Title: Ch 15 Kinetics: The Study of Reaction Rates
1Ch 15 Kinetics The Study of Reaction Rates
2Chapter 15 Kinetics
- The speed with which the reactants disappear and
the products form is called the rate of the
reaction - A study of the rate of reaction can give detailed
information about how reactants change into
products - The series of individual steps that add up to the
overall observed reaction is called the reaction
mechanism
3- There are five principle factors that influence
reaction rates - Chemical nature of the reactants
- Ability of the reactants to come in contact with
each other - Concentration of the reactants
- Temperature
- Availability of of rate-accelerating agents
called catalysts
4- Chemical nature of the reactants
- Bonds break and form during reactions
- The most fundamental difference in reaction rates
lie in the reactants themselves - Some reactions are fast by nature and others slow
- Ability of the reactants to meet
- Most reactions require that particles (atoms,
molecules, or ions) collide before the reaction
can occur - This depends on the phase of the reactants
5- In a homogeneous reaction the reactants are in
the same phase - For example both reactants in the gas (vapor)
phase - In a heterogeneous reaction the reactants are in
different phases - For example one reactant in the liquid and the
second in the solid phase - In heterogeneous reactions the reactants meet
only at the intersection between the phases - Thus the area of contact between the phases
determines the rate of the reaction
6Effect of crushing a solid. When a single solid
is subdivided into much smaller pieces, the total
surface area on all of the pieces becomes very
large.
7- Concentration of the reactants
- Both homogeneous and heterogeneous reaction rates
are affected by reactant concentration - For example, red hot steel wool bursts into
flames in the presence of pure oxygen - Temperature of the system
- The rates for almost all chemical reactions
increase as the temperature is increased - Cold-blooded creatures, such as insects and
reptiles, become sluggish at lower temperatures
as their metabolism slows down
8- Presence of a catalyst
- A catalysts is a substance that increases the
rate of a chemical reaction without being
consumed - Enzymes are biological catalysts that direct our
body chemistry - A rate is always expressed as a ratio
- One way to describe a reaction rate is to select
one component of the reaction and describe the
change in concentration per unit of time
9- Molarity (mol/L) is normally the concentration
unit and the second (s) is the most often used
unit of time - Typically, the reaction rate has the units
10- By convention, reaction rates are reported as a
positive number even when the monitored species
concentration decreases with time - If the rate is known with respect to one species,
the coefficients of the balanced chemical
equation can be used to find the rates with
respect to the other species
11- Consider the combustion of propane
- Compared to the rate with respect to propane
- Rate with respect to oxygen is five times faster
- Rate with respect to carbon dioxide is three
times faster - Rate with respect to water is four times faster
- Since the rates are all related any may be
monitored to determine the reaction rate
12Learning Check
- In the reaction 2A 3B ?5D We measured the rate
of disappearance of substance A to be
3.510-5M/s. What is the rate of appearance of
D? - In the reaction 3A 2B ?C, we measured the rate
of B. How does the rate of C relate?
8.7510-5 M/s
Rate of C1/2 rate of B
13- A reaction rate is generally not constant
throughout the reaction - Since most reactions depend on the concentration
of reactants, the rate changes as they are used
up - The rate at any particular moment is called the
instantaneous rate - It can be calculated from a concentration versus
time plot
14The progress of the reaction A ? B. The number of
A molecules (in red) decreases with time while
the number of B molecules (in blue) increases.
Some reaction rates are not dependent on the
concentrations
15Instantaneous Rates Changes With Time
- As reactants are consumed , the reaction slows
- The process of determining rates is important for
reproducibility
16The Rate Law Depends On The Concentrations Used
- rate kreactantorder
- k is a reaction rate constant, a measure of time
efficiency. (high values of k mean high
efficiency). - k must be determined experimentally
- Each experiment has its own rate law
- The rate law must be determined experimentally
17Learning Check
- The rate law for the reaction 2A B?3C is
- rate 0.045M-1s-1 AB
- if the concentration of A is 0.2M and that of B
is 0.3M, what will be the reaction rate?
