Title: Welcome to the CLAST Practice Test.
1Welcome to the CLAST Practice Test.
- Each question has four answers provided. Choose
the correct answer by clicking on the answer. - Click here to begin.
21. Skill 1 Identifying information contained in
bar, line, and circle graphs
- 1.1 The graph at the left compares the grades
between the males and females earned on the first
Chemistry test in Professor Bonds two Chemistry
I classes. What was the total number of
students in both these classes? - 59
- 34
- 29
- 63
No. of students
32. Skill 1 Identifying information contained in
bar, line, and circle graphs
- 1.2 The graph at the left represents the rainfall
for the first six months in a city. What is the
biggest difference in rainfall between any two
months? - 5 inches
- 6 inches
- 8 inches
- 9 inches
43. Skill 1 Identifying information contained in
bar, line, and circle graphs
- 1.3 The circle graph at the left represents the
menu selections of 600 people attending a
banquet. How many people attending the banquet
chose beef or fish? - 150
- 180
- 330
- 420
54. Skill 1 Identifying information contained in
bar, line, and circle graphs
- 1.4 The graph at the left compares the attendance
at two theme parts over the period of a year. In
which quarter did the attendance at Wally World
exceed the attendance at Animal World by the
greatest amount? - 1st quarter
- 2nd quarter
- 3rd quarter
- 4th quarter
65. Skill 1 Identifying information contained in
bar, line, and circle graphs
- 1.5 The line graph at the left shows the average
number of cars sold each day at a large
dealership over a four month period. What was
the highest daily average number of cars sold? - 20
- 28
- 85
- 90
76. Skill 1 Identifying information contained in
bar, line, and circle graphs
- 1.6 The pie graph at the left represents the
number of students by age enrolled in college
algebra for the summer term at a community
college. What percentage of the students are
less than 27 years old? - 45
- 55
- 60
- 70
87. Skill 2 Identifying relationships and making
predictions based on statistical data
- 2.1 The scatter diagram at the left represents
the price of a laptop computer versus the number
sold at a computer store. Which statement best
summarizes the relationship between price and
number sold. - Higher prices caused fewer laptops to be sold.
- Higher prices tend to be associated with fewer
laptops sold. - There is no apparent relationship between price
and number sold. - Lower prices cause a higher number of laptops
sold.
98. Skill 2 Identifying relationships and making
predictions based on statistical data
- 2.2 The scatter diagram at the left represents
the price of a laptop computer versus the number
sold at a computer store. Approximately how many
laptop where sold at the cheapest price (1000)? - 20
- 40
- 50
- 60
109. Skill 2 Identifying relationships and making
predictions based on statistical data
- 2.3 The graph at the left depicts the sales
figures (in thousands) for two competing burger
chains over a 7 year period from 1995 to 2002.
Identify which statement is true based on the
graph. - Both burger chains experienced in increase an
sales over the 7 year period. - Yummy Burger spent more on advertisements than
Big Burger. - During the time period between 1995 and 1997
Yummy Burger sold more burgers than Big Burger. - The number of burgers sold by both chains was
equal in 1999.
1110. Skill 2 Identifying relationships and
making predictions based on statistical data
- 2.4 The table at the left contains information
about the number of videos rented and movie
attendance at two businesses at a strip mall.
Which of the following statements describes the
relationship between the number of videos rented
and attendance at the movie theater? - An increase in the number of movies attended is
associated with an increase in the number of
videos rented. - Movies are just as good when viewed at home as
they are at the theater. - Its cheaper to rent videos than to go to the
theater. - The increase in videos rented is greater than the
increase in movie attendance.
1211. Skill 2 Identifying relationships and
making predictions based on statistical data
- 2.5 The table at the left presents information
about the average home price in various U. S.
cities in 2002 and the percent increase in price
in 2002. Which of the following statements is
true, based on the data provided in the table? - The city with the highest average home price had
the largest percent increase in 2002. - Houses are cheaper in Atlanta than in Orlando.
- All average home prices shown increased in 2002.
- Homes in warmer climates are cheaper.
