Title: EEE 498598 Overview of Electrical Engineering
1EEE 498/598Overview of Electrical Engineering
- Lecture 4
- Electrostatics Electrostatic Shielding
Poissons and Laplaces Equations Capacitance
Dielectric Materials and Permittivity
2Lecture 4 Objectives
- To continue our study of electrostatics with
electrostatic shielding Poissons and Laplaces
equations capacitance and dielectric materials
and permittivity.
3Ungrounded Spherical Metallic Shell
- Consider a point charge at the center of a
spherical metallic shell
Electrically neutral
4Ungrounded Spherical Metallic Shell (Contd)
- The applied electric field is given by
5Ungrounded Spherical Metallic Shell (Contd)
- The total electric field can be obtained using
Gausss law together with our knowledge of how
fields behave in a conductor.
6Ungrounded Spherical Metallic Shell (Contd)
(1) Assume from symmetry the form of the
field (2) Construct a family of Gaussian surfaces
spheres of radius r where
7Ungrounded Spherical Metallic Shell (Contd)
- Here, we shall need to treat separately 3
sub-families of Gaussian surfaces
1)
2)
3)
8Ungrounded Spherical Metallic Shell (Contd)
(3) Evaluate the total charge within the volume
enclosed by each Gaussian surface
9Ungrounded Spherical Metallic Shell (Contd)
Gaussian surfaces for which
Gaussian surfaces for which
Gaussian surfaces for which
10Ungrounded Spherical Metallic Shell (Contd)
Shell is electrically neutral The net charge
carried by shell is zero.
11Ungrounded Spherical Metallic Shell (Contd)
- For
- since the electric field is zero inside
conductor. - A surface charge must exist on the inner surface
and be given by
12Ungrounded Spherical Metallic Shell (Contd)
- Since the conducting shell is initially neutral,
a surface charge must also exist on the outer
surface and be given by
13Ungrounded Spherical Metallic Shell (Contd)
- (4) For each Gaussian surface, evaluate the
integral
surface area of Gaussian surface.
magnitude of D on Gaussian surface.
14Ungrounded Spherical Metallic Shell (Contd)
- (5) Solve for D on each Gaussian surface
(6) Evaluate E as
15Ungrounded Spherical Metallic Shell (Contd)
16Ungrounded Spherical Metallic Shell (Contd)
- The induced field is given by
17Ungrounded Spherical Metallic Shell (Contd)
E
total electric field
Eapp
r
a
b
Eind
18Ungrounded Spherical Metallic Shell (Contd)
- The electrostatic potential is obtained by taking
the line integral of E. To do this correctly, we
must start at infinity (the reference point or
ground) and move in back toward the point
charge. - For r gt b
19Ungrounded Spherical Metallic Shell (Contd)
- Since the conductor is an equipotential body (and
potential is a continuous function), we have for
20Ungrounded Spherical Metallic Shell (Contd)
21Ungrounded Spherical Metallic Shell (Contd)
V
No metallic shell
r
a
b
22Grounded Spherical Metallic Shell
- When the conducting sphere is grounded, we can
consider it and ground to be one huge conducting
body at ground (zero) potential. - Electrons migrate from the ground, so that the
conducting sphere now has an excess charge
exactly equal to -Q. This charge appears in the
form of a surface charge density on the inner
surface of the sphere.
23Grounded Spherical Metallic Shell
- There is no longer a surface charge on the outer
surface of the sphere. - The total field outside the sphere is zero.
- The electrostatic potential of the sphere is zero.
24Grounded Spherical Metallic Shell (Contd)
E
total electric field
Eapp
R
a
b
Eind
25Grounded Spherical Metallic Shell (Contd)
V
Grounded metallic shell acts as a shield.
R
a
b
26The Need for Poissons and Laplaces Equations
- So far, we have studied two approaches for
finding the electric field and electrostatic
potential due to a given charge distribution.
27The Need for Poissons and Laplaces Equations
(Contd)
- Method 1 given the position of all the charges,
find the electric field and electrostatic
potential using - (A)
28The Need for Poissons and Laplaces Equations
(Contd)
? Method 1 is valid only for charges in free
space.
29The Need for Poissons and Laplaces Equations
(Contd)
- Method 2 Find the electric field and
electrostatic potential using
Gausss Law
? Method 2 works only for symmetric charge
distributions, but we can have materials other
than free space present.
