Title: Section 6.4 Calculating Probabilities of Events Definition
1Section 6.4 Calculating Probabilities of
EventsDefinition
- Pr(Event) Number of Outcomes of the Event
- Total Number of Outcomes
2Section 6.4 Calculating Probabilities of
Events Coin Tossing
- When tossing a coin 8 times, what is the
probability of tossing exactly 6 tails? - C( 8, 6 ) (6 tails in
8 tosses) - 28 (Total
outcomes possible) - 28 7
- 256 64
3Section 6.4 Calculating Probabilities of
Events Having Children
- If a family has 8 children, what is the
probability it has exactly 6 girls? - C( 8, 6 ) (6 girls out
of 8 children) - 28 (Total
outcomes possible) - 28 7
- 256 64
4Section 6.4 Calculating Probabilities of
Events Coin Tossing
- When tossing a coin 8 times, what is the
probability of tossing at least 6 tails? - C( 8, 6 ) C(8, 7) C(8, 8) (6 tails or 7
tails or 8 tails) - 28
(Total outcomes possible) - 37
- 256
5Section 6.4 Calculating Probabilities of
Events Having Children
- If a family has 8 children, what is the
probability it has at least 6 girls? - C( 8, 6 ) C(8, 7) C(8, 8) (6 girls or 7
girls or 8 girls) - 28
(Total outcomes possible) - 37
- 256
6Section 6.4 Calculating Probabilities of
EventsSample Problems
- Pr (blond hair)?
- Pr (female)?
- Pr (male and brunette)?
- Pr (male or brunette)?
- Pr (female and not blond)?
7Section 6.4 Calculating Probabilities of
EventsPage 301, Problem 8
- Choose 2 white balls out of 6 Choose 2
red balls out of 5 - C(6,2) x C(5,2) 150
5 - C(11,4)
330 11 - Total balls available (6 white 5 red)
Sample Size
8Section 6.4 Calculating Probabilities of
EventsThe Complement Rule
- The Complement Rule relates the probability
of an event E to the probability of its
complement E'. - Pr(E) 1 Pr(E')
- It is beneficial to use this formula when
calculating Pr(E') is easier than calculating
Pr(E). -
9Section 6.4 Calculating Probabilities of
EventsPage 301, Problem 8 Extended
- The probability that at least one of the balls is
red? - (Calculate the complement ? all are white ?and
subtract this value from 1) - C(6,4) x C(5,0) 4 white balls and 0 red
balls - C(11,4) Combinations of 11
taken 4 at a time - 15 1 ? 1 (1/22)
21/22 - 330 22
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