1312. Skill 3 Determining the mean, median, and
mode of a set of numbers
- 3.1 Find the mean, median, and mode of the data
- 2, 3, 7, 4, 3, 11, 7, 6, 4, 13, 4, 8
- mean 6 median 5 mode 4
- mean 5 median 6 mode 4
- mean 6 median 5 mode 7
- mean 5 median 6 mode 7
1413. Skill 3 Determining the mean, median, and
mode of a set of numbers
- 3.2 Given the following set of numbers, determine
which statement is true - 5, 15, 25, 35, 35, 55, 75
- The mean is less than the median.
- The mode is greater than the mean.
- The mean, median, and mode are equal.
- The median is greater than the mode.
1514. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
- 3.3 The table at the left represents the
distribution for the number of pets per household
in a certain neighborhood. What is the mean
number of pets per household? - 0
- 2.00
- 2.18
- 3
1615. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
- 3.4 The table at the left represents the
distribution for the number of pets per household
in a certain city. What is the median number of
pets per household? - 1
- 2
- 3
- 4
-
1716. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
- 3.5 The table at the left represents the
distribution for the number of pets per household
in a certain city. What is the mode number of
pets per household? - 0
- 1
- 2
- 3
-
1817. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
- 3.6 The table at the left represents the
percentile distribution for employees of a
national retail chain. What per cent of the
employees have at least two years off college? - 16
- 25
- 45
- 75
-
1918. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
- 4.1 The table at the left represents the
percentile distribution for employees of a
national retail chain. What per cent of the
employees have more than the high school diploma
but less than a masters degree? - 15
- 16
- 45
- 84
2019. Skill 5 Recognizing relationships between
the mean, median, and mode in a variety of
distributions
- 5.1 In a survey of community college students
half reported they worked 15 hours a week. Equal
numbers reported working 20 hours a week and 25
hours a week, while less reported working more
than 35 hours per week. Select the statement
that is true about the distribution of numbers of
hours worked. - The median and the mode are the same.
- The mean is less than the mode.
- The median is greater than the mode.
- The mean is less than the median.
2120. Skill 5 Recognizing relationships between
the mean, median, and mode in a variety of
distributions
- 5.2 The graph at the left represents the
distribution of scores in a introductory science
class. Which of the following statements is true
about the distribution? - The mean and mode are the same.
- The mode and the mean are the same.
- The median is less than the mode.
- The mode is less than the mean.
2221. Skill 6 Choosing appropriate procedure for
selecting an unbiased sample from a target
population
- 6.1 Professor Powell wants to survey students at
a community college to determine whether they
found the mandatory fall orientations (there were
several sessions) to be worthwhile. Which of the
following procedures would be most appropriate
for selecting a statistically unbiased sample? - Ask all English composition instructors to
administer the survey to their students. - Have the research department call and survey the
first 100 students who attended fall orientation. - Post a notice in the cafeteria asking for
volunteers. - Survey 100 students whose names are randomly
chosen from a list of students attending the fall
orientation.
2322. Skill 6 Choosing appropriate procedure for
selecting an unbiased sample from a target
population
- 6.2 Professor Hakim wants to survey her students
to determine their opinions of the online
components she has added to her course. Which of
the following methods would be most appropriate
for obtaining an unbiased sample? - Survey all students who stop by her office for
help. - Pick names at random from all her class rolls and
interview those chosen after class. - Survey all students in her 800 am class.
- Mail a survey to all her students with a stamped,
self-addressed envelope.