30The Need for Poissons and Laplaces Equations
(Contd)
- Consider the following problem
? What are E and V in the region?
Conducting bodies
Neither Method 1 nor Method 2 can be used!
31The Need for Poissons and Laplaces Equations
(Contd)
- Poissons equation is a differential equation for
the electrostatic potential V. Poissons
equation and the boundary conditions applicable
to the particular geometry form a boundary-value
problem that can be solved either analytically
for some geometries or numerically for any
geometry. - After the electrostatic potential is evaluated,
the electric field is obtained using
32Derivation of Poissons Equation
- For now, we shall assume the only materials
present are free space and conductors on which
the electrostatic potential is specified.
However, Poissons equation can be generalized
for other materials (dielectric and magnetic as
well).
33Derivation of Poissons Equation (Contd)
34Derivation of Poissons Equation (Contd)
Poissons equation
? ?2 is the Laplacian operator. The Laplacian of
a scalar function is a scalar function equal to
the divergence of the gradient of the original
scalar function.
35Laplacian Operator in Cartesian, Cylindrical, and
Spherical Coordinates
36Laplaces Equation
- Laplaces equation is the homogeneous form of
Poissons equation. - We use Laplaces equation to solve problems where
potentials are specified on conducting bodies,
but no charge exists in the free space region.
Laplaces equation
37Uniqueness Theorem
- A solution to Poissons or Laplaces equation
that satisfies the given boundary conditions is
the unique (i.e., the one and only correct)
solution to the problem.
38Potential Between Coaxial Cylinders Using
Laplaces Equation
- Two conducting coaxial cylinders exist such that
39Potential Between Coaxial Cylinders Using
Laplaces Equation (Contd)
- Assume from symmetry that
-
40Potential Between Coaxial Cylinders Using
Laplaces Equation (Contd)
- Two successive integrations yield
- The two constants are obtained from the two BCs
41Potential Between Coaxial Cylinders Using
Laplaces Equation (Contd)
- Solving for C1 and C2, we obtain
- The potential is
42Potential Between Coaxial Cylinders Using
Laplaces Equation (Contd)
- The electric field between the plates is given
by - The surface charge densities on the inner and
outer conductors are given by
43Capacitance of a Two Conductor System
- The capacitance of a two conductor system is the
ratio of the total charge on one of the
conductors to the potential difference between
that conductor and the other conductor.
44Capacitance of a Two Conductor System
- Capacitance is a positive quantity measured in
units of Farads. - Capacitance is a measure of the ability of a
conductor configuration to store charge.
45Capacitance of a Two Conductor System
- The capacitance of an isolated conductor can be
considered to be equal to the capacitance of a
two conductor system where the second conductor
is an infinite distance away from the first and
at ground potential.
46Capacitors
- A capacitor is an electrical device consisting of
two conductors separated by free space or another
conducting medium. - To evaluate the capacitance of a two conductor
system, we must find either the charge on each
conductor in terms of an assumed potential
difference between the conductors, or the
potential difference between the conductors for
an assumed charge on the conductors.
47Capacitors (Contd)
- The former method is the more general but
requires solution of Laplaces equation. - The latter method is useful in cases where the
symmetry of the problem allows us to use Gausss
law to find the electric field from a given
charge distribution.
48Parallel-Plate Capacitor
- Determine an approximate expression for the
capacitance of a parallel-plate capacitor by
neglecting fringing.
Conductor 2
d
A
Conductor 1
49Parallel-Plate Capacitor (Contd)
- Neglecting fringing means to assume that the
field that exists in the real problem is the same
as for the infinite problem.
z
V V12
z d
V 0
z 0
50Parallel-Plate Capacitor (Contd)
- Determine the potential between the plates by
solving Laplaces equation.
51Parallel-Plate Capacitor (Contd)
52Parallel-Plate Capacitor (Contd)
- Evaluate the electric field between the plates
53Parallel-Plate Capacitor (Contd)
- Evaluate the surface charge on conductor 2
- Evaluate the total charge on conductor 2
54Parallel-Plate Capacitor (Contd)
55Dielectric Materials
- A dielectric (insulator) is a medium which
possess no (or very few) free electrons to
provide currents due to an impressed electric
field. - Although there is no macroscopic migration of
charge when a dielectric is placed in an electric
field, microscopic displacements (on the order of
the size of atoms or molecules) of charge occur
resulting in the appearance of induced electric
dipoles.
