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Ch 15 Kinetics: The Study of Reaction Rates

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Title: Ch 15 Kinetics: The Study of Reaction Rates


1
Ch 15 Kinetics The Study of Reaction Rates
  • Brady Senese, 4th Ed.

2
Chapter 15 Kinetics
  • The speed with which the reactants disappear and
    the products form is called the rate of the
    reaction
  • A study of the rate of reaction can give detailed
    information about how reactants change into
    products
  • The series of individual steps that add up to the
    overall observed reaction is called the reaction
    mechanism

3
  • There are five principle factors that influence
    reaction rates
  • Chemical nature of the reactants
  • Ability of the reactants to come in contact with
    each other
  • Concentration of the reactants
  • Temperature
  • Availability of of rate-accelerating agents
    called catalysts

4
  • Chemical nature of the reactants
  • Bonds break and form during reactions
  • The most fundamental difference in reaction rates
    lie in the reactants themselves
  • Some reactions are fast by nature and others slow
  • Ability of the reactants to meet
  • Most reactions require that particles (atoms,
    molecules, or ions) collide before the reaction
    can occur
  • This depends on the phase of the reactants

5
  • In a homogeneous reaction the reactants are in
    the same phase
  • For example both reactants in the gas (vapor)
    phase
  • In a heterogeneous reaction the reactants are in
    different phases
  • For example one reactant in the liquid and the
    second in the solid phase
  • In heterogeneous reactions the reactants meet
    only at the intersection between the phases
  • Thus the area of contact between the phases
    determines the rate of the reaction

6

Effect of crushing a solid. When a single solid
is subdivided into much smaller pieces, the total
surface area on all of the pieces becomes very
large.
7
  • Concentration of the reactants
  • Both homogeneous and heterogeneous reaction rates
    are affected by reactant concentration
  • For example, red hot steel wool bursts into
    flames in the presence of pure oxygen
  • Temperature of the system
  • The rates for almost all chemical reactions
    increase as the temperature is increased
  • Cold-blooded creatures, such as insects and
    reptiles, become sluggish at lower temperatures
    as their metabolism slows down

8
  • Presence of a catalyst
  • A catalysts is a substance that increases the
    rate of a chemical reaction without being
    consumed
  • Enzymes are biological catalysts that direct our
    body chemistry
  • A rate is always expressed as a ratio
  • One way to describe a reaction rate is to select
    one component of the reaction and describe the
    change in concentration per unit of time

9
  • Molarity (mol/L) is normally the concentration
    unit and the second (s) is the most often used
    unit of time
  • Typically, the reaction rate has the units

10
  • By convention, reaction rates are reported as a
    positive number even when the monitored species
    concentration decreases with time
  • If the rate is known with respect to one species,
    the coefficients of the balanced chemical
    equation can be used to find the rates with
    respect to the other species

11
  • Consider the combustion of propane
  • Compared to the rate with respect to propane
  • Rate with respect to oxygen is five times faster
  • Rate with respect to carbon dioxide is three
    times faster
  • Rate with respect to water is four times faster
  • Since the rates are all related any may be
    monitored to determine the reaction rate

12
Learning Check
  • In the reaction 2A 3B ?5D We measured the rate
    of disappearance of substance A to be
    3.510-5M/s. What is the rate of appearance of
    D?
  • In the reaction 3A 2B ?C, we measured the rate
    of B. How does the rate of C relate?

8.7510-5 M/s
Rate of C1/2 rate of B
13
  • A reaction rate is generally not constant
    throughout the reaction
  • Since most reactions depend on the concentration
    of reactants, the rate changes as they are used
    up
  • The rate at any particular moment is called the
    instantaneous rate
  • It can be calculated from a concentration versus
    time plot

14

The progress of the reaction A ? B. The number of
A molecules (in red) decreases with time while
the number of B molecules (in blue) increases.
Some reaction rates are not dependent on the
concentrations
15
Instantaneous Rates Changes With Time
  • As reactants are consumed , the reaction slows
  • The process of determining rates is important for
    reproducibility

16
The Rate Law Depends On The Concentrations Used
  • rate kreactantorder
  • k is a reaction rate constant, a measure of time
    efficiency. (high values of k mean high
    efficiency).
  • k must be determined experimentally
  • Each experiment has its own rate law
  • The rate law must be determined experimentally

17
Learning Check
  • The rate law for the reaction 2A B?3C is
  • rate 0.045M-1s-1 AB
  • if the concentration of A is 0.2M and that of B
    is 0.3M, what will be the reaction rate?

rate0.045 M-1 s-1 0.20.3
rate0.0027 M/s
18
Determining The Rate Law
  • Determined by running the reaction under the same
    conditions, varying only the concentrations of
    reactants
  • A ratio of rate laws for each experiment allows
    us to determine the orders of each reactant
  • The rate law is unique to temperature and
    concentration conditions
  • The rate law cannot be predicted from the
    chemical equation, but must be determined
    experimentally

