ENGR 112

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ENGR 112

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Aids in the decision making process when alternatives are compared ... Susan Cardinal deposited $500 in her savings account and six years later the ... – PowerPoint PPT presentation

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Title: ENGR 112


1
ENGR 112
  • Economic Analysis

2
Engineering Economic Analysis
  • Evaluates the monetary aspects of the products,
    projects, and processes that engineers design
  • Aids in the decision making process when
    alternatives are compared
  • Especially useful when resources are limited
  • Replace vs. keep
  • Build vs. buy

3
Time Value of Money
  • 1 today is more valuable than 1 a year later
  • Engineering economy adjusts for the time value of
    money to balance current and future revenues and
    cost

0
5
10
Years
4
Capital vs. Interest
  • Capital
  • Invested money and resources
  • Whoever owns it should expect a return from
    whoever uses it
  • Bank lends you money
  • Buy a car
  • Go to college
  • Firm invests in a project
  • Buy equipment
  • Buy knowledge

5
Capital vs. Interest
  • Interest
  • Return on capital
  • Typically expressed as an interest rate for a
    year
  • Interest rates are needed to evaluate engineering
    projects!!

6
Interest-ing Example
  • The engineering group of Baker Designs must
    decide whether to spend 90K (K for thousands) on
    a new project. This project will cost 5K per
    year for operations, and it will increase
    revenues by 20K annually. Both the costs and
    the revenues will continue for 10 years. Should
    the project be done?

Eschenbach, T.G., Engineering Economy Applying
Theory to Practice, Irwin, 1995, p.22
7
Types of Interest
  • Nomenclature
  • P Initial deposit (or principal)
  • N Number of years
  • i Interest rate per year
  • F Future value after N years

8
Types of Interest
  • Simple Interest
  • The interest calculated for N periods is based on
    the initial deposit

F0 P F1 P Pi P(1 i) F2 P Pi
Pi P (1 i i) P (1 2i) Fn P
Pi Pi P (1 i i ) P (1 Ni)
9
Types of Interest
  • Compound Interest
  • Interest type used in engineering economic
    evaluations
  • Interest is computed on the current balance that
    has not yet been paid
  • Includes accrued interest

F0 P F1 P Pi P (1 i) F2 P1 P1 i
P1 (1i) P (1i) (1i) P (1i)2 Fn
Pn-1 Pn-1 i Pn-1 (1i) P (1i)n-1
(1i) P (1i)n
10
Simple vs. Compound Interest
  • If 100 is deposited in a savings account, how
    much is in the account at the end of each year
    for 20 years, if interest is deposited in the
    account and no withdrawals are made? Assume a 5
    interest per year.

11
Simple vs. Compound Interest
Compound
Simple
12
In Class Problem 1
  • If 500 is deposited in a savings account, would
    a 5 simple interest rate be better than a 3
    compound interest rate if you were planning to
    keep the money for 3 years? For 35 years?
    Assume that all earned interest is deposited in
    the account and no withdrawals are made.

13
Example 1
  • Sam Bostro borrows 4000 from his parents for his
    final year of college. He agrees to repay it 3
    years later in one payment to which a 7 compound
    interest rate will be applied.
  • a) How much does he repay?
  • F (4000)(1 0.07)3 4,900.17
  • b) How much of this is interest and how much is
    principal?
  • F P I ? P 4,000 I 900.17

14
Example 2
  • Susan Cardinal deposited 500 in her savings
    account and six years later the account has 600
    in it. What compound rate of interest has Susan
    earned on her capital?
  • F P(1i)n ? i F/P1/n 1
  • i 600/500 1/6 1 .031
  • i 3.1

15
In Class Problem 2
  • Your friend is willing to loan you 1500 to buy a
    new computer, but you must agree to pay him back
    2500 when you graduate in 4 years? What is the
    compound interest rate you will be paying your
    friend?

16
Cash Flow Diagrams
  • Pictorial description of when and how much money
    is spent or received
  • Summarizes the economic aspects of an engineering
    project

17
Cash Flow Categories
  • First Cost
  • Expense to build or to buy and install
  • Operation and maintenance (OM)
  • Annual expenses (electricity, labor, minor
    repairs, etc.)
  • Salvage value
  • Receipt at project termination for sale or
    transfer of equipment
  • There can also be a salvage COST

18
Cash Flow Categories
  • Revenues
  • Annual receipts due to sale of products or
    services
  • Overhauls
  • Major capital expenditures that occurs part way
    through the life of the asset
  • Prepaid expenses
  • Annual expenses that must be paid in advance
    (e.g., leases, insurance)

19
Examples
  • Ernies Earthmoving is considering the purchase
    of a piece of heavy equipment. What is the cash
    flow diagram if the following cash flows are
    anticipated?
  • First cost 120K
  • OM cost 30k per year
  • Overhaul cost 35K in year 3
  • Salvage value 40K after 5 years
  • How would the cash flow diagram change if Ernie
    decides to lease the equipment (at 25K per year)
    instead of purchasing it?

a)
b)
20
Solution
40K
a)
30K
30K
30K
30K
30K 35K
120K
b)
25K
30K
25 30K
25 30K
25K 30K
25K 30K 35K
21
Frequency of Compounding
  • Interest rates are typically specified on an
    annual basis
  • However, interest is often compounded more often
  • Semiannually
  • Quarterly
  • Monthly
  • Daily

22
Frequency of Compounding
  • How does that change our formula?
  • m of compounding periods per year
  • n of compounding periods
  • n m x N
  • Quarterly? ?
  • Monthly? ?

m 4 n 4N ? F P(1i/m)mN P(1i/4)4N
m12 n 12N ? F P(1i/12)12N
23
Example
  • Suppose you borrow 3000 at the beginning of your
    senior year to meet college expenses. If you make
    no payments for 10 years and then repay the
    entire amount of the loan, including accumulated
    interest, how much money will you owe? Assume
    interest is 6 per year, compounded
  • Annually m1 P3,000
  • Quarterly m4 N10 years
  • Monthly m12 i6 per year
  • Daily m365
  • How significant is the frequency of compounding?

24
Solution
  • FA P(1i/1)1N 3000(10.06/1)10 5,372.54
  • FQ P(1i/4)4N 3000(10.06/4)40 5,442.05
  • FM P(1i/12)12N 3000(10.06/12)120
    5,458.19
  • FD P(1i/365)1N 3000(10.06/365)3650
    5,466.08

25
Solution
26
In Class Problem 3
  • You need to borrow 500 to pay for the text books
    you will need for your sophomore level courses.
    Which is the better loan assuming that you will
    pay the entire loan amount plus interest when you
    graduate in 3 years?
  • 3.0 compounded annually
  • 2.5 compounded quarterly
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