56Dielectric Materials (Contd)
- A dielectric is said to be polarized when induced
electric dipoles are present. - Although all substances are polarizable to some
extent, the effects of polarization become
important only for insulating materials. - The presence of induced electric dipoles within
the dielectric causes the electric field both
inside and outside the material to be modified.
57Polarizability
- Polarizability is a measure of the ability of a
material to become polarized in the presence of
an applied electric field. - Polarization occurs in both polar and nonpolar
materials.
58Electronic Polarizability
electron cloud
- In the absence of an applied electric field, the
positively charged nucleus is surrounded by a
spherical electron cloud with equal and opposite
charge. - Outside the atom, the electric field is zero.
nucleus
59Electronic Polarizability (Contd)
Eapp
- In the presence of an applied electric field, the
electron cloud is distorted such that it is
displaced in a direction (w.r.t. the nucleus)
opposite to that of the applied electric field.
60Electronic Polarizability (Contd)
- The net effect is that each atom becomes a small
charge dipole which affects the total electric
field both inside and outside the material.
dipole moment (C-m)
polarizability (F-m2)
61Ionic Polarizability
negative ion
positive ion
- In the absence of an applied electric field, the
ionic molecules are randomly oriented such that
the net dipole moment within any small volume is
zero.
62Ionic Polarizability (Contd)
Eapp
- In the presence of an applied electric field, the
dipoles tend to align themselves with the applied
electric field.
63Ionic Polarizability (Contd)
- The net effect is that each ionic molecule is a
small charge dipole which aligns with the applied
electric field and influences the total electric
field both inside and outside the material.
dipole moment (C-m)
polarizability (F-m2)
64Orientational Polarizability
- In the absence of an applied electric field, the
polar molecules are randomly oriented such that
the net dipole moment within any small volume is
zero.
65Orientational Polarizability (Contd)
Eapp
- In the presence of an applied electric field, the
dipoles tend to align themselves with the applied
electric field.
66Orientational Polarizability (Contd)
- The net effect is that each polar molecule is a
small charge dipole which aligns with the applied
electric field and influences the total electric
field both inside and outside the material.
dipole moment (C-m)
polarizability (F-m2)
67Polarization Per Unit Volume
- The total polarization of a given material may
arise from a combination of electronic, ionic,
and orientational polarizability. - The polarization per unit volume is given by
68Polarization Per Unit Volume (Contd)
- P is the polarization per unit volume. (C/m2)
- N is the number of dipoles per unit volume. (m-3)
- p is the average dipole moment of the dipoles in
the medium. (C-m) - aT is the average polarizability of the dipoles
in the medium. (F-m2)
69Polarization Per Unit Volume (Contd)
- Eloc is the total electric field that actually
exists at each dipole location. - For gases Eloc E where E is the total
macroscopic field. - For solids
70Polarization Per Unit Volume (Contd)
- From the macroscopic point of view, it suffices
to use
electron susceptibility (dimensionless)
71Dielectric Materials
- The effect of an applied electric field on a
dielectric material is to create a net dipole
moment per unit volume P. - The dipole moment distribution sets up induced
secondary fields
72Volume and Surface Bound Charge Densities
- A volume distribution of dipoles may be
represented as an equivalent volume (qevb) and
surface (qesb) distribution of bound charge. - These charge distributions are related to the
dipole moment distribution
73Gausss Law in Dielectrics
- Gausss law in differential form in free space
- Gausss law in differential form in dielectric
74Displacement Flux Density
- Hence, the displacement flux density vector is
given by
75General Forms of Gausss Law
- Gausss law in differential form
- Gausss law in integral form
76Permittivity Concept
- Assuming that
- we have
- The parameter e is the electric permittivity or
the dielectric constant of the material.
77Permittivity Concept (Contd)
- The concepts of polarizability and dipole moment
distribution are introduced to relate microscopic
phenomena to the macroscopic fields. - The introduction of permittivity eliminates the
need for us to explicitly consider microscopic
effects. - Knowing the permittivity of a dielectric tells us
all we need to know from the point of view of
macroscopic electromagnetics.
78Permittivity Concept (Contd)
- For the most part in macroscopic
electromagnetics, we specify the permittivity of
the material and if necessary calculate the
dipole moment distribution within the medium by
using
79Relative Permittivity
- The relative permittivity of a dielectric is the
ratio of the permittivity of the dielectric to
the permittivity of free space