Title: Absorbed Dose in Radioactive Media II
1Absorbed Dose in Radioactive Media II
- Beta Disintegration
- Electron-Capture Transitions
- Internal Conversion
2Beta Disintegration
- Nuclei having an excess of neutrons tend to emit
an electron (?--particle), thus leaving the
nucleus with one less neutron and one more
proton, i.e., the atomic number Z is increased by
1 - Conversely, nuclei with an excess of protons
usually emit a positron (?), effectively
decreasing Z by 1 while increasing the neutron
count by 1 - In either case the total number of nucleons
(protons neutrons) remains constant, so that
the daughter product is an isobar of the parent
3Beta Disintegration (cont.)
- The ?-rays emitted in a given mode of
disintegration (averaged over many such
disintegrations) have a spectrum of kinetic
energies extending from zero to a fixed maximum
Emax, with a skewed bell-shaped differential
distribution exemplified by the spectrum of
?--rays from P-32 shown in the following diagram
4?--ray spectrum emitted from P-32.
5Beta Disintegration (cont.)
- The maximum ?- kinetic energy (Emax 1.71 MeV in
this case) represents the net decrease in the
rest mass of the neutral P-32 atom in becoming a
neutral S-32 atom, since the ground state of the
S-32 is reached directly without ?-ray emission - The atomic mass-energy balance equation is
- where the atomic mass decrease 32P 32S
1.71 MeV, which appears as kinetic energy shared
between the ?- and the neutrino
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7Beta Disintegration (cont.)
- The electron on the left of the equation is
required to balance the charge and rest mass of
the ?- on the right - Physically, when the P-32 nucleus emits the ?-, a
positively charged ion (32S) results, which
promptly captures a bystanding electron to become
a neutral S-32 atom
8Beta Disintegration (cont.)
- A neutrino, which is a nearly zero-mass,
zero-charge particle, is emitted along with each
?--particle, thus conserving energy and momentum
in the disintegration process - The difference between the ?--ray kinetic energy
and Emax 1.71 MeV in each disintegration is
carried away by the associated neutrino
9Beta Disintegration (cont.)
- The average kinetic energy of the ?-- or
?-particles in a ?-ray spectrum is found to be
roughly 0.3 0.4 times Emax, depending on the
individual spectral shape, which is determined by
the forbiddenness classification of the ?-ray
transition - Often, for purposes of estimating the absorbed
dose deposited by charged particles, Eavg ? 1/3
Emax is assumed for ?-rays, if more accurate
information is not available
10Beta Disintegration (cont.)
- Since the neutrino is radiologically irrelevant,
the energy spent in the material in which the
?-ray emitter is located is just the product of
the number of ?-rays by their average energy, not
their maximum energy - It is important not to confuse Eavg with Emax
11Beta Disintegration (cont.)
- A simple example of ?-disintegration is that of
O-15 ? N-15, for which the atomic mass-energy
balance equation is - where the atomic-mass decrease from O-15 to
N-15 1.022 MeV 1.73 MeV 2.75 MeV, as
illustrated in the following diagram, and the
1.73 MeV kinetic energy is shared between the ?
and the neutrino
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13Beta Disintegration (cont.)
- During ?-emission a valence electron is
simultaneously released by the O-15 atom - Thus both the ? and the electron are lost by the
parent atom and appear on as free particles on
the right of the equation - The decrease in atomic mass is equal to the sum
of the released kinetic energy (1.73 MeV) and the
rest masses (0.511 MeV each) of the e- and the ? - When the ? stops, it combines in an annihilation
interaction with a nearby electron, emitting
1.022 MeV in the form of two 0.511-MeV oppositely
directed ?-rays
14Absorbed Dose from Beta Disintegration
- For present purposes we will ignore any radiative
losses (bremsstrahlung and in-flight positron
annihilation) by the ?-rays, and simply assume
that their kinetic energy is all spent in
collision interactions resulting in absorbed-dose
deposition - Such radiative loss corrections are relatively
unimportant in low-Z media
15Absorbed Dose from Beta Disintegration (cont.)
- Under CPE conditions the absorbed dose due to n
?-disintegrations per gram of medium is nEavg
(MeV/g) - Additional absorbed-dose contributions due to any
?-rays resulting from a particular radionuclide
must be treated separately as described earlier
16Electron-Capture (EC) Transitions
- Radioactive disintegrations through electron
capture (EC) are competitive with those by
?-disintegration - In the EC process the parent nucleus, instead of
emitting a ?-particle, captures one of its own
atomic electrons and emits a monoenergetic
neutrino
17Electron-Capture (EC) Transitions (cont.)
- The electrons most likely to be captured in the
EC process are K-shell electrons (?90), with
L-shell electrons supplying practically all of
the remainder - Resulting shell vacancies are promptly filled by
an electron from a higher orbit, with the release
of a fluorescence x-ray - The probability that a fluorescence photon will
escape from its native atom is called the
fluorescence yield, YK or YL
18Fluorescence yield (YK,L) and fractional
participation in the photoelectric effect (PK,L)
by K- and L-shell electrons
19Electron-Capture (EC) Transitions (cont.)
