Title: Comparison of Alternatives
1Comparison of Alternatives
2Introduction
- What will we learn in the class?
- Defining Investment Alternatives.
- Defining the Planning Horizon.
- Developing Cash Flow Profiles.
- Specifying the MARR.
3Introduction
- Most organizations, including Lamar, go through a
"Capital Budgeting" cycle, which means the
organization is deciding what projects to fund
for the coming budget period (usually a physical
year). - In most cases, several projects are considered at
one time. Only a few will be selected for
funding. - If your organization had 100,000 to spend, it is
likely that several projects could be funded.
Why? - By spreading out your money, you diversify your
investments and reduce your risk. - If one of the investments goes bad, then you
still have the remaining investments to provide
returns, therefore reducing your risk.
4Introduction
- An alternative is a collection of zero or more
investments (projects to be considered). - The null alternative is to do no investments.
- What is the danger of doing nothing?
- If the number of independent investments is m,
then 2m alternatives can be formed. - What is meant by mutually exclusive?
- Mutually exclusive alternatives means the
alternatives cannot occur together.
5Introduction
For example assume there are 3 independent
investments, A, B and C. Then there are 23 8
alternatives to select from. The alternatives are
best shown in Boolean table as follows
6Introduction
Alternative 1 is to do none of the investment
opportunities Alternative 2 is to do investment A
but not to do B or C. Alternative 3 is to do
investment B but not to do A or C. Alternative 4
is to do investment C but not to do A or B.
Alternative 5 is to do investments A and B but
not to do C. Alternative 6 is to do investments
A and C but not to do B. Alternative 7 is to do
investments B and C but not to do A. Alternative
8 is to do investments A, B and C.
Assumes Projects are independent Enough money
exists for all projects
7Introduction
Dependencies Mutually exclusive - A are mutually
exclusive if A and B cannot occur together
Contingent - Suppose project B is contingent on
project A. If you select B, then you must also
select A. If you select A, then you do not have
to select B.
8Introduction
Suppose that projects A and B are mutually
exclusive. What changes must we make to our
Boolean Table?
9Introduction
Suppose that project C was contingent on A.
What changes must we make to our Boolean Table?
For a more complete discussion of developing
investment alternatives see example 5.2 and Table
5.1 on page 146
10Introduction
- If PWj lt 0, do we reject it immediately?
- No. Why? PWj could be a contingent project that
has a huge PW. - For example
- Mach 3 razors. Might be sold as a loss, but once
customers have it, Gillet will profit from
selling the blades. - PWj could be thrown out immediately if it is not
contingent on other projects (it is independent)
or other projects are not contingent upon it
11Introduction
- If an investment decision involves more than one
project or investment options then it is wise to
follow the systematic procedure of page 143. - Define the set of feasible mutually exclusive
alternatives. - Define the planning horizon.
- Develop cash flow profiles for each alternative.
- Specify the MARR to be used.
- Compare the alternatives using a specified
measure of worth. - Perform supplementary analyses. (simulation,
scenarios - not in this course) - Select the preferred alternative.
12Defining The Planning Horizon
- Why can defining the planning horizon present a
major challenge? - Because it is common for the individual projects
which make upon alternative to each have a
different life length. - A simple answer does not exist.
13Defining The Planning Horizon
- Four common methods for dealing with unequal
lives as presented at the bottom of page 149 are
as follows - Least common multiple of lives for the set of
feasible alternatives, denoted T. - Shortest life among alternatives, denoted Ts.
- Longest life among alternatives, denoted Tl.
- Some other period of time.
- None of these methods is completely satisfactory
and this problem must be carefully solved by the
engineer using sound logic. - Illustrations of each of the four methods are
presented in Table 5.3 on page 152-153.
