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Welcome to the CLAST Practice Test.

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Title: Welcome to the CLAST Practice Test.


1
Welcome to the CLAST Practice Test.
  • Each question has four answers provided. Choose
    the correct answer by clicking on the answer.
  • Click here to begin.

2
1. Skill 1 Identifying information contained in
bar, line, and circle graphs
  • 1.1 The graph at the left compares the grades
    between the males and females earned on the first
    Chemistry test in Professor Bonds two Chemistry
    I classes. What was the total number of
    students in both these classes?
  • 59
  • 34
  • 29
  • 63

No. of students
3
2. Skill 1 Identifying information contained in
bar, line, and circle graphs
  • 1.2 The graph at the left represents the rainfall
    for the first six months in a city. What is the
    biggest difference in rainfall between any two
    months?
  • 5 inches
  • 6 inches
  • 8 inches
  • 9 inches

4
3. Skill 1 Identifying information contained in
bar, line, and circle graphs
  • 1.3 The circle graph at the left represents the
    menu selections of 600 people attending a
    banquet. How many people attending the banquet
    chose beef or fish?
  • 150
  • 180
  • 330
  • 420

5
4. Skill 1 Identifying information contained in
bar, line, and circle graphs
  • 1.4 The graph at the left compares the attendance
    at two theme parts over the period of a year. In
    which quarter did the attendance at Wally World
    exceed the attendance at Animal World by the
    greatest amount?
  • 1st quarter
  • 2nd quarter
  • 3rd quarter
  • 4th quarter

6
5. Skill 1 Identifying information contained in
bar, line, and circle graphs
  • 1.5 The line graph at the left shows the average
    number of cars sold each day at a large
    dealership over a four month period. What was
    the highest daily average number of cars sold?
  • 20
  • 28
  • 85
  • 90

7
6. Skill 1 Identifying information contained in
bar, line, and circle graphs
  • 1.6 The pie graph at the left represents the
    number of students by age enrolled in college
    algebra for the summer term at a community
    college. What percentage of the students are
    less than 27 years old?
  • 45
  • 55
  • 60
  • 70

8
7. Skill 2 Identifying relationships and making
predictions based on statistical data
  • 2.1 The scatter diagram at the left represents
    the price of a laptop computer versus the number
    sold at a computer store. Which statement best
    summarizes the relationship between price and
    number sold.
  • Higher prices caused fewer laptops to be sold.
  • Higher prices tend to be associated with fewer
    laptops sold.
  • There is no apparent relationship between price
    and number sold.
  • Lower prices cause a higher number of laptops
    sold.

9
8. Skill 2 Identifying relationships and making
predictions based on statistical data
  • 2.2 The scatter diagram at the left represents
    the price of a laptop computer versus the number
    sold at a computer store. Approximately how many
    laptop where sold at the cheapest price (1000)?
  • 20
  • 40
  • 50
  • 60

10
9. Skill 2 Identifying relationships and making
predictions based on statistical data
  • 2.3 The graph at the left depicts the sales
    figures (in thousands) for two competing burger
    chains over a 7 year period from 1995 to 2002.
    Identify which statement is true based on the
    graph.
  • Both burger chains experienced in increase an
    sales over the 7 year period.
  • Yummy Burger spent more on advertisements than
    Big Burger.
  • During the time period between 1995 and 1997
    Yummy Burger sold more burgers than Big Burger.
  • The number of burgers sold by both chains was
    equal in 1999.

11
10. Skill 2 Identifying relationships and
making predictions based on statistical data
  • 2.4 The table at the left contains information
    about the number of videos rented and movie
    attendance at two businesses at a strip mall.
    Which of the following statements describes the
    relationship between the number of videos rented
    and attendance at the movie theater?
  • An increase in the number of movies attended is
    associated with an increase in the number of
    videos rented.
  • Movies are just as good when viewed at home as
    they are at the theater.
  • Its cheaper to rent videos than to go to the
    theater.
  • The increase in videos rented is greater than the
    increase in movie attendance.

12
11. Skill 2 Identifying relationships and
making predictions based on statistical data
  • 2.5 The table at the left presents information
    about the average home price in various U. S.
    cities in 2002 and the percent increase in price
    in 2002. Which of the following statements is
    true, based on the data provided in the table?
  • The city with the highest average home price had
    the largest percent increase in 2002.
  • Houses are cheaper in Atlanta than in Orlando.
  • All average home prices shown increased in 2002.
  • Homes in warmer climates are cheaper.

