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Bioinformatics Algorithms and Data Structures

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Title: Bioinformatics Algorithms and Data Structures


1
Bioinformatics Algorithms and Data Structures
  • Chapter 11 Core String Edits
  • Lecturer Dr. Rose
  • Slides by Dr. Rose
  • January 30 February 4, 2003

2
Core String Edits
  • This chapter introduces inexact matching
  • Inexact matching is used to compute similarity.
  • Sequences similarity is a key concept.
  • Sequence similarity implies
  • Structural similarity
  • Functional similarity
  • We will consider a dynamic programming approach
    to inexact matching.

3
Edit Distance
  • One measure of similarity between two strings is
    their edit distance.
  • This is a measure of the number of operations
    required to transform the first string into the
    other.
  • Single character operations
  • Deletion of a character in the first string
  • Insertion of a character in the first string
  • Substitution of a character from the second
    character into the second string
  • Match a character in the first string with a
    character of the second.

4
Edit Distance
  • Example from textbook transform vintner to
    writers
  • vintner replace v with w ? wintner
  • wintner insert r after w ? wrintner
  • wrintner match i ? wrintner
  • wrintner delete n ? writner
  • writner match t ? writner
  • writner delete n ? writer
  • writer match e ? writer
  • writer match r ? writer
  • writer insert s ? writers

5
Edit Distance
  • Let S I, D, R, M be the edit alphabet
  • Defn. An edit transcript of two strings is a
    string over S describing a transformation of one
    string into another.
  • Defn. The edit distance between two strings is
    defined as the minimum number of edit operations
    needed to transform the first into the second.
    Matches are not included in the count.
  • Edit distance is also called Levenshtein distance.

6
Edit Distance
  • Defn. An optimal transcript is an edit transcript
    with the minimal number of edit operations for
    transforming one string into another.
  • Note optimal transcripts may not be unique.
  • Defn. The edit distance problem entails computing
    the edit distance between two strings along with
    an optimal transcript.

7
String Alignment
  • Defn. A global alignment of strings S1 and S2 is
    obtained by
  • Inserting dashes/spaces into or at the ends of S1
    and S2.
  • Aligning the two strings s.t. each
    character/space in either string is opposite a
    unique character/space in the other string.
  • Example 1 S1 qacdbd S2 qawxb
  • q a c - d b d
  • q a w x - b -

8
String Alignment
  • Example 2 S1 vintner S2 writers
  • v - i n t n e r -
  • w r i - t - e r s
  • Mathematically, string alignment and edit
    transcripts are equivalent.
  • From a modeling perspective they are not
    equivalent.
  • Edit transcripts express the idea of mutational
    changes.

9
Dynamic Programming
  • Observation 1 There are many possible ways to
    transform one string into another.
  • Observation 2 This is like the knapsack problem
  • Recall dynamic programming is used to solve
    knapsack-like problems.
  • Defn. Let D(i,j) denote the edit distance of
    S11..i and S21..j.
  • That is, D(i,j) is the minimum number of edit ops
    needed to transform the first i characters of S1
    into the first j characters of S2.

10
Dynamic Programming
  • Notice that we can solve D(i,j) for all
    combination of lengths of prefixes of S1 and S2.
  • Examples D(0,0),.., D(0,j), D(1,0),..,D(1,j),
    D(i,j)
  • Dynamic programming is a divide and conquer
    method.
  • The three parts to dynamic programming are
  • The recurrence relation
  • Tabular computation
  • Traceback

11
Dynamic Programming
  • The recurrence relation expresses the recursive
    relation between a problem and smaller instances
    of the problem.
  • For any recursive relation, the base condition(s)
    must be specified.
  • Base conditions for D(i,j) are
  • D(i,0) i
  • Q Why is this true? What does it mean in terms
    of edit ops?
  • D(0,j) j
  • Q Why is this true? What does it mean in terms
    of edit ops?

12
Dynamic Programming
  • The general recurrence is given by
  • D(i,j) minD(i - 1, j) 1, D(i, j - 1) 1,
    D(i - 1, j - 1) t (i,j)
  • Here t (i,j) 1 if S1(i) ? S2(j), o/w t (i,j)
    0.
  • Proof of correctness on Pages 218-219
  • Basic argument D(i,j) must be one of
  • D(i - 1, j) 1
  • D(i, j - 1) 1
  • D(i - 1, j - 1) t (i,j)
  • There are NO other ways of creating S21..j from
    S11..i.

13
Dynamic Programming
  • Q How do we use the recurrence relation to
    efficiently compute D(i,j) ?
  • Wrong Answer simply use recursion.
  • Q Why is this the wrong answer?
  • A recursion results in inefficient duplication
    of computations for subproblems.
  • Q How much duplication?
  • A Exponential duplication!
  • Example Fibonacci numbers

14
Dynamic Programming
  • Example Fibonacci numbers
  • f(n) f(n - 1) f(n - 2)
  • Base conditions f(0) 0, f(1) 1

15
Dynamic Programming
  • Note In calculating D(n,m), there are only (n
    1) ? (m 1) unique combinations of i and j.
  • Clearly an exponential number of computations is
    NOT required.
  • Soln instead of going top-down with recursion,
    go bottom-up. Compute each combination only once.
  • Decide on a data structure to hold intermediate
    results.
  • Start from base conditions. These are the
    smallest D(i,j) values and are already defined.
  • Compute D(i,j) for larger values of i and j.