14Defining The Planning Horizon
- Working life of equipment actual period of time
the equipment is capable of being used - Depreciable life of equipment allowable period
of time for depreciating the asset - Length of the planning horizon may have no
relationship to these time periods. - Only a time period for comparing alternatives
- Should be realistic
- Must be the same for each alternative
15Defining The Planning Horizon
- Least common multiple
- Each alternative's cash flow profile is assumed
to repeat in the future until a time is reached
when all alternatives under consideration
conclude at the same time. - Relying on this approach alone is not advised.
- Shortest life
- Considers each alternative based on the shortest
life on the alternatives under consideration. - What is wrong with this approach?
- It ignores the cash flows in years beyond
16Defining The Planning Horizon
- Longest life
- Alternatives with shorter life spans must be
replaced by new alternatives when their time
expires. - What is wrong with this approach?
- Since predicting what technology will be
available at that time, this method is not used
often.
17Example 5.3
Alternative 1 No investment required, probably
just keep on doing what we are doing Alternative
2 30,000 in revenues, 10,000 in costs and 20,000
in net cash flow for 6 years Alternative 3
various amounts in revenues, 7500 in costs and
various amounts in net cash flow for 5 years
18Example 5.3
What if we use the least common multiple
approach? The least common multiple for T 3, 5,
and 6 30. Thus Alternative 1 is repeated 10
times, Alternative is repeated 6 times and
alternative 3 is repeated 5 times. What are the
drawbacks to this approach? Inflation and
technological improvements are ignored. What if
we use the shortest life approach? Years 4-5 for
Alternative 2 and years 4-6 for Alternative 3 are
ignored. What if we use the longest life
approach? How do we project the cash flow for
Alternative 1 in years 4-6? We could assume that
more used equipment is bought in year 4, or that
a new unit is bought in year 4.
19Example 5.4
- Consider Figure 5.1 on page 154.
- Based on the numerical results, Alternative 2 is
the best choice - Never trust numbers alone!
- Balance logic with economic numbers.
6000
4500
5000
4000
3500
3500
3500
3000
2000
1000
1
2
3
4
1
2
3
4
5
6
Alternative 1
Alternative 2
Figure 5.1
4000
5000
20Example 5.4
- Why should we consider Alternative 1?
- Shorter time period thus less risk in later
years. - The longer you try to predict into the future,
the less accurate the prediction - Only about 300 difference between alternatives -
6 years in the future - so these projects are
very close - How did the engineers come up with these cash
flows in figure 5.1? - Educated guesses and calculations - thus a lot of
error - and more risk!
21Developing Cash Flow Profiles
- Specify the MARR to be used.
- Organizations normally decide at a high level of
management the value of the minimum attractive
rate of return (MARR). - For Example, Wal-Marts MARR 21 (Spring 2003)
- The author presents a worked example in section
5.4, Developing cash flow profiles. - You should read example 5.5 on page 155 and the
associated Tables 5.5 and 5.6 on page 156.
22Developing Cash Flow Profiles
- What issues contribute to determining the MARR?
- This number is a function of companys
- Cost of capital
- Risk level
- Desired minimum return after accounting for the
cost of capital and risk (profit). - Once the MARR is decided upon it is normally
passed down to the engineers who must design
projects whose projected return exceeds the MARR.
23MARR
- The value of the MARR should be greater than the
cost of capital. - Should represent the opportunity cost associated
with investing the candidate alternatives as
opposed to other available alternatives.
24The Cost Of Capital
- It costs money to obtain money for investment.
- Funding may come from two types
- Debt
- Equity funds.
- Two common debt investments are loans and bonds.
- The interest paid for the use of money is a cost
of capital. - Interest is deductible from income for tax
purposes
25The Cost Of Capital
The cost of capital (after taxes) for funds
obtained by bank or other loans is given by
Equation 5.1. kl (1 r/m)m 1 (1 T)
. . . Eq. 5.1 r loans nominal annual interest
rate m number of payment periods Where the
bracketed term is the effective interest rate
payable on the loan and T is the organizations
tax rate. Any business interest is tax
deductable, thus we use (1-T)
26The Cost Of Capital
The equation for bonds, Eq. 5.2, is exactly the
same as the equation for loans because bonds are
loans. kb (1 r/m)m 1 (1 T) . . .
