Continuous time formalism - PowerPoint PPT Presentation

1 / 15
About This Presentation
Title:

Continuous time formalism

Description:

Continuous time formalism. Exhaustible Problem. Max (e-rt p(t) h(t)) s.t. dx/dt = -h ... Since x 0 it can't be that h=inf for any measurable length of time. ... – PowerPoint PPT presentation

Number of Views:55
Avg rating:3.0/5.0
Slides: 16
Provided by: Peter5
Category:

less

Transcript and Presenter's Notes

Title: Continuous time formalism


1
Continuous time formalism
2
Exhaustible Problem
  • Max ? (e-rt p(t) h(t)) s.t. dx/dt -h
  • Hamiltonian
  • Objective function multiplier rhs of diffeq.
  • H e-rt p(t) h(t) l h

3
Rules
4
Exhaustible Resource
5
  • Since x gt0 it cant be that hinf for any
    measurable length of time.
  • If h0 forever then x doesnt go to zero, so by
    transverality l must 0, and by costate it is
    always zero, which cant be greater than or equal
    to pe-rt unless p is zero.
  • It must be that at least for long enough to
    exhaust h any and l pe-rt

6
  • During the time h any, l e-rtp
  • By costate -re-rtp e-rt dp/dt 0
  • Or dp/dt rp
  • Which is Hotellings rule.

7
Plausibility for costate
  • Let length of time between periods be n. We will
    make n small and see what happens to costate
    equation in discrete time problem.

8
Steady State Fish
  • State equationhold constant for n seconds
  • xtn xt f(xt)n - htn.
  • U(x,h) St (1r)-t pt ht n
  • here take p as constant
  • L(x,h,l) St (1r)-t pt ht n
  • St lt (xt f(xt)n - htn
    -xt1n)
  • Lx lt(1f(xt)n ) - lt-1n0

9
  • lt(1f(xt)n ) - lt-n0
  • lt - lt-n - ltf(xt)n
  • Limn-gt0 (lt - lt-n)/n - ltf(xt)
  • dl/dt-lf
  • Hamiltonian H pe-rth l(f(x)-h)
  • dH/dx - lf dl/dt Costate equation!

10
Finish Fish
  • H pe-rth l(f(x)-h)
  • restrict h to hmin, hmax
  • maxh H implies
  • pe-rt l 0 and h any
  • pe-rt l lt 0 and h hmin
  • pe-rt l gt 0 and h hmax

11
Exceptional Control
  • Suppose pe-rt l 0 and h any
  • hence -r pe-rt dl/dt 0
  • hence -r pe-rt lf 0
  • hence -r l lf
  • hence r f(x)
  • So the only way to have an interval with h not at
    hmin or hmax is for x to be x.

12
  • Suppose that x(0) is gt x.
  • Set h hmax until x x is an optimal control
  • x above x means that f(x) lt f(x) so
  • dl/dt gt - lr
  • when x x, pe-rt l
  • so l falls slower than pe-rt it must have started
    below it, which is what is needed for hhmax

13
  • Optional At home finish this upshow what
    happens if x(0) lt x, a moratorium. Also show
    that once one gets to x it is indeed optimal to
    stay there. (h f(x) so dx/dt 0.

14
  • Note that the moratorium is a function of the
    linearity of the problem in h.
  • Alternative-- monopoly max ? (p(h)h e-rt)
  • Try with p h-a and compare competition and
    monopoly
  • Competition for renewable resource. Berck Jeem
    1981

15
Competition Sketch
  • max int( p(t)h(t)e-rt s.t. dx/dt f(x) h
  • H p(t)h(t)e-rt l(f(x) h)
  • Costate
Write a Comment
User Comments (0)
About PowerShow.com