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Absorption Costing

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Absorption costing is an approach in which a share of ALL costs is ... This process is continued (yawn, yawn) until only a small amount is left in a cost centre ... – PowerPoint PPT presentation

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Title: Absorption Costing


1
Absorption Costing
  • 1 Definition
  • 2 Cost behaviour
  • 3 Cost build up
  • 4 External vs Internal Reporting
  • 5 Treatment of overheads
  • 6 Changes in activity levels
  • 7 Inventory valuation
  • 8 Benefits

2
1 - Definition
  • Absorption costing is an approach in which a
    share of ALL costs is included in the calculation
    of the cost of each unit of output.
  • It is sometimes known as total absorption
    costing or full costing

3
2 - Cost behaviour
  • Absorption costing does not differentiate
    between fixed and variable costs
  • This is logical, as the approach absorbs all
    costs into the cost of output
  • Thus, Inventory includes (as per IAS 2) a share
    of fixed costs as well as variable costs
  • In marginal costing, fixed costs are treated as
    period costs and are written off

4
3 - Cost build up
  • Materials estimated
  • Labour estimated
  • Overheads using OAR
  • OAR allocated costs
  • apportioned costs

5
4 - External Reporting
  • IAS 2 cost or NRV
  • cost normal course of business
  • present location and condition
  • at normal level of activity
  • includes
  • production overheads
  • other overheads
  • Thus, absorption costing is used for external
    reporting, which assists is achieving the
    objective of comparability

6
Internal Reporting
  • Beware of the obvious!
  • Whether absorption or marginal costing is used
    will depend on
  • Managements needs
  • How will the information be used?
  • What decision must be made?

7
5 - Overheads
  • Overhead allocation
  • Overhead absorption
  • Re-apportionment of general cost centres
  • Calculate OAR
  • Basis of OAR
  • Absorb overheads using OAR

8
Allocation
  • costs are charged directly to a cost unit or cost
    centre
  • key questions
  • who has responsibility for the cost?
  • is responsibility specific?
  • Costs may be allocated to general or service cost
    centres

9
Apportionment
  • the process of sharing costs between cost centres
    on the basis of a proxy measure
  • in questions the proxy measure will be clear for
    most costs
  • for those which are less clear, consider
  • if I had responsibility for a cost centre, would
    I accept a cost on that basis?

10
Re-apportionment
  • Service / general cost centres need to be
    re-apportioned to production cost centres using
    an appropriate basis
  • methods of re-apportionment are
  • step (elimination)
  • reciprocal (repeated distribution)
  • simultaneous equation

11
Step (elimination)
  • a department which does not receive a major
    benefit from another cost centre can be
    eliminated if re-apportioned first

12
Reciprocal
  • Where reciprocal services are provided, each
    stage of the re-apportionment process will put
    costs back into a cost centre which had
    previously been re-apportioned
  • This process is continued (yawn, yawn) until
    only a small amount is left in a cost centre
  • This small amount is finally re-apportioned on
    an arbitrary basis

13
Simultaneous equations
  • best considered by an example

14
Calculate OAR
  • Estimate overhead costs for next period
  • Allocate, apportion and re-apportion
  • Decide on basis of absorption / recovery
  • What bases could be used?
  • of a specific or total of direct cost
  • per direct labour hour / machine hour
  • per unit
  • OAR Budgeted cost budgeted activity level

15
Basis for OAR
  • essentially a matter of judgement
  • objective is to be as fair as possible
  • however it is an approximation
  • remember that it is simply dividing the total
    cost over the cost centres
  • therefore the basis will have no effect on total
    cost

16
Under/over absorption
  • Both cost and activity level are estimates
  • thus total absorbed
  • will not be equal to
  • actual cost
  • absorbed gt actual costs overabsorption
  • absorbed lt actual costs underabsorption

17
Reciprocal services
  • When service departments do not supply or
    receive services from one another
    re-apportionment of costs is done using the step
    (elimination) method.
  • When reciprocal services are provided, we need
    to use either
  • repeated distribution or
  • simultaneous equations

18
Example
  • After allocation and apportionment, the costs
    are
  • Mach Ass Stores Maint
  • Costs 000 100.3 85.6 48.5 54.6
  • Maint Hrs 480 340 120
  • Requisitions 120 90

19
Elimination
  • In this case, the logical approach is to
    re-apportion maintenance first, and then stores
  • However, if both service cost centres provide
    services to one another, the problem is less
    straightforward.
  • So, lets consider a more complex example .