19
Orders
  • Are indicated for each reactant
  • The overall reaction order is the sum of
    individual reactant orders
  • May be negative, fractional or integers, but in
    this course we will usually encounter positive
    integers
  • Must be determined from experimental data

20
  • The rate of a homogeneous reaction at any instant
    is proportional to the product of the molar
    concentrations of the reactants raised to a power
    determined from experiment

21
  • Consider the following reaction
  • From experiment, the rate law (determined from
    initial rates) is
  • At 0oC, k equals 5.0 x 105 L5 mol-5 s-1
  • Thus, at 0oC

22
  • The exponents in the rate law are generally
    unrelated to the chemical equations coefficients
  • Never simply assume the exponents and
    coefficients are the same
  • The exponents must be determined from the results
    of experiments
  • The exponent in a rate law is called the order of
    reaction with respect to the corresponding
    reactant

23
  • For the rate law
  • We can say
  • The reaction is first order with respect to
    H2SeO3
  • The reaction is third order with respect to I-
  • The reaction is second order with respect to H
  • The reaction order is sixth order overall
  • Exponents in a rate law can be fractional,
    negative, and even zero

24
Use Rate Laws To Determine Orders
  • Suppose the experimental concentration-rate data
    for five experiments is

25
  • For experiments 1, 2, and 3 B is held constant,
    so any change in rate must be due to changes in
    A
  • The rate law says that at constant B the rate
    is proportional to Am

Thus m1
26
Use Rate Laws To Determine Orders 2NO(g)
O2(g) ? 2NO2(g)
  • Select 2 rate laws that vary in concentration for
    only one of the substances
  • Next choose 2 rate laws where the unknown changes
  • Since we know the exponent on the other, at this
    stage it doesnt matter if it changes

ratekNO2O2
y1
x2
27
Determining The Value Of k
  • At this stage, we can solve for k. Use any rate
    law and substitute the now known orders.

ratekNO2O2
0.048M/s k0.015M20.015M
1.410-4 M-2s-1 k
28
  • The relationship between concentration and time
    can be derived from the rate law and calculus
  • Integration of the rate laws gives the integrated
    rate laws
  • Integrate laws give concentration as a function
    of time
  • Integrated laws can get very complicated, so only
    a few simple forms will be considered

29
Zero-Order Reactions
  • Ratek
  • Plot of reactant vs. time will be linear
  • The equation of the line will be AA0-kt
  • A amount remaining after elapsed time, t.
  • Aooriginal amount
  • Diffusion controlled - usually are fast reactions
    in viscous media
  • Rate is independent of concentrations of
    reactants, but the reaction still requires
    reactants

30
Learning Check
  • The rate law for the reaction of A?B is zero
    order in A and has a rate constant of 0.02 M/s.
    If the reaction starts with 1.50 M A, how much is
    present 15 seconds after the reaction begins?
  • AA0-kt
  • A1.3M

31
Learning Check
  • The rate law for the reaction of A?2B is zero
    order in A and has a rate constant of 0.12 M/s.
    If the reaction starts with 1.50 M A, after what
    time will the concentration of A be 0.90M?
  • AA0-kt
  • t5 s

32
First Order Reactions
  • RatekA1
  • Typically these reactions are decomposition type,
    or radioactive decay
  • If the rate law is specified as dA/dtkA or
    Integrating the equation gives us

33
Learning Check
  • The radioactive decay of a new atom occurs so
    that after 21 days, the original amount is
    reduced to 33. What is the rate constant for
    the reaction in s-?

k 0.0528 da-1
k 6.1110-7 s-1
34
  • Graphical methods can be used to determine the
    first-order rate constant, note

35
  • A plot of lnAt versus t gives a straight line
    with a slope of -k

The decomposition of N2O5. (a) A graph of
concentration versus time for the decomposition
at 45oC. (b) A straight line is obtained from a
logarithm versus time plot. The slope is negative
the rate constant.
36
  • The amount of time required for half of a
    reactant to disappear is called the half-life,
    t1/2
  • The half-life of a first-order reaction is not
    affected by the initial concentration

37
Half-Life Of First Order Rxn
  • In monitoring decay processes, a half-life (t
    1/2) is often recorded, rather than k. (carbon
    dating)
  • t 1/2 is the time needed for exactly half of the
    substance to decay. At this time, AA0/2

38
Learning Check
  • The half-life of I-132 is 2.295h. What
    percentage remains after 24 hours?

A .0711
0.302 h-1 k
39
Second Order Reaction
  • Are of several types RatekA2, RatekA1B1
    and RatekA2B0, etc
  • The integrated equation is of the form

40
Learning Check
  • The rate constant for the second order reaction
    2A?B is 5.310-5 M-1s-1. What is the original
    amount present if, after 2 hours, there is 0.35M
    available?

