Title: Buffer Example and Titration Calculations
1Buffer Example and Titration Calculations
- With your Chemistry 102 Host
- Dr. Mike Daniel
2pH Change to 1M Acetic Acid/1M Acetate Ion Soln.
0
Moles OH- Added
Moles H Added
3Buffers
- Buffer Solutions resist a change in pH
- Buffers contain relatively large concentrations
of either - An acid, HA and its conjugate base A-
- A base, B, and its conjugate acid (BH)
4Buffers
NH4 to react with OH-
5Buffers
NH3 to react with H
6Buffers
- When H is added, it reacts essentially to
completion with the weak base present - H A- ? HA or
- H B ? BH
7Buffers
- When OH- is added, it reacts essentially to
completion with the weak acid present - OH- HA ? H2O A-
- OH- BH ? H2O B
8Buffers
- pH pKa log (base/acid)
- Want pH ? pKa ? 1
- pH determined by
- Ka of acid and ratio of acid/conjugate base
- or
- Kb of base and ratio base/conjugate acid
9Buffer Choice
- Want pH ? pKa ? 1
- How do I make a pH 4.0 buffer?
- Choose a pKa near the desired pH
10Buffer Table
11Buffer Choice
- Choose a pKa near the desired pH
- pH pKa log (base/acid)
- 4.0 3.74 log (base/acid)
- 0.26 log (base/acid)
- 10.26 1.8 (Na formate / formic acid)
12Basic Buffer Choice
- Ammonia pKb 4.74
- pKa 14.00 4.74 9.26
- NH3 / NH4Cl used to buffer around pH 9.26
13Buffer Capacity
- As long as ratio remains virtually constant, the
pH will be virtually constant - This is true as long as concentrations of
buffering materials (HA/A-) or (B/BH) are large
compared with H or OH- added.
14Acid / Base Titrations Strong A B
- Follow Text page 714 (Brady Holum)
- 25 mL of .2 M HCl titrated with .2 M NaOH
- Equivalence Point Where Stoichiometric amounts
of acid and base have been added - End Point Where indicator color change occurs
15Acid / Base Titrations Strong A B
- VMHCl 5 X 10-3 mol
- -VMNaOH
- moles of H leftover till equivalent point
reached - At equivalence point,
- 5 X 10-3 mol NaCl/.050 L solution
- pH 7
16Acid / Base Titrations Strong A B
Equivalence Point
17Acid / Base Titrations Strong A B
HCl/NaCl buffer
18Acid / Base Titrations Strong A B
Phenolphthalein
Bromcresol Green
19Acid / Base Titrations Weak Acid with Strong
Base
- 25 mL of .2 M Acetic Acid (HAc) titrated with .2
M NaOH - Initial pH calculated as before
20Acid / Base Titrations Weak Acid with Strong
Base
- During titration up to equivalence point
- VMHAc 5 X 10-3 mol
- -VMNaOH
- moles of HAc leftover
- VMNaOH moles OH- added moles Ac-
- made
- Say 10. mL of .2 M NaOH added to 25 mL of .2 M
HAc
21Acid / Base Titrations Weak Acid with Strong
Base
22Acid / Base Titrations Weak Acid with Strong
Base
HAc/Ac- buffer
23Acid / Base Titrations Weak Acid with Strong
Base
- At Equivalence Point all acetic acid converted
to Acetate ion - At Equivalence Point you have a Sodium Acetate
Solution
24Acid / Base Titrations Weak Acid with Strong
Base
- At Equivalence Point you have a Sodium Acetate
Solution - To determine pH
- Use Kb and
- C2H3O2- H2O ? HC2H3O2 OH-
- To determine OH- and H and pH
25Acid / Base Titrations Weak Acid with Strong
Base
- At Equivalence Point you have a Sodium Acetate
Solution - pH lt or gt 7 ?
- pH 8.88
26Acid / Base Titrations Weak Acid with Strong
Base
Equivalence Pt pH 8.88
27Acid / Base Titrations Weak Acid with Strong
Base
- After Equivalence Point
- VMNaOH VMHAc(initial) moles OH- in total
volume. - From OH- determine H and pH
28Acid / Base Titrations Weak Acid with Strong
Base
Phenolphthalein
Bromocresol Green
29Acid / Base Titrations Weak Base with Strong
Acid
30Acid / Base Titrations Weak Base with Strong
Acid
NH3/NH4 buffer
31Acid / Base Titrations Weak Base with Strong
Acid
Phenolphthalein
Methyl Red