Eq. 5.2 The cost of equity capital is given by
Equation 5.3 and 5.4. Equation 5.3 is the cost of
capital for common stock. The cost of capital for
common for common stock is ks D / Ps . . .
Eq. 5.3 D is the annual dividend per share of
stock and Ps is the price per share. The cost of
capital for retained earnings is kr D / Ps .
. . Eq. 5.4 Why is this a measure that will
change quickly? Based on stock price, which
changes everyday.
27The Cost Of Capital
- Why is the cost of capital for retained earnings
the same as the cost of capital for common stock? - Because the money belongs to the same person
the stockholder. - An organizations total cost of capital is a
weighted average of the cost of debt and equity
as shown in equation 5.5. - ka kl pl kb pb ks ps kr pr . . . Eq. 5.5
- Where ki is the proportion of the organizations
assets obtained by funding source i (loans,
bonds, stock, or retained earnings) and - kl kb ks kr 1
28Example 5.8
29Example 5.8
30Approaches to Establish MARR
- Add a fixed percentage of return to the firms
cost of capital - Average rate of return over the past 5 years is
used as this years MARR - Use different MARR for different planning
horizons - Use different MARR for different magnitudes of
initial investment - Use different MARR for new ventures rather than
for cost-improvement projects - Use as a management tool to stimulate or
discourage capital investments depending on the
overall economic condition of the firm - Use the average stockholders return on
investment for all companies in the same industry
group
31Comparison of Alternatives
- There are two approaches for evaluating
alternatives - Ranking Approach
- Incremental Approach.
- The ranking approach can be use only with the PW,
AW and FW criterion. - The incremental approach is a little more complex
and time consuming but it can be used with all
criterion. (PW, AW, FW, I, I, and SIR) - The ranking approach simply calculates the PW, AW
or FW of each feasible alternative and selects
the one that Ranks the highest. - The incremental approach requires a number of
steps which are presented in the flow chart of
Figure 5.5 on page 167.
32Comparison of Alternatives
- The process of solving an investment analysis
problem involving more than one project can be
described as follows - Determine the time horizon.
- Determine the set of feasible mutually exclusive
alternatives. - Number the alternatives so that the lowest
costing alternative is number 1 and the second
lowest is number 2 and so on. - Compare alternatives 1 and 2 by obtaining the
cash flow of alternatives 2 minus the cash flow
of alternative 1 and applying the appropriate
measure of merit (PW, AW, FW, IRR, ERR, or SIR)
to the differential cash flow. - Select the preferred alternative and compare it
with the next higher numbered alternative.
Continue until the highest numbered alternative
has been considered. - Consider Example 5.9, p.167 - 168
33Comparison of Alternatives
5.6.1 Present Worth method 5.6.2 Annual Worth
Method 5.6.3 Future Worth Method All of these
methods are the same, meaning they will product
the same final decision.
34Comparison of Alternatives
An example application of the incremental rate of
return is Problem 5.10 page 230-231(See Table
12.1 below). A firm has available four proposals
A, B, C and D. Proposal A is contingent on
acceptance of either Proposal C or Proposal D. In
addition , Proposal C is contingent on Proposal
D, while D is contingent on either Proposal A or
Proposal B. The firm has a budget limitation of
500,000. The cash flows are as
follows Table 12.1 Problem 5.10 Data
35Comparison of Alternatives
- Specify the net cash flow profile associated with
each alternative. - Clearly show the alternatives to be considered.
- Use an incremental approach and internal rate of
return to determine the preferred alternative
assuming the MARR is 20. - Table 1
- 2.2 Boolean Table of
Alternatives
36Comparison of Alternatives
Table 12.2 shows that alternatives 2(D), 3(C),
4(CD), 7(BC), 9(A), 11(AC) and 13(A B) are
all infeasible because of contingencies.
