Title: Air, Gas and Mist Drilling
1PETE 689 Underbalanced Drilling (UBD)
Lesson 5 Air, Gas and Mist Drilling Read UDM
Chapter 2.1-2.4, Pages 2.1-2.74
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2Air, Gas, and Mist Drilling
- Circulating Pressures.
- Equipment design.
- Operating procedures.
- Limitations of Dry Air Drilling.
- Natural Gas Drilling.
- Mist Drilling.
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3Circulating Pressures
- Calculating standpipe pressure starts with
predicting the pressure just below the bit, and
working your way back to the surface.
4. Pi
2. Pb
3. Pa
Pressure Calculation Steps for Pure Gas Fluid
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4Bit Pressure Drop
- As air flows through the jets, it expands in
response to the decrease in pressure and its
velocity increases. - Once the pressure drop exceeds a certain level,
the air velocity reaches the prevailing speed of
sound.
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5Bit Pressure Drop
- At this point, the air cannot expand any faster
and the upstream pressure becomes independent of
the downstream pressure. - This implies that under sonic discharge
conditions the standpipe pressure is independent
of the annular pressure.
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6Bit Pressure Drop
The condition for the onset of sonic flow in
ideal gases is
Pa 2 Pb k1
-k K-1
Pa upstream pressure at the onset of sonic
flow, psia. Pb downstream pressure. k
ratio of specific heat at constant
pressure to that at constant volume. For air,
k 1.4 and Pa 1.89Pb
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7Bit Pressure Drop
- If the upstream pressure is more than 1.89 times
the annulus pressure beneath the bit, flow
through the bit will be sonic.
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8Upstream Bit Pressure Sonic Flow
G TaR 2 k1 0.5 An
Sgk k1
Pa
1-k
G mass flow rate of air in lbm/s An
total area of the bit nozzles, sq.in. Ta air
temperature above the bit, 0R R the
universal gas constant, 53.3 ft lbf/lbm 0R for
air. S gas gravity ( 1 for air). g
gravitational constant, 32.17 ft/s2
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9Upstream Bit Pressure Sonic Flow
Noting that the density of air under standard
conditions is 0.0764 lbm/cu.ft. the above
equation reduces to
GTa0.5 An
QTa0.5 An
Pa 1.88 0.00239 Q
air flow rate (scfm).
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10Upstream Bit PressureSub-sonic Flow
If the air flow velocity through the jets remains
sub-sonic, the pressure above the bit is related
to the mass flow rate and the annulus pressure
beneath the bit by
R ( k-1) G2Tb 2gSAn2Pb2
K K-1
Pa Pb 1
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11Upstream Bit Pressure Sub-sonic Flow
For air this becomes Tb Temperature
below the bit, 0R ?g Gas density at STP,
lbm/cu.ft. ?air 0.0764 at STP, lbm/cu.ft.
0.236 G2Tb 3.5 An2Pb2
Pa Pb 1
Q?g 60
G
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12Upstream Bit Pressure Sub-sonic Flow
The circulating air cools as it expands through
the bit. Assuming ideal behavior, the temperature
decrease can be estimated from Indicating
that the absolute air temperature below the bit
will be approximately 17 lower than that above
the bit if flow through the jets is sonic.
Pb Pa
K-1 k
Tb Ta
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13Standpipe Pressure
v
Pa2 ß Tav2 (e 2ah/Tav 1) e
2ah/Tav
Ps
S 53.3
a
1.625 x 10-6Q2 Di5.333
ß
Di internal diameter of the drillstring, ft.
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14Steps To Predicting Standpipe Pressure
- Assess whether flow through bit is sonic or
sub-sonic. - If sonic, the pressure above the bit is
determined with equation 2.21 - This value is used in equation 2.25 to predict
standpipe pressure.
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15Steps To Predicting Standpipe Pressure
- If flow through the bit is sub-sonic, the annulus
pressure below the bit must be first predicted
(Angels analysis, etc) using equation 2.12. - The pressure above the bit is determined by
equation 2.23. - This value is used in Equation 2.25 to determine
standpipe pressure.
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16Important Point
- When air drilling, large changes in
- annulus pressure may result in smaller
- changes in standpipe pressure, or in the
- case of sonic flow through the bit, no
- change in standpipe pressure at all.
- Hole problems that lead to an increase
- in annulus pressure may be indicated by
- small or no changes in standpipe pressure.
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17Important Point
- It is very important to monitor the
- standpipe pressure closely and react
- promptly to unanticipated changes.
- It is important to know if flow through
- the bit is sonic or not.
- If flow is sonic, standpipe pressure will
- not change with changes in annulus
- pressure.
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18Example
- 8.1/2 hole at 6000 drilled with
- 4.1/2 drillpipe air rate is 1,400 scfm.
Penetration rate ranges up to - 300 ft/hr. Bit has no nozzles in one example
and three 14/32s in the other.