13
12. Skill 3 Determining the mean, median, and
mode of a set of numbers
  • 3.1 Find the mean, median, and mode of the data
  • 2, 3, 7, 4, 3, 11, 7, 6, 4, 13, 4, 8
  • mean 6 median 5 mode 4
  • mean 5 median 6 mode 4
  • mean 6 median 5 mode 7
  • mean 5 median 6 mode 7

14
13. Skill 3 Determining the mean, median, and
mode of a set of numbers
  • 3.2 Given the following set of numbers, determine
    which statement is true
  • 5, 15, 25, 35, 35, 55, 75
  • The mean is less than the median.
  • The mode is greater than the mean.
  • The mean, median, and mode are equal.
  • The median is greater than the mode.

15
14. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
  • 3.3 The table at the left represents the
    distribution for the number of pets per household
    in a certain neighborhood. What is the mean
    number of pets per household?
  • 0
  • 2.00
  • 2.18
  • 3

16
15. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
  • 3.4 The table at the left represents the
    distribution for the number of pets per household
    in a certain city. What is the median number of
    pets per household?
  • 1
  • 2
  • 3
  • 4

17
16. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
  • 3.5 The table at the left represents the
    distribution for the number of pets per household
    in a certain city. What is the mode number of
    pets per household?
  • 0
  • 1
  • 2
  • 3

18
17. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
  • 3.6 The table at the left represents the
    percentile distribution for employees of a
    national retail chain. What per cent of the
    employees have at least two years off college?
  • 16
  • 25
  • 45
  • 75

19
18. Skill 4 Interpreting real-world data
involving frequency and cumulative frequency
tables
  • 4.1 The table at the left represents the
    percentile distribution for employees of a
    national retail chain. What per cent of the
    employees have more than the high school diploma
    but less than a masters degree?
  • 15
  • 16
  • 45
  • 84

20
19. Skill 5 Recognizing relationships between
the mean, median, and mode in a variety of
distributions
  • 5.1 In a survey of community college students
    half reported they worked 15 hours a week. Equal
    numbers reported working 20 hours a week and 25
    hours a week, while less reported working more
    than 35 hours per week. Select the statement
    that is true about the distribution of numbers of
    hours worked.
  • The median and the mode are the same.
  • The mean is less than the mode.
  • The median is greater than the mode.
  • The mean is less than the median.

21
20. Skill 5 Recognizing relationships between
the mean, median, and mode in a variety of
distributions
  • 5.2 The graph at the left represents the
    distribution of scores in a introductory science
    class. Which of the following statements is true
    about the distribution?
  • The mean and mode are the same.
  • The mode and the mean are the same.
  • The median is less than the mode.
  • The mode is less than the mean.

22
21. Skill 6 Choosing appropriate procedure for
selecting an unbiased sample from a target
population
  • 6.1 Professor Powell wants to survey students at
    a community college to determine whether they
    found the mandatory fall orientations (there were
    several sessions) to be worthwhile. Which of the
    following procedures would be most appropriate
    for selecting a statistically unbiased sample?
  • Ask all English composition instructors to
    administer the survey to their students.
  • Have the research department call and survey the
    first 100 students who attended fall orientation.
  • Post a notice in the cafeteria asking for
    volunteers.
  • Survey 100 students whose names are randomly
    chosen from a list of students attending the fall
    orientation.

23
22. Skill 6 Choosing appropriate procedure for
selecting an unbiased sample from a target
population
  • 6.2 Professor Hakim wants to survey her students
    to determine their opinions of the online
    components she has added to her course. Which of
    the following methods would be most appropriate
    for obtaining an unbiased sample?
  • Survey all students who stop by her office for
    help.
  • Pick names at random from all her class rolls and
    interview those chosen after class.
  • Survey all students in her 800 am class.
  • Mail a survey to all her students with a stamped,
    self-addressed envelope.