2423. Skill 7 Applying counting rules
- 7.1 At Samanthas Spa you can get a facial, a
pedicure, a manicure, or a steam treatment. How
many different combinations of options are
available, if at least one treatment is included? - 4
- 8
- 15
- 24
2524. Skill 7 Applying counting rules
- 7.2 At Samanthas Spa Josie can get a choice of
four treatments facial, a pedicure, a manicure,
or a steam treatment. If Josie is going to get
all four treatments, one after another, in how
many different orders can she have four
treatments? - 4
- 16
- 24
- 64
2625. Skill 7 Applying counting rules
- 7.3 Joaquin must choose three courses from the
five he needs to graduate this semester. How
many different combinations of three courses can
he choose? - 5
- 10
- 15
- 20
2726. Skill 7 Applying counting rules
- 7.4 The environmental club has 8 students on its
executive board. In how many ways can a
president, vice-president, and secretary be
chosen from this board? - 27
- 336
- 343
- 512
2827. Skill 7 Applying counting rules
- 7.5 Elizabeth takes 3 pairs of shoes, 4 pairs of
slacks, and 6 blouses on a weekend trip. How
many different outfits can she wear, choosing one
pair of shoes, one blouse, and one pair of
slacks. - 12
- 24
- 36
- 72
2928. Skill 7 Applying counting rules
- 7.6 A class of 22 students has 13 women and 9
men. A panel of 2 men and 2 women is chosen for
a debate. In how many different ways can the
panel be chosen? - 13 x 13 x 9 x 9
- 22 x 21 x 20 x 19
- 13 x 12 x 9 x 8
- 22 x 22 x 22 x 22
3029. Skill 8 Determining probabilities
- 8.1 There are 20 raffle tickets sold for a school
fundraiser. If Ray bought 3 tickets, what is the
probability that he will win, assuming all
tickets have an equal chance of being chosen? - 0
- 3/10
- 3/20
- 17/20
3130. Skill 8 Determining probabilities
- 8.2 A recent survey indicated that 12 of
students at a college are registered to vote.
What is the probability that a student at this
college chosen at random will not be registered
to vote? - 0
- .12
- .50
- .88
3231. Skill 8 Determining probabilities
- 8.3 A survey of homeowners indicated that 55 of
homeowners had two or more televisions, 20 had
DVD players, and 60 had cell phones. What is
the probability that two randomly selected
homeowners both have a DVD player? - .02
- .04
- .2
- .4
3332. Skill 8 Determining probabilities
- 8.4 In a survey of students at a community
college 35 work full-time, and 60 plan to
continue to a 4-year college after graduation,
and 20 both work full-time and plan to continue.
If a student is chosen at random from this
college, what is the probability that the student
works full-time or plans to continue to a 4-year
college after graduation? - .35
- .60
- .75
- .95
3433. Skill 8 Determining probabilities
- 8.5 Suppose the probability of a certain brand of
tire wearing out before the guaranteed 40,000
miles is .10. If you purchase 2 new tires, what
is the probability that at least one will wear
out before 40,000 miles? - .10
- .19
- .20
- .90
3534. Skill 8 Determining probabilities
- 8.6 In a recent election, 25 of eligible voters
registered to vote, and 30 of those registered
voted. What is the probability that an eligible
voter actually registered and voted? - .05
- .075
- .25
- .30
3635. Skill 9 Solving real-world problems using
probabilities
- 9.1 The table at the left shows the distributions
of absences of the students who passed
Professors Kilmers physics class for the fall
term. If a student who passed his class is
selected at random, what is the probability that
student had less than 2 absences? - .14
- .21
- .26
- .47
3736. Skill 9 Solving real-world problems using
probabilities
- 9.2 The table at the left shows the distributions
of absences of the students who passed
Professors Kilmers physics class for the fall
term. If a student who passed his class is
selected at random, what is the probability that
student had more than 1 but less than 5 absences? - .29
- .43
- .51
- .53
3837. Skill 9 Solving real-world problems using
probabilities
- 9.3 The table at the left shows the distributions
of absences of the students who pass an advanced
chemistry course on their first attempt at a
large university. If two students who passed this
class are selected at random, what is the
probability that neither student had more than 3
absences? - .001
- .01
- .10
- .20
3938. Skill 9 Solving real-world problems using
probabilities
- 9.4 The table at the left shows the distributions
of votes in a recent local mayoral election.
Based on these results, what is the probability
that a randomly selected voter voted for the
Libertarian candidate? - .01
- .03
- .04
- .05
4039. Skill 9 Solving real-world problems using
probabilities
- 9.5 The table at the left shows the distributions
of all votes in a recent local mayoral election.
