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Figure 12'27: Layers of ions surrounding charged colloidal particles'

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Comparing Experiment 1 and Experiment 3, you see that when the I- concentration ... What is the half-life of SO2Cl2 vapor at this temperature? ... – PowerPoint PPT presentation

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Title: Figure 12'27: Layers of ions surrounding charged colloidal particles'


1
Average84.2 Standard Deviation13.4
2
Average161.6 Standard Deviation24.9
3
Reaction Rates
  • Chemical kinetics is the study of reaction rates,
    how reaction rates change under varying
    conditions, and what molecular events occur
    during the overall reaction.
  • What variables affect reaction rate?

Surface area of a solid reactant or catalyst.
4
Dependence of Rate on Concentration
  • Reaction Order
  • Consider the reaction of nitric oxide with
    hydrogen according to the following equation.
  • Thus, the reaction is second order in NO, first
    order in H2, and third order overall.

5
Dependence of Rate on Concentration
  • Reaction Order
  • Zero and negative orders are also possible.
  • The concentration of a reactant with a zero-order
    dependence has no effect on the rate of the
    reaction.
  • Although reaction orders frequently have whole
    number values (particularly 1 and 2), they can be
    fractional.

6
Dependence of Rate on Concentration
  • Determining the Rate Law.
  • One method for determining the order of a
    reaction with respect to each reactant is the
    method of initial rates.
  • It involves running the experiment multiple
    times, each time varying the concentration of
    only one reactant and measuring its initial rate.
  • The resulting change in rate indicates the order
    with respect to that reactant.

7
Dependence of Rate on Concentration
  • Determining the Rate Law.
  • If doubling the concentration of a reactant has a
    doubling effect on the rate, then one would
    deduce it was a first-order dependence.
  • If doubling the concentration had a quadrupling
    effect on the rate, one would deduce it was a
    second-order dependence.
  • A doubling of concentration that results in an
    eight-fold increase in the rate would be a
    third-order dependence.

8
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9
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10
A Problem to Consider
  • Iodide ion is oxidized in acidic solution to
    triiodide ion, I3- , by hydrogen peroxide.
  • A series of four experiments was run at different
    concentrations, and the initial rates of I3-
    formation were determined.
  • From the following data, obtain the reaction
    orders with respect to H2O2, I-, and H.
  • Calculate the numerical value of the rate
    constant.

11
A Problem to Consider
  • Comparing Experiment 1 and Experiment 2, you see
    that when the H2O2 concentration doubles (with
    other concentrations constant), the rate doubles.
  • This implies a first-order dependence with
    respect to H2O2.

12
A Problem to Consider
  • Comparing Experiment 1 and Experiment 3, you see
    that when the I- concentration doubles (with
    other concentrations constant), the rate doubles.
  • This implies a first-order dependence with
    respect to I-.

13
A Problem to Consider
  • Comparing Experiment 1 and Experiment 4, you see
    that when the H concentration doubles (with
    other concentrations constant), the rate is
    unchanged.
  • This implies a zero-order dependence with respect
    to H.

14
A Problem to Consider
  • The reaction orders with respect to H2O2, I-, and
    H, are 1, 1, and 0, respectively.

15
A Problem to Consider
  • You can now calculate the rate constant by
    substituting values from any of the experiments.
    Using Experiment 1 you obtain

16
A Problem to Consider
  • You can now calculate the rate constant by
    substituting values from any of the experiments.
    Using Experiment 1 you obtain

17
Change of Concentration with Time
  • A rate law simply tells you how the rate of
    reaction changes as reactant concentrations
    change.
  • A more useful mathematical relationship would
    show how a reactant concentration changes over a
    period of time.

18
Change of Concentration with Time
  • A rate law simply tells you how the rate of
    reaction changes as reactant concentrations
    change.
  • Using calculus we can transform a rate law into a
    mathematical relationship between concentration
    and time.
  • This provides a graphical method for determining
    rate laws.

19
Concentration-Time Equations
  • First-Order Rate Law

20
Concentration-Time Equations
  • First-Order Rate Law
  • Using calculus, you get the following equation.
  • Here At is the concentration of reactant A at
    time t, and Ao is the initial concentration.
  • The ratio At/Ao is the fraction of A
    remaining at time t.

21
A Problem to Consider
  • The decomposition of N2O5 to NO2 and O2 is first
    order with a rate constant of 4.8 x 10-4 s-1. If
    the initial concentration of N2O5 is 1.65 x 10-2
    mol/L, what is the concentration of N2O5 after
    825 seconds?