24
23. Skill 7 Applying counting rules
  • 7.1 At Samanthas Spa you can get a facial, a
    pedicure, a manicure, or a steam treatment. How
    many different combinations of options are
    available, if at least one treatment is included?
  • 4
  • 8
  • 15
  • 24

25
24. Skill 7 Applying counting rules
  • 7.2 At Samanthas Spa Josie can get a choice of
    four treatments facial, a pedicure, a manicure,
    or a steam treatment. If Josie is going to get
    all four treatments, one after another, in how
    many different orders can she have four
    treatments?
  • 4
  • 16
  • 24
  • 64

26
25. Skill 7 Applying counting rules
  • 7.3 Joaquin must choose three courses from the
    five he needs to graduate this semester. How
    many different combinations of three courses can
    he choose?
  • 5
  • 10
  • 15
  • 20

27
26. Skill 7 Applying counting rules
  • 7.4 The environmental club has 8 students on its
    executive board. In how many ways can a
    president, vice-president, and secretary be
    chosen from this board?
  • 27
  • 336
  • 343
  • 512

28
27. Skill 7 Applying counting rules
  • 7.5 Elizabeth takes 3 pairs of shoes, 4 pairs of
    slacks, and 6 blouses on a weekend trip. How
    many different outfits can she wear, choosing one
    pair of shoes, one blouse, and one pair of
    slacks.
  • 12
  • 24
  • 36
  • 72

29
28. Skill 7 Applying counting rules
  • 7.6 A class of 22 students has 13 women and 9
    men. A panel of 2 men and 2 women is chosen for
    a debate. In how many different ways can the
    panel be chosen?
  • 13 x 13 x 9 x 9
  • 22 x 21 x 20 x 19
  • 13 x 12 x 9 x 8
  • 22 x 22 x 22 x 22

30
29. Skill 8 Determining probabilities
  • 8.1 There are 20 raffle tickets sold for a school
    fundraiser. If Ray bought 3 tickets, what is the
    probability that he will win, assuming all
    tickets have an equal chance of being chosen?
  • 0
  • 3/10
  • 3/20
  • 17/20

31
30. Skill 8 Determining probabilities
  • 8.2 A recent survey indicated that 12 of
    students at a college are registered to vote.
    What is the probability that a student at this
    college chosen at random will not be registered
    to vote?
  • 0
  • .12
  • .50
  • .88

32
31. Skill 8 Determining probabilities
  • 8.3 A survey of homeowners indicated that 55 of
    homeowners had two or more televisions, 20 had
    DVD players, and 60 had cell phones. What is
    the probability that two randomly selected
    homeowners both have a DVD player?
  • .02
  • .04
  • .2
  • .4

33
32. Skill 8 Determining probabilities
  • 8.4 In a survey of students at a community
    college 35 work full-time, and 60 plan to
    continue to a 4-year college after graduation,
    and 20 both work full-time and plan to continue.
    If a student is chosen at random from this
    college, what is the probability that the student
    works full-time or plans to continue to a 4-year
    college after graduation?
  • .35
  • .60
  • .75
  • .95

34
33. Skill 8 Determining probabilities
  • 8.5 Suppose the probability of a certain brand of
    tire wearing out before the guaranteed 40,000
    miles is .10. If you purchase 2 new tires, what
    is the probability that at least one will wear
    out before 40,000 miles?
  • .10
  • .19
  • .20
  • .90

35
34. Skill 8 Determining probabilities
  • 8.6 In a recent election, 25 of eligible voters
    registered to vote, and 30 of those registered
    voted. What is the probability that an eligible
    voter actually registered and voted?
  • .05
  • .075
  • .25
  • .30

36
35. Skill 9 Solving real-world problems using
probabilities
  • 9.1 The table at the left shows the distributions
    of absences of the students who passed
    Professors Kilmers physics class for the fall
    term. If a student who passed his class is
    selected at random, what is the probability that
    student had less than 2 absences?
  • .14
  • .21
  • .26
  • .47

37
36. Skill 9 Solving real-world problems using
probabilities
  • 9.2 The table at the left shows the distributions
    of absences of the students who passed
    Professors Kilmers physics class for the fall
    term. If a student who passed his class is
    selected at random, what is the probability that
    student had more than 1 but less than 5 absences?
  • .29
  • .43
  • .51
  • .53

38
37. Skill 9 Solving real-world problems using
probabilities
  • 9.3 The table at the left shows the distributions
    of absences of the students who pass an advanced
    chemistry course on their first attempt at a
    large university. If two students who passed this
    class are selected at random, what is the
    probability that neither student had more than 3
    absences?
  • .001
  • .01
  • .10
  • .20

39
38. Skill 9 Solving real-world problems using
probabilities
  • 9.4 The table at the left shows the distributions
    of votes in a recent local mayoral election.
    Based on these results, what is the probability
    that a randomly selected voter voted for the
    Libertarian candidate?
  • .01
  • .03
  • .04
  • .05

