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Stereochemistry of Oxime formation: Steps I

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Since we only have a weak nucleophile and a poor electrophile we need to activate the amide. Protonation of the amide carbonyl makes it more electrophilic. 2. ... – PowerPoint PPT presentation

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Title: Stereochemistry of Oxime formation: Steps I


1
Stereochemistry of Oxime formation Steps I II
2
Aim
  • Condensation Reaction.
  • Synthesize of an Oxime.
  • Beckman Rearrangement.
  • 1. React the oxime with polyphosphoric acid.
  • 2. Hydrolysis of the compound from the reaction
    of oxime and polyphosphoric acid.

3
Oximes Introduction
  • OXIMES, in organic chemistry, compounds
    containing the grouping C N-OH, derived from
    aldehydes and ketones by condensing them with
    hydroxylamine.

4
Types of Oximes
  • Two types of oximes are known
  • Aldoxime combination of aldehydes with
    hydroxylamine.
  • Ketoxime Combination of ketones with
    hydroxylamine.

5
Physical Properties
  • They were first prepared by V. Meyer in 1882.
  • They are either colorless liquids, which boil
    without decomposition, or crystalline solids.
  • BASIC (due to NITROGEN) and ACIDIC (due to
    HYDROXYL GROUP) in character.

6
Chemical Properties
  • On reduction by sodium amalgam in glacial acetic
    acid solution they yield PRIMARY AMINES.
  • They are hydrolyzed by dilute mineral acids
    yielding hydroxylamine and the parent ALDEHYDES
    or KETONES.

7
Chemical Properties
  • The aldoximes are converted by the action of
    dehydrating agents into NITRILES.
  • The ketoximes by the action of polyphosphoric
    acid undergo a peculiar intramolecular
    re-arrangement known as the BECKMAN REARRANGEMENT
    yielding as final products an acid-amide or
    anilide.

8
Isomers
  • If you use aldehydes or asymmetrical ketones,
    there is the possibility of getting TWO
    STEREOISOMERS of the oxime.

9
Part I Procedure
  • Make a solution of 1.8 g of hydroxyl amine
    hydrochloride and 1.8 g of sodium acetate in 8 mL
    of water.
  • Take 3 gram of p bromoacetophenone in a 50 mL
    RB flask and add 10 mL of ethanol (95 ).
  • Mix both solution and set up a refluxion
    apparatus.
  • Reflux the mixture for 20 minutes.

10
Part I Procedure
  • Filter the hot solution using filter paper and
    funnel (do not use Buchner funnel).
  • Once the mixture cooled to room temperature keep
    it on a ice bath for 10 minutes.

11
Part I Procedure
  • You will see a nice solid or crystals.
  • Filter them using Buchner funnel.
  • Wash the solid with little (may be 5 -10 mL) of
    50 ethanol.
  • Find the melting point of the dry oxime.

12
Possible Isomers
  • p Acetophenone is an asymmetric ketone.
  • Two possible products are

13
Characterization
  • Characterization of the Oxime by
  • Melting Point.
  • IR.

14
Beckman Rearrangement
  • It is an acid-catalyzed rearrangement of an oxime
    to an amide.
  • Named after the German chemist Ernst Beckmann.

15
Beckman Rearrangement
  • Open Chain oxime gives an open chain amide.
  • Cyclic oxime gives yields lactam.

16
Beckman Rearrangement
  • The Beckmann solution consists of acetic acid,
    hydrochloric acid and acetic anhydride, and was
    widely used to catalyze the rearrangement.
  • Other acids, such as polyphosphoric acid,
    sulfuric acid or phosphorous pentachloride, can
    also be used.

17
Beckman Rearrangement
  • The Beckman rearrangement is known to be
    catalyzed by Cyanuric chloride and Zinc Chloride.

18
Beckman Rearrangement
  • The reaction mechanism of the Beckmann
    rearrangement is generally believed to consist
  • 1. An alkyl migration (trans to OH) with
    expulsion of the hydroxyl group to form a
    nitrilium ion.
  • 2. Followed by hydrolysis.