16
Dynamic Programming
  • Example Fibonacci numbers
  • Decide on a data structure simple array
  • Start from base conditions f(0) 0, f(1) 1
  • Compute f(i) for larger values of i. From bottom
    up.
  • Each f(i) is computed only once!

17
Dynamic Programming
  • Q What kind of data structure should we use for
    edit distance?
  • Has to be a random access data structure.
  • Has to support the dimensionality of the problem.
  • D(i,j) is two-dimensional S1 and S2.
  • We will use a two-dimensional array, i.e., a
    table.

18
Dynamic Programming
Example edit distance from vintner to
writers. Fill in the base condition values.
19
Dynamic Programming
  • Q How do we fill in the other values?
  • A use the recurrence
  • D(i,j) minD(i - 1, j) 1, D(i, j - 1) 1,
    D(i - 1, j - 1) t (i,j)
  • where t (i,j) 1 if S1(i) ? S2(j), o/w t (i,j)
    0.
  • We can first compute D(1,1) because we have
    D(0,0), D(0,1), and D(1,0)
  • D(1,1) min 11, 11, 01 1
  • Then we have all the values needed to compute in
    turn D(1,2), D(1,3),..,D(1,m)

20
Dynamic Programming
First compute D(1,1) because we have D(0,0),
D(0,1), and D(1,0) Then compute in turn D(1,2),
D(1,3),..,D(1,m)
21
Dynamic Programming
Fill in subsequent values, row by row, from left
to right.
22
Dynamic Programming
Alternatively, first compute D(1,1) from D(0,0),
D(0,1), and D(1,0) Then compute in turn D(2,1),
D(3,1),..,D(n,1)
23
Dynamic Programming
Fill in subsequent values, column by column, from
top to bottom.
24
Dynamic Programming
  • Filling each cell entails a constant number of
    operations.
  • Cell (i,j) depends only on characters S1(i) and
    S2(j) and cells (i - 1, j - 1), (i, j - 1), and
    (i - 1, j).
  • There are O(nm) cells in the table
  • Consequently, we can compute the edit distance
    D(n, m) in O(nm) time by computing the table in
    O(nm).

25
Dynamic Programming
  • Having computed the table we know the value of
    the optimal edit transcript.
  • Q How do we extract the optimal edit transcript
    from the table?
  • A One way would be to establish pointers from
    each cell, to predecessor cell(s) from which its
    value was derived, i.e,
  • If D(i,j) D(i - 1, j) 1 add a pointer from
    (i,j) to (i - 1, j)
  • If D(i,j) D(i, j - 1) 1 add a pointer from
    (i,j) to (i, j - 1)
  • If D(i,j) D(i - 1, j - 1) t(i,j) add a
    pointer from (i,j) to (i - 1, j - 1)

26
Dynamic Programming
27
Dynamic Programming
  • We can recover an optimal edit sequence simply by
    following any path from (n,m) to (0,0)
  • The interpretation of the path links are
  • A horizontal link , (i,j) ?(i,j-1), corresponds
    to an insertion of character S2(j) into S1.
  • A vertical link, (i,j) ?(i-1,j), corresponds to a
    deletion of S1(i) from S1.
  • A diagonal link, (i,j) ?(i-1,j-1), corresponds to
    a match S1(i) S2(j) and a substitution if
    S1(i) ? S2(j)

28
Dynamic Programming
29
Dynamic Programming
An optimal edit path. What edit transcript
does this path correspond to?
S,S,S,M,D,M,M,I
30
Dynamic Programming
Another optimal edit path. What edit transcript
does this path correspond to?
I,S,M,D,M,D,M,M,I
31
Dynamic Programming
The third possible optimal edit path. What edit
transcript does this path correspond to?
S,I,M,D,M,D,M,M,I
32
Dynamic Programming
  • Alternatively we can interpret any path from
    (n,m) to (0,0) as an alignment of S1 and S2.
  • The interpretation of the path links are
  • A horizontal link , (i,j) ?(i,j-1), corresponds
    to an insertion of a space/dash into S1.
  • A vertical link, (i,j) ?(i-1,j), corresponds to
    an insertion of a space/dash into S2.
  • A diagonal link, (i,j) ?(i-1,j-1), corresponds to
    a match if S1(i) S2(j) or a mismatch if S1(i)
    ? S2(j)

33
Dynamic Programming
Possible optimal path. What alignment does
this optimal path correspond to?
w r i t - e r s v i n t n e r -
34
Dynamic Programming
A second possible optimal path. What alignment
does this optimal path correspond to?
w r i - t - e r s v - i n t n e r -
35
Dynamic Programming
A third possible optimal path. What alignment
does this optimal path correspond to?
w r i - t - e r s - v i n t n e r -
36
Summary
  • Any path from (n,m) to (0,0) corresponds to an
    optimal edit sequence and an optimal alignment
  • We can recover all optimal edit sequences and
    alignments simply by extracting all paths from
    (n,m) to (0,0)
  • The correspondence between paths and edit
    sequences is one-to-one.
  • The correspondence between paths and alignments
    is one-to-one.
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