40
39. Skill 9 Solving real-world problems using
probabilities
  • 9.5 The table at the left shows the distributions
    of all votes in a recent local mayoral election.
    Based on these results, what is the probability
    that a randomly selected voter is female, given
    that the voter voted for the Democratic
    candidate?
  • .2
  • .3
  • .5
  • .6

41
40. Skill 9 Solving real-world problems using
probabilities
  • 9.6 The pie chart at the left represents the
    distribution of beverage choices of students at
    the school cafeteria. If a student who uses the
    cafeteria is randomly chosen, what is the
    probability that the student does not choose
    coffee?
  • .11
  • .22
  • .74
  • .89

42
41. Skill 9 Solving real-world problems using
probabilities
  • 9.7 The pie chart at the left represents the
    distribution of beverage choices of students at
    the school cafeteria. If a student who uses the
    cafeteria is randomly chosen, what is the
    probability that the student chooses either soda
    or diet soda?
  • .22
  • .52
  • .74
  • .89

43
42. Skill 9 Solving real-world problems using
probabilities
  • 9.8 For a certain variety of citrus trees sold
    at a nursery, 90 are guaranteed to bear fruit
    within the first five years. Of the trees that
    bear fruit, 20 will be tangerines, 40 will be
    oranges and the rest will be grapefruit. If one
    of these trees is selected at random from the
    nursery, what is the probability that the tree
    will bear fruit within five years and be a
    tangerine tree?
  • .18
  • .20
  • .36
  • .54

44
End of Test

45
1. Correct Answer!
Return to previous slide

The solution is D, 63 students. 5 males and 9
females made A, 8 males and10 females made B,
12 males and 12 females made C, 3 males and 2
females made D,, and 1 male and 1 female made
F.
46
2. Correct Answer!
Return to previous slide

The solution is D, 9 inches. In April it rained
15 inches and in May it rained 6 inches. The
difference is 15 6 9 inches.
47
3. Correct Answer!
Return to previous slide

The correct answer is C, 330 people. 40 chose
beef and 15 chose chicken, for a total of 55.
55 of 600 people is .55 X 600 330.
48
4. Correct Answer!
Return to previous slide

The correct answer is A, the first quarter. The
distance between the dark blue and light blue
bars are the greatest for this quarter.
49
5. Correct Answer!
Return to previous slide

The correct answer is D, 90 cars each day. It
is the highest point on the graph over the month
of August, and it lies half-way between 80 and
100.
50
6. Correct Answer!
Return to previous slide

The correct answer is D, 70. The total number
of students is 2000. The total number of
students from 17 to 26 is 7506501400.
1400/2000.70 or 70.
51
7. Correct Answer!
Return to previous slide

The correct answer is B. The graph indicates
that more computers are sold at lower prices, and
fewer computers are sold at higher prices. Thus
C is incorrect. Answers A and D incorrectly
infer a cause and effect relationship between
price and number sold which cannot be proven.
52
8. Correct Answer!
Return to previous slide

The correct answer is D, 60 laptops sold at
1,000
53
9. Correct Answer!
Return to previous slide

The correct answer is D. Each dot on the lines
represents a year, starting with 1999. The lines
cross at the 5th dot from the left, which
represents 1999. Big Burger experienced a
decrease in sales. Big Burger sold more between
1995 and 1997. We know nothing about advertising
for either chain.
54
10. Correct Answer!
Return to previous slide

The correct answer is D. From 2.4 to 13.1 is
greater than from 3.3 to 6.0. The other
statements may be true but the information in the
table does not support them
55
11. Correct Answer!
Return to previous slide

The correct answer is C. Boston had the highest
average home price, but San Diego had the highest
price increase. The average home price is higher
in Atlanta than in Orlando. Salem, Oregon, had
the cheapest average home price and it is not in
a warm climate.
56
12. Correct Answer!
Return to previous slide

The correct answer is A. When the data is
arranged in ascending order, we
have 2,3,3,4,4,4,6,7,7,8,11,13 The mean is
the sum of the numbers divided by 12 or 72
divided by 12, which equals 6. The median is
the average of the 6th and 7th number in the list
above, or (46)/25. The mode is the number
that occurs most frequently, which is 4.
57
13. Correct Answer!
Return to previous slide

The correct answer is C. The mean is the sum
of the numbers divided by 7, or 245 divided by 7,
which equals 35. When the numbers are arranged
in ascending order, 5, 15, 25, 35, 35, 55, 75,
the median is the middle most number, which is
35. The mode is the most frequently occurring
number, which is 35.
58
14. Correct Answer!
Return to previous slide

