Title: The decision to replace an asset
1The decision to replace an asset
2 3Exemplification
- Larry Likkonen, the manager of Kenora Heavy Works
Inc. is considering replacing the current
excavator of the company with a new model. - The existing excavator was originally purchased
for 326,000 three years ago, but its market
value has dropped to only 100,000 today. In ten
years it will be worth only 20,000. - The new excavator costs 200,000, and would
increase operating revenues by 20,000 annually.
The new equipment has a 10-year life span and
expected salvage value of 40,000. - The tax rate of the company is 42, the required
rate of return is 12, and the CCA rate for both
excavators is 30. For simplicity, assume that
the current UCC of the old excavator is 100,000.
Should Larry replace the old excavator?
4Approach
- Calculate the NPV of the incremental cash flow.
5The incremental cash flow of replacing a fixed
asset
- Replacing an asset will always impact the PV of
- - Initial outlay
- - Depreciation tax shields
- - Net capital spending (PV of the salvaged asset)
6The incremental cash flow of replacing a fixed
asset
- Replacing an asset may or may not impact the PV
of - - ATNOR
- - Changes in NWC
7Incremental initial cost
- Cost of new - Current market value of old
- 200,000 - 100,00 100,000
- Note that the original purchase price of the old
excavator is irrelevant
8Incremental ATNOR
- Change in ATNOR (Change in NOR)(1- T)
- 20,000(1- 0.42) 11,600 each year,
- PV change in ATNOR 11,600PVA(12,10) 65,543
9Incremental depreciation tax savings (CCATS)
- PV changes in depreciation tax shields
- T(d)(Cnew-Cold)(1r/2)/(rd)(1r) -
T(d)(Snew-Sold)/(dr)(1r)t - PV changes in depreciation tax shields 26,461
10Incremental Net Capital Spending
- Change in NCS (40,000-20,000)/(1.12)10 6,439
11Putting it together
- Change in NPV Change in PV of
- (ATNOR Tax shields NCS - Chg in NWC - Initial
outlay) - Change in NPV
- 65,543 26,461 6,439 0 - 100,000
-1,557
12Recommendation
- Do not replace the old excavator
13Equipment with unequal lives
- How should we evaluate the choice of purchasing
relatively similar essential equipment, but with
different economic lives?
14Exemplification 1
- Machine A costs 100 m to buy and 10 m/year to
operate. Its expected economic life is two years,
and has to be replaced after it wears out. - Machine B costs 140 m to buy and 8 m/year to
operate. Its expected economic life is three
years, and has to replaced after it wears out. - Both machines are similar in their technological
performance. Buying either one is essential to
our project. - No taxes or depreciation and r 10
15Problem
- We ought to choose the one that costs less.
- Since they have unequal lives, comparing the PV
of acquisition and operating costs is not
relevant. - PV cost(A) 100 10/(1.1) 10/(1.1)2
117.36 m - PV cost(B) 140 8/(1.1) 8/(1.1)2
8/(1.1)3 159.89 m
16Solution
- Find a common denominator
- Calculate an equivalent annual cost EAC
- Choose the project with the lowest EAC
17EAC calculation
- PV (costs) PV(EAC)
- PV costs EAC/(1r) EAC/(1r)2 EAC/(1r)t
- EAC(A) PVcosts(A)/PVA(10, 2) 117.36/1.7355
67.62 - EAC(B) PVcosts(B)/PVA(10, 3) 159.89/2.4869
64.29 - Choose B
18Exemplification 2 EAC with taxes
- Equipment X costs 1.1 m to install and
60,000/year to operate. - Expected life 5 yrs.
- Equipment Y costs 1.9 m to install and
10,000/year to operate. - Expected life 8 yrs.
- Both assets are considered lease-hold
improvements (straight line depreciation), and
will have zero salvage value at the end of their
life. - Tax rate 40
- Discount rate 12
19PV of costs
20PV of costs
21PV of costs
22PV of costs
23PV of costs
24PV of costs
- PV costs(X) -1.1 m 52,000PVA(12, 5)
-912,550 - PV costs(Y) -1.9 m 89,000PVA(12, 8)
-1,457,884
25EAC calculation
- PV (costs) PV(EAC)
- EAC(X) -912,550/PVA(12, 5) -253,149
- EAC(Y) -1,457,884/PVA(12, 8) -293,479
- Choose X
26Summary
- EAC is standardizing the cost associated with
replacement choices. - EAC enables a meaningful comparison.
- EAC calculation requires that the assets under
question be very similar and essential to the
operation of the project.