19
Beckman Rearrangement
Anti group always migrates. No question of
migratory aptitude!
20
Beckman Rearrangement
The OH is converted into a good leaving group by
reaction with PCl5. Phenyl migration expels the
leaving group, and hydrolysis generates the amide
product.
21
Part II Procedure
  • Take 20 mL of polyphosphoric acid in a 125 mL
    Erlenmeyer flask.
  • Heat it for 10 minutes using steam bath.
  • Add 2 gram of the oxime which you made once the
    acid is hot.
  • Continue the heating for 20 more minutes using
    the steam bath.

22
Part II Procedure
  • Add the hot solution into a beaker contain 80 mL
    of ice water (take 40 mL of water and 40 gram of
    ice).
  • Stir the mixture till all ice melts.
  • Filter the solid using Buchner Funnel.
  • Wash the solid using cold water until the
    filtrate is neutral (no longer acidic).
  • Dry the solid using suction pump.

23
Possible Product
24
Characterization
  • Melting Point.
  • IR

25
Substituents Effects in 1H NMR
26
1H NMR
  • Effects of Substituents
  • 1. Proton NMR signal always shifts to upfield
    if the substituents are electron releasing.
  • 2. Proton NMR signal always shifts to
    downfield if the substituents are electron
    withdrawing.

27
1H NMR
  • Effect of Substituents on benzene ring
  • Ortho hydrogen's have low chemical shift value
    (upfield shift) if the substituents are Electron
    Releasing.
  • Ortho hydrogen's have high chemical shift value
    (downfield shift) if the substituents are
    Electron Withdrawing.

28
1H NMR
  • Electron Releasing Group.
  • 1. CH3
  • 2. NH2 NMe2 (due to lone pair of electrons)

29
1H NMR
  • Electron Withdrawing Group.
  • 1. COOH
  • 2. NO2
  • 3. CHO CO

30
1H NMR
  • P Toluidine
  • Both CH3 and -NH2 groups are electron
    releasing!.
  • NH2 is stronger electron releasing group than
    -CH3.
  • So Ar-H, ortho to -NH2 will be having low
    chemical shift value.

31
1H NMR
  • P Acetotoluidide
  • Both methyl group is an electron releasing!
  • NH-CO-CH3 is an little electron withdrawing group
    compare to CH3 group due to CO attached to -NH.
  • So Ar-H, ortho to CH3 will be having low chemical
    shift value.

32
1H NMR
  • P Acetoamidobenzoic acid
  • -COOH group is an electron withdrawing group!
  • NH-CO-CH3 is less electron withdrawing group than
    -COOH.
  • So Ar-H, ortho to NH-CO-CH3 will be having low
    chemical shift value.

33
1H NMR
  • P Aminobenzoic acid
  • NH2 group is an electron releasing group!
  • -COOH is a strong electron withdrawing group!.
  • So Ar-H, ortho to -NH2 will be having low
    chemical shift value and ortho to -COOH will be
    having high chemical shift value.

34
Stereochemistry of Oxime formation Step III
35
Aim
  • To do an acid hydrolysis of an amide.
  • Check the solubility of the final product.
  • Find out what kind of Beckmann Rearrangement
    taken place in the last lab.

36
Preparation of Amides
  • Amides are prepared from amines by acylation
    with
  • 1. Acyl chlorides R-CO-Cl.
  • 2. Anhydrides (R-CO)2O See the 2 lab.
  • 3. Esters R-CO-O-R.

37
Preparation of Amides
  • Amides can also be prepared from the Beckmann
    Rearrangement reaction.
  • Its an acid catalyzed rearrangement of an oxime
    to an amide

38
Preparation of Amides
39
Hydrolysis of Amides
  • Hydrolysis of amide means cleavage of amide bond
    i.e. NH CO bond.
  • Two Types
  • 1. Acid Hydrolysis
  • 2. Basic Hydrolysis

40
Acid Hydrolysis of Amides
  • Hydrolysis of amides is irreversible. In acid
    solution the amine product is protonated to give
    an ammonium salt.


