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3IMP IP Subnetting

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3IMP IP Sub-netting. 3IMP. Session 4. Binary AND. X. 0. 0. 1. 1. Y. 0. 1. 0. 1. X & Y. 0. 0. 0. 1. If two conditions are combined by a binary AND, they must both ... – PowerPoint PPT presentation

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Title: 3IMP IP Subnetting


1
3IMP IP Sub-netting
  • 3IMP
  • Session 4

2
Binary AND
If two conditions are combined by a binary AND,
they must both be true for the compound condition
to be true as well.
3
Determining the network portion of an address
  • The router separates the network and host parts
    of an IP address by ANDing the address with its
    Subnet Mask.
  • e.g. the destination address 195 . 120 . 24 . 18
    is expressed in binary as
  • 11000011 . 01111000 . 00011000 . 00010010
  • 11111111 . 11111111 . 11111111 . 11110000
  • 11000011 . 01111000 . 00011000 . 00010000

4
Determining the network portion of an address
  • IP- 11000011 .01111000 .00011000 . 00010010
  • SNM- 11111111 .11111111 .11111111 . 11110000
  • Net ID-11000011 . 01111000.00011000 . 00010000
  • IP-192.120.24.18
  • SNM-255.255.255.240
  • Net ID-195 . 120 . 24 . 16

5
Determining the network portion of an address
  • Determine the network ID for the following
  • IP address 192.100.10.33
  • Subnet Mask 255.255.255.0
  • HOW??
  • Convert the IP address subnet Masks to binary.
  • Perform a Binary AND on them.
  • Convert the result to Decimal
  • THE RESULT?
  • 192.100.10.0

6
What About Custom Subnet Masks?
  • Determine the network ID for the following
  • IP address 192.100.10.33
  • Subnet Mask 255.255.255.240
  • The Result 192.100.10.32

7
Number of Hosts
  • This concept also works for calculating the
    number of hosts on your network but we use all of
    the bit in the address, not just the bits we want
    to pinch for the network subnets
  • For example, our problem with the 5000 computers
    what setup would we use to get all 5000 PCs on
    one subnet???
  • 2n 2

8
Number of Hosts
  • 213 2 8190
  • Still just over 3000 spare addresses but better
    than wasting 60,036 addresses!!!)
  • Therefore, 13 bits would be used for the host
    portion of the address and 19 would be used for
    the network portion this would give us a CIDR
    (Classless Inter-Domain Routing) notation of /19
  • SNM 11111111.111111111.11100000.00000000
  • Again, get your lecturer to run through another
    example or three

9
Reserved Addresses
  • The following address ranges are PRIVATE
    addresses.
  • 10.0.0.0 to 10.255.255.255
  • 172.16.0.0 to 172.31.255.255
  • 192.168.0.0 to 192.168.255.255
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