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19Predicted bottomhole annular and standpipe
pressure at various penetration rates in a 6,000
foot dry, air drilled hole.
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20Predicted standpipe pressure as functions of
penetration rate, for a bit with and without
nozzles, in a 6,000 foot deep, air drilled hole.
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21Equipment Design
- Compressor output is often expressed in standard
cubic feet per minute, scfm. - Common output ratings are 750 to 1,000 cfm.
- Altitude (and corresponding atmospheric pressure)
has an effect on the actual output of compressors.
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22Compressor Design(Assuming that air behaves as
an ideal gas)
14.7 ( T1 460) 520 P1
Vt Vo
The air delivery rate, Qo, expressed in scfm, can
be found from
520 P1 14.7 (T1460)
Qo Q
Appendix A includes a table showing atmospheric
pressure at differing elevations.
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23Normal Atmospheric Pressure at Different Altitudes
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24Effect Of Elevation On Compressor Output
- At 6,000 above sea level the ambient pressure is
11.8 psia. - At this elevation, a compressor rated at 1,000
scfm free air delivery will deliver only 803 scfm
if the ambient temperature is 600F. - At ambient temperature 6,000 elevation, the
delivery rate will drop to 745 scfm.
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25Compressor Rating
- Single stage compressors typically have a maximum
discharge pressure of - 135 psi.
- Multi-stage compressors have discharge pressures
from 250 - 350 psi. - Boosters will be required for standpipe pressures
up to 1,500 psi.
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26Mist And Formers Pump
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27Blooie Lines
- Diameter too large will not carry cuttings
efficiently to the reserve pit. - Too small, additional pressure imposed downhole.
- Blooie line cross-section should be at least
equal to that in the annulus over the longest
section of the hole to be drilled with air.
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28Frictional pressure losses down two different 150
foot long blooie lines
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29 Blooie Line
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30Measurement of Air Injection Rate
An orifice meter should be installed between the
compressor and the mist injector to measure the
air injection rate. Fb orifice flow factor,
(Appendix B) Fg (1/s) 0.5 S Gas gravity, (1
for air). Remember to add the prevailing
atmospheric pressure to the gauge pressure to
obtain the absolute pressure.
v
520 hwPf Tf
Q Fb Fg
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31Meter chart from a well in the Arkoma Basin. The
drillstring became stuck at 345 a.m. while
drilling at 10,845 feet.
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32Operating Procedures
- Unloading a well with air.
- Dmax Pmax/0.433 .
- Dmax maximum water interval to be
- unloaded by air compressors.
- Pmax delivery pressure of the air system.
- It is, however unusual to unload more than 2,000
of water at any one time.
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33Limitations of Dry Air Drilling
- Water inflows.
- Downhole fires.
- Wellbore instability.
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34Water Inflows
Mud ring formed from formation water wetting the
cuttings. Cuttings stick together and accumulate
at the shoulder on the top of the BHA,
Drillstring and the walls of the hole.
Cuttings mixed with a small amount of water will
form a mud ring at the top of the drill collars
where hole cleaning is critical.
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35Downhole Fires
Effect of pressure on combustible concentrations
of natural gas in air
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36Reverse Circulation Air Drilling Advantages
- Reduced Damage to Permeable formations.
- Quality and size of drill cuttings is improved.
- Wellbore integrity is improved
- Less air volume required.
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37Reverse Circulation Air Drilling Disadvantages
- Greater likelihood of cuttings plugging the bit.
- Surface equipment needs improvement.
- Large inflows above the bit may cause problems
circulating down the annulus.
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38Natural Gas Drilling
v
?c ?f 3Cd?f
Vt 4gdc
Vt Terminal Velocity (ft/s). g
Gravitational acceleration, 32.17 ft/sec2 dc
Characteristic particle diameter, ft. Cd Drag
coefficient. ?c Density of cuttings,
lbm/ft3 ?f Density of fluid, lbm/ft3
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39Terminal Velocity Of Natural Gas At Atmospheric
Pressure
Vtg Vtair (1/S)0.5
Vtg terminal velocity in natural
gas. Vtair Terminal velocity in air. S
Specific gravity gas.
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40Natural Gas Drilling
- Lower density of natural gas than air results in
- Lower BHP.
- Lower drag forces.
- Higher required circulation rates.
- Non-ideal behavior of natural gas is not usually
a problem since operating pressures are low (lt
2,200 psi) and ideal behavior can be assumed.
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41Natural Gas Injection Rate
- A first order estimate of the minimum injection
rates can be derived by taking Angels figures
for air drilling at the appropriate depth and
penetration rate and dividing these by the square
root of the gass specific gravity. - Usually acceptable in practice.
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42Mist Drilling
- Liquid volumes are only
- 1 to 2 percent at the prevailing temperature
and pressure.