Based on these results, what is the probability
that a randomly selected voter is female, given
that the voter voted for the Democratic
candidate? - .2
- .3
- .5
- .6
4140. Skill 9 Solving real-world problems using
probabilities
- 9.6 The pie chart at the left represents the
distribution of beverage choices of students at
the school cafeteria. If a student who uses the
cafeteria is randomly chosen, what is the
probability that the student does not choose
coffee? - .11
- .22
- .74
- .89
4241. Skill 9 Solving real-world problems using
probabilities
- 9.7 The pie chart at the left represents the
distribution of beverage choices of students at
the school cafeteria. If a student who uses the
cafeteria is randomly chosen, what is the
probability that the student chooses either soda
or diet soda? - .22
- .52
- .74
- .89
4342. Skill 9 Solving real-world problems using
probabilities
- 9.8 For a certain variety of citrus trees sold
at a nursery, 90 are guaranteed to bear fruit
within the first five years. Of the trees that
bear fruit, 20 will be tangerines, 40 will be
oranges and the rest will be grapefruit. If one
of these trees is selected at random from the
nursery, what is the probability that the tree
will bear fruit within five years and be a
tangerine tree? - .18
- .20
- .36
- .54
44End of Test
451. Correct Answer!
Return to previous slide
The solution is D, 63 students. 5 males and 9
females made A, 8 males and10 females made B,
12 males and 12 females made C, 3 males and 2
females made D,, and 1 male and 1 female made
F.
462. Correct Answer!
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The solution is D, 9 inches. In April it rained
15 inches and in May it rained 6 inches. The
difference is 15 6 9 inches.
473. Correct Answer!
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The correct answer is C, 330 people. 40 chose
beef and 15 chose chicken, for a total of 55.
55 of 600 people is .55 X 600 330.
484. Correct Answer!
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The correct answer is A, the first quarter. The
distance between the dark blue and light blue
bars are the greatest for this quarter.
495. Correct Answer!
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The correct answer is D, 90 cars each day. It
is the highest point on the graph over the month
of August, and it lies half-way between 80 and
100.
506. Correct Answer!
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The correct answer is D, 70. The total number
of students is 2000. The total number of
students from 17 to 26 is 7506501400.
1400/2000.70 or 70.
517. Correct Answer!
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The correct answer is B. The graph indicates
that more computers are sold at lower prices, and
fewer computers are sold at higher prices. Thus
C is incorrect. Answers A and D incorrectly
infer a cause and effect relationship between
price and number sold which cannot be proven.
528. Correct Answer!
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The correct answer is D, 60 laptops sold at
1,000
539. Correct Answer!
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The correct answer is D. Each dot on the lines
represents a year, starting with 1999. The lines
cross at the 5th dot from the left, which
represents 1999. Big Burger experienced a
decrease in sales. Big Burger sold more between
1995 and 1997. We know nothing about advertising
for either chain.
5410. Correct Answer!
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The correct answer is D. From 2.4 to 13.1 is
greater than from 3.3 to 6.0. The other
statements may be true but the information in the
table does not support them
5511. Correct Answer!
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The correct answer is C. Boston had the highest
average home price, but San Diego had the highest
price increase. The average home price is higher
in Atlanta than in Orlando. Salem, Oregon, had
the cheapest average home price and it is not in
a warm climate.
5612. Correct Answer!
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The correct answer is A. When the data is
arranged in ascending order, we
have 2,3,3,4,4,4,6,7,7,8,11,13 The mean is
the sum of the numbers divided by 12 or 72
divided by 12, which equals 6. The median is
the average of the 6th and 7th number in the list
above, or (46)/25. The mode is the number
that occurs most frequently, which is 4.
5713. Correct Answer!
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The correct answer is C. The mean is the sum
of the numbers divided by 7, or 245 divided by 7,
which equals 35. When the numbers are arranged
in ascending order, 5, 15, 25, 35, 35, 55, 75,
the median is the middle most number, which is
35. The mode is the most frequently occurring
number, which is 35.
5814. Correct Answer!
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The correct answer is C, mean 2.18. The
mean is given by the sum of the products of
values times proportion Mean
0(.20)1(.12)2(.23) 3(.10)4(.08)5(.04)6(.03)
2.18
5915. Correct Answer!
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The correct answer is B, median 2. The middle
of the distribution is at the .50 or 50 mark.
If we add .20 for 0 pets, .12 for 1 pet, and .23
for 2 pets, .20 .12 .23 .55, we see that
the .50 mark lies at 2 pets.