rate0.045 M-1 s-1 0.20.3
rate0.0027 M/s
18Determining The Rate Law
- Determined by running the reaction under the same
conditions, varying only the concentrations of
reactants - A ratio of rate laws for each experiment allows
us to determine the orders of each reactant - The rate law is unique to temperature and
concentration conditions - The rate law cannot be predicted from the
chemical equation, but must be determined
experimentally
19Orders
- Are indicated for each reactant
- The overall reaction order is the sum of
individual reactant orders - May be negative, fractional or integers, but in
this course we will usually encounter positive
integers - Must be determined from experimental data
20- The rate of a homogeneous reaction at any instant
is proportional to the product of the molar
concentrations of the reactants raised to a power
determined from experiment
21- Consider the following reaction
- From experiment, the rate law (determined from
initial rates) is - At 0oC, k equals 5.0 x 105 L5 mol-5 s-1
- Thus, at 0oC
22- The exponents in the rate law are generally
unrelated to the chemical equations coefficients - Never simply assume the exponents and
coefficients are the same - The exponents must be determined from the results
of experiments - The exponent in a rate law is called the order of
reaction with respect to the corresponding
reactant
23- For the rate law
- We can say
- The reaction is first order with respect to
H2SeO3 - The reaction is third order with respect to I-
- The reaction is second order with respect to H
- The reaction order is sixth order overall
- Exponents in a rate law can be fractional,
negative, and even zero
24Use Rate Laws To Determine Orders
- Suppose the experimental concentration-rate data
for five experiments is
25- For experiments 1, 2, and 3 B is held constant,
so any change in rate must be due to changes in
A - The rate law says that at constant B the rate
is proportional to Am
Thus m1
26Use Rate Laws To Determine Orders 2NO(g)
O2(g) ? 2NO2(g)
- Select 2 rate laws that vary in concentration for
only one of the substances - Next choose 2 rate laws where the unknown changes
- Since we know the exponent on the other, at this
stage it doesnt matter if it changes
ratekNO2O2
y1
x2
27Determining The Value Of k
- At this stage, we can solve for k. Use any rate
law and substitute the now known orders.
ratekNO2O2
0.048M/s k0.015M20.015M
1.410-4 M-2s-1 k
28- The relationship between concentration and time
can be derived from the rate law and calculus - Integration of the rate laws gives the integrated
rate laws - Integrate laws give concentration as a function
of time - Integrated laws can get very complicated, so only
a few simple forms will be considered
29Zero-Order Reactions
- Ratek
- Plot of reactant vs. time will be linear
- The equation of the line will be AA0-kt
- A amount remaining after elapsed time, t.
- Aooriginal amount
- Diffusion controlled - usually are fast reactions
in viscous media - Rate is independent of concentrations of
reactants, but the reaction still requires
reactants
30Learning Check
- The rate law for the reaction of A?B is zero
order in A and has a rate constant of 0.02 M/s.
If the reaction starts with 1.50 M A, how much is
present 15 seconds after the reaction begins?
31Learning Check
- The rate law for the reaction of A?2B is zero
order in A and has a rate constant of 0.12 M/s.
If the reaction starts with 1.50 M A, after what
time will the concentration of A be 0.90M?
32First Order Reactions
- RatekA1
- Typically these reactions are decomposition type,
or radioactive decay - If the rate law is specified as dA/dtkA or
Integrating the equation gives us
33Learning Check
- The radioactive decay of a new atom occurs so
that after 21 days, the original amount is
reduced to 33. What is the rate constant for
the reaction in s-?
k 0.0528 da-1
k 6.1110-7 s-1
34- Graphical methods can be used to determine the
first-order rate constant, note
35- A plot of lnAt versus t gives a straight line
with a slope of -k
The decomposition of N2O5. (a) A graph of
concentration versus time for the decomposition
at 45oC. (b) A straight line is obtained from a
logarithm versus time plot. The slope is negative
the rate constant.
36- The amount of time required for half of a
reactant to disappear is called the half-life,
t1/2 - The half-life of a first-order reaction is not
affected by the initial concentration
37Half-Life Of First Order Rxn
- In monitoring decay processes, a half-life (t
1/2) is often recorded, rather than k. (carbon
dating) - t 1/2 is the time needed for exactly half of the
substance to decay. At this time, AA0/2
38Learning Check
- The half-life of I-132 is 2.295h. What
percentage remains after 24 hours?
A .0711
0.302 h-1 k
39Second Order Reaction
- Are of several types RatekA2, RatekA1B1
and RatekA2B0, etc - The integrated equation is of the form
40Learning Check
- The rate constant for the second order reaction
2A?B is 5.310-5 M-1s-1. What is the original
amount present if, after 2 hours, there is 0.35M
available?