20
Example
  • After allocation and apportionment, the costs
    are
  • Mach Ass Stores Maint
  • Costs 000 100.3 85.6 48.5 54.6
  • Maint Hrs 480 340 120
  • Requisitions 120 90 40

21
Elimination
  • a department which does not receive a major
    benefit from another cost centre can be
    eliminated if re-apportioned first
  • in exam, indicate why you have selected a
    particular cost centre for elimination

22
Elimination
  • Mach Ass Stores
    Maint Total
  • Maint Hrs 480 340 120 940
  • Requisitions 120 90 40
    250
  • Costs 100,300 85,600 48,500 54,600
    289,000
  • Maint first 27,881 19,749 6,970 (54,600)
  • Then stores 120/210 90/210
  • 31,697 23,773 (55,470) NB
  • 159,878 129,122 nil
    nil 289,000

23
Repeated distribution
  • Mach Ass Stores Maint Total
  • Maint Hrs 480 340 120 940
  • Requisitions 120 90 40
    250
  • Costs 100,300 85,600 48,500 54,600
    289,000
  • Maint 940ths 27881 19749 6,970 (54,600)
  • Stores 250ths 26,626 19,969 (55,470) 8,875
  • Maint 940ths 4,532 3,210 1,133
    (8,875)
  • Stores 250ths 544 408 (1,133)
    181
  • Maint 820ths 106 75 (181)
  • Total 159,989 129,011 nil
    nil 289,000

24
Simultaneous equations
  • If we let S total stores cost and
  • If we let M total maintenance cost
  • We have two equations
  • S 120/940 M 48,500
  • M 40/250 S 54,600
  • With simultaneous equations, the key is to
    multiply one or both so that one of the unknown
    variables has the same value in both equations.

25
Simultaneous equations
  • If we multiply the Maintenance equation
  • By 250/40 we have
  • 250/40 M S 341,250
  • This can be re-arranged to express S
  • S 250/40 M 341,250

26
Simultaneous equations
  • Our two equations are now
  • S 120/940 M 48,500 or
  • 0.1276 M 48,500 and
  • S 250/40 M - 341,250 or
  • 6.25 M - 341,250
  • If we subtract the top from the bottom, we have
    ..

27
Simultaneous equations
  • S 6.25 M - 341,250 less
  • S 0.1276 M 48,500
  • 0 6.1224 M - 389,750 or
  • 6.1224 M 389,750 thus
  • M 389,750/6.1244 63,660
  • By substituting this into any of our equations,
    we find that S what?
  • Answer 56,627

28
Simultaneous equations
  • These values can now be substituted
  • Mach Ass Stores Maint
    Total
  • Costs 100,300 85,600 48,500 54,600
    289,000
  • Result (56,627)(63,660)
  • and are re-apportioned using the original data
  • Maint Hrs 480 340 120 940
  • Requisitions 120 90 40
    250
  • Maint 32,507 23,026 8,127
  • Stores 27,181 20,386 9,060
  • Total 159,988 129,012 289,000
  • NB same as repeated distribution method

29
Absorption Costing Example
  • Ray Vaughan has the following budgeted
    information for the next period
  • Machining Assembly Canteen Maintenance
    Total

  • Indirect wages 18,500 19,000
    17,400 20,100 75,000
  • Indirect materials 6,200 5,100
    2,300 2,200 15,800
  • Rent 17,480
  • Insurance of buildings 6,308
  • Power 9,700
  • Heating oil 5,168
  • Electricity 3,002
  • Depreciation Machinery 35,500
  • Machine value 170,000 114,500
    70,500 355,000
  • Floor area m2 1,630 1,100
    350 720 3,800
  • Direct labour hours 11,400 27,400
    38,800

30
6 - Changes in activity levels
  • Impact of fixed costs can distort results
  • e.g. company producing a single product
  • Selling price 5.00 per unit
  • Variable cost 1.75 per unit
  • Fixed costs 40,000
  • Budgeted volume 20,000 units
  • Budgeted profit 25,000

31
Profit calculation
  • Sales 20,000 x 5 100,000
  • Costs
  • Variable 20,000 x 1.75 35,000
  • Fixed 40,000
  • Total cost 75,000
  • Profit 25,000
  • i.e. 1.25 per unit or

32
Profit calculation
  • Per unit
  • Selling price 5.00
  • Variable cost 1.75
  • Fixed costs 2.00
  • Profit 1.25
  • X 20,000 units 25,000

33
BUT!!
  • if the level of activity changes to say
  • 15,000 or 25,000
  • the profit is NOT 1.25 x level of activity
  • because fixed costs do not change
  • So, what is the profit at 15,000 units?
  • 8,750
  • Here we have used marginal costing

34
7 Inventory valuation
  • because fixed costs are included in the
    valuation of Inventory
  • they are carried forward and written off in a
    future period
  • once again this highlights the difference in the
    purposes of external and internal reporting

35
8 - Benefits
  • Requires fixed costs to be considered
  • While fixed costs can be less relevant for
    certain decisions, they are important and must be
    considered in the long run
  • Applies the accruals concept by matching fixed
    costs against revenue earned
  • Avoids seasonal swings in profitability
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