Alternatives 14, 15 and 16 are over budget. So of
the sixteen alternatives only alternatives 1, 5,
6, 8, 10 and 12 are feasible. The next step is to
renumber the feasible alternatives from lowest
investment required. In doing this alternative 10
becomes 2, 12 becomes 3, 5 becomes 4, 6 becomes 5
and 8 becomes 6. These alternatives have cash
flows as shown in Table 12.3.
37Comparison of Alternatives
Table 12.3 Cash Flows for Feasible
Alternatives The analysis is presented below the
Table 12.4. The cash flow for alternative 2 minus
1 is simply the cash flow of alternative 2 since
alternative 1 is the null alternative and has no
cash flow. IRR2-1 PW2-1(i) -288,000
88,000(P/A, i, 5) 5,000(P/G, i, 5)
65,000(P/F, i, 5) 0 I used the Excel function
IRR(range) to solve for i and obtained 24.
Since 24 is greater than the MARR select the
higher costing alternative.
38Comparison of Alternatives
Table 12.4 Incremental Cash Flow of Alternatives
2 minus 1 Now compare alternatives 3 and 2
IRR3-2 PW3-2(i) -50,000 10,000(P/A, i,
5) The rate of return of 3 2 is 0 because the
positive cash flows equal the negative cash
flows. Since 0 is less than the MARR select 2,
the lower costing alternative.
39Comparison of Alternatives
Now compare alternatives 4 and 2. The cash flow
and IRR from Excel are as shown in Table 12.5
below. The IRR is 29 which is greater than the
MARR. Therefore, choose alternative 4 and
compare 5 with 4. The cash flow and IRR for 5
minus 4 is 16. Since the IRR5-4 is less than the
MARR select 4 and compare 6 and 4. Again the
IRR6-4 is 8 which is below the MARR so select 4.
Alternative 4 is the final selection, since there
are no additional feasible alternatives Table
12.5 Incremental Cash Flows
40Replacement Analysis
- Two choices
- Maintain the status quo
- Various replacement options
- Why consider replacement Analysis?
- Current asset (defender) may have a number of
deficiencies such as high set-up costs, excessive
maintenance, declining production efficiency,
high energy consumption or physical impairment - Example Your car is becoming expensive to
operate or may need a major repair. Ryan replaced
his 1997 Grand Am when the transmission started
to slip (thus a major was likely because a
transmission overhaul would be needed).
41Replacement Analysis
- Why consider replacement Analysis?
- Potential replacement assets (challengers) may
take advantage of new technology and be easily
set-up, maintained a low cost, high in output,
energy efficient, and posses increased
capabilities - Environmental impacts
- Customer preference change present equipment
may not be capable of adapting to new demands - Low utilization sell equipment and outsource
such as lease, rent, or contract to another
company - What are some examples of challengers who fit
this description?
42Replacement Analysis
- Is replacement Analysis similar to alternative
comparison? - Yes- they follow the same systematic seven-step
approach outlined in Ch5 - All six consistent measures of investment worth
are also applicable - What are some confounding issues related to
Replacement Analysis? - Personnel may have emotional attachment to the
current equipment (particularly if they were
involved in selecting, installing or operating
it). - Attempts to hold on to old equipment is often an
attempt to recover sunk costs, which are past
costs that are unrecoverable and should not be
considered in a replacement analysis - To include sunk costs penalizes or burdens the
potential replacement asset and unfairly favors
the current asset
43Replacement Analysis
- What should sunk costs be excluded from
Replacement Analysis? - Sunk costs penalizes or burdens the potential
replacement asset and unfairly favors the current
asset - What are the two approaches commonly used in
replacement analysis? - Cash flow approach actual cash flows associated
with keeping, purchasing or leasing an asset are
used directly - Outsider viewpoint approach cash flow profiles
faced by an objective outsider are used - Are the two approaches equivalent?