A00.40 M
41Second Order Half-Life
- Depends on the amount present at the start of the
time period - What is the relationship between k and t1/2 for
this reaction type?
42Learning Check
- The rate constant for a second order reaction is
4.510-4 M-1s-1. What is the half-life if we
start with a reactant concentration of 5.0 M?
t1/2 440 s 7.4 min
43Collision Theory Of Reactions
- For a reaction to occur, three conditions must be
met - Reactant particles must collide
- Collision energy must be enough to break
bonds/initiate - Particles must be oriented so that the new bonds
can form
44- The minimum energy kinetic energy the colliding
particles must have is called the activation
energy, Ea - In a successful collision, the activation energy
changes to potential energy as the bonds
rearrange to for products - Activation energies can be large, so only a small
fraction of the well-orientated, colliding
molecules have it - Temperature increases increase the average
kinetic energy of the reacting particles
45- Transition state theory explains what happens
when reactant particles come together - Potential-energy diagrams are used to help
visualize the relationship between the activation
energy and the development of total potential
energy - The potential energy is plotted against reaction
coordinate or reaction progress
46Formation of the activated complex in the
reaction between NO2Cl and Cl.
NO2ClCl?NO2Cl2
47Kinetic energy distribution for a reaction at two
different temperatures. At the higher
temperature, a larger fraction of the collisions
have sufficient energy for reaction to occur. The
shaded area under the curves represent the
reacting fraction of the collisions.
48- The activation energy is related to the rate
constant by the Arrhenius equation - k rate constant
- Ea activation energy
- e base of the natural logarithm
- R gas constant 8.314 J mol-1 K-1
- T Kelvin temperature
- A frequency factor or pre-exponential factor
49Working With The Arrhenius Equation
- Linear Form To determine the Ea and A value
Ratio form Can be used when A isnt known.
50Learning Check
- Given that k at 25C is 4.6110-1 M/s and that at
50C it is 4.6410-1, what is the activation
energy for the reaction?
208 J/molEa
51Reaction Mechanisms
- Tell what happens on the molecular level, and in
what order - Tell us which steps in a reaction are fast and
slow - The rate determining step is the slowest step of
the reaction that accounts for most of the
reaction time - Elementary steps sum to the overall reaction
52Elementary Steps
53Intermediates And Catalysts
- Because catalysts interact with the reactant,
they will appear in the mechanism recognizable by
their presence in an early step and their
regeneration in subsequent step - Intermediates are temporary products recognizable
by their formation in an early step and their
subsequent reaction in a later step
54Learning Check
- The reaction mechanism that has been proposed for
the decomposition of H2O2 is - H2O2 I- ? H2O IO- (slow)
- H2O2 IO- ? H2O O2 I- (fast)
- Which is the rate determining step?
- Are there any intermediates?
step 1
IO-
55Rate Laws And Mechanisms
- The majority of the reaction time is taken by the
rate determining step - Those substances which appear in this step have
the greatest effect on the reaction rate - The observed rate law usually matches the rate
law based on the rate determining step where the
order of each reactant is its stoichiometric
coefficient
56Learning Check
- The reaction mechanism that has been proposed for
the decomposition of H2O2 is - H2O2 I- ? H2O IO- (slow)
- H2O2 IO- ? H2O O2 I- (fast)
- What is the expected rate law?
ratekH2O2I-
57Learning Check
- The reaction A 3 B ? D F was
studied and the following mechanism was finally
determined - A B ? C (fast)
- C B ? D E (slow)
- E B ? F (very fast)
- What is the expected rate law?
ratekCB or kAB2
58- Consider the reaction
- The mechanism is thought to be
- The second step is the rate-limiting step, which
gives
59- N2O2 is a reactive intermediate, and can be
eliminated from the expression - The first step is a fast equilibrium
- At equilibrium, the rate of the forward and
reverse reaction are equal
60- Substituting, the rate law becomes
- Which is consistent with the experimental rate law
61Catalysts
- Speed a reaction, but are not consumed by the
reaction - May appear in the rate law
- Lower the Ea for the reaction.
- May be heterogeneous or homogeneous
62Catalytic Actions
- May serve to weaken bonds through induction
- May serve to change polarity through amphipathic
/ surfactant effects - May reduce geometric orientation effects
- Heterogeneous catalyst reactant and product
exist in different states. - Homogeneous catalyst reactants and catalyst
exist in the same physical state
63Heterogeneous catalysts