- The parallel atomic mass-energy equations for the
case of 22Na ? 22Ne are given below for ?-decay
and for the EC process - The half-life for decay by both branches together
is 2.60 y - The corresponding atomic energy-level diagram is
shown after the equations
20Electron-Capture (EC) Transitions (cont.)
- ?-Branch
- where the atomic mass decrease is equal to
21Electron-Capture (EC) Transitions (cont.)
- EC Branch
- where the atomic mass decrease is equal to
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23Electron-Capture (EC) Transitions (cont.)
- It will be seen from the diagram that for
?-disintegration to take place in any
radionuclide requires a minimum mass difference
between the parent neutral atom and its daughter
atom of 2m0 ( 1.022 MeV) - Otherwise only EC can occur, since no kinetic
energy would be available for a ?-particle, and
in that case the dose deposited in EC events
becomes relatively important
24Electron-Capture (EC) Transitions (cont.)
- In the EC branch equation the Eb-term indicates
the electron binding energy in the K- or L-shell - The kinetic energy of the emitted neutrino equals
the difference in atomic rest mass between the
Na-22 and the excited state of Ne-22 ( 1.568
MeV), less the electron binding energy Eb (? 1
keV for the K shell)
25Absorbed Dose for the EC Process
- When a ? is emitted, it contributes its average
kinetic energy to the production of absorbed
dose, and then its annihilation ?-rays may
contribute more dose, depending upon the size and
shape of the radioactive mass of material - If an EC event occurs instead of ?emission,
neither of these dose components is present, and
virtually all of the energy available for
absorbed dose in an EC event (if there is no
subsequent ?-ray emission from an excited state)
is contained in the electron-binding term Eb,
which is very small compared to the energy that
is removed by the neutrino
26Absorbed Dose for the EC Process (cont.)
- EC contributes a more significant fraction of the
dose when ?-emission is prohibited and only EC
can occur - An example is 55Fe ? 55Mn, which emits Mn
fluorescence x-rays of 5.9 keV and no other
radiation (besides monoenergetic neutrinos) - These photons are so easily attenuated that
radiation equilibrium exists at the center of a
1-cm-radius water sphere
27Absorbed Dose for the EC Process (cont.)
- Thus the energy contributing to the dose there
per EC event is equal to the electron binding
energy Eb in each case, whether a fluorescence
x-ray is emitted or not - Since approximately 88 of these EC events
involve the K-shell, and the other 12 can be
assumed to be with the L, the energy spent on the
dose per EC event is - where the binding energies are those for the
daughter product, Mn
28Internal Conversion vs. ?-Ray Emission
- An excited nucleus, instead of emitting a ?-ray
of energy h?, can impart the same amount of
energy directly to one of its own atomic
electrons, which then escapes the atom with a net
kinetic energy of h? - Eb, where Eb is the
binding energy of the electrons original shell - This process, called internal conversion (IC),
has nothing to do with the photoelectric effect,
since the nucleus emits no photons in this case - The ratio of the number Ne of conversion
electrons emitted to the number N? of ?-rays
emitted by a given species of excited nucleus is
called the internal-conversion coefficient
29Internal Conversion vs. ?-Ray Emission
- An example of internal conversion is shown in the
following diagram for - It will be seen that 94.6 of the 137Cs atoms
decay to an excited state of 137Ba, indicated as
137mBa, where the m indicates a metastable or
long-lived isomeric state with a half-life of
2.55 minutes
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31Internal Conversion vs. ?-Ray Emission
- Isomers are nuclei having the same Z and the same
number A of nucleons, but differing energy states - These excited 137mBa nuclei then decay in the
following proportions - 89.9 ?-ray emission (0.662 MeV)
- 8.2 conversion of K-shell electrons
- 1.9 other-shell conversions
32Internal Conversion vs. ?-Ray Emission
- Normally IC branching is not shown on
energy-level diagrams, but the figure here
includes it for clarity - Note that the percentages shown there have been
normalized to a total of 96.4, so that, for
example, there are 85.0 ?-rays emitted per 100
disintegrations of 137Cs - Internal conversion is always possible in place
of ?-ray emission by an excited nucleus - However, in many cases the probability of IC is
negligibly small and can be ignored
33Absorbed Dose for Internal Conversion
- When IC occurs in competition with ?-ray
emission, it generally results in a net increase
in absorbed dose in small objects, since the
penetrating ?-radiation is thus replaced by a
relatively short-range electron of nearly the
same energy - That is, the energy of the conversion electron is
- which will all be spent on absorbed dose
under CPE conditions, neglecting radiative losses
34Absorbed Dose for IC (cont.)
- In addition, the binding energy Eb also will be
entirely contributed to the dose, provided that
no part of it escapes from the radioactive body
in the form of fluorescence x-rays - If the fraction p 1 AF of these x-rays can
escape from the radioactive body, then the energy
contributed per IC event to dose under CPE
conditions becomes - where
- with ?en and r defined as before
35Tables for Dose Estimation in Appendix C
- For each source the table gives the types of
radiations emitted, the number of particles (or
photons) of each type emitted per parent
disintegration, the mean energy per particles,
and the corresponding equilibrium dose constant
in g rad/?Ci h - The latter quantity can be converted into J/Bq h
by multiplying by 2.703 ? 10-10 - It represents the energy contributed to the
absorbed dose, per unit activity and time, under
RE conditions (or CPE conditions for ?-rays)