A00.40 M
41
Second Order Half-Life
  • Depends on the amount present at the start of the
    time period
  • What is the relationship between k and t1/2 for
    this reaction type?

42
Learning Check
  • The rate constant for a second order reaction is
    4.510-4 M-1s-1. What is the half-life if we
    start with a reactant concentration of 5.0 M?

t1/2 440 s 7.4 min
43
Collision Theory Of Reactions
  • For a reaction to occur, three conditions must be
    met
  • Reactant particles must collide
  • Collision energy must be enough to break
    bonds/initiate
  • Particles must be oriented so that the new bonds
    can form

44
  • The minimum energy kinetic energy the colliding
    particles must have is called the activation
    energy, Ea
  • In a successful collision, the activation energy
    changes to potential energy as the bonds
    rearrange to for products
  • Activation energies can be large, so only a small
    fraction of the well-orientated, colliding
    molecules have it
  • Temperature increases increase the average
    kinetic energy of the reacting particles

45
  • Transition state theory explains what happens
    when reactant particles come together
  • Potential-energy diagrams are used to help
    visualize the relationship between the activation
    energy and the development of total potential
    energy
  • The potential energy is plotted against reaction
    coordinate or reaction progress

46

Formation of the activated complex in the
reaction between NO2Cl and Cl.
NO2ClCl?NO2Cl2
47

Kinetic energy distribution for a reaction at two
different temperatures. At the higher
temperature, a larger fraction of the collisions
have sufficient energy for reaction to occur. The
shaded area under the curves represent the
reacting fraction of the collisions.
48
  • The activation energy is related to the rate
    constant by the Arrhenius equation
  • k rate constant
  • Ea activation energy
  • e base of the natural logarithm
  • R gas constant 8.314 J mol-1 K-1
  • T Kelvin temperature
  • A frequency factor or pre-exponential factor

49
Working With The Arrhenius Equation
  • Linear Form To determine the Ea and A value

Ratio form Can be used when A isnt known.
50
Learning Check
  • Given that k at 25C is 4.6110-1 M/s and that at
    50C it is 4.6410-1, what is the activation
    energy for the reaction?

208 J/molEa
51
Reaction Mechanisms
  • Tell what happens on the molecular level, and in
    what order
  • Tell us which steps in a reaction are fast and
    slow
  • The rate determining step is the slowest step of
    the reaction that accounts for most of the
    reaction time
  • Elementary steps sum to the overall reaction

52
Elementary Steps
53
Intermediates And Catalysts
  • Because catalysts interact with the reactant,
    they will appear in the mechanism recognizable by
    their presence in an early step and their
    regeneration in subsequent step
  • Intermediates are temporary products recognizable
    by their formation in an early step and their
    subsequent reaction in a later step

54
Learning Check
  • The reaction mechanism that has been proposed for
    the decomposition of H2O2 is
  • H2O2 I- ? H2O IO- (slow)
  • H2O2 IO- ? H2O O2 I- (fast)
  • Which is the rate determining step?
  • Are there any intermediates?

step 1
IO-
55
Rate Laws And Mechanisms
  • The majority of the reaction time is taken by the
    rate determining step
  • Those substances which appear in this step have
    the greatest effect on the reaction rate
  • The observed rate law usually matches the rate
    law based on the rate determining step where the
    order of each reactant is its stoichiometric
    coefficient

56
Learning Check
  • The reaction mechanism that has been proposed for
    the decomposition of H2O2 is
  • H2O2 I- ? H2O IO- (slow)
  • H2O2 IO- ? H2O O2 I- (fast)
  • What is the expected rate law?

ratekH2O2I-
57
Learning Check
  • The reaction A 3 B ? D F was
    studied and the following mechanism was finally
    determined
  • A B ? C (fast)
  • C B ? D E (slow)
  • E B ? F (very fast)
  • What is the expected rate law?

ratekCB or kAB2
58
  • Consider the reaction
  • The mechanism is thought to be
  • The second step is the rate-limiting step, which
    gives

59
  • N2O2 is a reactive intermediate, and can be
    eliminated from the expression
  • The first step is a fast equilibrium
  • At equilibrium, the rate of the forward and
    reverse reaction are equal

60
  • Substituting, the rate law becomes
  • Which is consistent with the experimental rate law

61
Catalysts
  • Speed a reaction, but are not consumed by the
    reaction
  • May appear in the rate law
  • Lower the Ea for the reaction.
  • May be heterogeneous or homogeneous

62
Catalytic Actions
  • May serve to weaken bonds through induction
  • May serve to change polarity through amphipathic
    / surfactant effects
  • May reduce geometric orientation effects
  • Heterogeneous catalyst reactant and product
    exist in different states.
  • Homogeneous catalyst reactants and catalyst
    exist in the same physical state

63
Heterogeneous catalysts
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