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Exam Examples

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How many J-K flip flops to make a MOD-33 counter? will count 0-32 reset on 33. takes six. ... Tie MSB of LSD (least significant digit) to Cp0 of middle decade counter. ... – PowerPoint PPT presentation

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Title: Exam Examples


1
Exam Examples
  • Kleitz Chapters 10 and 12

2
Example 10-3
G S R Q
3
7475 D Flip Flop Timing Example
G D D Q
4
7475 D Flip Flop Timing Example
G D D Q
Gate is high and D high so reset initially. Then
D sets high. No change when clock is low.
5
7475 D Flip Flop Timing Example
G D D Q
Reset, then set during clock pulse. No change
when clock is low.
6
7474 D Flip Flop Timing Example (Asynchronous
Inputs Held High)
G D D Q
hold
set
reset
reset
7
7475 D Flip Flop Timing Example Problem 10-10
G D Q
Q follows D when enable is on. Otherwise Q
remains where it was.
8
7474 D Flip Flop Timing Example Problem 10-16
Q D at positive gate edge.
G SD RD D Q
AS
AR
AR
SR
SS
SS
9
Example 10-15 7474
  • from overhead

10
Homework 10-26
  • 7476 is J-K Pulse triggered master-slave
    flip-flop
  • Master output reflects all changes during clock
    pulse.
  • State of master J-K at end of pulse will transfer
    to slave Q when pulse goes low.

11
Homework 10-26 Sketch Q for 7476
G S R J K Q
12
Homework 10-26
  • 74LS76 is J-K negative edge triggered flip-flop
  • State of J-K at falling edge of pulse will
    transfer to Q.

13
Homework 10-26 Sketch Q for 74LS76
G S R J K Q
Toggle Hold Hold Toggle
14
Homework 10-28 Sketch Q for 74LS76
Cp S R J K Q
ST
AR
ST
ST
ST
Resets then toggles at 1/2 frequency.
15
Homework 10-40
  • See Electronic Workbench solution
  • 10_1bsolve.ewb

16
Homework
  • Due Monday 11-22
  • Late homework will not be accepted.
  • End of Chapter 12, page 462-464
  • 12-6, 12-8, 12-16
  • multiple choice or short answer
  • 12-18, 12-28
  • design problem

17
Example 12-4
  • from overhead

18
Example 12-7 e
  • How many J-K flip flops to make a MOD-33
    counter?
  • will count 0-32 reset on 33.
  • takes six. 25 32
  • 33 100001. Six bits to reset.

19
Example Problem 12-27
  • Assume you have one 7490 and one 7492. Show the
    external connections required to form a divide by
    24.

20
Recall 7490
  • 7490.
  • Divide by 2.
  • Divide by 5.

21
Recall 7492
  • Divide by 2
  • Divide by 6

22
Solution
  • Use 7490 to
  • divide by 2
  • Use 7492 to
  • divide by 2 and divide by 6
  • Result is divide by 2 x 2 x 6 24

23
Connections 7490
  • Connect Vcc and ground pins
  • MR1, MR2, MS1, MS2 to ground
  • defeats asynchronous set/reset
  • Cp1 is not used
  • connect to low to prevent problems
  • Q1, Q2, Q3 not used
  • External clock to Cp0
  • Q0 of 7490 to Cp0 of 7492

24
Connections 7492
  • Connect Vcc and ground pins
  • MR1, MR2 to ground
  • defeats asynchronous reset
  • Cp0 connected to 7490 Q0
  • Cp1 connected to 7492 Q0
  • Q3 is the desired output.

25
Example 12-13
  • Goal use 7490 for a MOD-8 counter.
  • Counts from 0 to 7 and resets on 8.
  • And when turned on, counter is set at 9.
  • First negative clock edge will set count to 0.

26
Example 12-13
  • See 7490 pin-out inside front cover.
  • Must output 9 (1001) which requires 4 bits
  • Need both divide by 2 section and divide by 5
    section.
  • Tie Q0 to Cp1

27
Example 12-13
  • MOD-8
  • reset at 8 (1000) after 7 (0111)
  • thus reset when S31
  • however 9 (1001) is the power up state. Do not
    reset on 9.
  • so reset on S31 AND S00

28
Example 12-13
  • Set to 9 on power up.
  • Need 1s to both Master Sets.
  • Use series R-C circuit.
  • voltage across capacitor to MS1,2
  • capacitor initially discharged
  • voltage across it is zero (logic low)
  • capacitor charges to logic high
  • Problem capacitor rise time is slow.
  • Desire fast and certain transition.

29
Schmitt Trigger
  • Chapter 11 topic skipped
  • For us
  • This is an electronic circuit which takes a
    noisy or slow signal and converts it to a clean
    square wave.
  • Examples

30
Application 12-3 Counter
  • Goal count from 0 to 999 in decimal.
  • First recall 0 to 9 counter.
  • 7490
  • Decade counter MOD-10
  • Gives BCD output
  • Clock input is negative edge triggered.
  • Output will count to 9 (1001) then next count
    will be 0 (0000).
  • MSB transitioned from 1 to 0

31
Application 12-3 Counter
  • MSB high to low gives falling edge for input to
    next 0-9 counter.
  • Second counter increments by 1.
  • Each 7490 provides BCD output for one power of
    ten.

32
Application 12-3 Counter
  • Connections
  • Master Resets to ground to defeat.
  • Master Sets to ground to defeat.
  • Tie each ICs Q0 to Cp1 so divide by 2 section
    is tied to divide by 5 section.
  • Tie MSB of LSD (least significant digit) to Cp0
    of middle decade counter.
  • Tie MSB of middle to Cp0 of MSD.
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