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43For A Lightened Drilling Fluid
VgP VgP VmP VgP
VfP VsP
FgP
g gas
VfP VfP VmP VgP
VfP VsP
FfP
Eq. 2.35
f liquid
VsP VsP VmP VgP
VfP VsP
FsP
P solids
FgP FfP FsP 1
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44For A Lightened Drilling Fluid
- We can assume that the gaseous phase acts as an
ideal gas. - Solid and liquid phases are incompressible.
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45For A Lightened Drilling Fluid
Po P
VgP Vgo VP Vo V VsP VsoVs
Eq. 2.37
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46Substituting Eq. 2.37 into 2.35
Po P
Vgo Vgo Vf Vs
FgP
Po P
From this, the gas fractional at pressure is
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47Substituting Eq. 2.37 into 2.35
Fgo Fgo (Fo Fso)
FgP
P Po
Fgo Fgo (1- Fgo)
P Po
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48For The Liquid And Solid Volume Fractions
Fo (1-Fgo) (Fgo)
FfP
P Po
Fgo (1-Fgo) (Fgo)
FsP
P Po
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49Mixture Density (mist)
Vmo VmP
?mP ?mo
Assuming that the gaseous phase obeys the ideal
gas law and the solid and liquid are
incompressible,
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50Mixture Density (mist)
?mo ( Vgo V Vs) Vgo V Vs
?mP
Po P
?moVmo VmoFo VmoFso VmoFgo
Po P
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51Mixture Density (mist)
Finally
?mo 1-Fgo 1 -
?mP
Po P
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52Example Mist Drilling
- Liquid is metered at 10.7 BPH (1cfm)
- Dry air injection rate 2,000 scfm
- Standpipe pressure 210 psig
- Liquid volume fraction at atmospheric pressure
is - 1cfm/(2,000 scfm 1cfm)5 x 10-4 .05
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53Example cont
- Assume atmospheric pressure 15 Psia
- (P/Po) (21015)/15 15
- VgP 133 cfm
- Substituting into equation 2.40
- FfP 7.5 x 10-3
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54Example cont
- Assume that there is a water inflow of 96.3 BWPH
at BHP 135 psig - Assume volume of cuttings is negligible.
- Total fluid volume is now 10 cfm.
- At the blooie line exit, the liquid volume
fraction will be 10/2,000 x 100 0.5 - At bottom hole conditions the liquid fraction
would be 4.78 - foam will probably form.
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55Effect Of Temperature On Mist Density
- Equation 2.37 can be re-written
Po P
T To
VgP,T Vgo
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56Effect Of Temperature On Mist Density
- BHT, in reality has little effect on bottom hole
flow rates.
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57Effect Of Temperature On Mist Density
- Depth Temp Flow rate Liquid
- 5000 140 0F 231 cfm 4.15
- 10,000 220 0F 262 cfm 3.68
- Pressure changes can result in up to 10 fold
changes in volumetric flow rates.
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58Hole Cleaning, Mist
- Water droplets act similarly to cuttings with
slip velocity of near zero - mists do not clean
the wellbore more efficiently than dry gas.
Therefore annular velocities are high. - Circulating fluid density is increased however
and may add to the frictional pressure losses.
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59Hole Cleaning, Mist
- The increased density will lower the terminal
velocity of the cuttings, but will increase the
BHP reducing the volumetric flow rate at the
bottom of the hole. - Higher air injection rates are usually required
when misting than with dry air.
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60Application Of Angels Method To Mist Drilling
- Determine the penetration rate that would
generate the same mass of cuttings as the mass of
liquid entering the well over a time period. This
includes any base liquid, foamer, and water
influx.
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61Apparent Equivalent ROP
If the total liquid rate is L (BPH) the mass flow
of liquid entering the well will be 350.5L
assuming that the liquid is water ( 62.4
lbm/ft.cu.)
350.5L 380L 169
Db2
ROP?
p Db 2 4 12
This is added to the actual anticipated
penetration rate.
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62Angels Method For Mist
- The minimum air injection rate, required for good
hole cleaning during mist drilling, is
determined either from Angels charts or from
the approximation in equation 2.17.
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63Example
- Hole size 7 7/8
- depth 5,000
- Drillpipe size 4 1/2
- Anticipated ROP 30 feet/hr
- Qo 671, N 65, H 5,000/1,000 5
- Minimum air rate for dry air
- Qa Qa NH 670 65x5 995 scfm
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64Example
- Liquid injection rate is 6 BPH.
- Water influx is 3.8 BPH.
- Total liquid rate is 9.8 BPH.
- Penetration rate that would give this mass
cuttings per hour is 60 ft/hr.
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65Example
- The minimum air rate required for dry air
drilling at a penetration rate of 90 ft/hr using
the value of N for 90 ft/hr, N 98.3 would be
1,162 scfm.
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66Limitations To Mist Drilling
- Higher air injection rates than dry gas (up to
40). - Waste water disposal.
- Wellbore instability.
- Corrosion.
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