The correct answer is C, mean 2.18. The
mean is given by the sum of the products of
values times proportion Mean
0(.20)1(.12)2(.23) 3(.10)4(.08)5(.04)6(.03)
2.18
59
15. Correct Answer!
Return to previous slide

The correct answer is B, median 2. The middle
of the distribution is at the .50 or 50 mark.
If we add .20 for 0 pets, .12 for 1 pet, and .23
for 2 pets, .20 .12 .23 .55, we see that
the .50 mark lies at 2 pets.
60
16. Correct Answer!
Return to previous slide

The correct answer is D, mode 3. The mode is
the value that occurs most frequently in the
distribution. This is the value with the largest
proportion, .30, in this distribution.
61
17. Correct Answer!
Return to previous slide

The correct answer is B, 25. Since two years of
college has a percentile rank of 75, this means
that 75 of the employees do not have two years
of college, and 100 75 25 do have two years
or more of college. Percentile rankings refer to
the percentage of scores below a particular value.
62
18. Correct Answer!
Return to previous slide

The correct answer is C, 45. Since high school
graduate has a percentile rank of 45, 45 of the
employees have less than a high school diploma.
Since the masters degree has a 90 percentile
rank, 90 of the employees have less than a
masters degree. The difference, 90 45 45,
is the per cent who have more than a high school
degree but less than a masters.
63
19. Correct Answer!
Return to previous slide

The correct answer is C. Since exactly half of
the students reported working 15 hours per week,
15 is the mode. To compute the mean, we would
have half the numbers equal 15 and half greater
than 15, including equal numbers of 20s and
25s, and a few 35s. Thus the mean would be
larger than 15, and the mean is larger than the
mode. The median is 17.5, the average of 15, the
value of the bottom half, and 20, the next
largest value. Thus the median is greater than
the mode, but smaller than the mean. Thus C is
the correct answer.
64
20. Correct Answer!
Return to previous slide

The correct answer is D. The mode is the tallest
column, which is a 2. The median is also a 2,
since there are 17 units of scores, and the 8th
through 13th are 2s, counting from the left.
The mean will be greater than 2, since there are
more 3s than 1s and there are also 4s to
average in with the column of 2s. Thus the mean
is greater than the mode and the median, which
are equal to each other.
65
21. Correct Answer!
Return to previous slide

The correct answer is D. Method A is not from
the target audience. Not all students in these
classes attended fall registration. Method B
is not random because the first 100 may have a
different experience from those who attended
later. Method C is not random because
volunteers can produce a biased samplethose with
a particular reason for responding. Method D
selects a random sample from the target
population (those who attended fall orientation).
66
22. Correct Answer!
Return to previous slide

The correct solution is B. Method A is not
random. Only students with the time and interest
to stop by her office will be surveyed. This is
not an unbiased sample. Method B is a random
sample from her target populationall of her
students. Method C is not random. The
experiences of one class does not represent an
unbiased sample of all her students. Method D
allows students to self-select. Only those with
an interest will respond, not an unbiased sample.
67
23. Correct Answer!
Return to previous slide

The correct answer is C, 15. There is 1
choice of all 4 treatments, 4 choices of 3
treatments, 6 choices of 2 treatments, and 4
choices of 1 treatment. The sum of all these
possibilities is 1 4 6 4 15.
68
24. Correct Answer!
Return to previous slide

The correct answer is C, 24 different orders.
Using the Fundamental Counting Principle, there
are 4 choices for the first treatment, 3 choices
for the second treatment, 2 choices for the third
treatment, and 1 choice left for the four
treatment. Thus the number of possible orders,
or permutations, is 4 x 3 x 2 x 1 24 possible
orders.
69
25. Correct Answer!
Return to previous slide

The correct answer is B, 10 combinations. We
can list the possibilities If A, B, C, D, and
E, represent the five courses, all possible
combinations with 3 are all 3-course groups
containing A (ABC, ABD, ABE, ACD, ACE, ADE) all
3-course groups with B but no A (BCA, BCE, BDE)
the remaining 3-course group with out A or B
(CDE). You may also use the combination formula
for nCr, with n 5, r 3. nCr
70
26. Correct Answer!
Return to previous slide

The correct answer is B, 336. Using the
Fundamental Counting Principle, there are 8
choices for the president, 7 choices left for the
vice-president, and 6 choices left for the
secretary. Thus there are 8 x 7 x 6 336
ways to chose the three offices. Note a
permutation (8P3) would work too as order matters
with specific office titles.
71
27. Correct Answer!
Return to previous slide

