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Physics 106P: Lecture 15 Notes

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Physics 211: Lecture 27, Pg 1. Electric Christmas tree. lights were first used. in what year? ... Movie (super) will add constructively. will add destructively ... – PowerPoint PPT presentation

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Title: Physics 106P: Lecture 15 Notes


1
Electric Christmas tree lights were first used
in what year?a. 1925b. 1897c. 1882d. 1939
2
Physics 211 Lecture 27Todays Agenda
  • Wave power
  • Flow of energy
  • Superposition Interference
  • The wave equation

3
Lecture 27, Act 1Wave Motion
  • A boat is moored in a fixed location, and waves
    make it move up and down. If the spacing between
    wave crests is 20 meters and the speed of the
    waves is 5 m/s, how long Dt does it take the boat
    to go from the top of a crest to the bottom of a
    trough?

(a) 2 sec (b) 4 sec (c) 8 sec
t
t Dt
4
Lecture 27, Act 1 Solution
  • We know that v l / T, hence T l / v
  • In this case l 20 m and v 5 m/s, so T 4
    sec
  • The time to go from a crest to a trough is T/2
    (half a period)

So Dt 2 sec
t
t Dt
5
Wave Power
  • A wave propagates because each part of the medium
    communicates its motion to adjacent parts.
  • Energy is transferred since work is done!
  • How much energy is moving down the string per
    unit time.
  • (i.e. how much power?)

P
6
Wave Power...
Slinky
  • Think about grabbing the left side of the string
    and pulling it up and down in the y direction.
  • You are clearly doing work since F.dr gt 0 as your
    hand moves up and down.
  • This energy must be moving away from your hand
    (to the right) since the kinetic energy (motion)
    of the string stays the same.

P
Movie (pump)
7
How is the energy moving?
  • Consider any position x on the string. The
    string to the left of x does work on the string
    to the right of x, just as your hand did

x
?
x
8
Power along the string
  • Since v is along the y axis only, to evaluate
    Power F.v we only need to find Fy -F sin ? ?
    -F ? if ? is small.
  • We can easily figure out both the velocity v and
    the angle ? at any point on the string
  • If

y
?
x
Fy
F
v
dy
?
dx
Recall sin ? ? ? cos ? ? 1
for small ?
tan ? ? ?
9
Power...
  • So
  • But last time we showed that and

10
Average Power
  • We just found that the power flowing past
    location x on the string at time t is given by
  • We are often just interested in the average power
    movingdown the string. To find this we recall
    that the averagevalue of the function sin2 (kx -
    ?t) is 1/2 and find that
  • It is generally true that wave power is
    proportional to thespeed of the wave v and its
    amplitude squared A2.

11
Energy of the Wave
  • We have shown that energy flows along the
    string.
  • The source of this energy (in our picture) is the
    hand that is shaking the string up and down at
    one end.
  • Each segment of string transfers energy to (does
    work on) the next segment by pulling on it, just
    like the hand.

12
Power Example
  • A rope with a mass of ? 0.2 kg/m lays on a
    frictionless floor. You grab one end and shake
    it from side to side twice per second with an
    amplitude of 0.15 m. You notice that the
    distance between adjacent crests on the wave you
    make is 0.75 m.
  • What is the average power you are providing the
    rope?
  • What is the average energy per unit length of the
    rope?
  • What is the tension in the rope?

f 2 Hz
? 0.75 m
A 0.15 m
13
Power Example...
  • We know A, ? and ? 2?f. We need to find v!
  • Recall v ?f (.75 m)(2 s-1) 1.5 m/s .
  • So

Average power
14
Power Example...
  • So

Average energy per unit length
15
Power Example...
  • We also know that the tension in the rope is
    related to speed of the wave and the mass
    density

Tension in rope F 0.45 N
16
Recap Useful Formulas
y
?
A
x
  • Waves on a string
  • General harmonic waves

tension
mass / length
17
Lecture 27, Act 2Wave Power
  • A wave propagates on a string. If both the
    amplitude and the wavelength are doubled, by what
    factor will the average power carried by the wave
    change? (The velocity of the wave is unchanged).

(a) 1 (b) 2 (c) 4
18
Lecture 27, Act 2 Solution
  • We have shown that the average power

So
19
Lecture 27, Act 2 Solution
  • But since v lf lw / 2p is constant,

i.e. doubling the wavelength halves the frequency.
Pi
Pf
20
Lecture 27, Act 2 Solution
So
same power
21
Superposition
Shive model
  • Q What happens when two waves collide?
  • A They ADD together!
  • We say the waves are superposed.

Movie (super_pulse)
Movie (super_pulse2)
22
Aside Why superposition works
  • As we will see shortly, the equation governing
    waves (a.k.a. the wave equation) is linear.
  • It has no terms where variables are squared.
  • For linear equations, if we have two (or more)
    separate solutions, f1 and f2 , then Bf1 Cf2 is
    also a solution!
  • You have already seen this in the case of simple
    harmonic motion

linear in x!
x B sin(?t) C cos(?t)
23
Superposition Interference
Bead model
  • We have seen that when colliding waves combine
    (add) the result can either be bigger or smaller
    than the original waves.
  • We say the waves add constructively or
    destructively depending on the relative sign of
    each wave.
  • In general, we will have both happening

Movie (super)
24
Superposition Interference
  • Consider two harmonic waves A and B meeting at
    x0.
  • Same amplitudes, but ?2 1.15 x ?1.
  • The displacement versus time for each is shown
    below

A(?1t)
B(?2t)
What does C(t) A(t) B(t) look like??
25
Superposition Interference
  • Consider two harmonic waves A and B meeting at x
    0.
  • Same amplitudes, but ?2 1.15 x ?1.
  • The displacement versus time for each is shown
    below

A(?1t)
B(?2t)
C(t) A(t) B(t)
26
Beats
Sound generator
  • Can we predict this pattern mathematically?
  • Of course!
  • Just add two cosines and remember the identity

where
and
cos(?Lt)
27
The Wave Equation
  • Harmonic waves have the form y(x,t) A cos(kx -
    ?t).
  • In general, a wave traveling to the right with
    velocity v is given by y(x,t) f(x - vt)
  • How do we know a wave of this form really
    satisfies Newtons 2nd Law??
  • We will now prove this is the case.

where
28
The Wave Equation...
  • Suppose we have the plucked string shown below
  • The displacement is greatly exaggerated in the
    picture...?1 and ?2 are both close to 0.

F
dm
?2
?1
y
F
x
29
The Wave Equation...
sin ? ? ? cos ? ? 1 for small ? tan ? ?
?
  • ?FX F cos(?2) ? F cos(?1) 0 (no net force
    in x direction)
  • But ?FY F sin(?2) ? F sin(?1) ? F(?2 - ?1) Fd?

F
y
dm
?2
?1
F
dx
x
30
The Wave Equation...
  • So ?FY F

?FY
  • Use

and
dx
31
Finally
  • The is called the Wave Equation
  • Any time the analysis of a physical system leads
    to an equation of this form, that system supports
    waves propagating with speed v.
  • y f(x - vt) is a solution of the above, see
    Tipler chapter 15.

32
Recap of todays lecture
  • Wave power and intensity
  • Superposition
  • Interference
  • The Wave Equation
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