6016. Correct Answer!
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The correct answer is D, mode 3. The mode is
the value that occurs most frequently in the
distribution. This is the value with the largest
proportion, .30, in this distribution.
6117. Correct Answer!
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The correct answer is B, 25. Since two years of
college has a percentile rank of 75, this means
that 75 of the employees do not have two years
of college, and 100 75 25 do have two years
or more of college. Percentile rankings refer to
the percentage of scores below a particular value.
6218. Correct Answer!
Return to previous slide
The correct answer is C, 45. Since high school
graduate has a percentile rank of 45, 45 of the
employees have less than a high school diploma.
Since the masters degree has a 90 percentile
rank, 90 of the employees have less than a
masters degree. The difference, 90 45 45,
is the per cent who have more than a high school
degree but less than a masters.
6319. Correct Answer!
Return to previous slide
The correct answer is C. Since exactly half of
the students reported working 15 hours per week,
15 is the mode. To compute the mean, we would
have half the numbers equal 15 and half greater
than 15, including equal numbers of 20s and
25s, and a few 35s. Thus the mean would be
larger than 15, and the mean is larger than the
mode. The median is 17.5, the average of 15, the
value of the bottom half, and 20, the next
largest value. Thus the median is greater than
the mode, but smaller than the mean. Thus C is
the correct answer.
6420. Correct Answer!
Return to previous slide
The correct answer is D. The mode is the tallest
column, which is a 2. The median is also a 2,
since there are 17 units of scores, and the 8th
through 13th are 2s, counting from the left.
The mean will be greater than 2, since there are
more 3s than 1s and there are also 4s to
average in with the column of 2s. Thus the mean
is greater than the mode and the median, which
are equal to each other.
6521. Correct Answer!
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The correct answer is D. Method A is not from
the target audience. Not all students in these
classes attended fall registration. Method B
is not random because the first 100 may have a
different experience from those who attended
later. Method C is not random because
volunteers can produce a biased samplethose with
a particular reason for responding. Method D
selects a random sample from the target
population (those who attended fall orientation).
6622. Correct Answer!
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The correct solution is B. Method A is not
random. Only students with the time and interest
to stop by her office will be surveyed. This is
not an unbiased sample. Method B is a random
sample from her target populationall of her
students. Method C is not random. The
experiences of one class does not represent an
unbiased sample of all her students. Method D
allows students to self-select. Only those with
an interest will respond, not an unbiased sample.
6723. Correct Answer!
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The correct answer is C, 15. There is 1
choice of all 4 treatments, 4 choices of 3
treatments, 6 choices of 2 treatments, and 4
choices of 1 treatment. The sum of all these
possibilities is 1 4 6 4 15.
6824. Correct Answer!
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The correct answer is C, 24 different orders.
Using the Fundamental Counting Principle, there
are 4 choices for the first treatment, 3 choices
for the second treatment, 2 choices for the third
treatment, and 1 choice left for the four
treatment. Thus the number of possible orders,
or permutations, is 4 x 3 x 2 x 1 24 possible
orders.
6925. Correct Answer!
Return to previous slide
The correct answer is B, 10 combinations. We
can list the possibilities If A, B, C, D, and
E, represent the five courses, all possible
combinations with 3 are all 3-course groups
containing A (ABC, ABD, ABE, ACD, ACE, ADE) all
3-course groups with B but no A (BCA, BCE, BDE)
the remaining 3-course group with out A or B
(CDE). You may also use the combination formula
for nCr, with n 5, r 3. nCr
7026. Correct Answer!
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The correct answer is B, 336. Using the
Fundamental Counting Principle, there are 8
choices for the president, 7 choices left for the
vice-president, and 6 choices left for the
secretary. Thus there are 8 x 7 x 6 336
ways to chose the three offices. Note a
permutation (8P3) would work too as order matters
with specific office titles.
7127. Correct Answer!
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The correct answer is D, 72 outfits. Using the
Fundamental Counting Principle, there are 3
choices for shoes, 4 choices for slacks, and 6
choices for blouses. The possible number of
outcomes is 3 x 4 x 6 72.