- Both approaches are mathematically equivalent and
yield consistent decisions
44Replacement Analysis Cash Flow Approach
- Cash flow insider viewpoint
- No additional cost of capital if asset is kept
(in most cases) - Trade-in allowance for most assets
- How are cash flows developed?
- Decision maker must determine how much money
will be spent and received if an alternative is
adopted - Past costs sunk costs - which are not included
in economic studies that deal with the future - Decision maker determines planning horizon, but
the shortest life is often chosen because the
existing asset will not likely last as long as
the new asset under consideration
45Replacement Analysis Cash Flow Approach
- For replacement analysis, the planning horizon is
a window through which only the cash flows that
occur during the planning horizon can be seen - What about a salvage value that occur after the
planning horizon? - Even though a salvage value may occur later than
the planning horizon, it is included in the
calculations
46Replacement Analysis Outsider Viewpoint Approach
- Outsider viewpoint is preferred in some cases
because it forces the decision maker to view both
the existing asset and its challengers from an
objective point of view as would an outsider - Outsiders
- Have no existing assets
- Free to choose either a used asset (the defender)
available for the price of its market value - Considers the salvage value of the existing asset
to be its investment cost if it is retained in
service - Since the retention of the defender is equivalent
to a decision to forego the receipt of the
salvage value, then an opportunity cost is
assigned to the defender
47Replacement Analysis Outsider Viewpoint Approach
- What if there is little correspondence between
the market value and the trade in value? - Usually a high trade in value indicates that the
seller is using an inflated selling price - If a purchase was made without a trade in, then
the selling price would likely be lower. - When using the Outsider Approach decrease the
inflated selling price of the asset by the
difference between the trade in value and a lower
market value
48Example 5.32
49Example 5.32
A chemical plant owns a filter press that was
purchased 3 years ago for 30,000. Actual OM
expenses (excluding labor) for the press have
been 4,000 , 5,000 and 6,000 each of the past 3
years. It is anticipated that the filter press
can be used for 5 more years and salvaged for
2,000. The undepreciated worth of the press as
indicated on our accounting books is 12,600,
however, new technological developments have
produced new presses that are very competitive,
thus the current press is worth only 9,000. A
new filter press is available and can be
purchased for 36,000. It has anticipated life of
10 years. Alternative 1 is to keep the old
press and Alternative 2 is to replace the old
press with the new press.
50Example 5.32
Since the old press can only be used for 5 more
years, the planning horizon will be 5 years. The
salvage value of the new press in 5 years is
anticipated to be 12,000. Note that the 9,000
market value of the existing press is applied as
a positive cash flow for the challenger since the
old unit will be sold if the new unit is
purchased. Annual worth using a MARR
15 AW1(15) -7000 1000(AG, 15, 5)
2000(A\F, 15, 5) AW1(15) -7000 1000(1.7228)
2000(.1483) AW1(15) 8426.20/year
51Example 5.32
Annual worth using a MARR 15 AW2(15)
-27000(AP, 15, 5) 1000(AG, 15, 5)
12000(AF, 15, 5) AW2(15) -27000(.2983)
1000(1.7228) 12000(.1483) AW2(15)
7997.30/year -8426.20 7997.30 428.90/year,
so it is recommended that the new filter press be
purchased and the old press be sold Note that
the 30,000 first cost for the Old press was not
considered because it occurred in the past and
the 12,600 book value was not considered. Using
the 9,000 which the old press can be sold
for Sunk cost 12600 9000 3600 To add
this cost to the new press in cash flow analysis
gives the old press an unfair advantage.
52Example 5.32
53Example 5.33
If we use a 10 year planning horizon, we
recommend that the old press be replaced in 5
years. In 5 years, we anticipate that a filter
press will be available for 31,000.
