the of tables.
32ExamplePass 1
Sailors B tree on rating Hash on
sid Reserves B tree on bid
- Sailors
- Choice1 B tree matches ratinggt5,
probably cheapest. - If selection is expected to retrieve a lot of
tuples, and index is unclustered, file scan may
be cheaper. - Decision B tree plan kept (because tuples are
in rating order). - Reserves
- B tree on bid matches bid100 cheapest.
33ExamplePass 2
Sailors B tree on rating Hash on
sid Reserves B tree on bid
- Pass1
- Sailors
- Choice1 B tree matches ratinggt5,
- Reserves
- B tree on bid matches bid100.
- Pass 2
- each plan retained from Pass 1 as the outer.
- how to join it with the (only) other relation.
- e.g., Reserves as outer Hash index can be
used to get Sailors tuples - that satisfy sid outer tuples sid value.
- e.g., Sailors as outer Could possibly use
sort-merge join, etc.
34Example
Sailors B tree on rating Hash on
sid Reserves B tree on bid
- Pass1
- Sailors
- Choice1 B tree matches ratinggt5,
probably cheapest. - if selection is expected to retrieve a lot of
tuples, and index is unclustered, file scan may
be cheaper. - Decision B tree plan kept (because tuples are
in rating order). - Reserves B tree on bid matches bid100
cheapest.
- Pass 2
- each plan retained from Pass 1 as the outer.
- how to join it with the (only) other relation.
e.g., Reserves as outer Hash index can be
used to get Sailors tuples - that satisfy sid outer tuples sid value.
35Nested Queries
SELECT S.sname FROM Sailors S WHERE EXISTS
(SELECT FROM Reserves R WHERE
R.bid103 AND R.sidS.sid)
- Nested block is optimized independently, with the
outer tuple considered as providing a selection
condition. - Outer block is optimized with the cost of
calling nested block computation taken into
account. - Implicit ordering of these blocks means that some
good strategies are not considered. The
non-nested version of the query is typically
optimized better.
Nested block to optimize SELECT FROM
Reserves R WHERE R.bid103 AND S.sid
outer value
Equivalent non-nested query SELECT S.sname FROM
Sailors S, Reserves R WHERE S.sidR.sid AND
R.bid103
36Highlights of System R Optimizer
- Impact
- Most widely used currently works well for lt 10
joins. - Cost estimation
- Statistics, maintained in system catalogs, used
to estimate cost of operations and result sizes. - Considers combination of CPU and I/O costs.
- Plan Space
- Only the space of left-deep plans is considered.
- Left-deep plans allow output of each operator to
be pipelined into the next operator without
storing it in a temporary relation. - Focus on optimizing SQLs without nesting. No
duplication in projections. (unless DISTINCT
used) - Cartesian products avoided.
37Highlights of System R Optimizer
- Impact of R Optimizer
- Most widely used currently works well for lt 10
joins. - Cost estimation Approximate art at best.
- Statistics, maintained in system catalogs, used
to estimate cost of operations and result sizes. - Considers combination of CPU and I/O costs.
- Plan Space Too large, must be pruned.
- Only the space of left-deep plans is considered.
- Left-deep plans allow output of each operator to
be pipelined into next operator without storing
it in temporary relation. - Cartesian products avoided.
38Other Approaches to Query Optimization
- Exhaustive search is not suitable for large
number of Joins. - Rule-based optimizers a set of rules to guide
the generation of candidate plans. - Randomized plan generation probabilistic
algorithms to explore a large space of plans. - Estimating the size of intermediate relations
accurately. - Parametric query optimization find good plans
for a given query for each of several different
conditions that might be encountered at run-time. - Multiple-query optimization take concurrent
execution of several queries into account.
39Summary
- There are several alternative evaluation
algorithms for each relational operator. - A query is evaluated by converting it to a tree
of operators and evaluating the operators in the
tree. - Must understand query optimization in order to
fully understand the performance impact of a
given database design (relations, indexes) on a
workload (set of queries). - Two parts to optimizing a query
- Consider a set of alternative plans.
- Must prune large search space.
- Must estimate cost of each considered plan
- Must estimate size of result and cost for each
plan node. - Key issues Statistics, indexes, operator
implementations.
40Summary
- Two parts to optimizing a query
- Consider a set of alternative plans.
- Must prune search space
- Typically, left-deep plans only.
- Must estimate cost of each plan that is
considered. - Estimate size of result
- Estimate cost for each plan node.
- Key issues Statistics, indexes, operator
implementations.
41Summary (Contd.)
- Single-relation queries
- All access paths considered, cheapest is chosen.
- Issues Selections that match index, whether
index key has all needed fields and/or provides
tuples in a desired order. - Multiple-relation queries
- All single-relation plans are first enumerated.
- Selections/projections considered as early as
possible. - Next, for each 1-relation plan, all ways of
joining another relation (as inner) are
considered. - Next, for each 2-relation plan that is
retained, all ways of joining another relation
(as inner) are considered, etc. - At each level, for each subset of relations, only
best plan for each interesting order of tuples is
retained.