7228. Correct Answer!
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The correct answer is C, 13 x 12 x 9 x 8. The
number of ways to choose two women, using the
Fundamental Counting Principle, is 13 x 12. The
number of ways to choose two men is 9 x 8. The
number of ways to choose two women, then choose
two men is (13 x 2) x (9 x 8) 13 x 12 x 9 x 8
7329. Correct Answer!
Return to previous slide
The correct answer is C, 3/20. The probability
of success is (number of tickets sold to the
person) divided by (total number of tickets
sold). The correct answer is 3 divided by 20 or
3/20.
7430. Correct Answer!
Return to previous slide
The correct answer is D, .88. Since 12 of the
students were registered to vote, the probability
that a randomly selected student is registered is
12/100 or .12, and the probability that a
randomly selected student is not registered is 1
- .12 .88. Alternatively, 100 - 12 88 or
.88.
7531. Correct Answer!
Return to previous slide
The correct answer is B, .04. We use the
formula P(A and B) P(A) x P(B, given A), where
A and B are the event homeowner has a DVD.
P(A) 20 .2 Since the homeowners are
selected independently, P(B, given A) P(B)
20 .2 Thus P(Both have DVDs) P(A and B)
P(A) x P(B) .2 x .2 .04 Note that both
means and which means to multiply.
7632. Correct Answer!
Return to previous slide
The correct answer is C, .75. We use the
formula that P(A or B) P(A) P(B) P(A and
B) Where A works full-time B plans to
continue A and B works full-time and plans to
continue P(A) 35 .35 P(B) 60 .60 P(A
and B) 20 .20 Thus P(A or B) .35 .60 -
.20 .75
7733. Correct Answer!
Return to previous slide
The correct answer is B, .19. Let A 1st tire
will not wear out, B 2nd tire will not wear
out. The probability that at least one will wear
out is 1 (the probability that neither will
wear out) 1 P(A and B) 1 P(A) x P(B)
1 .9 x .9 1 - .81 .19
7834. Correct Answer!
Return to previous slide
The correct answer is B, .075. We use the rule
P(A and B) P(A) x P(B, given A), where A
eligible voter B registered to vote P(A
and B) the probability an eligible voter
voted P(A) 25 .25 P(B, given A) 30
.30 Thus P(A and B) .25 x .30 .075
7935. Correct Answer!
Return to previous slide
The correct answer is D, .47. A student with
less than 2 absences has 0 absences or 1 absence.
The sum of the per cent of students with 0 or
1 absence is 26 21 47. Converting this to
probability, 47 .47
8036. Correct Answer!
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The correct answer is C, .51. The sum of the
percentages for students who missed 2, 3, or 4
absences is 14 29 8 51 or .51
8137. Correct Answer!
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The correct answer is B, .01. The probability
of one student randomly selected having more than
3 absences is 8 2 10 .10. Since it is a
large university, we can assume the events are
independent. Thus the probability of two
students randomly selected both having more than
3 absences is the product of the probabilities,
(.10)x(.10) .01
8238. Correct Answer!
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The correct answer is D, .05, since 3 (males)
and 2 (females) of all voters voted Libertarian,
and 3 2 5 .05
8339. Correct Answer!
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The correct answer is D, .6. Since the voter
voted for the Democratic candidate, we use the
percentages from column one only. The
probability of a randomly selected candidate from
column one being female is (favorable female
democrat) divided by (total all democrats)
or (30)/ (30 20) or 30/50 .6
8440. Correct Answer!
Return to previous slide
The correct solution is D, .89. The
probability that the student does not choose
coffee is 1 the probability that s/he does
choose coffee, which is 1 - .11 .89
8541. Correct Answer!
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The correct solution is C, .74. The
probability that the student chooses either soda
or diet soda is the sum of the probabilities for
these two events, since they are mutually
exclusive events. Thus, P( soda or diet soda)
P(soda) P(diet soda) .52 .22 .74
(Note or means add.)
8642. Correct Answer!
Return to previous slide
The correct answer is A, .18. The probability
of a randomly selected tree bearing fruit and
being a tangerine tree is the product of the
probabilities of each, P(bear fruit and
tangerine) P(bear fruit) x P( tangerine,
given bears fruit) .9 x . 2 .18
87Incorrect.
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