Title: TI 84 Calculator: Part II
1TI 84 Calculator Part II
- Macon State College
- Mary Dwyer Wolfe, Ph.D.
- Gaston Brouwer, Ph.D.
- July 2009
- http//calculator.maconstate.edu
2 TI 84 Calculator
- Solving equations using the Intersection of
Graphs Method - Scatterplots and Line Graphs
- Linear Regression
- Applications
- Quadratic Equations and the Vertex
- Maximum/Minimum Applications
3Solving by the Intersections of Graphs Method
The Intersections of Graphs method of solving
equations is an alternate method of solving
equations (not a replacement method). This
method sometimes leads to approximate solutions
whereas traditional symbolic methods can usually
produce exact solutions. The Intersections of
Graphs method is particularly useful when
symbolic solutions are not possible.
4Solving by the Intersections of Graphs Method
- Step 1 Enter the left side of the equation for
Y1 and the right side of the equation for Y2
(Under Y) - Step 2 Graph the equations in a window where the
Intersection is visible. - Step 3 Compute the Intersection (2nd CALC 5)
- Step 4 The x coordinate of the intersection
point is the solution to the equation
Solve 2 (3x 5) 8x 17
5Solving by the Intersections of Graphs Method
Solve 2 (3x 5) 8x 17
Step 1
Step 2
Step 3
Step 3 continued
Step 4 The solution is approximately x
-1.818182 or x -1.82 to the nearest hundredth
6Solving by the Intersections of Graphs Method
- Try this one Solve 2x2 5x 12
x -1.5 or x 4
7Solving by the Intersections of Graphs Method
Solve ex2 52x for x
8Solving a Linear Inequality Graphically Example
1
? 2, 15, 1 by ? 2, 15, 1
S T E P 1
S T E P 2
First we find the intersection of the left and
right side just as we do with equations. Note
that the graphs intersect at the point (8.20,
7.59). Since this is an inequality, we must now
determine if the correct sign is gt or it flips to
lt.
S T E P 3
9Solving a Linear Inequality Graphically Example
1 -- continued
Y1
Y2
S T E P 4
Note that the graphs intersect at the point
(8.20, 7.59). So we center an x-value of 8. When
x lt 8.20, Y1 lt Y2, but when x gt 8.20, Y1 gt
Y2. Since our original equation was Y1 gt Y2 , we
know x gt 8.20. Thus in interval notation the
solution set is (8.20, 8).
10Solving a Linear Inequality Graphically Example
2
?10, 10, 1 by ?10, 10, 1
S T E P 1
S T E P 2
Note that the graphs intersect at the point
(?1.36, 2.72). Since this is an inequality, we
must now determine if the correct sign is gt or it
flips to lt.
S T E P 3
11Solving a Linear Inequality Graphically Example
2
Y1
Y2
S T E P 4
Note that the graphs intersect at the point
(?1.36, 2.72). We find that x ?1.36 when Y1
gt Y2. Thus in interval notation the solution set
is (? 8, ?1.36.
12Solving Compound Inequalities
- Example Suppose the Fahrenheit temperature x
miles - above the ground level is given by T(x) 88
32 x. - Determine the altitudes where the air temp is
from 300 to 400. - We must solve the inequality
- 30 lt 88 32 x lt 40
- Graph all three parts in the same window
13Solving Compound Inequalities
- We must solve the inequality -- continued
- 30 lt 88 32 x lt 40
- Find the 2 intersection points
Note Use the down arrow to switch to the 2nd two
equations.
Symbolically, Between 1.5 and 1.8125 miles above
ground level, the air temperature is between 30
and 40 degrees Fahrenheit.
14Scatterplots and Line Graphs
x 1 2 3 4 5 6 7
y -1 1 3 5 7 9 11
15Scatterplots and Line Graphs
x 1 2 3 4 5 6 7
y -1 1 3 5 7 9 11
Scatterplot
Line Graph
16Least Squares Regression (Line of Best Fit)
- Note that this data appears to be linear
x 1 2 3 4 5 6 7
y -1 1 3 5 7 9 11
17Least Squares Regression (Line of Best Fit)
x 1 2 3 4 5 6 7
y -1 1 3 5 7 9 11
f(x) 2x - 3
18Least Squares Regression (Line of Best Fit)
x 1 2 3 4 5 6 7
y -1 1 3 5 7 9 11
Using this regression equation, f(x) 2x - 3,
what y (or f(x)) is paired with x 10?
That is, find f(10).
f(10) 17
19Least Squares Regression (Line of Best Fit)
x 1 2 3 4 5 6 7
y -1 1 3 5 7 9 11
Using this regression equation, f(x) 2x - 3,
what x is paired with y f(x) 10?
That is, solve 10 2x - 3.
x 6.5 is paired with y 10
20More Linear Regression
- Find the equation of the line that passes
through the points (2, -3) and (-5, -4).
We could use point-slope form and find the
equation symbolically or
We could use linear regression.
21Nearly Linear Data An Application
From NCTM.org
Predict the maximum height for a bike that weighs
21.5 pounds if all other factors are held
constant.
22Nearly Linear Data An Application
Predict the maximum height for a bike that weighs
21.5 pounds if all other factors are held
constant.
A height of 9.994 inches is expected for a weight
of 21.5 pounds.
23Nearly Linear Data An Application
Your turn! You already have the model in your
calculator!
Predict the maximum weight for a bike that so
that it can reach a height of 10.5 inches if all
other factors are held constant.
24Nearly Linear Data An Application
Predict the maximum weight for a bike that so
that it can reach a height of 10.5 inches if all
other factors are held constant.
A weight of about 18.3 pounds is expected for a
height of 10.5 inches.
25Finding a Vertex (Max/Min Point)
- Find the vertex of y 2x2 7x - 1
The vertex is approximately (1.75, -7.125)
26Find the Vertex
Your Turn!
Find the vertex of y -3x2 5x - 4
The vertex is approximately (0.833, -1.912)
27Application Find a Maximum
A home owner has 200 feet of fencing to make a
rectangular garden in his yard that is protected
from the rabbits and deer. He decides to use the
long side of the house as one side of the fenced
area so a larger area can be obtained as less
fencing is needed. That way he can walk out the
back door into the garden. What of the
dimensions of garden that maximize the area for
planting?
200 2x
x
x
The house!
A(x) x(200 2x)
28Application Find a Maximum
A(x) x(200 2x)
X 50 200 2x 200 2(50) 100 The
dimensions are 50 by 100 feet.