The correct answer is D, 72 outfits. Using the
Fundamental Counting Principle, there are 3
choices for shoes, 4 choices for slacks, and 6
choices for blouses. The possible number of
outcomes is 3 x 4 x 6 72.
72
28. Correct Answer!
Return to previous slide

The correct answer is C, 13 x 12 x 9 x 8. The
number of ways to choose two women, using the
Fundamental Counting Principle, is 13 x 12. The
number of ways to choose two men is 9 x 8. The
number of ways to choose two women, then choose
two men is (13 x 2) x (9 x 8) 13 x 12 x 9 x 8
73
29. Correct Answer!
Return to previous slide

The correct answer is C, 3/20. The probability
of success is (number of tickets sold to the
person) divided by (total number of tickets
sold). The correct answer is 3 divided by 20 or
3/20.
74
30. Correct Answer!
Return to previous slide

The correct answer is D, .88. Since 12 of the
students were registered to vote, the probability
that a randomly selected student is registered is
12/100 or .12, and the probability that a
randomly selected student is not registered is 1
- .12 .88. Alternatively, 100 - 12 88 or
.88.
75
31. Correct Answer!
Return to previous slide

The correct answer is B, .04. We use the
formula P(A and B) P(A) x P(B, given A), where
A and B are the event homeowner has a DVD.
P(A) 20 .2 Since the homeowners are
selected independently, P(B, given A) P(B)
20 .2 Thus P(Both have DVDs) P(A and B)
P(A) x P(B) .2 x .2 .04 Note that both
means and which means to multiply.
76
32. Correct Answer!
Return to previous slide

The correct answer is C, .75. We use the
formula that P(A or B) P(A) P(B) P(A and
B) Where A works full-time B plans to
continue A and B works full-time and plans to
continue P(A) 35 .35 P(B) 60 .60 P(A
and B) 20 .20 Thus P(A or B) .35 .60 -
.20 .75
77
33. Correct Answer!
Return to previous slide

The correct answer is B, .19. Let A 1st tire
will not wear out, B 2nd tire will not wear
out. The probability that at least one will wear
out is 1 (the probability that neither will
wear out) 1 P(A and B) 1 P(A) x P(B)
1 .9 x .9 1 - .81 .19
78
34. Correct Answer!
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The correct answer is B, .075. We use the rule
P(A and B) P(A) x P(B, given A), where A
eligible voter B registered to vote P(A
and B) the probability an eligible voter
voted P(A) 25 .25 P(B, given A) 30
.30 Thus P(A and B) .25 x .30 .075
79
35. Correct Answer!
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The correct answer is D, .47. A student with
less than 2 absences has 0 absences or 1 absence.
The sum of the per cent of students with 0 or
1 absence is 26 21 47. Converting this to
probability, 47 .47
80
36. Correct Answer!
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The correct answer is C, .51. The sum of the
percentages for students who missed 2, 3, or 4
absences is 14 29 8 51 or .51
81
37. Correct Answer!
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The correct answer is B, .01. The probability
of one student randomly selected having more than
3 absences is 8 2 10 .10. Since it is a
large university, we can assume the events are
independent. Thus the probability of two
students randomly selected both having more than
3 absences is the product of the probabilities,
(.10)x(.10) .01
82
38. Correct Answer!
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The correct answer is D, .05, since 3 (males)
and 2 (females) of all voters voted Libertarian,
and 3 2 5 .05
83
39. Correct Answer!
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The correct answer is D, .6. Since the voter
voted for the Democratic candidate, we use the
percentages from column one only. The
probability of a randomly selected candidate from
column one being female is (favorable female
democrat) divided by (total all democrats)
or (30)/ (30 20) or 30/50 .6
84
40. Correct Answer!
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The correct solution is D, .89. The
probability that the student does not choose
coffee is 1 the probability that s/he does
choose coffee, which is 1 - .11 .89
85
41. Correct Answer!
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The correct solution is C, .74. The
probability that the student chooses either soda
or diet soda is the sum of the probabilities for
these two events, since they are mutually
exclusive events. Thus, P( soda or diet soda)
P(soda) P(diet soda) .52 .22 .74
(Note or means add.)
86
42. Correct Answer!
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The correct answer is A, .18. The probability
of a randomly selected tree bearing fruit and
being a tangerine tree is the product of the
probabilities of each, P(bear fruit and
tangerine) P(bear fruit) x P( tangerine,
given bears fruit) .9 x . 2 .18
87
Incorrect.
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