R'NH3


H2O
H


41
Acid Hydrolysis of Amides
H2O

H2SO4heat
(88-90)
42
Basic Hydrolysis of Amides
  • In basic solution the carboxylic acid product is
    deprotonated to give a carboxylate ion.




R'NH2
HO

43
Basic Hydrolysis of Amides
KOH

H2Oheat
(95)
44
Acid Hydrolysis of Amides
  • Acid-catalyzed amide hydrolysis proceeds via the
    customary two stages
  • 1. Formation of tetrahedral intermediate.
  • 2. Dissociation of tetrahedral intermediate

45
Acid Hydrolysis of Amides Stage I
  • 1. Since we only have a weak nucleophile and a
    poor electrophile we need to activate the amide.
    Protonation of the amide carbonyl makes it more
    electrophilic.
  • 2. water adds to the carbonyl group of the amide
    and forms a active tetrahedral intermediate

H
46
Acid Hydrolysis of Amides Stage II

Collapse of the tetrahedral intermediate into the
acid
H
47
Step 1
48
Step 1
  • Carbonyl oxygen is protonated because cation
    produced is stabilized by electron delocalization
    (by resonance)

49
Step 2
The water O functions as the nucleophile
attacking the electrophilic C in the CO, with
the electrons moving towards the Oxonium ion,
creating the tetrahedral intermediate
50
Step 3
Deprotonate the oxygen that came from the water
molecule to neutralize the charge.
51
Step 4
Need to make the -NH2 leave, but need to convert
it into a good leaving group first by
protonation.
52
Step 5
Use the electrons of an adjacent oxygen to help
push out the leaving group, a neutral ammonia
molecule.
53
Step 6

NH4

54
Step 6
Resonance structure
55
Step 6

Deprotonation of the oxonium ion reveals the
carbonyl in the carboxylic acid product and
regenerates the acid catalyst.
56
Acid Hydrolysis of Amides
  • We made these amides in the last lab.
  • We need to characterize by 1H NMR.

From Phenyl migration
From Methyl migration
57
Acid Hydrolysis of Amides
  • The phenyl migrated amide gives following
    products after acid hydrolysis
  • 1. P bromoaniline
  • 2. Acetic Acid

58
Acid Hydrolysis of Amides
  • The Methyl migrated amide gives following
    products after acid hydrolysis
  • 1. P bromobenzoic acid
  • 2. Methylamine

59
Characterization
  • Solubility test will tell you what kind of
    hydrolyzed product you have obtained.
  • Organic acids are soluble in aqueous basic
    solutions.
  • e.g. Benzoic acid is soluble in aqueous NaOH
  • Organic bases are soluble in aqueous acid
    solutions.
  • e.g. Aniline is soluble in aqueous HCl

60
Characterization
  • If your final product (after the hydrolysis) is
    soluble in aqueous HCl then you have obtained
    phenyl migrated amide in the Beckmann
    Rearrangement reaction.
  • If your final product is soluble in aqueous NaOH
    then you have obtained methyl migrated amide in
    the Beckmann Rearrangement reaction.

61
Procedure
  • Take 1 gram of the product from the Beckmann
    Rearrangement Reaction in a 50 mL RB flask.
  • Add 6 mL of concentrated hydrochloric acid.
  • Set up a refluxion apparatus with HCl trapper.
  • Do the refluxion for 30 minutes.

62
Procedure
  • Add 5 mL distilled water and cool them using ice
    bath.
  • Keep the solution in the hood and carefully pour
    this solution into an ice cold ammonia hydroxide
    solution (10 mL) in a 125 mL Erlenmeyer Flask.
  • Swirl the flask when you do mixing.

63
Procedure
  • After sometime you will see nice crystals or
    solid.
  • Filter them using Buchner Funnel.
  • Wash the solid with cold water (may be with 10 mL
    of water).
  • Dry the product as much as you can using suction
    filtration.
  • Then do the solubility test.

64
Caution!
  • Concentrated hydrochloric acids and Concentrated
    ammonium hydroxides fumes are dangerous to
    health. Please do not inhale them.
  • Always wear safety glass.
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