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5.1 Factoring the Greatest Common Factor

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Choose the smallest exponents for variables and prime factors. Multiply the primes and variables from step 3 ... Factoring ax2 bx c by using FOIL (in reverse) ... – PowerPoint PPT presentation

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Title: 5.1 Factoring the Greatest Common Factor


1
5.1 Factoring the Greatest Common Factor
  • Finding the Greatest Common Factor
  • Factor write each number in factored form.
  • List common factors
  • Choose the smallest exponents for variables and
    prime factors
  • Multiply the primes and variables from step 3
  • Always factor out the GCF first when factoring an
    expression

2
5.1 Factoring the Greatest Common Factor
  • Example factor 5x2y 25xy2z

3
5.1 Factoring Factor By Grouping
  • Factoring by grouping
  • Group Terms collect the terms in 2 groups that
    have a common factor
  • Factor within groups
  • Factor the entire polynomial factor out a
    common binomial factor from step 2
  • If necessary rearrange terms if step 3 didnt
    work, repeat steps 2 3 until you get 2 binomial
    factors

4
5.1 Factoring Factor By Grouping
  • ExampleThis arrangement doesnt work.
  • Rearrange and try again

5
5.2 Factoring Trinomials
  • Factoring x2 bx c (no ax2 term yet)Find 2
    integers product is c and sum is b
  • Both integers are positive if b and c are
    positive
  • Both integers are negative if c is positive and b
    is negative
  • One integer is positive and one is negative if c
    is negative

6
5.2 Factoring Trinomials
  • Example
  • Example

7
5.3 Factoring Trinomials Factor By Grouping
  • Factoring ax2 bx c by grouping
  • Multiply a times c
  • Find a factorization of the number from step 1
    that also adds up to b
  • Split bx into these two factors multiplied by x
  • Factor by grouping (always works)

8
5.3 Factoring Trinomials Factor By Grouping
  • Example
  • Split up and factor by grouping

9
5.3 More on Factoring Trinomials
  • Factoring ax2 bx c by using FOIL (in reverse)
  • The first terms must give a product of ax2 (pick
    two)
  • The last terms must have a product of c (pick
    two)
  • Check to see if the sum of the outer and inner
    products equals bx
  • Repeat steps 1-3 until step 3 gives a sum bx

10
5.3 More on Factoring Trinomials
  • Example

11
5.3 More on Factoring Trinomials
  • Box Method (not in book)

12
5.3 More on Factoring Trinomials
  • Box Method keep guessing until cross-product
    terms add up to the middle value

13
5.4 Special Factoring Rules
  • Difference of 2 squares
  • Example
  • Note the sum of 2 squares (x2 y2) cannot be
    factored.

14
5.4 Special Factoring Rules
  • Perfect square trinomials
  • Examples

15
5.4 Special Factoring Rules
  • Difference of 2 cubes
  • Example

16
5.4 Special Factoring Rules
  • Sum of 2 cubes
  • Example

17
5.4 Special Factoring Rules
  • Summary of Factoring
  • Factor out the greatest common factor
  • Count the terms
  • 4 terms try to factor by grouping
  • 3 terms check for perfect square trinomial. If
    not a perfect square, use general factoring
    methods
  • 2 terms check for difference of 2 squares,
    difference of 2 cubes, or sum of 2 cubes
  • Can any factors be factored further?

18
5.5 Solving Quadratic Equations by Factoring
  • Quadratic Equation
  • Zero-Factor PropertyIf a and b are real numbers
    and if ab0then either a 0 or b 0

19
5.5 Solving Quadratic Equations by Factoring
  • Solving a Quadratic Equation by factoring
  • Write in standard form all terms on one side of
    equal sign and zero on the other
  • Factor (completely)
  • Set all factors equal to zero and solve the
    resulting equations
  • (if time available) check your answers in the
    original equation

20
5.5 Solving Quadratic Equations by Factoring
  • Example

21
5.6 Applications of Quadratic Equations
  • This section covers applications in which
    quadratic formulas arise.Example Pythagorean
    theorem for right triangles (see next slide)

22
5.6 Applications of Quadratic Equations
  • Pythagorean Theorem In a right triangle, with
    the hypotenuse of length c and legs of lengths a
    and b, it follows that c2 a2 b2

c
a
b
23
5.6 Applications of Quadratic Equations
  • Example

x2
x
x1
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