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TELECOMMUNICATIONS

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... 90o lead and -j = 90o lag. Complex Number Definitions. Rectangular Coordinate ... A - B = (2 1) j(1 ( 2)) = 1 j3. For vector multiplication use polar form. ... – PowerPoint PPT presentation

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Title: TELECOMMUNICATIONS


1
TELECOMMUNICATIONS
  • Dr. Hugh Blanton
  • ENTC 4307/ENTC 5307

2
Complex Numbers
3
Complex numbers
ARGAND diagram
  • M A jB
  • Where j2 -1 or j v-1
  • M v(A2 B2)
  • and tan ? B/A

Imaginary
B
M
?
A
Real
4
j notation
  • Refers to the expression
  • Z R jX
  • X is not imaginary
  • Physically the j term refers to
  • j 90o lead and -j 90o lag

5
Complex Number Definitions
  • Rectangular Coordinate System
  • Real (x) and Imaginary (y) components, A x jy
  • Complex Conjugate (A?A) refers to the same real
    part but the negative of the imaginary part.
  • If A x jy, then A x ? jy.

jy
2
1
?x
x
1
2
?1
?2
?jy
6
Complex Number Definitions
  • Polar Coordinates Magnitude and Angle
  • Complex conjugate has the same magnitude but the
    negative of the angle.
  • If A M?90?, then AM?-90?

7
  • Rectangular to Polar Conversion
  • By trigonometry, the phase angle q is,
  • Polar to Rectangular Conversion
  • y imaginary part M(sin q)
  • x real part M(cos q)

8
jy
2
1
x
1
2
?1
?2
?jy
9
Vector Addition Subtraction
  • Vector addition and subtraction of complex
    numbers are conveniently done in the rectangular
    coordinate system, by adding or subtracting their
    corresponding real and imaginary parts.
  • If A 2 j1 and B 1 j2
  • Then their sum is
  • A B (21) j(1 2) 3 j1
  • and the difference is
  • A - B (2 ? 1) j(1 ?( 2)) 1 j3

10
  • For vector multiplication use polar form.
  • The magnitudes (MA,MB) are multiplied together
    while the angles (q) are added.
  • MuItiplying A and B
  • AB (2.24 ?26.60?)(2.24 ??63.40?)
  • 5 ??36.8 ?

11
  • Vector division requires the ratio of magnitudes
    and the differences of the angles

12
jy
A-B
2
1
x
?1
?2
1
2
?1
AB
?2
?jy
13
Complex Impedance System
inductive
  • RF components are frequently defined by their
    terminal impedances or admittances in the complex
    rectangular coordinate system.
  • Complex impedance is the vector sum of resistance
    and reactance.
  • Impedance Resistance j Reactance

jX
?R
R
?jX
capacitive
14
  • Series connections are handled most conveniently
    in the impedance system.

?
15
Complex Admittance System
  • Parallel circuit descriptions may be viewed in
    the complex admittance system
  • Complex impedance is the vector sum of
    conductance and susceptance.
  • Admittance Conductance j Susceptance
  • where and

capacitive
jB
?G
G
?jB
inductive
16
  • Parallel connections are handled most
    conveniently in the admittance system.

17
Z dependence on ??(RCL )
Impedance
1000
500
series
100
50
parallel
?o
10
5
frequency
1
1
2
5
10.
20.
50.
100.
18
Currrent dependence on ??
Current (ma)
1000
parallel
??o
500
Imaxxv2
series
Imin
100
frequency
1
2
5
10.
20.
50.
100.
?o
19
  • At RF, particularly at high power levels, it is
    very important to maximize power transfer through
    careful impedance matching.
  • Improperly matched component connection leads to
    mismatch loss.

20
RF Components Related Issues
  • Unique component problems at RF
  • Parasitics change behavior
  • Primary and secondary resonances
  • Distributed vs. lumped models
  • Limited range of practical values
  • Tolerance effects
  • Measurements and test fixtures
  • Grounding and coupling effects
  • PC-board effects

21
V and I Phase relationships
22
R, XC and Z relationships
XL
Z
XL-XC
?
I
R
XC
23
Example 1
  • Consider this circuit with ? 105 rad s-1

1 k?
0.01 ?F
24
Example 2
20 ?
10 ?
10 ?
5 ?
25
Example 2 Contd
200 V
20 ?
10 ?
10 ?
5 ?

26
Example 2 Contd
VL
XL
VR
R
?
VL-VC
?
XL-XC
I
I
VS
Z
VC
XC
Z 15 - 10j
I 8/13(15 10j)
27
General procedures
  • convert all reactances to ohms
  • express impedance in j notation
  • determine Z using absolute value
  • determine I using complex conjugate
  • draw phasor diagram
  • Note j -1/j so
  • R (1/j?C) R - j/?C

28
Example 3
10 ?
20 ?
15 ?
5 ?
- express the impedance in j notation - determine
Z (in ?s) and ? - determine I for a voltage of 24V
29
Example 3 Contd
10 ?
20 ?
5 ?
5 ?
30
Example 3 Contd
24V
20 ?
10 ?
10 ?
5 ?

31
Example 4
  • Construct a circuit which contains at least one L
    and one C components which could be represented
    by
  • Z 10 - 30j

32
Parallel circuits

10 - 30j
20 - 10j

33
Parallel circuits

20 - 30j
20 - 30j
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