54Example 5.33
Annual worth using a MARR 15 AW1(15)
-7000(PA, 15, 5) 1000(AG, 15, 5) -
29000(PF, 15, 5) 1000(PG, 15, 5)(PF, 15, 5,)
15000(PF, 15, 10)(AP, 15, 10) AW1(15)
-7000(3.3522) 1000(5.7751) - 29000(.4872)
1000(5.7751)(.4972) 15000(.2472)(.1993) AW1(15
) 8534.56/year AW2(15) -27000(PA, 15,
5) 1000(AG, 15, 5) 3000(AF, 15,
10) AW2(15) -27000(.1993) 1000(3.3832)
3000(.0493) AW2(15) -8616.40/year
8534.56/year (-8616.40/year) 81.84/year thus
choose Alternative 1
55Example 5.33
What are the risks associated with a 10 year
planning horizon? The degree of uncertainty in
our forecast of the cash flows
56Example 5.35
Consider Example 5.32 with the Outsider Approach.
The present filter press has a market value of
9,000, a life of 5 years and a salvage value of
2,000 at that time. The challenger has a cost of
36,000, a life of 10 years and an estimated
salvage values at any point in time as given in
the table. Use a 5 year planning horizon and MARR
15.
57Example 5.32
58Example 5.35
Annual worth using a MARR 15 AW1(15)
-9000(AP, 15, 5) 7,000 1000(AG, 15, 5)
2000(AF, 15, 5) AW1(15) -9000(.2983) 7,000
1000(1.7228) 2000(.1483) AW1(15)
11,110.90/year AW2(15) -36,000(AP, 15, 5)
1000(AG, 15, 5) 12000(AF, 15, 5) AW2(15)
-36,000(.2983) 1000(1.7228)
12000(.1483) AW2(15) -10,682.00/year
11,110.90/year (-10,682.00/year) 428.90/year
thus buy the new press, which is the same
conclusion we had in Example 5.32
59Replacement Analysis
First, for the cash flow of alternative 2 in
Table 5.20, the cash flow in year 1 should be
-1000. The minus sign was omitted in my edition
of the book. Second, in the calculation of
annual worth for alternative 1 (below Table 5.20
on page 217), there should be an open parentheses
in front of the P/A, 15, 5) and the sign
following the P/A, 15, 5) should be minus not
plus. Three lines down there is a missing open
bracket it should look like this
(-7,000(3.3522) (1,000)(5.7751) . . . You
should read and understand examples 5.33 and 5.34
on pages 216 218. The next section covers the
Outsider Viewpoint approach for replacement
analysis problems. This approach assumes you own
neither the current asset (Defender) nor the
possible replacement asset (Challenger). If this
were the case then you would need to pay the
current market value for the asset that in
reality you already own.
60Replacement Analysis
Table 5.22 on page 219 shows that the different
in cash flows between the two alternatives is the
same whether you use the cash flow approach (See
Table 5.19) or the outsider viewpoint
approach. You should read and understand example
5.35 and 5.36 on pages 219 and 220, respectively
61Replacement Analysis
- Problem 5.24. p. 233
- The ABC Company is considering three investment
proposals, A, B and C. Proposals A and B are
mutually exclusive, and proposal C is contingent
on Proposal B. The cash flow data for the
investments over a 10-year planning horizon are
given below. The ABC Company has a budget limit
of 1 million for investments of the type being
considered currently. MARR 15 - a) Clearly specify the alternatives available and
their net cash flow profiles. -
- b) Determine which alternative ABC's decision
maker should select. Use a ranking approach and
the present worth method. -
- c) Determine which alternative ABC's decision
maker should select. Use a incremental approach
and the present worth method.
62Example Section 5.5.1
Consider the following capital structure
63Example Section 5.5.1
The tax rate is 20. Determine the firm's
overall average after-tax cost of capital. kl
(1 r/m) m - 1(1-T) (1 .12/2) 2 -
1(1-.20) 0.09888 kb (1 r/m) m -
1(1-T) (1 .16/4) 4 - 1(1-.20)
0.13589 ks D/Ps 8.00/40 0.20 or 20 ka
kl pl kb pb ks ps kr pr 0.09888(3/17)
0.13589(2/17) 0.20(12/17) ka .01744
.015987 .14117 .1746 17.46