22
A Problem to Consider
  • The decomposition of N2O5 to NO2 and O2 is first
    order with a rate constant of 4.8 x 10-4 s-1. If
    the initial concentration of N2O5 is 1.65 x 10-2
    mol/L, what is the concentration of N2O5 after
    825 seconds?
  • Substituting the given information we obtain

23
A Problem to Consider
  • The decomposition of N2O5 to NO2 and O2 is first
    order with a rate constant of 4.8 x 10-4 s-1. If
    the initial concentration of N2O5 is 1.65 x 10-2
    mol/L, what is the concentration of N2O5 after
    825 seconds?
  • Substituting the given information we obtain

24
A Problem to Consider
  • The decomposition of N2O5 to NO2 and O2 is first
    order with a rate constant of 4.8 x 10-4s-1. If
    the initial concentration of N2O5 is 1.65 x 10-2
    mol/L, what is the concentration of N2O5 after
    825 seconds?
  • Taking the inverse natural log of both sides we
    obtain

25
A Problem to Consider
  • The decomposition of N2O5 to NO2 and O2 is first
    order with a rate constant of 4.8 x 10-4 s-1. If
    the initial concentration of N2O5 is 1.65 x 10-2
    mol/L, what is the concentration of N2O5 after
    825 seconds?
  • Solving for N2O5 at 825 s we obtain

26
Concentration-Time Equations
  • Second-Order Rate Law

27
Concentration-Time Equations
  • Second-Order Rate Law
  • Using calculus, you get the following equation.
  • Here At is the concentration of reactant A at
    time t, and Ao is the initial concentration.

28
Graphing Kinetic Data
  • In addition to the method of initial rates, rate
    laws can be deduced by graphical methods.
  • If we rewrite the first-order concentration-time
    equation in a slightly different form, it can be
    identified as the equation of a straight line.
  • This means if you plot lnA versus time, you
    will get a straight line for a first-order
    reaction. (see Figure 14.9)

29
Figure 14.9 A plot of log R versus time.
30
Graphing Kinetic Data
  • In addition to the method of initial rates, rate
    laws can be deduced by graphical methods.
  • If we rewrite the second-order concentration-time
    equation in a slightly different form, it can be
    identified as the equation of a straight line.

y mx b
31
Graphing Kinetic Data
  • In addition to the method of initial rates, rate
    laws can be deduced by graphical methods.
  • If we rewrite the first-order concentration-time
    equation in a slightly different form, it can be
    identified as the equation of a straight line.

32
Half-life
  • The half-life of a reaction is the time required
    for the reactant concentration to decrease to
    one-half of its initial value.
  • For a first-order reaction, the half-life is
    independent of the initial concentration of
    reactant.

33
Half-life
  • The half-life of a reaction is the time required
    for the reactant concentration to decrease to
    one-half of its initial value.
  • Solving for t1/2 we obtain
  • Figure 14.8 illustrates the half-life of a
    first-order reaction.

34
Figure 14.8 A graph illustrating that the
half-life of a first-order reaction is
independent of initial concentration.
Half life, t1/2, is the time it takes for the
R to decrease by 1/2.
This is exactly like radioactive decay.
35
Half-life
  • Sulfuryl chloride, SO2Cl2, decomposes in a
    first-order reaction to SO2 and Cl2.
  • At 320 oC, the rate constant is 2.2 x 10-5 s-1.
    What is the half-life of SO2Cl2 vapor at this
    temperature?

36
A model of SO2CI2(g)
37
Half-life
  • Sulfuryl chloride, SO2Cl2, decomposes in a
    first-order reaction to SO2 and Cl2.
  • At 320 oC, the rate constant is 2.20 x 10-5 s-1.
    What is the half-life of SO2Cl2 vapor at this
    temperature?
  • Substitute the value of k into the relationship
    between k and t1/2.

38
Half-life
  • Sulfuryl chloride, SO2Cl2, decomposes in a
    first-order reaction to SO2 and Cl2.
  • At 320 oC, the rate constant is 2.20 x 10-5 s-1.
    What is the half-life of SO2Cl2 vapor at this
    temperature?
  • Substitute the value of k into the relationship
    between k and t1/2.

39
Half-life
  • For a second-order reaction, half-life depends on
    the initial concentration and becomes larger as
    time goes on.
  • Each succeeding half-life is twice the length of
    its predecessor.
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